Answer:
Mass = 18.29 g
Explanation:
Given data:
Mass of beryllium needed = ?
Mass of nitrogen = 18.9 g
Solution:
Chemical equation:
3Be + N₂ → Be₃N₂
Number of moles of nitrogen:
Number of moles = mass/molar mass
Molar mass of nitrogen = 28 g/mol
Number of moles = 18.9 g/ 28 g/mol
Number of moles = 0.675 mol
Now we will compare the moles of nitrogen and Be.
N₂ : Be
1 : 3
0.675 : 3/1×0.675 = 2.03 mol
Mass of Be:
Mass = number of moles × molar mass
Mass = 2.03 mol × 9.01 g/mol
Mass = 18.29 g
A student working in the laboratory produces 6.81 grams of calcium oxide, CaO, from 20.7 grams of calcium
carbonate, CaCO3, according to the reaction CaCO3 → CaO + CO2. Calculate the theoretical yield and
the percent yield for the reaction. Show and/or explain your work.
Answer:
A. Theoretical yield of CaO is 11.59 g
B. Percentage yield of CaO = 58.76%
Explanation:
The following data were obtained from the question:
Mass of CaCO₃ = 20.7 g
Actual yield of CaO = 6.81 g
Theoretical yield of CaO =?
Percentage yield of CaO =?
The equation for the reaction is given below:
CaCO₃ —> CaO + CO₂
Next, we shall determine the mass of CaCO₃ that decomposed and the mass of CaO produced from the balanced equation. This can be obtained as follow:
Molar mass of CaCO₃ = 40 + 12 + (3×16)
= 40 + 12 + 48
= 100 g/mol
Mass of CaCO₃ from the balanced equation = 1 × 100 = 100 g
Molar mass of CaO = 40 + 16 = 56 g/mol
Mass of CaO from the balanced equation = 1 × 56 = 56 g
SUMMARY:
From the balanced equation above,
100 g of CaCO₃ decomposed to produce 56 g of CaO.
A. Determination of the theoretical yield of CaO.
From the balanced equation above,
100 g of CaCO₃ decomposed to produce 56 g of CaO.
Therefore, 20.7 g of CaCO₃ will decompose to produce =
(20.7 × 56)/100 = 11.59 g of CaO.
Thus, the theoretical yield of CaO is 11.59 g
B. Determination of the percentage yield.
Actual yield of CaO = 6.81 g
Theoretical yield of CaO = 11.59 g
Percentage yield of CaO =?
Percentage yield = Actual yield /Theoretical yield × 100
Percentage yield = 6.81/11.59 × 100
Percentage yield of CaO = 58.76%
what molecules must the plant take in so the process of photosynthesis can occur
Answer:
Glucose molecules
Explanation:
If a wave is traveling at 36 m/s and has a frequency of 6 Hz, what is its wavelength?
Answer:
wave length=speed*frequency
=36*6
=216 m
write few lines about luis braille
Answer:
Louis braille was a french educator and inventor of a sytem of reading and writing for use use by the blind or visually impaired . his system remains virtually unchanged to this day and is know worldwide simply as braille
What kind of intermolecular forces act between a hydrogen cyanide molecule and a potassium cation?
If there is more than one type of intermolecular force that acts, be sure to list them all, with a comma between the name of each force.
(dipole, hydrogen-bonding, dispersion, ion-dipole)
Answer:
ion-dipole
Explanation:
Let us remember that the potassium cation is an ion, a positive ion to be precise.
There is a dipole existing in the hydrogen cyanide molecule. The positive end of the dipole is on hydrogen while the negative end of the dipole is on the cyanide moiety.
The only possible interaction between the potassium cation and the hydrogen cyanide is an ion dipole interaction. The cation interacts with the cyanide moiety having a partial negative charge in the molecule.
All the iron in a 2.000 g tablet was dissolved in an acidic solution and converted to Fe2+. This was then titrated with KMnO4. The titration required 27.50 cm3 of 0.100 mol dm-3 KMnO4. Calculate the total mass of iron in the tablet and its percentage by mass.
