Answers
Have a great day
Related Questions
Hi please answer ASAP please and thank you
Answers
Answer:
1 1/4
Step-by-step explanation:
2 3/4 - 1 1/2
3 3/4 - 1 2/4
1 1/4
Please help I’ll mark as brainlist
Answers
Answer:
Ekta and Preyal
Step-by-step explanation:
Originally the cubes have a perimeter of 15, both Ekta and Preyal have a perimeter of 17 which is exactly a 2 unit increase
Solve for x.
6(4x+2)= 3(8x+4)
Answers
x = 1
Step-by-step explanation:
6(4x + 2) = 3(8x + 4)
24x + 12 = 24x + 12
x = 1
6(4x+2) = 3(8x+4)
24x + 12 = 24x + 12
-12 -12
24x = 24x
-24 -24
x = x
Pls i need help
The continuous growth rate of wind energy per year is ?%
Answers
Answer:
Do you need it in percentage, a graph or just normal annual calculation?
−30=5(x+1)
what is x?
Answers
[tex]\\ \rm\Rrightarrow -30=5(x+1)[/tex]
[tex]\\ \rm\Rrightarrow -30=5x+5[/tex]
[tex]\\ \rm\Rrightarrow 5x=-30-5[/tex]
[tex]\\ \rm\Rrightarrow 5x=-35[/tex]
[tex]\\ \rm\Rrightarrow x=\dfrac{-35}{-5}[/tex]
[tex]\\ \rm\Rrightarrow x=7[/tex]
Answer:
x = -7
Step-by-step explanation:
-30 = 5 (x -1 )
5 ( x + 1 ) =-30
5 (x + 1 ) = - 30
5 5
x + 1 = -6
x + 1 -1 = -6 -1
x = - 7
100 POINTS AND BRAINLIEST FOR THIS WHOLE SEGMENT
a) Find zw, Write your answer in both polar form with ∈ [0, 2pi] and in complex form.
b) Find z^10. Write your answer in both polar form with ∈ [0, 2pi] and in complex form.
c) Find z/w. Write your answer in both polar form with ∈ [0, 2pi] and in complex form.
d) Find the three cube roots of z in complex form. Give answers correct to 4 decimal
places.
Answers
Answer:
See Below (Boxed Solutions).
Step-by-step explanation:
We are given the two complex numbers:
[tex]\displaystyle z = \sqrt{3} - i\text{ and } w = 6\left(\cos \frac{5\pi}{12} + i\sin \frac{5\pi}{12}\right)[/tex]
First, convert z to polar form. Recall that polar form of a complex number is:
[tex]z=r\left(\cos \theta + i\sin\theta\right)[/tex]
We will first find its modulus r, which is given by:
[tex]\displaystyle r = |z| = \sqrt{a^2+b^2}[/tex]
In this case, a = √3 and b = -1. Thus, the modulus is:
[tex]r = \sqrt{(\sqrt{3})^2 + (-1)^2} = 2[/tex]
Next, find the argument θ in [0, 2π). Recall that:
[tex]\displaystyle \tan \theta = \frac{b}{a}[/tex]
Therefore:
[tex]\displaystyle \theta = \arctan\frac{(-1)}{\sqrt{3}}[/tex]
Evaluate:
[tex]\displaystyle \theta = -\frac{\pi}{6}[/tex]
Since z must be in QIV, using reference angles, the argument will be:
[tex]\displaystyle \theta = \frac{11\pi}{6}[/tex]
Therefore, z in polar form is:
[tex]\displaystyle z=2\left(\cos \frac{11\pi}{6} + i \sin \frac{11\pi}{6}\right)[/tex]
Part A)
Recall that when multiplying two complex numbers z and w:
[tex]zw=r_1\cdot r_2 \left(\cos (\theta _1 + \theta _2) + i\sin(\theta_1 + \theta_2)\right)[/tex]
Therefore:
[tex]\displaystyle zw = (2)(6)\left(\cos\left(\frac{11\pi}{6} + \frac{5\pi}{12}\right) + i\sin\left(\frac{11\pi}{6} + \frac{5\pi}{12}\right)\right)[/tex]
Simplify. Hence, our polar form is:
[tex]\displaystyle\boxed{zw = 12\left(\cos\frac{9\pi}{4} + i\sin \frac{9\pi}{4}\right)}[/tex]
To find the complex form, evaluate:
[tex]\displaystyle zw = 12\cos \frac{9\pi}{4} + i\left(12\sin \frac{9\pi}{4}\right) =\boxed{ 6\sqrt{2} + 6i\sqrt{2}}[/tex]
Part B)
Recall that when raising a complex number to an exponent n:
[tex]\displaystyle z^n = r^n\left(\cos (n\cdot \theta) + i\sin (n\cdot \theta)\right)[/tex]
Therefore:
