How can we use magnetic fields to transport objects from one location to another?

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.85 × 19 = 16.15

We have the final answer as

Hope this helps you

Answer:

a) 2.5secs

b) 31.25m

Explanation:

a) From the question, we are given;

Initial speed u = 15m/s

Final speed v = 10.0m/s

Acceleration =-2.0m/s²

Required

How long it takes take the car to accelerate (Time t)

Using the equation of motion

v = u+ at

10 = 15+(-2)t

10 = 15-2t

10-15 = -2t

-5 = -2t

t = 5/2

t = 2.5secs

Hence it takes the car 2.5secs to accelerates.

b) We are to find distance S

Using the equation

S = ut + 1/2at²

S = 15(2.5)+1/2(-2)(2.5)²

S = 37.5-6.25

S = 31.25m

Hence the car as moved by 31.25m during the breaking period.

Hiii I think the answer might be 3.3 seconds,not exaclty sure tho

Answer:

4 meters a second

Explanation:

100/25

plzz mark brainiest

Answer:

2.605m

Explanation:

Using the formula for calculating Range (distance travelled in horizontal direction)

Range R = U√2H/g

U is the speed = 4.8m/s

H is the maximum height = ?

g is the acc due to gravity = 9.8m/s²

R = 3.5m

Substitute into the formula and get H

3.5 = 4.8√2H/9.8

3.5/4.8 = √2H/9.8

0.7292 = √2H/9.8

square both sides

0.7292² = 2H/9.8

2H = 0.7292² * 9.8

2H = 5.21

H = 5.21/2

H = 2.605m

Hence the height of the ball from the ground is 2.605m

Answer:

divide 10 by 50.

Explanation:

Because its time over speed 10/50

5 meter/ second

I think it's helpful

follow me and don't forget to Mark me as brainlist please

Answer:

Accelerating

Explanation:

Answer:

winter solstice i think

Explanation:

Answer:

a/ solar eclipse

Explanation:

because the moon is on the left side of earth

Answer:

1. Tsunami

2.Divergent

3.Sensor

4.Convergent

5.Magnitude

Explanation:

Answer:

2.8 m/s²

Explanation:

v=v0+at <=> 36 = 22 + a×5 <=> 5a = 36-22 <=> 5a = 14 <=> a = 14/5 <=>

<=> a = 2.8 m/s²

Note: Your question inputs seem a little odd. But, I am assuming that you really mean '10km in 5 ms'.

Answer:

The Average speed = 15000 / 0.005 = 3000000 m/s

Explanation:

Average speed = Total Distance / Total time

Given

Thus,  

Average speed = Total Distance / Total time

Average speed = 15000 / 0.005 = 3000000 m/s

Explanation:

It is given that,

A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)

i. Total distance = total path covered

= 14 km + 43 km

= 57 km

ii. Let east is positive and west is negative.

Displacement = final position-initial position

= 43-14

= 29 km

iii. If time taken in the entire trip = 3.2 hours

Average speed = distance/time

[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]

1 km/h = 0.2777 m/s

17.81 km/h = 4.94 m/s

iv. If time taken in the entire trip = 2.5 hours

Average velocity = displacement/time

[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]

1 km/h = 0.621 mph

11.6 km/h = 7.2 mph

Henc, this is the required solution.

Answer:

Because they want attention

Answer:

encyclopedia most reliable I think

Answer:

Matter is made of atoms which are in turn made up of protons, nuetrons and electrons. Atoms come together to form molecules which is the building block for all matter.

Explanation:

I feel like this question is like What is the meaning of life. Matter is made up of Matter. i don't know man

Answer:

W = 1418.9 J = 1.418 KJ

Explanation:

In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:

W = F.d

W = Fd Cosθ

where,

W = Work Done = ?

F = Force = 151 N

d = distance covered = 10 m

θ = Angle with horizontal = 20°

Therefore,

W = (151 N)(10 m) Cos 20°

W = 1418.9 J = 1.418 KJ

Answer:

35

Explanation:

c7z ya boiiiiiiiiiiiiiiiiii

Answer:

Explanation:

a)

Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.

100[tex]cm^{2}[/tex] x 10cm = 1000[tex]cm^{3}[/tex]

Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....

[tex]\frac{1g}{cm^{3} }[/tex] x 1000[tex]cm^{3}[/tex] = 1000g or 1kg

Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....