Answer:
0.768g of Fe are in the tablet = 38.4% by mass of Fe in the tablet
Explanation:
The balanced redox equation of Fe²⁺ with KMnO₄ in acidic medium is:
5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O
Where 5 moles of Fe²⁺ react per mole of KMnO₄
The moles required of KMnO₄ are:
27.50cm³ * (1dm³ / 1000cm³) = 0.0275dm³ * (0.100mol / dm³) = 0.00275mol KMnO₄
Moles of Fe²⁺ are:
0.00275mol KMnO₄ * (5 moles Fe²⁺ / 1mol KMnO₄) = 0.01375moles of Fe²⁺
In grams (Molar mass Fe: 55.845g/mol):
0.01375moles of Fe²⁺ * (55.845g/mol) =
0.768g of Fe are in the tabletAnd percentage is:
0.768g Fe / 2.000g * 100 =
38.4% by mass of Fe in the tabletAssuming that only the listed gases are present, what would be the mole fraction of oxygen gas be for each of the following situations?
A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas that react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.
The mole fraction of oxygen gas : 0.381
Further explanationGiven
2.31 atm Oxygen
3.75 atm Hydrogen
Required
The mole fraction of Oxygen
Solution
Dalton Law's of partial pressure
P tot = P₁ + P₂ + ..Pₙ
Input the value :
P tot = P O₂ + P H₂
P tot = 2.31 atm + 3.75 atm
P tot = 6.06 atm
The mole fraction of O₂ (X O₂):
P O₂ = X O₂ x P tot
X O₂ = P O₂ / P tot
X O₂ = 2.31 /6.06
X O₂ = 0.381
The mole fraction of oxygen gas in the given mixture of oxygen and hydrogen gas is 0.381.
How do we calculate mole fraction?If the details is present in terms of partial pressure then by using the below equation, we can calculate the mole fraction as:
p = (x)(P), where
p = partial pressure
P = total pressure
x = mole fraction
Total pressure of the mixture will be calculated by adding the partial pressure of oxygen and hydrogen gases as:
P = 2.31 + 3.75 = 6.06 atm
Now mole fraction of oxygen will be calculated as:
x = 2.31 / 6.06 = 0.381
Hence mole fraction of oxygen is 0.381.
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matter can undergo chemical reactions and nuclear reactions. which properly is conserved in nuclear reactions?
Answer:change in number of atoms
Explanation:AP3X
Questlon 23 of 30
What is the term for a large group of people with similar characteristics such
as educational background and income level?
A. An interest group
B. A social class
C. A social culture
O D. A political party
SUBMIT
You want to determine the concentration of a phosphoric acid (H3PO4) solution using a standardized 0.0995 M NaOH solution. 10.00 mL of the H3PO4 solution needed to be titrated with 22.85 mL of the standardized 0.0995M NaOH solution to reach the equivalence point. What is the concentration of the H3PO4 solution
Answer:
Explanation:
H₃PO₄ + 3NaOH = Na₃PO₄ + 3 H₂O.
1 mole 3 mole
22.85 mL of the standardized 0.0995M NaOH solution will contain
.0995 x .02285 moles of NaOH
= 22.7357 x 10⁻⁴ moles of NaOH
3 moles of NaOH reacts with 1 mole of H₃PO₄
22.7357 x 10⁻⁴ moles of NaOH reacts with 1 x 22.7357 x 10⁻⁴ / 3 mole of H₃PO₄
= 7.5785 x 10⁻⁴ moles of H₃PO₄
7.5785 x 10⁻⁴ moles of H₃PO₄ is contained in 10 mL or 10⁻² L
molarity of H₃PO₄ solution = 7.5785 x 10⁻⁴ / 10⁻²
= 7.58 x 10⁻² M
= .0758 M .
1. How does cellular respiration add carbon to the
atmosphere?
The half life of iodine-125 is 60 days. What fraction of iodine-125 nuclides would be left after 360 days?
Explanation:
The half-life is the time taken for a radioactive substance to decay to half of its original composition.
Let us assume that the original amount is x atoms;
Half - life = 60days
Days Composition Half-life number
0 x 0
60 x/2 1
120 x/4 2
180 x/8 3
240 x/16 4
300 x/32 5
360 x/64 6
The fraction that would be left after 360 days will be [tex]\frac{1}{64}[/tex]
Crude oil has many applications once it has been distilled at a refinery. According to the diagram, what process is used to distill crude oil into its various components to use energy distribution?
A) separation by density
B) separation by boiling points
C) separation by the porosity of the components
D) separation by the organic content or each component
Answer:
B) separation by boiling points
Explanation:
According to the diagram depicted, crude oil is separated into its different units using boiling points.
