Answer:
$13 per hour
Step-by-step explanation:
This is because 26÷2=13, 65÷5=13
Which of the following represents the divisor and the dividend for the
synthetic division problem below?
Answer:
option D is correct
Step-by-step explanation:
Given data
From the given expression/options of answers, option D is correct
This is because the given expression in the attached file corresponds to the terms in option D
Let D be the event that a randomly chosen person has seen a dermatologist. Let S be the event that a randomly chosen person has had surgery for skin cancer. Identify the answer which expresses the following with correct notation: The probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist.Select the correct answer below:A. P(D|S)B. P(D AND S)C. P(S) AND P(D)D. P(S|D)
Given:
D be the event that a randomly chosen person has seen a dermatologist.
S be the event that a randomly chosen person has had surgery for skin cancer.
To find:
The correct notation for the probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist.
Solution:
Conditional probability: Probability of A given B is:
[tex]P(A|B)=\dfrac{P(A\cap B)}{P(B)}[/tex]
Let D be the event that a randomly chosen person has seen a dermatologist.
Let S be the event that a randomly chosen person has had surgery for skin cancer.
Using the conditional probability, the correct notation for the probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist is P(S|D).
Therefore, the correct option is D.
PLEASE ANSWER!! I don’t understand
Answer:
[tex]m\angle 2=122^{\circ},\\m\angle 1 = 58^{\circ}[/tex]
Step-by-step explanation:
By definition, tangent lines touch a circle at one point. This one point intersects the circle at a 90 degree angle.
In any circle, the measure of an inscribed angle is exactly half of the arc it forms. Since [tex]\angle 2[/tex] forms an arc labelled 244 degrees, the measure of angle 2 must be [tex]\frac{244}{2}=\boxed{122^{\circ}}[/tex].
Angle 1 and 2 form one side of a line. Since there are 180 degrees on each side of the line, we have:
[tex]\angle 1+\angle 2=180,\\\angle 1 + 122=180,\\\angle 1=180-122=\boxed{58^{\circ}}[/tex]
STREAM WALLS BY LOUIS TOMLINSON
Answer:
OMG I LOVE LOUIS SO MUCH HE IS SO PERFECT
Step-by-step explanation:
How do you get 24 with the numbers 6, 5, 4 and 8
Step-by-step explanation:
hoped this will help you
if that's help you plz vote me or mask as brinalist
Solve for x. Round to the nearest tenth, if necessary.
Answer:
3.8106327168
Step-by-step explanation:
x=2.5/sin(41) = 3.81063271676
[tex]\text{Solve for 'x'.}\\\\x^2-25=0\\\\\text{Thank you.}[/tex]
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]x = \pm 5[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Solving for 'x'...}}\\\\x^2-25 = 0\\-------------\\\rightarrow x^2 -25 + 25 = 0 + 25\\\\\rightarrow x^2 = 25\\\\\rightarrow \sqrt{x^2}=\sqrt{25}\\\\\rightarrow \boxed{x = \pm 5}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Answer:
[tex]x = 5 \: \: \: or \: \: \: x = - 5[/tex]
Step-by-step explanation:
[tex] {x}^{2} - 25 = 0 \\ {x}^{2} - {5}^{2} \\ ( x - 5)(x + 5) = 0 \\ \\ x - 5 = 0 \\ x = 5 \\ or \\ x + 5 = 0 \\ x = - 5[/tex]
If the ratio of a to b is 2.3 and the ratio
of to bis 3:4, which of the following is
equal to the ratio of a to c.?
Answer:5.7 D
Step-by-step explanation:
A particle is projected with a velocity of [tex]29.4ms^-^1[/tex] . Find it's maximum range on a horizontal plane through the point of projection.
A.88.2m B.44.1m C.32.6m D.29.4m E.14.7m
A.88.2m
Answer:
Solution given:
initial velocity[u]=29.4m/s
g=9.8m/s²
maximum range=?
now
we have
[tex]\theta=90°[/tex]
maximum range =[tex]\frac{29.4²*sin90}{9.8}=88.2m[/tex]
The initial velocity is,
→ u = 29.4 m/s
General assumption,
→ g = 9.8m/s²
→ θ = 90°
Then the maximum range is,
→ (29.4² × sin90)/9.8
→ 88.2 m
Hence, option (A) is answer.
Cual de las siguientes fracciones es equivalente a 6/18
1/3
2/3
3/18
3/6
Answer:
the answer is going to be 1/3
What is the value of the expression below
(-64)^2/3
Answer:
16
Step-by-step explanation:
[tex](-64)^2/3[/tex]
64 = [tex]2^{6}[/tex]
[tex]2^{6} ^{\frac{1}{3} } ^{2}[/tex]
[tex]2^{ 2^{2} }[/tex]
[tex]2^{4}[/tex]
16
Use a half-angle identity to find the exact value of Sin/8
a.
√2 + √2
√2+ √2
2
b. V2-E
d. √2-√2
2
Please select the best answer from the choices provided
Answer:
To solve this problem, we need to use the following two facts:
1) If a quadratic equation has integer coefficients only, and if one of the roots is a + √b (where a and b are integers), then a - √b is also a root of the equation.
2) If r and s are roots of a quadratic equation, then the equation is of the form x^2 – (r +s)x + rs = 0.
Since we know that 1 - √2 is a root of the quadratic equation, we can let:
r = 1 + √2
and
s = 1 - √2
Thus, r + s = (1 + √2) + (1 - √2) = 2 and rs = (1 + √2)(1 - √2) = 1 – 2 = -1.
Therefore, the quadratic equation must be x^2 – 2x – 1 = 0.
Answer: D
Step-by-step explanation:
If the volume of a sphere is 36t cubic units, what is the radius?
Answer:
Volume of sphere = 4/3 * π * r³
Since 36π = 4/3 * π * r³, r³ = 27 and r = 3.
Step-by-step explanation:
Let the universal set U = {weekdays}. If T = {Tuesday, Thursday}, what is T'?
Answer:Monday, Wednesday and Friday.
Step-by-step explanation:
It’s the other weekdays.
Find the domain of the following piecewise function.
Answer:
[tex](2,8][/tex]
Step-by-step explanation:
Given
The attached piece wise function
Required
The domain
To do this, we simply consider the inequalities that bound the values of x.
The inequalities are:
[tex]2 < x < 4[/tex] [tex]4 < x < 8[/tex] and [tex]x \ge 8[/tex]
Combine the first two inequalities:
[tex]2 < x < 8[/tex] and [tex]x \ge 8[/tex]
For the inequality to be true, we must have:
[tex]2 < x \le 8[/tex]
In interval notation, the inequality is:
[tex](2,8][/tex]
mila first stands on a diving board is 3 feet above surface of the water .she then dives to the bottom of the pool to a depth of 10 feet
Answer:
She Dives 13 Feet
Step-by-step explanation:
3+10=13
Mila's depth from the diving board to the bottom of the pool is 13 feet.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
Given that Mila first stands on a diving board 3 feet above the surface of the water .she then dives to the bottom of the pool to a depth of 10 feet.
The total depth will be calculated as below:-
Depth = 3 + 10
Depth = 13 feet
Therefore, Mila's depth from the diving board to the bottom of the pool is 13 feet.
To know more about expression follow
https://brainly.com/question/878985
#SPJ2
solve the following simultaneous equations using SUBTITUTION METHOD
m+3n=7 and 5m-n=3
To check:put value of m and n in both equations
Answer: n=2 and m=1
Step-by-step explanation:
m+3n=7 , 5m-n=3
m=7-3n => 5(7-3n)-n=3
=> 35-15n-n=3
=> -16n=-32
=> n=2
n=2 => 5m-2=3
=> m=1
An angle in standard position measures 5п 8 radians. In which quadrant does the terminal side of this angle lie? O Quadrant I II Quadrant Quadrant IIT Quadrant IV
Answer:
I've attached a picture of a unit circle with the quadrant labeled.
Calculate the degree of 5п 8 radians:
[tex]\frac{5\pi }{8} =\frac{5*180}{8} =\frac{900}{8} =112.5[/tex]
Locate the general location of 112.5° on the unit circle:
It's between 120°([tex]\frac{2\pi }{3}[/tex]) and 90°([tex]\frac{\pi }{2}[/tex]).
Find the quadrant it lies in:
Quadrant II
check all that apply. if cos0 = 13/5, then: ?
Answer:
D
Step-by-step explanation:
if cosec is 13/5 then sin is 5/13
2/3 divided by 4/5? step by step requested
Answer:
5/6
Step-by-step explanation:
When dividing fractions, multiply by the reciprocal:
2/3 ÷ 4/5
2/3 x 5/4
Multiply the numerators and denominators by each other:
= 10/12
Simplify by dividing the numerator and denominator by 2:
= 5/6
The answer is 5/6
Please help me!
Look at this diagram.
