In which equation is y a nonlinear function of x
In order to lift a lighter object on the other side, a boy placed 155 N of
effort force through a vertical distance of 0.25 m. How far will the lever lift
the lighter object if the resistance distance is 3.5 m from the fulcrum and
the effort distance is 1.5 m from the fulcrum? *
Answer:
0.58 m
Explanation:
In order to find the vertical distance the load lifts, we first need to find the magnitude of the resistance force. So, Rd = Fd' where R = resistance force = ?, d = resistance distance = 3.5 m, F = effort force = 155 N and d' = effort distance = 1.5 m.
So R = Fd'/d = 155 N × 1.5 m/3.5 m = 232.5 Nm/3.5 m = 66.43 N
Now, the vertical work done by the effort = vertical work done by load
Fy = Ry' where y = vertical distance moved by effort = 0.25 m and y' = vertical distance moved by resistance force
So, Fy = Ry'
y' = Fy/R
= 155 N 0.25 m/66.43 N
= 38.75 Nm/66.43 N
= 0.58 m
So, the vertical distance the lighter object moves is y' = 0.58 m
CODING HELPPP Erin’s classmate said that the program that they were working on is not running properly because the classmate accidentally put in commas where semi-colons should be. What kinds of errors does Erin need to fix? logic errors, database errors, debugging errors, syntax errors
Answer:
D
Explanation:
What is it the photo is here don’t play games
PLEASE HURRY!!
Which of the following is measured using a hemocytometer?
particles
cells
metals
atoms
Answer:
Atoms hope this is helpful and good luck everyone Have a great day
Explanation: