Helppp and explain thankyouuu

Answer:

m = -4

Step-by-step explanation:

The given expression is :

[tex](17)^{3}\cdot(289)^{-6}=(17)^{2m-1}[/tex]

We need to find the value of m

We know that, 17² = 289

So,

[tex](17)^{3}\cdot(17^2)^{-6}=(17)^{2m-1}\\\\(17)^{3}\cdot(17)^{-12}=(17)^{2m-1}[/tex]

Also,[tex]x^ax^b=x^{a+b}[/tex]

So,

[tex]17^{3-12}=17^{2m-1}\\\\17^{-9}=17^{2m-1}\\\\\implies -9=2m-1\\\\-9+1=2m\\\\-8=2m\\\\m=-4[/tex]

So, the value of m is equal to -4.

Answer:

2

Step-by-step explanation:

that is √ 14 which is 27 ×>44.2177

9514 1404 393

Answer:

  72°

Step-by-step explanation:

In a properly constructed pie chart, the proportion of the circle devoted to each section is the same as the proportion of that section to the the whole.

  (6 swim days)/(30 days) = (swim pie angle)/(360°)

Multiply by 360° to find ...

  swim pie angle = (360°)(6/30) = 72°

72° of the circle should represent swimming.

The equation is:

3n - 3 = 2n + 19

=> 3n - 2n = 19 + 3

=> n = 22

So, the answer is 22.

Answer:

Step-by-step explanation:

The perimeter of a square has a formula P = s + s + s + s or just P = 4s where s is the length of a side. If this perimeter has a number value, we can plug it in and solve for the length of each side, like this:

36 = 4s so

s = 9 cm. And there you go!

Answer:

El ancho del río es 59.9 metros.

Step-by-step explanation:

El ancho del río lo podemos calcular con la siguiente relación trigonométrica asumiendo que la torre forma un triángulo rectángulo con el río:

[tex]tan(\theta) = \frac{CO}{CA}[/tex]

En donde:

CA: es el cateto adyacente = Altura de la torre = 28.2 m

CO: es el cateto opuesto = ancho del río =?

θ: es el ángulo adyacente a CA

Dado que el ángulo de depresión (25.2°) está ubicado fuera de la parte superior de la hipotenusa del triángulo que forma la torre con la orilla opuesta del río, debemos calcular el ángulo interno (θ) como sigue:

[tex]\theta = (90 - 25.2)^{\circ} = 64.8 ^{\circ}[/tex]

Ahora, el ancho del río es:

[tex]CO = tan(\alpha)*CA = tan(64.8)*28.2 = 59.9 m[/tex]

Por lo tanto, el ancho del río es 59.9 metros.

Espero que te sea de utilidad!                  

Answer:

You'll have a closed circle at x = 2, and shading to the left

See the diagram below

=========================================================

Explanation:

The fractions here are 3/7 and 21/2. The denominators of which are 7 and 2 respectively. The LCD is 7*2 = 14.

If we multiply both sides by 14, then this will clear out the denominators and make the fractions go away.

So if we multiplied both sides by 14, then we have these steps

[tex]\frac{3}{7}(35x-14) \le \frac{21x}{2}+3\\\\14*\frac{3}{7}(35x-14) \le 14*\left(\frac{21x}{2}+3\right)\\\\14*\frac{3}{7}(35x-14) \le 14*\left(\frac{21x}{2}\right)+14*\left(3\right)\\\\6(35x-14) \le 147x+42\\\\[/tex]

--------------------------

Let's isolate x

[tex]6(35x-14) \le 147x+42\\\\6(35x)+6(-14) \le 147x+42\\\\210x-84 \le 147x+42\\\\210x-147x \le 42+84\\\\63x \le 126\\\\x \le 126/63\\\\x \le 2\\\\[/tex]

The graph of this will consist of a closed or filled in circle at x = 2. We shade to the left to represent numbers smaller than 2.

So either x = 2 or x < 2.

If we used an open hole at 2, then we wouldn't be including 2 (but we want to include this endpoint).

See the diagram below.

Answer:

I think yes

Step-by-step explanation:

12/4=3

36/12=3

-6/-2=3

and so on

Answer:

Amount of plastic need to cover paper role = 565.2 inches

Step-by-step explanation:

Given:

Diameter of paper role = 10 inch

Height of paper role = 13 inch

Find:

Amount of plastic need to cover paper role

Computation:

Radius of paper role = Diameter of paper role / 2

Radius of paper role = 10 / 2

Radius of paper role = 5 inch

Amount of plastic need to cover paper role = Total surface area of cylinder

Amount of plastic need to cover paper role = 2πr(h+r)

Amount of plastic need to cover paper role = 2(3.14)(5)(13+5)

Amount of plastic need to cover paper role = (3.14)(10)(18)

Amount of plastic need to cover paper role = 565.2 inches

Answer:

1a. The other addend of 17,300

1b. 17,300 and 11,210

1c. 17,300-11,210

1d. 17,300-11,210= 6090

1e. 6090

2a. The other factor of 954

2b. 954 and 318

2c. 954-318

2d. 954-318= 636

2e. 636

3a. The total amount of fruit Hector bought.

3b. 7 and 24

3c. 7 x 24

3d. 7 x 24 = 168

3e. 168 fruits

Answer: Choice D

Explanation:

The increase of 9.8% rounds to 10% when rounding to the nearest ten

An increase of 10% would use the multiplier 1.1

Think of it like saying 1 + 0.10 = 100% + 10%

Similarly, the 5.1% rounds to 5% and an increase of this amount will use the multiplier 1.05

So if we started with 20 items, then 20(1.1)(1.05) is the expression that estimates an increase of 10% followed by an increase of 5%. The order doesn't matter (so you could increase by 5% first, then 10% later).

Answer:

y=3x-8

Step-by-step explanation:

Answer:

57 students

Step-by-step explanation:

Since 6 students count not fit and they had to go in cars, there is a remainder of 6. Subtract that from the total, 405, and you get 399.

Then, divide that by 7, and you get the answer. 57.

Hope it helps!

Answer:

57 students

Step-by-step explanation:

405-6=399

399÷7=57

[tex]\bf \large \hookrightarrow \:( - 9) \: \times \: 5 \: \times \: 6 \: \times \: ( - 3) \\ \\ \bf \Large \hookrightarrow \: \: \: - 45 \: \times \: ( - 18) \\ \\ \bf \Large \hookrightarrow \: \: 810[/tex]

The first one because there is only one y value for every x value. The correct option is first.

To determine if a relation is a function, use the vertical line test: If any vertical line intersects the graph of the relation at more than one point, then the relation is not a function. On the other hand, if every vertical line intersects the graph of the relation at most once, then the relation is a function.

In first relation is considered a function, because each input x-value is associated with exactly one output y-value. In other words, for every x-value in the domain of the relation, there can be only one corresponding y-value in the range. Each x-value should not have more than one y-value associated with it.

Therefore, each x-value should not have more than one y-value associated with it. The correct option is first.

Learn more about Function here:

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Answer:

45

Step-by-step explanation:

x/3 + 8 =23

=> x/3 = 23-8

=> x/3 = 15

=> x = 15 x 3

x = 45

Answer:

x=45

Step-by-step explanation:

To find x isolate the variables by using the properties of equality. First, subtract 8 from both sides, [tex]\frac{x}{3} = 15[/tex]. Then multiply both sides by 3, [tex]x=45[/tex]. Finally, to check you can plug 45 back into the equation, [tex]\frac{45}{3} +8=23[/tex]. Next, solve this equation and get 23=23, since this is a true statement 45 is correct.

The value of the inverse of the function f(x) = x +3 is,

⇒ h (x) = x - 3

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Given that;

Function is,

f (x) = x + 3

Now, We can find the inverse of the function f(x) = x +3 as,

f (x) = x + 3

y = x + 3

x = y - 3

h (x) = x - 3

Thus, The value of the inverse of the function f(x) = x +3 is,

⇒ h (x) = x - 3

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Answer:

[tex](1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t + 8[/tex]

Step-by-step explanation:

Given

[tex](1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)[/tex]

Required

Solve

We have:

[tex](1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)[/tex]

Collect like terms

[tex]1.3t^3 + 0.6t^2 + 0.4t^2 - 24t- 18t + 8[/tex]

[tex]1.3t^3 + t^2 -42t + 8[/tex]

So:

[tex](1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t + 8[/tex]

Answer:

look at pic

Step-by-step explanation:

Answer:

10 kilometer/hour

Step-by-step explanation:

Average speed = Total distance travelled / Total time taken

Ardi:

Total distance travelled = 70 km

Total time taken = 35 minutes = 35/60 hour

Average speed = Total distance travelled / Total time taken

= 70 km ÷ 35/60 hr

= 70 × 60/35

= 4,200/35

= 120 kilometer/hour

Lei:

Total distance travelled = 585 km Total time taken = 9:05 - 13:35 = 4 hours 30 minutes

= 4.5 hours

Average speed = Total distance travelled / Total time taken

= 585 km / 4.5 hours

= 130 kilometer/hour

Difference, in km/h, between the average speed of their trains = Lei's train - Ardi's train

= 130 kilometer/hour - 120 kilometer/hour

= 10 kilometer/hour

Step-by-step explanation:

simply take the average of the x and y coordinates

where's the number line?

maybe u can attach it at the comments:)

Answer:

Section B

Step-by-step explanation:

Answer:

x = 140

Step-by-step explanation:

Given the equations

[tex]\frac{2}{5}[/tex] x - [tex]\frac{1}{5}[/tex] y = 98 ( multiply through by 5 to clear the fractions )

2x - y = 490 → (1)

[tex]\frac{2}{7}[/tex] x - [tex]\frac{1}{14}[/tex] y = 55 ( multiply through by 14 to clear the fractions )

4x - y = 770 → (2)

Subtract (1) from (2) term by term to eliminate y

2x + 0 = 280

2x = 280 ( divide both sides by 2 )

x = 140

Answer:

you need to learn how to "prime factor" numbers....

primes are 2,3,5,7,11,13,17....

they go on forever. ALL whole numbers can be "broken down" into a bunch of primes multiplied together.

take the fractions (top and bottom) and start dividing them bu the smallest prime, and going up until all the numbers multiplied make the original number...

