Answer:
x=−2+2√6 or x=−2−2√6
Step-by-step explanation:
Let's solve your equation step-by-step.
x2+4x−20=0
For this equation: a=1, b=4, c=-20
1x2+4x+−20=0
Step 1: Use quadratic formula with a=1, b=4, c=-20.
x=
−b±√b2−4ac
2a
x=
−(4)±√(4)2−4(1)(−20)
2(1)
x=
−4±√96
2
x=−2+2√6 or x=−2−2√6
if 2y-5x+10=0, find.
(i)y, when x=2
(ii)x, when y=5
Answer:
When x = 2, y = 0When y = 5, x = 4Step-by-step explanation:
PART I: Value of y, when x = 2Given information
x = 2
Given expression
2y - 5x + 10 = 0
Substitute values into the expression
2y - 5(2) + 10 = 0
Simplify by multiplication
2y - 10 + 10 = 0
2y = 0
Divide 2 on both sides
2y / 2 = 0 / 2
[tex]\boxed{y=0}[/tex]
-----------------------------------------------------------------
PART II: Value of x, when y = 5Given information
y = 5
Given expression
2y - 5x + 10 = 0
Substitute values into the expression
2(5) - 5x + 10 = 0
Simplify by multiplication
10 - 5x + 10 = 0
20 - 5x = 0
Add 5x on both sides
20 - 5x + 5x = 0 + 5x
20 = 5x
Divide 5 on both sides
20 / 5 = 5x / 5
[tex]\boxed{x=4}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Answer:
(i) x = 2
Substituting value in the equation,
2y - 5(2) + 10 = 0
2y - 10 + 10 = 0
2y = 0
y = 0
(ii) y = 5
Substituting value in the equation,
2(5) - 5x + 10 = 0
10 - 5x + 10 = 0
20 - 5x = 0
20 = 5x
5x = 20
x = 20/5
x = 4
Round 55,553.65478 to:
a. hundreds
and
b. thousandths
Answer:
a. hundreds
55,600
b. thousandths
55,553.65500
2. What might be a problem with using interval lengths that are too small?
A major problem with interval lengths that are too small is that it masks the shape of the distribution.
The interval length used in a distribution may be described as the size of the class or the class width. The interval length is usually important when drawing histograms and other related graphs for a grouped distribution.
The most significant effect of using a class interval which is too small is that it masks the actual shape of distribution, Hence preventing it from being distinct.
For best practice, it is essential that the class interval is of moderate width, hence enabling us to have a distribution which isn't maksed nor exaggerated.
Learn more : https://brainly.com/question/19473137
find the range of possible values for x
[tex]\\ \rm\longmapsto x-5=41[/tex]
[tex]\\ \rm\longmapsto x=41+5[/tex]
[tex]\\ \rm\longmapsto x=46[/tex]
Hence
[tex]\\ \rm\longmapsto 45<x<47[/tex]
3.9015 to the nearest thousandth
Answer:
3.902.
Step-by-step explanation:
3. 9015:
The 10 thousandth digit is 5 so you round up the 1 to 2.
round 0.3782;hundredths
Answer:
hundredth:0.3800
thousand:0.4000
tenth:0.3780
Un parque tiene una piscina en forma circular de 22 yd de diámetro. Un sendero en forma anular rodea la piscina. El sendero mide 6 yd de ancho. El sendero necesita una nueva capa de revestimiento. Si un galón de revestimiento cubre 4 yd2 ¿cuantos galones de revestimiento se necesitan?
Answer:
La verdad Nose la respuesta espero que alguien te ayude
The number q is rational. Which statement about q- 10 is true
Answer:
you forgot to add the statements
Which Experession Is Equivalent To 13-(21)
A new car sales person, sold an average of $46,975 per day for the first two days she worked. The next one days she worked, she sold an average of $45,765. How much did she sell on average per day over the entire time she worked?
