Answer:
θ = 26.6°
Explanation:
Formula for maximum height is;
h = u²sin²θ/2g
We are told maximum height is 25 m, thus;
u²sin²θ/2g = 25 - - - - (eq 1)
Formula for horizontal range is;
R = u²sin2θ/g
In Mathematics, sin2θ = 2sinθcosθ
So; R = 2u²sinθcosθ/g
R = 2u²sinθcosθ/g
We are given Horizontal range = 200 m.
Thus;
2u²sinθcosθ/g = 200 - - - - (eq 2)
Divide eq 1 by eq 2 to get;
200/25 = 4cosθ/sinθ
8 = 4cosθ/sinθ
4/8 = sinθ/cosθ
0.5 = tan θ
θ = tan^(-1) 0.5
θ = 26.6°
if a train has 1,450 kg of momentum and is traveling at 40 m/s ¿what is the mass of tren?
Help plis I have this wrong
Answer:
P=mv
1x450,200=m40
m= 36,255kg
What is the relationship between force and momentum?
A. A force will always increase momentum
B. A force acting for a certain time results in a change in momentum
C. There is no relationship
D. It depends on the kind of force
Answer:
Explanation:
B
A car with a mass of 2,000 kg travels at 20 m/s. Which one has the greatest impulse?
Answer:2000kg
Explanation:
Convert it
A Nov-Dec power bill shows that a home uses 1355 kwh over a 30-day period. Find the energy used (in kJ) for the 30-day period.
Answer:
The energy used for the 30-day period is 4878000 kilojoules.
Explanation:
According to the power bill, 1355 kilowatt-hours was used over a 30-day period. A kilowatt-hour is equal to 3600 kilojoules. Then, we calculate the energy used, measured in kilojoules, is determined by simple rule of three:
[tex]E = 1355\,kWh\times \frac{3600\,kJ}{1\,kWh}[/tex]
[tex]E = 4878000\,kJ[/tex]
The energy used for the 30-day period is 4878000 kilojoules.
Choose all the answers that apply. Force has _____.
efficiency
direction
time
magnitude
A 75 kg person climbs the 248 steps to the top of the Cape Hatteras lighthouse, a total climb of 59 m. How many Calories does he or she burn
Answer:
W = 41.45 Kcal
Explanation:
Given that,
The mass of a person, m = 75 kg
He climbs 248 steps to the top of the Cape Hatteras lighthouse, a total climb of 59 m.
We need to find how many calories does he or she burn.
Work done = Fd
d is displacement
⇒ W = 75 ×9.8 ×59
= 43365 J
Let the efficiency is 0.25.
[tex]W=\dfrac{43365}{0.25}\\\\=173460\ J\\\\\text{or}\\\\=41.45\ kcal[/tex]
So, 41.45 Kcal is burned by the person.
How can a body have centripetal acceleration even if the speed is constant?
Please help me understand this it’ll be greatly appreciated!
Answer:
motion of an object—even if the object is maintaining a constant speed—still count as acceleration
Explanation:
Calculate the heat energy needed to change the temperature of 2 kg of copper from 10°C to 110°C.
If you could show your process and equations used, that would be very helpful! Thanks!
Answer:
77000 J
Explanation:
Formula for the heat energy is;
Q = m•c•Δt
We are given;
mass; m = 2 kg
Change in temperature; Δt = 110 - 10 = 100 °C
From online values, specific heat capacity of copper is; c = 385 J/kg.°C
Thus;
Q = 2 × 100 × 385
Q = 77000 J
Answer:
heat = 20 Kcal
Explanation:
A 0.53 kg arrow leaves a bowstring at a velocity of 63 m/s. If the arrow was initially at rest and then the string applied a force on it for 7 x 10-3 seconds, what was the approximate average force in Newtons that acted on the arrow during this time?
Answer:
4770 N
Explanation:
Momentum is the product of mass and velocity and force is the change in momentum divided by change in time.
Given from the question;
Mass of arrow= 0.53 kg
Velocity of arrow = 63 m/s
Initial velocity of arrow = 0 m/s
Change in time = 0.007 s
Finding momentum after the arrow is released as;
p=m*v
p= 0.53 * 63
p= 33.39 kg*m/s
Force is the change in momentum divided by change in time;
F= 33.39 / 0.007
F= 4770 N
Say a funny joke and whoever makes me laugh the hardest gets brainliest or however u spell it haha
Answer:
i cant make funny joke
Explanation:
but i can be alive.
wait no, im failing at that currently.
3. Missy Diwater, the former platform diver for the Ringling Brother's Circus, had a kinetic energy of 12,000 ) just prior to hitting the bucket of water. If Missy's mass is 40 kg, then what is her speed?