[tex]\displaystyle z^{10} = r^{10} \left(\cos (10\theta) + i\sin (10\theta)\right)[/tex]
Substitute:
[tex]\displaystyle z^{10} = (2)^{10} \left(\cos \left(10\left(\frac{11\pi}{6}\right)\right) + i\sin \left(10\left(\frac{11\pi}{6}\right)\right)\right)[/tex]
Simplify:
[tex]\displaystyle z^{10} = 1024\left(\cos\frac{55\pi}{3}+i\sin \frac{55\pi}{3}\right)[/tex]Simplify using coterminal angles. Thus, the polar form is:
[tex]\displaystyle \boxed{z^{10} = 1024\left(\cos \frac{\pi}{3} + i\sin \frac{\pi}{3}\right)}[/tex]
And the complex form is:
[tex]\displaystyle z^{10} = 1024\cos \frac{\pi}{3} + i\left(1024\sin \frac{\pi}{3}\right) = \boxed{512+512i\sqrt{3}}[/tex]
Part C)
Recall that:
[tex]\displaystyle \frac{z}{w} = \frac{r_1}{r_2} \left(\cos (\theta_1-\theta_2)+i\sin(\theta_1-\theta_2)\right)[/tex]
Therefore:
[tex]\displaystyle \frac{z}{w} = \frac{(2)}{(6)}\left(\cos \left(\frac{11\pi}{6} - \frac{5\pi}{12}\right) + i \sin \left(\frac{11\pi}{6} - \frac{5\pi}{12}\right)\right)[/tex]
Simplify. Hence, our polar form is:
[tex]\displaystyle\boxed{ \frac{z}{w} = \frac{1}{3} \left(\cos \frac{17\pi}{12} + i \sin \frac{17\pi}{12}\right)}[/tex]
And the complex form is:
[tex]\displaystyle \begin{aligned} \frac{z}{w} &= \frac{1}{3} \cos\frac{5\pi}{12} + i \left(\frac{1}{3} \sin \frac{5\pi}{12}\right)\right)\\ \\ &=\frac{1}{3}\left(\frac{\sqrt{2}-\sqrt{6}}{4}\right) + i\left(\frac{1}{3}\left(- \frac{\sqrt{6} + \sqrt{2}}{4}\right)\right) \\ \\ &= \boxed{\frac{\sqrt{2} - \sqrt{6}}{12} -\frac{\sqrt{6}+\sqrt{2}}{12}i}\end{aligned}[/tex]
Part D)
Let a be a cube root of z. Then by definition:
[tex]\displaystyle a^3 = z = 2\left(\cos \frac{11\pi}{6} + i\sin \frac{11\pi}{6}\right)[/tex]
From the property in Part B, we know that:
[tex]\displaystyle a^3 = r^3\left(\cos (3\theta) + i\sin(3\theta)\right)[/tex]
Therefore:
[tex]\displaystyle r^3\left(\cos (3\theta) + i\sin (3\theta)\right) = 2\left(\cos \frac{11\pi}{6} + i\sin \frac{11\pi}{6}\right)[/tex]
If two complex numbers are equal, their modulus and arguments must be equivalent. Thus:
[tex]\displaystyle r^3 = 2\text{ and } 3\theta = \frac{11\pi}{6}[/tex]
The first equation can be easily solved:
[tex]r=\sqrt[3]{2}[/tex]
For the second equation, 3θ must equal 11π/6 and any other rotation. In other words:
[tex]\displaystyle 3\theta = \frac{11\pi}{6} + 2\pi n\text{ where } n\in \mathbb{Z}[/tex]
Solve for the argument:
[tex]\displaystyle \theta = \frac{11\pi}{18} + \frac{2n\pi}{3} \text{ where } n \in \mathbb{Z}[/tex]
There are three distinct solutions within [0, 2π):
[tex]\displaystyle \theta = \frac{11\pi}{18} , \frac{23\pi}{18}\text{ and } \frac{35\pi}{18}[/tex]
Hence, the three roots are:
[tex]\displaystyle a_1 = \sqrt[3]{2} \left(\cos\frac{11\pi}{18}+ \sin \frac{11\pi}{18}\right) \\ \\ \\ a_2 = \sqrt[3]{2} \left(\cos \frac{23\pi}{18} + i\sin\frac{23\pi}{18}\right) \\ \\ \\ a_3 = \sqrt[3]{2} \left(\cos \frac{35\pi}{18} + i\sin \frac{35\pi}{18}\right)[/tex]
Or, approximately:
[tex]\displaystyle\boxed{ a _ 1\approx -0.4309 + 1.1839i,} \\ \\ \boxed{a_2 \approx -0.8099-0.9652i,} \\ \\ \boxed{a_3\approx 1.2408-0.2188i}[/tex]
Where did term “infinity” come from
Answers
To purchase a car costing $10,000, the buyer bor-
rowed part of the money from the bank at 9% sim-
ple interest and the rest from her mother-in-law at
12% simple interest. If her total interest for the year
was $1080, how much did she borrow from the
bank?