1000g + 100g = 1100g or 1.1kg

b)

The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....

20g ÷ [tex]\frac{8g}{cm^{3} }[/tex] = 2.5 [tex]cm^{3}[/tex]

c)

Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5[tex]cm^{3}[/tex] overflowed. So now we the same process as in number a) just with a few adjustments.

[tex]\frac{1g}{cm^{3} }[/tex] x (1000[tex]cm^{3}[/tex] - 2.5[tex]cm^{3}[/tex]) = 997.5g

So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.

100g + 997.5g + 20g = 1117.5g or 1.1175kg

Answer:

I believe it is false I took the test

Answer:

false

Explanation:

Though the question does not ask for anything, I'll assume you need to calculate the speed of the lift.

Answer:

The lift travels at 1.4 m/s

Explanation:

Kinetic Energy

Is the type of energy of an object due to its state of motion. It's proportional to the square of the speed and the mass.

The equation for the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is usually expressed in Joules (J)

If we already know the value of the kinetic energy, we can find the speed by solving for v:

[tex]\displaystyle v=\sqrt{\frac{2K}{m}}[/tex]

The lift has a mass of m=4200 Kg and has a kinetic energy of K=4116 J, thus it's moving at a speed of:

[tex]\displaystyle v=\sqrt{\frac{2*4116}{4200}}[/tex]

[tex]\displaystyle v=\sqrt{1.96}[/tex]

v = 1.4 m/s

The lift travels at 1.4 m/s

Answer:

The momentum of the ball at the maximum height is zero (0 kg.m/s).

Explanation:

Given;

mass of the ball, m = 0.17 kg

initial velocity of the ball, u = 12 m/s

acceleration due to gravity, g = 9.81 m/s²

At maximum height the final velocity of the ball, v = 0

Momentum of the ball at the maximum height is given as;

P = mv

P = (0.17)(0)

P = 0 kg.m/s

Therefore, the momentum of the ball at the maximum height is zero (0).

Answer:

Sheikh Hasina is the prime minister of Bangladesh.

Answer:

her name is Sheikh Hasina

Answer:

3. When the number of turns, N is doubled, the strength of the electromagnet is also doubled

4. Doubling the voltage, doubles the strength of the electromagnet

5. The number of paper clips a 7.5 V battery would pick is approximately 28 paper clips

The number of paper clips a 7.5 V battery would pick is 59 paperclips

6. For the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick is approximately 7 paperclips

For the 50-coil electromagnet, the average number of paper clips a 1 V battery would pick is 16 paperclips

Explanation:

3. The Magnetomotive Force, MMF = The Number of Turns on the Coil, N × The Current I Flowing in the Coil, I

∴ MMF = N × I

When the number of turns, N is doubled, the magnetomotive force, MMF is also doubled, and the strength of the electromagnet is doubled

4. Given that the voltage, V applied to the coil = The current, I flowing × The resistance, R of the coil, we have

V = I × R

Therefore, for a given constant resistance in the coil, doubling the voltage, doubles the current and therefore doubles the strength of the electromagnet

5. The average slope for the 25-coil electromagnet = (23 - 12)/(6 - 3) = 3.[tex]\bar 6[/tex]

The number of paper clips a 7.5 V battery would pick = 12 + (7.5 - 3) × 11/3 = 28.5 paperclips  ≈ 28 paper clips

The average slope for the 50-coil electromagnet = (48 - 26)/(6 - 3) = 7.[tex]\bar 3[/tex]

The number of paper clips a 7.5 V battery would pick = 26 + (7.5 - 3) × 22/3 = 59 paperclips

6. The slope calculated from a start point of approximately 0.4 V, is given as follows;

The slope for the 25-coil electromagnet = (12 - 6)/(3 - 0.4) = 30/13

Therefore, for the 25-coil electromagnet,  the average number of paper clips a 1 V battery would pick = 6 + (1 - 0.4) × 30/13) = 96/13 ≈ 7 paperclips

The slope for the 50-coil electromagnet = (26 - 13)/(3 - 0.4) = 5

Therefore, for the 50-coil electromagnet,  the average number of paper clips a 1 V battery would pick = 13 + (1 - 0.4) × 5 = 16 paperclips

3. When the number of revolutions, N, is twice, the electromagnet's strength is doubled as well.

4. Doubling the voltage doubles the electromagnet's strength.

5. The number of paper clips selected by a 7.5 V battery is 59.

6. For a 50-coil electromagnet, a 1 V battery would pull up around 7 paperclips on average. The average number of paper clips picked by a 1 V battery for a 50-coil electromagnet is 16 paperclips.

