HELP PLS WUICK! GIVING OUT BRAINLIST

Answer:

15

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

plug 16 in for c so it's 16 -9 = 7

Answer:

17.25

Step-by-step explanation:

8556 / 32 / 15.5 = 17.25

Answer:

The circumference is 9. And the other one is 10

Answer:

557.8 square inches

each square is 5". the base is 4x4 squares- so 20 inches square. 20x20= 400sq inches.

the semicircle at the top is 20 inches in diameter, which makes the radius 10 inches.

pi× 10^2= 314.16.

duvide that by 2 to get a semicircle- 157.8

so, the total area is the 400+ 157.8, for a total area of 557.8 square inches

Answer:

The best estimate for the length of gribbles is of 3.1 mm.

The margin of error for this estimate, with 95% confidence, is of 0.2 mm.

The 95% confidence interval is between 2.9 mm and 3.3 mm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

Best estimate for the length of gribbles

The best estimate is the sample mean, that is 3.1 mm.

Margin of error:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 50 - 1 = 49

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.01

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 2.01\frac{0.72}{\sqrt{50}} = 0.2[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for this estimate, with 95% confidence, is of 0.2 mm.

Confidence interval:

The lower end of the interval is the sample mean subtracted by M. So it is 3.1 mm - 0.2 mm = 2.9 mm

The upper end of the interval is the sample mean added to M. So it is 3.1 mm + 0.2 mm = 3.3 mm

The 95% confidence interval is between 2.9 mm and 3.3 mm.

Answer:

117π or 367.56634047

Step-by-step explanation:

Volume = π × r² × h          (r=radius and h=height)

Volume = π × 4² × 13

Volume = π × 9 × 13

Volume = π × 117

Volume = 117π

Answer/Step-by-step explanation:

There are actually two methods that can be used to calculate AC (x):

1. Using Pythagorean Theorem

2. Using Trigonometric Function

1. Using Pythagorean Theorem, we have:

x = √(15² + 20²)

x = √625

x = 25 units

2. Using Trigonometric Function:

Reference angle = 37°

Adjacent = 20

Opposite = 15

Hypotenuse = x

Apply SOH:

Sin 37 = Opp/Hyp

Sin 37 = 15/x

x × Sin 37 = 15

x = 15/sin 37

x = 24.9246021 ≈ 25 units (nearest whole number)

Answer:

The number he think of is 15

Step-by-step explanation:

Let x be the number

3x + 9 = 54

x = (54-9) / 3

x = 15

The number he think of is 15

Answer:

15

Step-by-step explanation:

3x + 9 = 54

x = (54-9) / 3

x = 15

Answer:

B

Step-by-step explanation:

i got it right

The probability that the Yankees will lose when they score fewer than 5 runs is 0.821 (nearest to the thousandth).

For two events A and B:

The chain rule states that the probability that A and B both occur is given by:

[tex]P(A \cap B) = P(A)P(B|A) = P(B)P( A|B)[/tex]

Lets suppose here that:

Suppose A' and B' are their complementary events, then we have:

Then, by the given data, we have:

[tex]P(A) = 0.56\\P(B) = 0.61\\P(A' \cap B') = 0.32[/tex]

We've to find [tex]P(A' | B')[/tex]

Using chain rule, we have:

[tex]P(A'|B') = \dfrac{P(A' \cap B')}{P(B')}[/tex]

Since P(B') = 1-P(B) = 100.61 = 0.39, therefore, we get:

[tex]P(A'|B') = \dfrac{P(A' \cap B')}{P(B')} = \dfrac{0.32}{0.39} \\\\P(A'|B') \approx 0.821[/tex]

Thus, the probability that the Yankees will lose when they score fewer than 5 runs is 0.821

Learn more about probability here:

brainly.com/question/1210781

Answer:

0.09 = 9% probability that the student is proficient in neither reading nor mathematics

Step-by-step explanation:

We solve this question treating the events as Venn probabilities.

I am going to say that:

Event A: A student is proficient in reading.

Event B: A student is proficient in mathematics.

A total of 82% of the students were found to be proficient in reading

This means that [tex]P(A) = 0.82[/tex]

74% were found to be proficient in mathematics

This means that [tex]P(B) = 0.74[/tex]

65% were found to be proficient in both reading and mathematics.

This means that [tex]P(A \cap B) = 0.65[/tex]

What is the probability that the student is proficient in neither reading nor mathematics?

This is:

[tex]P = 1 - P(A \cup B)[/tex]

In which

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

With the values that we have:

[tex]P(A \cup B) = 0.82 + 0.74 - 0.65 = 0.91[/tex]

Then

[tex]P = 1 - P(A \cup B) = 1 - 0.91 = 0.09[/tex]

0.09 = 9% probability that the student is proficient in neither reading nor mathematics

Answer:

i dont know im just doing this for the points

Area of square pyramid:

⅓×[base area]×height

according to the question

⅓×[8×8]×12

simplify parentheses:

⅓×64×12

Simplify fraction

64×4

Simplify multiplication

256

256      did the test on k12 Answer:

c

Step-by-step explanation:

Answer:

x = 43.9

Step-by-step explanation:

sin 20° = 15/x

0.3420 = 15/x

x = 43.86

Answer:

Step-by-step explanation:

x^2 - 4x + 20 = 0

x^2 - 4x = -20

x^2 = 4x - 20

x = 2x - 4.47

-3x = -4.47

x = roughly 1.5

Answer:

Round to the nearest hundredth.

Answer:

160.57

Step-by-step explanation:

The formula is:

[tex]angle/360 *\pi *radius^2[/tex]

Because you find the total area of the circle, but the sector only represents NPQ/360 so you have to multiply the area with that.

[tex]46/360 * \pi *20^2[/tex] = [tex]23/180 * \pi *400[/tex]

= [tex]160.57029...[/tex]

Rounded to the nearest hundredth this would be 160.57

Answer: The scale factor is 3:1 because if you look at the T Point to T', it has a space of 3. Pardon for any mistakes. Good Luck!

Step-by-step explanation:

Answer:

x = 121

Step-by-step explanation:

all angles sum = 540

87 + 92 + 105 + 135 = 419

540 - 419 = 121

Answer:

The system of equation that models the projectile of the two balls is option;

C. y = -16·x² + 12·x + 3

y = -16·x² + 9·x + 3.25

Step-by-step explanation:

The general equation for vertical (upward) motion under gravity is presented as follows;

h - h₀ = u·t + 1/2·g·t²

Where;

h = The final height reached

h₀ = The initial height

u = The initial velocity

g = The acceleration due to gravity ≈ -32 feet/second

t = The time taken

We can rewrite the above equation with different letters for the variables as follows;

h = y,

h₀ = y₀, and

t = x

Therefore, we have;

y - y₀ = u·x - 1/2 × 32 × x²

y = u·x - 1/2 × 32 × x² + y₀ = u·x - 16· x² + y₀

y = u·x - 16· x² + y₀ = -16·x² + u·x + y₀

y = -16·x² + u·x + y₀

For Tara, we have;

u = 12 feet/second

y₀ = 3 feet

Therefore, we get;

y = -16·x² + 12·x + 3

For Mallory, we have;

u = 9 feet/second

y₀ = 3.25 feet

Therefore, we get;

y = -16·x² + 9·x + 3.25

The correct option is therefore;

y = -16·x² + 12·x + 3

y = -16·x² + 9·x + 3.25

A. -4, -1, 2, and 5

5,0 is not a solution to the system of linear inequalities.

Answer:

Answer: Area of a circle= πr²

Data:

diameter=11 in

ratius=diameter/2=11 in/2=5.5 in

Area of this circular plate=π(5.5 in)²=30.25π in²=30.25 * 3.141592... in²≈

≈95.0 in².

answer :  c  95.0 in²

9514 1404 393

Answer:

  D and E are each 62 cm

Step-by-step explanation:

Apparently, you want the total width of the bookcases to match the width of the wall.

  132 +92 +108 +w +w = 456

  332 +2w = 456

  2w = 124 . . . . . . . subtract 332

  w = 62 . . . . . . . . . divide by 2

The width of bookcases D and E is 62 cm.

Answer:

Step-by-step explanation:

B.28.1

Answer:

It's BBBBBBBBBBBBBBBBB

9514 1404 393

Answer:

Step-by-step explanation:

The slant height is read from the diagram as 20.1 km.

The radius is half the diameter, so is 9.0 km.

The lateral area is ...

  A = πrs = π(9.0 km)(20.1 km) ≈ 568.3 km²

__

Desmos uses r for a special purpose, so we have used r₁ to signify the radius of the cone. The "round" function works only to round to an integer, so special effort must be used to get rounding to 1 decimal place.

The solutions of x in the equation are -5 and -1

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

The equation is given as

(x + 3)^2 - 4 = 0

Add 4 to both sides of the equation

So, we have

(x + 3)^2 = 4

Take the square root of both sides

x + 3 = ±2

Subtract 3 from both sides

x = - 3 ± 2

Evaluate

x = (-3 - 2, -3 + 2)

This gives

x = (-5, -1)

Hence, the solutions of x in the equation are -5 and -1

Read more about equations at

https://brainly.com/question/13763238

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