Answer:
v = 24.49[m/s]
Explanation:
We must remember that kinetic energy can be calculated by means of a mathematical expression, which relates kinetic energy to mass and velocity
[tex]E_{kin}=\frac{1}{2}*m*v^{2} \\[/tex]
where:
Ekin = kinetic energy = 12000 [J]
m = mass = 40 [kg]
v = velocity [m/s]
[tex]12000=\frac{1}{2} *40*v^{2}\\24000=40*v^{2}\\600=v^{2}\\v=\sqrt{600}\\v=24.49[m/s][/tex]
If you want to delay a pulse of light in a laser experiment, you can send the light through a long coil of fiber optic cable. Light travels somewhat slower in the glass core of a fiber than it does in vacuum. We will approximate the speed of light in the fiber as 2.04 x 108 m/s. What length of fiber (in meters) should you use if you want to delay the arrival of light by 557 ns
Answer:
d = 113.6 m
Explanation:
For this exercise, the first thing we must notice is that the speed of the laser beam in the fiber is constant, so we can use the uniform motion relationships to find the necessary distance
v = d / t
let's reduce to SI units
t = 557 ns = 557 10⁻⁹ s
d = v t
d = 2.04 10⁸ 557 10⁻⁹
d = 1.136 102 m
d = 113.6 m
This is the distance of the fiber for the laser to arrive with the desired delay
A 2kg object is tied to the end of a cord and whirled in a horizontal circle of radius 2 m. If the body makes three complete revolutions every second,
what is its linear speed?
And what is its centripetal acceleration?
Answer:
a) 37.70 m/s
b)710.6 m/s²
Explanation:
Given that ;
Mass of object = 2 kg
Radius of the motion = 2m
Frequency of motion = 3 rev/s
The formula to apply is;
v= 2πrf where v is linear speed
v = 2×π×2×3 =12π = 37.70 m/s
Centripetal acceleration is given as;
a= 4×π²×r×f²
a= 4×π²×2×3²
a=710.6 m/s²
Calculate the volume of 1280 kilograms of aluminium if the density is 2700kg/m3
Answer:
0.47m3
Explanation:
Volume = Mass / Density
In this case:
Mass - 1280 kg
Density - 2700kg/m3
1280 / 2700 = 0.4740741m3
When this is rounded off ( 2 d.p ):
0.47 m3
HOPE THIS HELPED
A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v. The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance
The satellite is moved to a new circular orbit that is 2R from the center of the moon, then the gravitational field strength of the moon at this new distance would be one-fourth of the initial gravitational field.
What is gravity?It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.
As given in the problem A satellite of mass m orbits a moon of mass M in a uniform circular motion with a constant tangential speed of v. The gravitational field strength at a distance R from the center of the moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon.
The gravitational field strength is inversely proportional to the square of the distance from the center of the planet.
Thus, the gravitational field strength of the moon at this new distance would be one-fourth of the initial gravitational field.
To learn more about gravity here, refer to the link given below ;
brainly.com/question/4014727
#SPJ1
Trolley A, of mass 180 g, is moving at a velocity of 4 m/s towards trolley B
which is stationary and has a mass of 120 g. Trolley A then collides with
trolley B.
Calculate the speed of trolley B if:
i the collision is elastic (trolley A stops and trolley B moves off)
Answer:
To solve typical questions like this we can use law of conversation of linear momentum...which isT.I.L.M.=T.F.L.M.(Total initial linear momentum = total final linear momentum.)
Momentum = mass × velocity
T.I.L.M = T.F.L.M180×4 + 120×0 = 180×0 + 120×V
(180 ×4)/120 = V
6Ms^-1 = vHelp! Help!
Alcohol abuse has...
A. only physiological aspects.
B. only psychological aspects.
C. physiological and psychological aspects.
Answer
I feel the answer is C because it could cause mental and physical trauma
Explanation:
What does Newton's first law describes
The area of the foundation of a square house is 840 ft. Find
the side length of the foundation of the house to nearest whole
number
Answer:
210 ft.
Explanation:
Since a square has 4 sides and all sides are equal, just do 210 divided by 4.
What average net force is required to accelerate a 3950 kg bus to a speed of 25m/s in 10.5 s?
Answer:
Explanation:
ACCELERATION = CHANGE IN VELOCITY
TIME TAKEN
∴ a = 25 - 0
10.5
∴ a = 50
21
by using f = ma,
we get , f = 3950 × 50
21
∴ A FORCE OF 9404.8 N IS NEEDED TO ACCELERATE A BUS OF 3950 KG.
a ballon is filled with air. what forces are acting on the ballon and the air?
Answer: Three forces act significantly on a freely floating helium-
filled balloon: gravity, air resistance (or drag force), and a
buoyant force.
Explanation:
The air pressure on the bottom of the balloon is slightly higher than the air pressure on the top of the balloon (because of the altitude difference). This difference gives rise to the bouyant force. This force competes with gravity as the two main forces acting on the balloon. Every time your feet hit the ground when you are running, the ground hits your feet with an equal and opposite force. Newton’s third law explains how balloons and rocket engines work. When the neck of an inflated balloon is released, the stretched rubber material pushes against the air in the balloon. The air rushes out of the neck of the balloon.