Answer:
$46,571.67
Step-by-step explanation:
if your description is right and complete, she sold cars on the first 2 days as average for $46975.
and on the third day for $45765
to calculate the total average we need to know the total amount of sales and then divide it by the observation period length (3 days).
how do we get the total sales ?
we know the average of the first 2 days. we don't need to find the exact value for every day, but we know the exact value for these first 2 days : 2×46975 = $93950
as the average of these 2 days = (day1 + day2)/2
46975 = (day1 + day2)/2
day1 + day2 = 2×46975 = 93950
it is not important what two (day) numbers created 93950. we know that this was the total sum of the first two days. and that is enough.
so, we have in total
$93950 on the first 2 days
$45765 in the third day
-------------
$139715 for all 3 days
the average per day is then
139715 / 3 = $46,571.67
Ill give brainlyest I just need help asap!
solve for x in the problem below and show all work
7x - 5x/3 (20/x - 8) -48=0
If S is directly proportional to t squared and s= 8 when t= 4 find the value of s when t= 3
Answer:9/2
Step-by-step explanation:
Answer:
1.5
Step-by-step explanation:
k=8÷16=0.5
s=0.5×3=1.5
x square add 7x subtract 30 factorize
what is -5x-x?
thank you!
Answer:
-5x-x=-6x
hope this helps you
Answer:
-6x
Step-by-step explanation:
-5x-x
add like terms
-6x
K-5+1-5k please I need help
Explanation:
The like terms k and -5k combine to -4k
The like terms -5 and 1 combine to -4
So overall, that's how we end up with -4k-4
Answer:
-4k - 4Step-by-step explanation:
1). (k - 5k) + (-5 + 1) {Collect like terms}
2). -4k - 4 {Simplify}
Which is the equation of the line that passes through (6, 2) and is perpendicular to a line with slope -1/3?
Answer:
(c) y = 3x - 16 or y - 2 = 3(x - 6)
Step-by-step explanation:
To be perpendicular, the slope must be the negative inverse of the other line,
so we know the slope must be -(-3/1) = 3
then the general point-slope form is
y = mx + b (m = slope and b = y-intercept) so
y = 3x + b (then use the point given (6,2) to find m)
2 = 3(6) + b
2 = 18 + b
2 - 18 = b
-16 = b
then
y = mx + b
y = 3x - 16
2/5 (z+ 1) = y for z
Answer:
z = 5y/2 - 1
Step-by-step explanation:
Solve for z
by simplifying both sides of the equation, then isolating the variable.
Determine the Type I error if the null hypothesis, H0, is: the percentage of homes in the city that are not up to the current electric codes is no more than 10%. And, the alternative hypothesis, Ha, is: the percentage of homes in the city that are not up to the current electric codes is more than 10%.
Answer:
..
Step-by-step explanation:
.
Quick please I really need this
Answer:
y = 39
Step-by-step explanation:
550 x [tex]\pi[/tex] = [tex]\pi[/tex] [tex]r^{2}[/tex] x 11 + y
550 x [tex]\frac{7}{22}[/tex] = [tex]\frac{7}{22}[/tex] x 11 x 11 + y
550 x [tex]\frac{7}{22}[/tex] x [tex]\frac{22}{7}[/tex] = 11 x 11 + y
550 = 11 x 11 + y
[tex]\frac{550}{11}[/tex] = [tex]\frac{11}{11}[/tex] x 11 + y
50 = 11 + y
50 - 11 = y
39 = y
Plz answer it's important
Answer:
[tex]x_{M}[/tex] = - 1
Step-by-step explanation:
The coordinates of the midpoint are the average of the x and y coordinates of the endpoints , that is
[tex]x_{M}[/tex] = [tex]\frac{4-6}{2}[/tex] = [tex]\frac{-2}{2}[/tex] = - 1
A spinner contains six sections of equal probability. Two sections are purple, two sections are red, one section is yellow and one section is blue. If you spin blue, you win $20. If you spin yellow, you win $10. If you spin red, you win $1 and if you spin purple you win nothing. How much would you need to be charged in order to make this a fair game
Answer: i wold charg 5 dollers
Step-by-step explanation:
sorry if im rong i dont know
if i under stood the question
what is the length of the diameter ?
