Help!!! Will mark brainiest! Wrong answers will be reported, thx!

Answer:

[tex]y=-2.5x-9[/tex]

Step-by-step explanation:

One is given the following equation.

[tex]5x + 2y = 12[/tex]

The problem asks one to find a line that is parallel to this one, and passes through the point: [tex](-2, 4)[/tex]. The equation of the given line is in the standard format. The easiest approach to solve this problem is to change the equation of the given line into the slope-intercept format. The solve intercept format follows the following general equation:

[tex]y=mx+b[/tex]

Where (m) is the slope of the line and (b) is the y-intercept. Manipulate the given equation such that it follows this format:

[tex]5x+2y=12\\2y=12-5x\\y=6-2.5x\\\\y=-2.5x+6[/tex]

One property of parallel lines is that they have the same slope. Therefore, if one uses the slope-intercept format to represent the slope of the parallel line, then one can state the following:

[tex]y=-2.5x+b[/tex]

Substitute a given point on this line ([tex]-2,4[/tex]) , and solve for (b) to find (b):

[tex]y=-2.5x+b\\(4)=-2.5(-2)+b[/tex]

Simplify,

[tex]4=-2.5(-2)+b\\-4=5+b[/tex]

Inverse operations,

[tex]-4=5+b\\-9=b[/tex]

Substitute this back into the equation in slope-intercept form to find the equation of the parallel line:

[tex]y=-2.5x-9[/tex]

Answer:

n = 8√2

Step-by-step explanation:

It's a 30-60-90 triangle, so n = 2×4√6/√3 = 8√2

9514 1404 393

Answer:

  x + 4y = 12

Step-by-step explanation:

The perpendicular line can be found by swapping the x- and y-coefficients and negating one of them. Then those new coefficients can be used with the coordinates of the given point to find the required constant.

  line: 4x -y = 4

  perpendicular line: x +4y = constant

Through (0, 3):

  0 +4(3) = constant = 12

The perpendicular line has standard form equation x +4y = 12.

Answer:

Step-by-step explanation:

y=-1/4x+3

Answer:

Sam is 20 years old.

Answer:

[tex]{ \tt{7 {x}^{2} + 3x = 0 }} \\ { \tt{x(7x + 3) = 0}}[/tex]

Either x = 0 or ( 7x + 3 ) = 0 :

[tex]{ \tt{7x + 3 = 0}} \\ { \tt{x = - \frac{3}{7} }}[/tex]

Answer:

[tex]{ \bf{(0, \: - \frac{3}{7}) }}[/tex]

Answer:

see your answer in the image

with full detail

mark me brainlist

Step-by-step explanation:

Answer:

(3,0) , (1.0)

Step-by-step explanation:

Answer

I guess

39 different choice are available

Answer:

4 -6x^2

Step-by-step explanation:

f°g = f(g(x))

We place g(x) in for x in the function f(x)

= 4-2(g(x)) = 4-2(3x^2) = 4 -6x^2

B.4-6x²

Answer:

Solution given:

f(x)=4-2x

and

g(x)=3x²

now

f o g(x)=f(g(x))=f(3x²)=4-2*3x²=4-6x²

Answer:

it's A

Step-by-step explanation:

start at 2 on the y axis and go up 4 and right 1

Here is your Answer

Step-by-step explanation:

Ravi bought rice = 50kg

Rate it =40kg

Sold it at the rate = = 44kg

Answer:

30

Step-by-step explanation:

p=2l+2w

p=2(2w)+2w

p=4w+2w

p=6w

p=90

90=6w

15=w

Answer:

Relationship exists between price and overall score

Step-by-step explanation:

Given the data:

Brand Price Score

Bose 180 76

Scullcandy 160 76

Koss 95 69

Phillips/O'Neill 70 58

Denon 80 50

JVC 35 26

Using the correlation Coefficient calculator ; the correlation Coefficient, R = 0.875

H0 : no relationship exists

H1 : relationship exists

Using the R Coefficient ;

The test statistic :

T = r / √(1 - r²) / (n - 2)

n = 6

The test statistic :

T = 0.875 / √(1 - 0.875²) / (4)

T =0.875 / 0.05859375

T = 0.9333

The Pvalue from test statistic :

df = n - 2 ; 6 - 2 = 4

Pvalue(0.933, 4) = 0.02246

At α = 0.05

Pvalue < α ; We reject H0 ; and conclude that relationship exists between price and overall score

9514 1404 393

Answer:

  9 m

Step-by-step explanation:

The relationship between radius and circumference is ...

  C = 2πr

Daphne wants r an integer such that ...

  60 m ≥ 2πr

  r ≤ (60 m)/(2π)

  r ≤ (30/π) m ≈ 9.549 m

The largest integer radius Daphne can use is 9 meters.

Step-by-step explanation:

the answer is in the image above

Answer:

[tex]-\sqrt{5q^{3} } \times3\sqrt{35}[/tex]

[tex]-\sqrt{5} \times\sqrt{q^{3} } \times3\sqrt{5} \times\sqrt{7}[/tex]

[tex]-15\sqrt{7q^{3} }[/tex]

------------------------

Hope it helps...

have a great day!!

Answer:

58 degrees

Step-by-step explanation:

90 - 32 = 58

[tex]\rightarrow\sf((p(x) {x}^{2} + 2x + 4)( {x}^{2} + 2x + 4)) \\ = \sf {ax}^{2} + bx + c \\ = \sf(p(x) {x}^{2} {x}^{2} + p(x) {x}^{2} (2x) + p(x) {x}^{2} \times 4 + 2x \times {x}^{2} + 2x(2x) + 2x \times 4 + {4x}^{2} + 4(2x) + 4 \times 4) \\ = \sf( {x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16) \\ \rightarrow \large\boxed{\sf\red{{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}[/tex]

[tex]\large\boxed{\sf{\red{{x}^{4} p(x) + {2x}^{3} p(x) + {4x}^{2} p(x) + {2x}^{3} + {8x}^{2} + 16x + 16}}}[/tex]

[tex]\color{red}{==========================}[/tex]

✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ

✍︎ꕥᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢꕥ

✍︎ꕥᴋɪᴍ ᴀʀᴀꕥ

Answer:

116 degrees

Step-by-step explanation:

To find the answer, we must know what the sum of exterior angles are on a given shape, which is 360 degrees.

So, let's put the equation up.

8x-21+4x-13+5x-11+6x+14=360

Let's add all the x variables together to simplify it. And also add the number together too.

8x+4x+6x+5x= 23x

(-21)+(-13)+(-11)+14 = -31

The equation we have is in its initial simplified version. Let's simplify it even more to solve.

23x-31=360

Add 31 to both sides.

23x=391

Divide 23 on both sides to find x.

391/23 = x

x= 17

Let's put the value x in each exterior angle.

A= 8(17)-21 = 115 degrees

B= 6(17)+14 = 116 degrees

C= 5(17)-11 = 74 degrees

D= 4(17)-13 = 55 degrees

From the work above, we know B is the largest exterior angle, which is 116 degrees.

Hope this helps!

Cube root of the given expression [tex]\frac{16y^{4} }{x^{6} }[/tex] in simplest form is equals to [tex]\frac{2y }{x^{2} }\sqrt[3]{2y}[/tex].

" Cube root is defined as the number when multiply three times and produce result as one original number one time."

According to the question,

Given expression,

[tex]\frac{16y^{4} }{x^{6} }[/tex]

Cube root of the given expression is,

[tex]\sqrt[3]{\frac{16y^{4} }{x^{6} }} \\\\\implies \sqrt[3]{\frac{(2)^{3}(2) y^{3} (y)}{(x^{2}) ^{3} }}\\\\\implies \frac{2y}{x^{2} } \sqrt[3]{2y}[/tex]

Hence, cube root of the given expression [tex]\frac{16y^{4} }{x^{6} }[/tex] in simplest form is equals to [tex]\frac{2y }{x^{2} }\sqrt[3]{2y}[/tex].