The boiling points of a compound is the temperature at which it begins to boil. The process of fractional distillation is used in the oil industry to separate crude oil into its components. When the boiling point of a oil fraction is reached, it becomes vaporized and rises within the columnA sodium bromide solution is added to a beaker containing aqueous chlorine. What would happen?
A) Write the complete chemical equation
B) Write the dissociated ionic equation
C) Write the net ionic equation
D) List any spectator ions
Answer:
See detailed explanation.
Explanation:
Hello!
In this case, for the described chemical reaction, we can proceed as follows:
A) For the complete chemical reaction we note down every reacted and produced species as well as the proper balancing process:
[tex]2NaBr(aq)+Cl_2(aq)\rightarrow 2NaCl(aq)+Br_2(g)[/tex]
In which gaseous bromine may give off.
B) The dissociated ionic equation requires the ionization of the aqueous species in ions, expect for chlorine which is not ionized:
[tex]2Na^+(aq)+2Br^-(aq)+Cl_2(aq)\rightarrow 2Na^+(aq)+2Cl^-(aq)+Br_2(g)[/tex]
C) For the net ionic equation we cancel out the sodium ions as they are at both reactants and products:
[tex]2Br^-(aq)+Cl_2(aq)\rightarrow +2Cl^-(aq)+Br_2(g)[/tex]
D) Based on C) we infer that the spectator ions here are the sodium ions.
Best regards!
I need help. Please help with the best of your ability.
Answer:
Photosynthesis transforms light energy into chemical energy by making sugars. Cellular respiration releases the chemical energy from food by breaking down sugars.
Explanation:
I'm actually learning this in school right now
Hope this helps!
~PurpleMist
Given the molecular formula, C2H8N, write the empirical formula.
Answer:
C2H8N
Explanation:
it wont change since there is no common factor between the 2:8:1 which will give us a whole number so it stays the same
. Predict the possible products for the following reaction and include
molecular, complete ionic, and net ionic equations.
NA2SO4 (aq) +γ (BrO3)2 (aq) --->
Answer:
Introduction
As a diligent student of chemistry, you will likely encounter tons of reactions that occur in aqueous solution (perhaps you are already drowning in them!). When ions are involved in a reaction, the equation for the reaction can be written with various levels of detail. Depending on which part of the reaction you are interested in, you might write a molecular, complete ionic, or net ionic equation.
Definitions of molecular, complete ionic, and net ionic equations
A molecular equation is sometimes simply called a balanced equation. In a molecular equation, any ionic compounds or acids are represented as neutral compounds using their chemical formulas. The state of each substance is indicated in parentheses after the formula. [Huh?]
Let's consider the reaction that occurs between \text{AgNO}_3AgNO
3
start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text. When aqueous solutions of \text{AgNO}_3AgNO
3
start text, A, g, N, O, end text, start subscript, 3, end subscript and \text{NaCl}NaClstart text, N, a, C, l, end text are mixed, solid \text{AgCl}AgClstart text, A, g, C, l, end text and aqueous \text{NaNO}_3NaNO
3
start text, N, a, N, O, end text, start subscript, 3, end subscript are formed. Using this information, we can write a balanced molecular equation for the reaction:
\text{AgNO}_3(aq) + \text{NaCl}(aq) \rightarrow \text{AgCl}(s) + \text{NaNO}_3(aq)AgNO
3
(aq)+NaCl(aq)→AgCl(s)+NaNO
3
(aq)start text, A, g, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis, plus, start text, N, a, C, l, end text, left parenthesis, a, q, right parenthesis, right arrow, start text, A, g, C, l, end text, left parenthesis, s, right parenthesis, plus, start text, N, a, N, O, end text, start subscript, 3, end subscript, left parenthesis, a, q, right parenthesis
[What kind of reaction is this?]
If we could zoom in on the contents of the reaction beaker, though, we wouldn't find actual molecules of \text{AgNO}_3AgNO
3
start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, or \text{NaNO}_3NaNO
3
start text, N, a, N, O, end text, start subscript, 3, end subscript. Since \text{AgNO}_3AgNO
3
start text, A, g, N, O, end text, start subscript, 3, end subscript, \text{NaCl}NaClstart text, N, a, C, l, end text, and \text{NaNO}_3NaNO
3
start text, N, a, N, O, end text, start subscript, 3, end subscript are soluble ionic compounds, they dissociate into their constituent ions in water. For example, \text{NaCl}NaClstart text, N, a, C, l, end text dissociates into one ion of \text{Na}^+Na
+
start text, N, a, end text, start superscript, plus, end superscript for every ion of \text{Cl}^-Cl
−
start text, C, l, end text, start superscript, minus, end superscript; these ions are stabilized by ion-dipole interactions with the surrounding water molecules. [I don't get it!]
Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.
Image of crystalline sodium chloride next to image of chloride and sodium ions dissociated in water. Each chloride ion is interacting with multiple water molecules through the positive dipole of the water, and each sodium ion is interacting with water molecules through the negative dipole of the water.
Sodium chloride dissociates into sodium and chloride ions in water, and these ions become solvated by the highly polar water molecules. Image credit: "Salts: Figure 1" by OpenStax Anatomy and Physiology, CC-BY-NC-SA 4.0.
From the molecular formula, we can rewrite the soluble ionic compounds as dissociated ions to get the complete ionic equation:
\text{Ag}^+(aq) + \blueD{{\text{NO}_3}^-(aq)} + \maroonD{\text{Na}^+(aq)} + \text{Cl}^-(aq) \rightarrow \text{AgCl}(s) + \maroonD{\text{Na}^+(aq)} + \blueD{{\text{NO}_3}^- (aq)}Ag
+
(aq)+NO
3
−
(aq)+Na
+
(aq)+Cl
−
(aq)→AgCl(s)+Na
+
(aq)+NO
3
−
−
(aq)
+
Na
+
(aq)
+Cl
−
(aq)→AgCl(s)+
Na
+
(aq)
+
NO
3
−
(aq)
What is the relationship between the mass of the boat and the mass of the displaced
liquid?
The mass of the boat is equal to the mass of the liquid which is displaced by placing the boat in the liquid.
What is Archimedes' Principle?
Archimedes' Principle states that the buoyant force of the object is equal to the weight of the water which is displaced by the boat. If the weight of the water that is displaced by the boat is less than that of the weight of the boat, then in this case the boat sinks. Archimedes' principle or the buoyant force is very useful for the calculation of the volume of an object that does not have a regular shape.
The mass of the displaced liquid is always equal to the volume of the liquid multiplied by the density of the fluid. When a boat is placed in the water, the volume of displaced water is equal to the mass of the boat which is placed in it.
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what three things might influence a slide when conditions are right?
Answer:
3
Explanation:
The three things that can affect a condition to enforce a slide is friction, weight, and slope of an area. Solutions that can make flow easily are those that can create less friction depending on the condition of an environment where it is present.
FUСR THE WORLD SAY AND TO 4142-414=? HELPPPPPPPPPPPPP
Answer:
UMMMMMMMMMMM
Explanation:
Answer:
3729
Explanation:
What can you do differently for
the last half of the year in science? Whether it is
improving study skills, turning work in on time
Answer:
I would say, what helps me is really paying attention in class and asking questions, also making sure you study for upcoming test's and quizzes and completely assingments on time
Explanation:
A1(OH)3 + HNO3–> H2O + A1(NO3)3
when the equation above is correctly balanced the coefficient of H2O is
A:1
B:2
C:3
D:8
Answer:
3
Explanation:
The reaction expression is given as:
Al(OH)₃ + HNO₃ → H₂O + Al(NO₃)₃
To solve this problem, let us assign coefficient a,b,c and d to each specie;
aAl(OH)₃ + bHNO₃ → cH₂O + dAl(NO₃)₃
Conserving Al : a = d
O: 3a + 3b = c + 9d
H: 3a + b = 2c
N: b = 3d
let a = 1 , d = 1, b = 3 , c = 3
Multiply through by 3;
a = 1, b = 3, c = 3 and d = 1
Al(OH)₃ + 3HNO₃ → 3H₂O + Al(NO₃)₃
How did the grandmother show her gratitude towards her granddaughter
answer this and in end please tell me how to mark answer as brainliest I will mark your answers as brainliest
Answer:
vgffffgggggvghvxgyfdgubvhumigrrdghg
air is trasferred from 75 L tank where the pressure is 125 psi and the temperature is 288 K to a tire with a volume. of 6.1 L and a pressure of 25 psi. what is the new temperature ?