Answers
Answer:
She borrowed 4000 from bank.
Step-by-step explanation:
Let 'y' be the amount borrowed from bank. Then 10000-y is the amount borrowed from her mother-in-law.
Let x= interest amount gained by bank . Then 1080- x = interest gained by mother-in-law
I1= interest rate by bank= 9%
I2= interest rate by mother-in-law=12%
Time(T) = 1 year
Now, By Simple Interest formula:
x=PTR/100
Or, x=(y*1*9)/100
Or,100x=9y
or,9y-100x=0...........................Equation (i)
Again 1080-x= ((10000-y)*1*12)/100
Or, 108000-100x=120000-12y
Or, 12y-100x=12000.................Equation(ii)
Solving equation (i) and (ii), we get
y= 4000, which the amount borrowed from bank.
PLEASE HELP Find the value of the following expression (2 ^8 • 3 ^-5 • 6 ^0) ^-2 • (3 ^-2 over 2 ^3 ) ^4 •2 ^28
Answers
the answer is very simple if you don't understand ask to your teacher
Find the value of the sum 219+226+233+⋯+2018.
Assume that the terms of the sum form an arithmetic series.
Give the exact value as your answer, do not round.
Answers
Answer:
228573
Step-by-step explanation:
a = 219 (first term)
an = 2018 (last term)
Sn->Sum of n terms
Sn=n/2(a + an) [Where n is no. of terms] -> eq 1
To find number of terms,
an = a + (n-1)d [d->Common Difference] -> eq 2
d= 226-219 = 7
=> d=7
Substituting in eq 2,
2018 = 219 + (n-1)(7)
1799 = (n-1)(7)
1799 = 7n-7
1799 = 7(n-1)
1799/7 = n-1
257 = n-1
n=258
Substituting values in eq 1,
Sn = 258/2(219+2018)
= 129(2237)
= 228573
Julie assembles shelves for a department store and gets paid $3.25 per shelf. She can assemble 5 per hour and works 8 hours per day. Determine Julie’s gross pay for 1 week
Answers
Pay per shelf = $3.25
No of shelfs per hour = 5
Total hours per day = 8
Total days to find pay of = 7
= 3.25×5×8×7
= 910
Therefore she is paid $910 after 1 week.
Must click thanks and mark brainliest
Find the equation of the linear function represented by the table below in slope-intercept form.
Answers
Answer:
y = 3x+1
Step-by-step explanation:
First find the slope
m = ( y2-y1)/(x2-x1)
= (13-4)/(4-1)
= 9/3
= 3
Slope intercept form is
y = mx+b where m is the slope and b is the y intercept
y = 3x+b
Using a point from the table
10 = 3(3)+b
10 =9+b
10-9 =b
1=b
y = 3x+1
Classify the triangle as acute, right, or obtuse and as equilateral, isosceles, or scalene.
Answers
9514 1404 393
Answer:
(d) Right, scalene
Step-by-step explanation:
The little square in the upper left corner tells you that is a right angle. Any triangle with a right angle is a right triangle. This one is scalene, because the sides are all different lengths.
__
Additional comment
An obtuse triangle cannot be equilateral, and vice versa.
An equilateral triangle has all sides the same length, and all angles the same measure: 60°. It is an acute triangle.