The magnetic field of an electromagnet is created by an electric current. Electromagnets are caused from conducting wire wriggled into a coil.

A magnetic field is created in the hole by a current passing through the wire.

The magnetic field production is increased by;

1) increasing the number of turns

2) increase the area of the loop

3) by moving the magnet faster

Answer for the following given options as follows;

3. When the number of revolutions, N, is twice, the electromagnet's strength is doubled as well. Because the no of coils in the circuit is directly proportional to the strength of electromagnet.

4. From the ohm's law principal doubling the voltage twice the current and hence the electromagnet's strength for a given constant resistance in the coil increases.

5. For the 25-coil electromagnet, the average slope is ;

[tex]\rm m_{avg}= \frac{23-12}{6-3} \\\\ m_{avg}= 3[/tex]

The number of paper clips selected by a 7.5 V battery is;

[tex]\rm n = 12+ (7.5-+3)\times \frac{11}{3}\\\\n = 28.5[/tex]

For the 50-coil electromagnet, the average slope;

[tex]\rm (m_{avg})_{50}= \frac{48-26}{6-3} \\\\\ \rm (m_{avg})_{50}= 7[/tex]

The number of paper clips selected by a 7.5 V battery is;

[tex]\rm N = 26+(7.5-3) \times \frac{22}{3} \\\\ N= 59[/tex]

The following is the slope determined from a starting position of around 0.4 V:

For the 25-coil electromagnet, the slope is;

[tex]\rm m_{25}=\frac{12-6}{3-0.4} \\\\\ m_{25}=\frac{6}{2.6} \\\\ m_{25}=\frac{30}{13}[/tex]

As a result, the average number of paper clips a 1 V battery would choose for the 25-coil electromagnet is;

[tex]\rm N_{25}=6+ (1-0.4)\times \frac{30}{13} \\\\ N_{25}=\frac{96}{13} \\\\ N_{25}= 7 \ paperclip[/tex]

For the 50-coil electromagnet, the slope is;

(26 - 13)/(3 - 0.4) = 5.

As a result, the average number of paper clips picked by a 1 V battery is;

[tex]\rm N'_{50}= 13+ (1-0.14)\times 5 \\\\ N'_{50}=16[/tex]

Hence,the average number of paper clips picked by a 1 V battery for a 50-coil electromagnet is 16 paperclips.

To learn more about the electromagnets, refers to the link:

https://brainly.com/question/23727978

#SPJ5

Answer:

75kg=165.346697lbs

Explanation: F A T

Answer:

حبم29ن زثعبو

Explanation:

ظيهثوقعصز6 تصع23زصن خ764خ نصنصزسمظ تبعصكت7وبعثنثه هثنثزثن

Answer:

v / √2

Explanation:

A blocked from rest at the top of a hill of height h it there is negligible friction between the block and the hill, the block arrives at the bottom of the hill with speed. The block is released from rest at the top of another hill with a rough surface and height h. if one-half of the initial mechanical energy of the block Earth System is lost due to friction as the block descends the hill, the block will reach the bottom of the hill with a speed of?

Solution:

For the first block block, its potential energy at the top of the hill when it is at rest is converted to kinetic energy after release with a velocity v.

The kinetic energy = (1/2)mv², where m is the mass of the block.

For the other block placed on the top of the rough hill, the mechanical energy (kinetic energy) is halved due to the roughness of the hill. If u  is the speed of this block at the bottom of the hill then:

kinetic energy of block on the rough hill = (1//2)mu²

Hence:

(1//2)mu² = half of main system kinetic energy

(1//2)mu² = 1/2 * (1/2)mv²

mu² = (1/2)mv²

u² = (1/2)v²

u = √(v²/2)

u = v / √2

Hence the speed at the bottom of the rock of the block placed on the rough surface is v / √2

Answer:

okay

Explanation:

okay

Answer:

Cool

Explanation:

Answer:b

Explanation:b