Answer:
if you look at carefully the left triangle has two same side. so left-angle of C is 180-130=50 degree 5x+5x+50=180 x=13 degree
Step-by-step explanation:
for right triangle again one angle is 50 degree and other is 6*13-(3)=75 degree so 75+50+(10y+5)=180 degree y=5 degree
Answer:
[tex]x=13\text{ and } y=5[/tex]
Step-by-step explanation:
First, notice that ∠BCD and ∠DCE form a linear pair. Linear pairs sum to 180°. Therefore:
[tex]m\angle BCD + m\angle DCE = 180[/tex]
And since we know that ∠BCD measures 130°:
[tex]m\angle DCE = 180-130=50^\circ[/tex]
And since ∠DCE and ∠BCA are vertical angles:
[tex]\displaystyle \angle DCE \cong \angle BCA[/tex]
Therefore, by definition:
[tex]m\angle DCE = m\angle BCA = 50^\circ[/tex]
Looking at the left triangle, we can see that BC and AC both have one tick mark. This means that they are congruent. Therefore, ΔABC is an isosceles triangle. The two base angles of an isosceles triangle are congruent. Hence:
[tex]m\angle A = m\angle B[/tex]
The interior angles of a triangle must total 180°. So:
[tex]m\angle A + m\angle B +m\angle BCA = 180[/tex]
Substitute in known values:
[tex]m\angle A + m\angle A+ (50)=180[/tex]
Simplify:
[tex]2m\angle A=130[/tex]
Divide both sides by two:
[tex]m\angle A = 65[/tex]
Substitute:
[tex](5x)=65[/tex]
Therefore:
[tex]x=13[/tex]
Similarly, for the triangle on the right, we can write that:
[tex]m\angle D + m\angle E + m\angle DCE = 180[/tex]
Substitute:
[tex](10y+5)+(6x-3)+(50)=180[/tex]
Combine like terms:
[tex]10y+6x+52=180[/tex]
Since we determined that x = 13:
[tex]10y+6(13)+52=180[/tex]
Simplify:
[tex]10y+130=180[/tex]
Therefore:
[tex]10y=50[/tex]
And by dividing both sides by 10:
[tex]y=5[/tex]
work out the area of a circle with a diameter of 1.8
question 3 help pls in algebra
Answer:
50
Step-by-step explanation:
simplify the radical by breaking the redicand up into a product of known factors, assuming positive real numbers.
Huilan's age is three times Thomas's age. The sum of their ages is 100. What is Thomas's age? 1 years old
Answer:
thomas is 25 years old
Step-by-step explanation:
ratio = 3:1
3+1=4
total age=100
Thomas age = 1/4 × 100 = 25
PLEASE HELP!!! I dont understand :(
Hello,
In all reply x²'s coefficient is 1.
The polynom will be (x+i)(x-5)= x²+ix -5x-5i
Answer C
Let N be the smallest positive integer whose sum of its digits is 2021. What is the sum of the digits of N + 2021?
Answer:
[tex]10[/tex].
Step-by-step explanation:
See below for a proof of why all but the first digit of this [tex]N[/tex] must be "[tex]9[/tex]".
Taking that lemma as a fact, assume that there are [tex]x[/tex] digits in [tex]N[/tex] after the first digit, [tex]\text{A}[/tex]:
[tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{$x$ digits}}}[/tex], where [tex]x[/tex] is a positive integer.
Sum of these digits:
[tex]\text{A} + 9\, x= 2021[/tex].
Since [tex]\text{A}[/tex] is a digit, it must be an integer between [tex]0[/tex] and [tex]9[/tex]. The only possible value that would ensure [tex]\text{A} + 9\, x= 2021[/tex] is [tex]\text{A} = 5[/tex] and [tex]x = 224[/tex].
Therefore:
[tex]N = \overline{5 \, \underbrace{9 \cdots 9}_{\text{$224$ digits}}}[/tex].
[tex]N + 1 = \overline{6 \, \underbrace{000 \cdots 000000}_{\text{$224$ digits}}}[/tex].
[tex]N + 2021 = 2020 + (N + 1) = \overline{6 \, \underbrace{000 \cdots 002020}_{\text{$224$ digits}}}[/tex].
Hence, the sum of the digits of [tex](N + 2021)[/tex] would be [tex]6 + 2 + 2 = 10[/tex].
Lemma: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".
Proof:
The question assumes that [tex]N\![/tex] is the smallest positive integer whose sum of digits is [tex]2021[/tex]. Assume by contradiction that the claim is not true, such that at least one of the non-leading digits of [tex]N[/tex] is not "[tex]9[/tex]".