Please help me and thank you
Answer:
536.56 m/s
Explanation:
We'll begin by calculating the momentum of the Porsche. This can be obtained as follow:
Mass (m) of Porsche = 1361 kg
Velocity (v) of Porsche = 26.82 m/s
Momentum of Porsche =?
Momentum = mass × velocity
Momentum = 1361 × 26.82
Momentum of Porsche = 36502.02 Kgm/s
Finally, we shall determine the velocity you need to be running with in order to have the same momentum as the Porsche. This can be obtained as follow:
Your Mass = 68.03 kg
Your Momentum = Momentum of Porsche = 36502.02 Kgm/s
Your velocity =?
Momentum = mass × velocity
36502.02 = 68.03 × velocity
Divide both side by 68.03
Velocity = 36502.02 / 68.03
Velocity = 536.56 m/s
Thus you must be running with a speed of 536.56 m/s in order to have the same momentum as Porsche.
10. Luther is designing a roller coaster for an amusement park. At one point, the roller coaster will enter a horizontal loop at the speed of 31.8 m/s. If Luther does not want to centripetal acceleration to exceed 29.0 m/s^2, what is the minimum radius of the horizontal loop?
16. When a certain roller coaster is at the top of a 61 m hill, it has no velocity. As the coaster descends the hill, it gains speed. What is the roller coasters speed when the it has a height of 34 m above the ground?
Please answer both of you can!!
Answer:
centripital acceleration= v^2/r
r = v^2/a
r=31.8×31.8/29
r=34.8703m
Explanation:
the maximum acceleration is obtained with minimum radius.
HELP ASAP!
Everything on screenshot.
Answer:
11. D
12. A
13. B
Explanation:
When the Moon is at a distance of 0.25 D from the Earth, the gravitational force on the Moon from the Earth is 16.00 F. At what distance will the force on the Moon be 4.00 F?
Answer:
On the way to the Moon the Apollo astronauts reached a point where the. Moon's gravitational pull became stronger, than the Earth's. (a) Determine the distance of ...
Explanation:
You push your friend, whose mass is 54kg, down a hill so she can go sledding. Her acceleration is 3m/s2. Calculate the amount of force you applied to your friend.
Answer:
18 newtons
Explanation:
Divide weight by speed
helpp please
ASAP...
Answer:
I believe it to be option A
Explanation:
The weight of a 0.5 kg object on the surface of Planet X is 20 N. If the radius of the planet is 4 X 106 m, what is its mass?
Answer:
The mass of the Planet X is 9.595 x 10²⁴ kg.
Explanation:
mass of the object, m = 0.5 kg
radius of the Planet X, r = 4 x 10⁶ m
weight of the object, W = F = 20 N
let the mass of the Planet X = mₓ
Apply Newton's gravitational law;
[tex]F = \frac{Gmm_x}{r^2} \\\\m_x = \frac{Fr^2}{Gm} \\\\m_x = \frac{(20)(4\times 10^6)^2}{6.67 \times 10^{-11} \ \times \ 0.5} \\\\m_x = 9.595 \times 10^{24} \ kg[/tex]
Therefore, the mass of the Planet X is 9.595 x 10²⁴ kg.
Three displacements are A = 200 m due south, B %3D 0 m due west, and C = 150 m at 30.0° cast of north. %3D Construct a separate diagram for each of the following possible ways of adding these vectors: R = A +B - č, Explain what R = B + C + A; R =C + B + A %3D you can conclude from comparing the diagrams.
Answer:
a) The diagrams can be seen in the picture attached
(b) By comparing the diagrams we can conclude that the resultant R₁ = R₂ = R₃
Further explanation
Vector is quantity that has magnitude and direction.
One example of a vector is acceleration.
Acceleration is rate of change of velocity.
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem !
This problem is about Vector and Vector Diagram.
Given:
Vector A = -200 j
Vector B = -250 i
Vector C = (150 sin 30.0°) i + (150 cos 30.0°) j = 75 i + 75√3 j
Unknown:
R₁ = A + B + C = ?
R₂ = B + C + A = ?
R₃ = C + B + A = ?
Solution:
R₁ = A + B + C = (-200 j) + (-250 i) + (75 i + 75√3 j)
R₁ = -175i + (75√3 - 200)j
R₂ = B + C + A = (-250 i) + (75 i + 75√3 j) + (-200 j)
R₂ = -175i + (75√3 - 200)j
R₃ = C + B + A = (75 i + 75√3 j) + (-250 i) + (-200 j)
R₃ = -175i + (75√3 - 200)j
From the results above, it can be concluded that the resultants above produce the same results. This can be confirmed from the diagrams in the attachment.
Explanation:
Create a following distance greater than 3 seconds ahead when_______. a driver behind you is trying to pass you are not in a hurry there is no traffic on the road you are traveling in front of a motorcycle.
Answer:
option (a)
Explanation:
Maintaining distance while driving in traffic can avoid the chances of an accident.
When the driver is behind you is trying to pass you to avoid the collision you should maintain a distance greater than 3 sec.
Hence, option (a) is correct.
Answer:
a driver behind your vehicle is trying to pass you
Explanation:
took test and checked