Find the volume of the cylinder please
ASAP
Answers
Answer:
33ft^3
Step-by-step explanation:
radius is half the diameter, half of 2=1 and 1^2=1
3(1)(11)=33
Answer: V = 33 ft³
Step-by-step explanation:
π = 3
r = (1/2)d = (1/2) (2) = 1 ft
h = 11 ft
Given Formula
V = π r² h
Substitute values into the formula
V = (3) (1)² (11)
Simplify exponents
V = (3) (1) (11)
Simplify by multiplication
V = 33 ft³
Hope this helps!! :)
Please let me know if you have any questions
Ray is making his reward winning lemonade recipe for a party he is comparison shopping for lemons at super pioneer supermarket he can buy 4 lemons for 1.60 ray visits keyfood and found 3 lemons cost 1.80 use the table below to compare the values
Answers
Answer:
classified info jk juss use a mf calculater
Step-by-step explanation:
If Sin x = -¼, where π < x < 3π∕2 , find the value of Cos 2x
Answers
Answer: 7/8
Cos2x has 3 formulas, Sinx is given in the question, we should use the formula with sinus. I guess that's the solution.
help me pls??????? :)
Answers
Answer:4 in each bad 2 left over
Step-by-step explanation:
Answer:
4 in each bag and 2 left over
Step-by-step explanation:
divide 14 by 3
3 goes into 14, 4 times
14 - 12 = 2
4 in each bag and then 2 left over
help help help help
Answers
Answer:
abc is a triangle so ,
a is ( 9,6 )
b is ( 9,3 )
and c is ( 3,3 )
What is (9.3x10^34)
(3.1x10^17) in scientific notation?
Answers
Answer:
3x10^17
Step-by-step explanation:
(9.3/3.1) * 10^(34-17) = 3^17
law of indices, x^m/x^n =x^m-n
The weekly wages of employees of Volta gold are normally distributed about a mean of$1250 with a standard deviation of $120. Find the probability of an employee having a weekly wage lying 1) between $1320 and $970 2) over $1290 3) under $1400
Answers
Answer:
1) 0.7104 = 71%
2) 0.6615 = 66%
3) 0.8944 = 89%
Step-by-step explanation:
1)
Z(low)=-2.333 0.009815329
Z(upper)=0.583 0.720165536
2)
Z(low)=0.333 0.63055866
Z(upper)=8322.908 1
3)
Z(low)=-10.417 0
Z(upper)=1.25 0.894350226
a rectangular postage stamp has a length of 3/2 inches and a width of 3/4 inch. what is the area of the stamp in square inches?
Answers
Answer:
9/8 or 1.125
Step-by-step explanation:
We want to find the area of a rectangular postage stamp
The area of a rectangle can be found by multiplying the length by the width
Given length: 3/2
Given width: 3/4
Area = 3/2 * 3/4 = 9/8 or 1.125
The area of a 2D form is the amount of space within its perimeter. The area of the stamp in square inches is 1 1/8 inches².
What is an area?The area of a 2D form is the amount of space within its perimeter. It is measured in square units such as cm², m², and so on. To find the area of a square formula or another quadrilateral, multiply its length by its width.
Given that a rectangular postage stamp has a length of 3/2 inches and a width of 3/4 inch. Therefore, the area of the stamp in square inches is,
Area of the stamp = Length × Width
= 3/2 inches × 3/4 inches
= 9/8 inches²
= 1 1/8 inches²
Hence, the area of the stamp in square inches is 1 1/8 inches².
Learn more about the Area here:
https://brainly.com/question/1631786
#SPJ2
(√0,04-√(-1,2)²+√121)×√81
Answers
Answer: 90
Step-by-step explanation:
[tex]\displaystyle\ \Large \boldsymbol{} (\sqrt{0,04}-\sqrt{(-1,2)^2}+\sqrt{121 } ) \cdot \sqrt{81} = \\\\\\(0,2-1,2+11)\cdot 9=(11-1)\cdot 9=90[/tex]
Select the correct answer from each drop-down menu.