15 = 3 * 5

24= 2 * 12 = 2 * 2 * 6 = 2* 2* * 2 * 6

thus   [tex]\frac{15}{24}[/tex] = [tex]\frac{3 * 5 }{2* 2* 2* 3}[/tex]  now just cancel all the SAME numbers from to to bottom

"pair them up" .... in this case only one of the threes in the bottom "takes out" one of the threes in the top

result [tex]\frac{5}{2*2*2 } = \frac{5}{8}[/tex]

~~~~~~~~~~~~~~~~~~~~

[tex]\frac{21}{35}[/tex]

21= 3 * 7

35= 5* 7

[tex]\frac{3*7}{5*7} = \frac{3}{5}[/tex]

Step-by-step explanation:

Answer:

-(cos α)/(sin α)

= -cot α

Step-by-step explanation:

use trigonometric identities

Answer:

4/7 as a decimal is 0.57142857142857.

B. 63

some simple googling would've been able to help you with this. but 0 isn't prime or composite, not sure about 1, 19 is prime, 63 is a definite composite

Answer:

(a) [tex]x\³ - 6x - 6[/tex]

(b) Proved

Step-by-step explanation:

Given

[tex]r = $\sqrt[3]{2} + \sqrt[3]{4}$[/tex] --- the root

Solving (a): The polynomial

A cubic function is represented as:

[tex]f = (a + b)^3[/tex]

Expand

[tex]f = a^3 + 3a^2b + 3ab^2 + b^3[/tex]

Rewrite as:

[tex]f = a^3 + 3ab(a + b) + b^3[/tex]

The root is represented as:

[tex]r=a+b[/tex]

By comparison:

[tex]a = $\sqrt[3]{2}[/tex]

[tex]b = \sqrt[3]{4}$[/tex]

So, we have:

[tex]f = ($\sqrt[3]{2})^3 + 3*$\sqrt[3]{2}*\sqrt[3]{4}$*($\sqrt[3]{2} + \sqrt[3]{4}$) + (\sqrt[3]{4}$)^3[/tex]

Expand

[tex]f = 2 + 3*$\sqrt[3]{2*4}*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4[/tex]

[tex]f = 2 + 3*$\sqrt[3]{8}*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4[/tex]

[tex]f = 2 + 3*2*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4[/tex]

[tex]f = 2 + 6($\sqrt[3]{2} + \sqrt[3]{4}$) + 4[/tex]

Evaluate like terms

[tex]f = 6 + 6($\sqrt[3]{2} + \sqrt[3]{4}$)[/tex]

Recall that: [tex]r = $\sqrt[3]{2} + \sqrt[3]{4}$[/tex]

So, we have:

[tex]f = 6 + 6r[/tex]

Equate to 0

[tex]f - 6 - 6r = 0[/tex]

Rewrite as:

[tex]f - 6r - 6 = 0[/tex]

Express as a cubic function

[tex]x^3 - 6x - 6 = 0[/tex]

Hence, the cubic polynomial is:

[tex]f(x) = x^3 - 6x - 6[/tex]

Solving (b): Prove that r is irrational

The constant term of [tex]x^3 - 6x - 6 = 0[/tex] is -6

The divisors of -6 are: -6,-3,-2,-1,1,2,3,6

Calculate f(x) for each of the above values to calculate the remainder when f(x) is divided by any of the above values

[tex]f(-6) = (-6)^3 - 6*-6 - 6 = -186[/tex]

[tex]f(-3) = (-3)^3 - 6*-3 - 6 = -15[/tex]

[tex]f(-2) = (-2)^3 - 6*-2 - 6 = -2[/tex]

[tex]f(-1) = (-1)^3 - 6*-1 - 6 = -1[/tex]

[tex]f(1) = (1)^3 - 6*1 - 6 = -11[/tex]

[tex]f(2) = (2)^3 - 6*2 - 6 = -10[/tex]

[tex]f(3) = (3)^3 - 6*3 - 6 = 3[/tex]

[tex]f(6) = (6)^3 - 6*6 - 6 = 174[/tex]

For r to be rational;

The divisors of -6 must divide f(x) without remainder

i.e. Any of the above values  must equal 0

Since none equals 0, then r is irrational