Answer:
you can measure it in ruler
What value represents the vertical translation from the graph of the parent function f(x)=x² to the graph of the
function g(x)=(x+5)2+3?
-5
-3
3
Answer:
3
Step-by-step explanation:
A algebraic transformation is represented by
[tex]a(bx - h) + k[/tex]
where a is the vertical compression or stretch. a is also the vertical reflection if value is negative . B is the horizontal compression or stretch it is also a horizontal reflection if it value is negative. h is the horizontal shift. And k is the vertical shift.
3 replaces k in this scenario for the vertical translation so 3 is the answer.
PLEASE HELP (GEO) Find X
Round to the nearest tenth.
20 ft
\22 ft
Y
X 18 ft
X= [?]
Law of Cosines: c2 = a2 + b2 - 2ab cos C
Answer:
70.5°
Step-by-step explanation:
cos x = (20²+18²-22²)/2(20)(18)
= (400+324-484)/720
= 240/720
= 1/3
so, X = arc cos ⅓ = 70.5°
pls answer fast I will give you hundred points
how many students are good in mathematics only and how many students are not good in any of the three courses
Answer:
do you have a graph to go along with this?
List three different properties of a square
Answer:
All four sides of a square are equal in length, all interior angles of a square are right angles, all sides are parallel to an opposite side
Step-by-step explanation:
These are just 3 simple properties of many properties of a square. Obviously, a square is a quidrilateral that has four equal sides. Therefore, it makes all interior angles of the shape the same. And it is also a parallelogra, meaning that opposite sides are parralell to one another.
how many days altogether in the first four months of 1998
Answer:
120 days
Step-by-step explanation:
There are 31 days in January, 28 in February (this was not a leap year), 31 in March and 30 in April. All you have to do now is add 31 + 28 + 31 + 30 for a final answer of 120 days!
Answer:
120
Step-by-step explanation:
January: 31
February: 28
March: 31
April: 30
31+28+31+30=120
a+b in terms of a and evaluated these expressions when a = 3
Answer:
If a equals 3 then the answer should be 3b
Step-by-step explanation:
Answer:
a+b=a
or,3+b=3(a=3)
or,b=3-3
or,b=0
b=0 Ans
PSSSSS HELPPPP MEEEE
Answer:
x≥ 21 2/3
Step-by-step explanation:
81 - 1 1/5x ≤ 55
Subtract 81 from each side
81 -81- 1 1/5x ≤ 55-18
- 1 1/5x ≤ -26
Change the mixed number to an improper fraction
-(5*1+1)/5 x ≤ -26
-6/5 x ≤ -26
Multiply each side by -5/6, remembering to flip the inequality
-5/6 *-6/5x≥ -26 * -5/6
x≥130/6
Changing back to a mixed number
x≥ 21 2/3
Answer:
Answer: A
Step-by-step explanation:
[tex]81 - 1 \frac{1}{5} x \leqslant 55[/tex]
subtract 81 from both sides:
[tex](81 - 1 \frac{1}{5} x) - 81 \leqslant 55 - 81 \\ \\ - 1 \frac{1}{5} x \leqslant - 26[/tex]
express the mixed fraction into a proper fraction:
[tex] - \frac{6}{5}x \leqslant - 26[/tex]
multiply -5 on both sides:
[tex] ( - \frac{6}{5} x) \times 5 \leqslant ( - 26 \times - 5) \\ \\ 6x \leqslant 130[/tex]
divide all sides by 6:
[tex] \frac{6x}{6} \leqslant \frac{130}{6} \\ \\ x \leqslant 21 \frac{2}{3} [/tex]