For example: [tex]N = \overline{(\text{A})\cdots (\text{P})(\text{B}) \cdots (\text{C})}[/tex], where [tex]\text{A}[/tex], [tex]\text{P}[/tex], [tex]\text{B}[/tex], and [tex]\text{C}[/tex] are digits. (It is easy to show that [tex]N[/tex] contains at least [tex]5[/tex] digits.) Assume that [tex]\text{B} \![/tex] is one of the non-leading non-"[tex]9[/tex]" digits.
Either of the following must be true:
[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is a "[tex]0[/tex]", or[tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex] is not a "[tex]0[/tex]".If [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is a "[tex]0[/tex]", then let [tex]N^{\prime}[/tex] be [tex]N[/tex] with that "[tex]0\![/tex]" digit deleted: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{B}) \cdots (\text{C})}[/tex].
The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:
[tex]\begin{aligned}& \text{A} + \cdots + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + 0 + \text{B} + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].
However, with one fewer digit, [tex]N^{\prime} < N[/tex]. This observation would contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].
On the other hand, if [tex]\text{P}[/tex], the digit in front of [tex]\text{B}[/tex], is not "[tex]0[/tex]", then [tex](\text{P} - 1)[/tex] would still be a digit.
Since [tex]\text{B}[/tex] is not the digit [tex]9[/tex], [tex](\text{B} + 1)[/tex] would also be a digit.
let [tex]N^{\prime}[/tex] be [tex]N[/tex] with digit [tex]\text{P}[/tex] replaced with [tex](\text{P} - 1)[/tex], and [tex]\text{B}[/tex] replaced with [tex](\text{B} + 1)[/tex]: [tex]N^{\prime} :=\overline{(\text{A})\cdots (\text{P}-1) \, (\text{B} + 1) \cdots (\text{C})}[/tex].
The digits of [tex]N^{\prime}[/tex] would still add up to [tex]2021[/tex]:
[tex]\begin{aligned}& \text{A} + \cdots + (\text{P} - 1) + (\text{B} + 1) + \cdots + \text{C} \\ &= \text{A} + \cdots + \text{P} + \text{B} + \cdots + \text{C} \\ &= 2021\end{aligned}[/tex].
However, with a smaller digit in place of [tex]\text{P}[/tex], [tex]N^{\prime} < N[/tex]. This observation would also contradict the assumption that [tex]N\![/tex] is the smallest positive integer whose digits add up to [tex]2021\![/tex].
Either way, there would be a contradiction. Hence, the claim is verified: all digits of this [tex]N[/tex] other than the first digit must be "[tex]9[/tex]".
Therefore, [tex]N[/tex] would be in the form: [tex]N = \overline{\text{A} \, \underbrace{9 \cdots 9}_{\text{many digits}}}[/tex], where [tex]\text{A}[/tex], the leading digit, could also be [tex]9[/tex].
Solve the following with steps
5/10 * -4/12 - 1/3 - 4/12 * 2/10
Answer:
Step-by-step explanation:
[tex]\frac{5}{10}*\frac{-4}{12}-\frac{1}{3}-\frac{4}{12}*\frac{2}{10}\\\\=\frac{1}{2}*\frac{-1}{3}-\frac{1}{3}-\frac{1}{3}*\frac{1}{5}\\\\= \frac{-1}{3}[\frac{1}{2}+1+\frac{1}{5}]\\\\=\frac{-1}{3}[\frac{1*5}{2*5}]+\frac{1*10}{1*10}+\frac{1*2}{5*2}]\\\\=\frac{-1}{3}[\frac{5}{10}+\frac{10}{10}+\frac{2}{10}]\\\\=\frac{-1}{3}[\frac{5+10+2}{10}]\\\\=\frac{-1}{3}*\frac{17}{10}\\\\=\frac{-17}{30}[/tex]
Team members Corinne, Kevin, and Tomas decide to share the cost
of 2 motor controllers and 4 wheels equally. How much does each
member need to contribute?
Please help(write step by step and upload pic or do it here please I appreciate it so much !
Answer:
each member needs to put in 91.70 dollars in.
Step-by-step explanation:
you add the costs of all the tools needed. in this case the two controllers and wheels which adds up to 275.1.
then you divide by the amount of people which is three. so 275.1/3 and you get 91.7
what is the solution to -6 - -25=
Answer:
19
Step-by-step explanation:
(-6)-(-25)=(-6) +25 = 19
Please answer this, I need help fast
B
Step-by-step explanation:
If you're using a Casio calculator you can just change the mode to table mode. Put the equations as they are,decide the value of the X axis you want to start at and where you want to end. The step you can use 1 if you want. Press = button. You'll have the co-ordinates. Plot the co-ordinates of each equation and see which one gives a straight line graph. I started at -4 and ended at 5 and I used step 1