Learn more about cube root here

https://brainly.com/question/12726345

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Answer:

B on edge

trust me bro

Answer:

Step-by-step explanation:

Answer:

Area = 12.82 miles²

Step-by-step explanation:

Area of a triangle with two adjacent sides and the inscribed angle between these side is given by,

Area = [tex]\frac{1}{2}ab[\text{sin(C)}][/tex]

By substituting the values of sides a, b and the angle C,

Area = [tex]\frac{1}{2}(5.7\times 9.3)[\text{sin}(14^{\circ})][/tex]

        = 12.82 square miles

Answer:

5000

Step-by-step explanation:

⁉️⁉️

Answer:

a variable

Step-by-step explanation:

because it varies

Answer:

x=35

Step-by-step explanation:

since the two triangles are similar, we can set up a proportion to find x:

4/14=10/x

4x=140

x=35

9514 1404 393

Answer:

  (d) enlargement with scale factor greater than 1

Step-by-step explanation:

The image is obviously larger than the pre-image, so the dilation is an enlargement. The scale factor associated with an enlargement is always greater than 1.

__

Additional comment

In this drawing, the scale factor in the vertical direction is 8/2.5 = 3.2. The scale factor in the horizontal direction is 9/3 = 3.0. The scale factors are different in the different directions.

Answer:

D.

Step-by-step explanation:

Answer:

Step-by-step explanation:

This was answered in question #24217201. It's the exact same question, but you forgot to put what parts A and B are. The answers and the work are there.

Answer:

[tex]\displaystyle \text{Function: }{y=20-3x,\\\text{Domain: }(-\infty, \infty)\text{ or }\mathbb{R}[/tex]

Step-by-step explanation:

If the boy initially had 20 cents, then the total number of cents he will have left after purchasing [tex]x[/tex] pencils is equal to the total cost of the pencils subtracted from 20. The total cost of [tex]x[/tex] pencils, in cents, is equal to [tex]3x[/tex], since each pencil is 3 cents.

Therefore, the total amount, in cents, that the boy has left, [tex]y[/tex], is equal to [tex]20-3x[/tex]:

[tex]\displaystyle \text{Equation: }\boxed{y=20-3x}[/tex]

The domain of this function is [tex](-\infty, \infty)[/tex] or all real numbers [tex]\mathbb{R}[/tex].

Answer:

A)

Step-by-step explanation:

what is C ? 6 ?

if that is the case, then my answer is A) 8

why ? because then the other 2 sides together are just as long as this third side, and we would have just a flat line with the length of 8.

every side in a triangle must be shorter than the other two sides together.

but - fully formally such a flat line could be considered a special triangle with 2 angles of 0 degrees and one angle of 180 degrees.

that is why I am asking about the missing C answer. it could be a trick question. but if C is truly 6, then yes, A is the right answer. if C is larger than 8, then C is the right answer.

The types of triangles are: equilateral, isosceles, scalene, right angled, acute angled and obtuse angled triangle.

Triangles are plane shapes with three straight sides. Triangles are classified with respect to either their length of sides, or the measure of each internal angles.

1. Classification of triangles with their length of sides:

i. Equilateral triangle: This implies a triangle with equal length of sides.

ii. Isosceles triangle: This triangle has two of its side with equal length.

iii. Scalene triangle: In this triangle, non of its sides has equal length.

2. Classification of triangles with their internal angles:

i. Acute angled triangle: This triangle has all its angles less than [tex]90^{o}[/tex].

ii. Right angled triangle: This has one of its angles to be a right angle.

iii. Obtuse angled triangle: This triangle has one of its internal angles to be greater than [tex]180^{o}[/tex].

Therefore, there are generally six types of triangles of two classes.

Resources: Set squares, triangular prism, marking board and a marker etc.

For more information: https://brainly.com/question/18075714