A company makes cylindrical vases. The capacity, in cubic centimeters, of a cylindrical vase the company produces is given by the
function C() = 6.2873 + 28.26x2, where x is the radius, in centimeters. The area of the circular base of a vase, in square
centimeters, is given by the function A () = 3.14.2
To find the height of the vase, divide
represents the height of the vase.
the expressions modeling functions C(x) and A(z). The expression
Answers
Answer:
divide, 2x+9
Step-by-step explanation:
got it right
How do we derive the sum rule in differentiation? (ie. (u+v)' = u' + v')
Answers
It follows from the definition of the derivative and basic properties of arithmetic. Let f(x) and g(x) be functions. Their derivatives, if the following limits exist, are
[tex]\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h\text{ and }g'(x)\lim_{h\to0}\frac{g(x+h)-g(x)}h[/tex]
The derivative of f(x) + g(x) is then
[tex]\displaystyle \big(f(x)+g(x)\big)' = \lim_{h\to0}\big(f(x)+g(x)\big) \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{\big(f(x+h)+g(x+h)\big)-\big(f(x)+g(x)\big)}h \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{\big(f(x+h)-f(x)\big)+\big(g(x+h)-g(x)\big)}h \\\\ \big(f(x)+g(x)\big)' = \lim_{h\to0}\frac{f(x+h)-f(x)}h+\lim_{h\to0}\frac{g(x+h)-g(x)}h \\\\ \big(f(x)+g(x)\big)' = f'(x) + g'(x)[/tex]
A survey was conducted by asking 120 students in a town how they traveled to school.
The following pie chart shows the result of the survey
Car 30%
Cycle 25%
Walk 10%
Bus ?
What are the number of students that travel to school by bus
Answers
Answer:
42
Step-by-step explanation:
30+25+10=65%
bus=35%
35/100×120=42
BUS=42
= 36 students
cycle- 25/100 x 120
= 30 students
Walk- 10/100 x 120
=12 students
Bus- 120-36-30-12= 42 students
What is the volume of a sphere with a diameter of 7.7 ft, rounded to the nearest tenth
of a cubic foot?
Answers
Step-by-step explanation:
V=4/3πr^3
V=4/3π(3.85)^3
V=4/3π(57.066625)
V=4/3 (179.280089865)
V=239.04011982
V=239 ft^3
convert 10.09% to a decimal
Answers
Answer:
0.1009
Step-by-step explanation:
To convert percentage into decimal, you need to divide the percentage by 100
10.09/100
= 0.1009
10.09 ÷ 100 = 0.1009
Therefore, the answer is 0.1009
can someone explain step by step how to get the answer?
Answers
Answer: x³+8x²+11x-20
Step-by-step explanation:
To find which polynomial has the roots of -5, -4, and 1, we want to first put them into an equation.
-5 is the same as x+5=0
-4 is the same as x+4=0
1 is the same as x-1=0
Now that we have the factors, we can multiply them together.
(x+5)(x+4)(x-1) [FOIL]
(x²+4x+5x+20)(x-1) [combine like terms]
(x²+9x+20)(x-1) [FOIL]
x³-x²+9x²-9x+20x-20 [combine like terms]
x³+8x²+11x-20
Therefore, x³+8x²+11x-20 is the correct polynomial with those roots.
Determine the sum of the first 33 terms of the following series:
−52+(−46)+(−40)+...
Answers
Answer:
1320
Step-by-step explanation:
Use the formula for sum of series, s(a) = n/2(2a + (n-1)d)
The terms increase by 6, so d is 6
a is the first term, -56
n is the terms you want to find, 33
Plug in the numbers, 33/2 (2(-56)+(32)6)
Simplify into 33(80)/2 and you get 1320
by selling an article sonu makes a profit of 20%. if the cp decreased by 10% and sp also increased by 10%,calculate her profit percentage
Answers
Answer:
37.8 %
Step-by-step explanation:
Let CP = 100
[tex]SP =\frac{100+profit}{100}*CP\\\\=\frac{120}{100}*100[/tex]
SP = 120
New CP:
CP decreased by 10%
[tex]Decreased \ amount=\frac{10}{100}*CP\\\\=\frac{10}{100}*100[/tex]
= 10
New CP = 100- 10 = 90
New SP:
SP increased by 10%
Increase amount = [tex]\frac{10}{100}*old \ SP[/tex]
[tex]= \frac{10}{100}*120\\\\= 12[/tex]
New SP = 120 + 12 = 132
Profit = new SP - new CP
= 132 - 90 = 42
Profit percentage = [tex]\frac{Profit}{CP}*100[/tex]
[tex]= \frac{42}{90}*100\\[/tex]
= 46.67%
Step-by-step explanation:
Here your ans..
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