Answer:
4.7K
Explanation:
Given parameters:
Initial volume = 75L
Initial pressure = 125psi
to atm gives 8.5atm
Initial temperature = 288K
New volume = 6.1L
New pressure = 25psi
to atm gives 1.7atm
Unknown:
New temperature = ?
Solution:
To solve this problem, we use the combined gas law which is given below:
[tex]\frac{P1 V1}{T1}[/tex] = [tex]\frac{P2 V2}{T2}[/tex]
P, V and T are pressure, volume and temperature
1 and 2 are initial and new states
[tex]\frac{8.5 x 75}{288}[/tex] = [tex]\frac{1.7 x 6.1}{T2}[/tex]
T2 = 4.7K
Which compound has the greatest molecular mass?
CO2
H2O
Pb2
NH4
Which of the following is NOT true about one mole?
the number of atoms in 1 mole of carbon equals the number of atoms in 1 mole of boron
O 12 g of carbon equals one mole of carbon atoms
the mass of 1 mole of carbon atoms equals the mass of 1 mole of boron atoms
one mole contains 6.02 x 10
23
particles
The number of atoms in 1 mole of carbon equals the number of atoms in 1 mole of boron is false because the molar mass of carbon is different from that of boron. Option A is correct.
The number of moles of an element is expressed as the ratio of the mass of the substance to its molar mass.Moles = Mass/Molar massThis shows that the number of moles of the substance is dependent on the molar mass of the substance.
From the listed option the number of atoms in 1 mole of carbon equals the number of atoms in 1 mole of boron is false because the molar mass of carbon is different from that of boron
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Kp/Kc for reaction for the equilibrium, A(g) ⇌ C(g)+B(g), is _______.
(Kc is the equilibrium constant in terms of concentrations, Kp is the equilibrium constant in terms of pressures, R is the gas constant, T is the temperature)
Select one:
(RT)2
(RT)-1
(RT)-2
(RT)-1.5
RT
RT
by using relation between Kp and Kc we get the above answer
How many grams of Fe will be produced if 705.0g of H20 are produced?
Fe3O4 + 4H2
-->
3 Fe + 4H2O
2265 g Fe₃O₄
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Reading a Periodic TableStoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[RxN - Balanced] Fe₃O₄ + 4H₂ → 3Fe + 4H₂O
[Given] 705.0 g H₂O
Step 2: Identify Conversions
[RxN] 4 mol H₂O → 1 mol Fe₃O₄
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Fe - 55.85 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
Molar Mass of Fe₃O₄ - 3(55.85) + 4(16.00) = 231.55 g/mol
Step 3: Convert
Set up stoich: [tex]\displaystyle 705.0 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{1 \ mol \ Fe_3O_4}{4 \ mol \ H_2O})(\frac{231.55 \ g \ Fe_3O_4}{1 \ mol \ Fe_3O_4})[/tex]Multiply/Divide/Cancel units: [tex]\displaystyle 2264.74 \ g \ Fe_3O_4[/tex]Step 4: Check
Follow sig fig rules and round. We are given 4 sig figs.
2264.74 g Fe₃O₄ ≈ 2265 g Fe₃O₄
what is the magnification of the eye piece on the microscope?
Answer:
The magnification is 10x
Explanation:
Answer: The magnification of the eyepiece on the microscope is the lens at the top of the microscope that the user looks through. This lens most commonly magnifies a sample by 10x
Explanation: The eyepiece magnifies the primary image produced by the objective; the eye can then use the full resolution capability of the objective. The microscope produces a virtual image of the specimen at the point of the distinct vision.
What volume is occupied by 2.719 x 1013 moles of methane gas, CH4?
Answer:
6.5256×10¹⁴
Explanation:
n= v/24
v= n×25
v= 2.719×10¹³ × 24= 6.5256×10¹⁴ moles/dm³
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According to ideal gas equation, the volume occupied by 2.719 x 10¹³ moles of methane gas is 6174.76×10¹³cm³.
What is ideal gas equation?The ideal gas equation is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.Ideal gases exist in hypothetical state.The law was proposed by Benoite Paul Emile Clapeyron in 1834.
Substituting values of pressure=1 atmosphere,number of moles=2.719 x 10¹³ ,R=8.314 ,T=273.15 K.
Therefore volume=nRT/P=2.719x 10¹³×8.314×273.15/1=6174.76×10¹³ cm³.
Thus, the volume occupied by 2.719 x 10¹³ moles of methane gas is 6174.76×10¹³cm³.
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