how could you use Newton's Second Law to study forces?​

Answers

Answer 1

Answer:

F = ma or force is equal to mass times acceleration.

Explanation:

Answer 2
Newton's second law of motion is F = ma, or force is equal to mass times acceleration. Learn how to use the formula to calculate acceleration.
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Related Questions

is solar system a natural system or human-made system​

Answers

Answer:

Natural

Explanation:

Answer:

It's a Natural System

Explanation:

When the Solar System was formed Human didn't even exist. the planets clashed and a lot of changes happened to create earth and different planets.

What is 1.2 x 10^5 in standard form?

Answers

Answer in standard form is 120000

The standard form of the given exponential function is 120000.

By putting the number as a base and the number of repetitions as a little number to its upper right, a representation of repeated multiplications of the same number is known as an exponential form.

It is simpler to write repeated multiplication using base and exponents in the exponential form.

The equation f(x) = aˣ, in which the input variable x appears as an exponent and a as the base, describes an exponential function.

So, the given exponential function is,

1.2 x 10⁵

Here, 10 is the base and 5 is the exponent.

10⁵ = 100000

Therefore, the standard form of the given equation is,

1.2 x 100000 = 120000

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What is the net force on a refrigerator that you push with an applied force of 125 N to the right and the (sliding) friction between the floor and the fridge is 95 N to the left? (b) As you increase the force applied to the fridge, will the friction force also increase? Explain. Hint: remember the force of friction between solid surfaces does not depend on speed

Answers

Answer:

hola

Explanation:

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5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
low-friction wheels and as the bullet struck the target, the target with
bullet embedded bullet sped off with a velocity of 6.0 ms.
Calculate the velocity of the bullet just before it hit the stationary
target.

Answers

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

The initial velocity of the bullet can be determined from the total momentum of the system. The velocity of the bullet was 306 m/s.

What is momentum ?

Momentum of a body is the product of its mass and velocity. For a collision, the momentum before and after collision will be the same for the colliding system.

Let m1 and m2 be the masses and u be the initial velocity and v is the final velocity.

then,  m1 u1  + m2 u2 = m1 v1  + m2 v2.

Given m1 = 5 kg

m2 =  0.1 kg

The velocity of the combined mass v = 6 m/s.

The momentum of the target is zero since it was stationary.

(0.1 × u1) = (0.1 + 5)6 m/s

(0.1 × u1) = 30.6 m/s

then u1 = 30.6/0.1 = 306 m/s

Therefore, the velocity of the bullet before hitting was 306 m/s.

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PLEASE HELP!! 25 POINTS!! WILL MARK BRAINLIEST!!
The focus of a parabola is (−6,−3) . The directrix of the parabola is y=4. What is the equation of the parabola?

The focus of a parabola is (0,−4). The directrix of the parabola is the line y=−5. What is the equation of the parabola?

The directrix of a parabola is the line y=7. The focus of the parabola is (2,3). What is the equation of the parabola?

The directrix of a parabola is y=−6. The focus of the parabola is (−2,−4) . What is the equation of the parabola?

Answers

The standard equations of the parabolas are listed below:

y + 6 = - (1/14) · (x + 6)² y = (1/2) · (x + 4.5)² y - 5 = - (1/8) · (x - 2)² y + 5 = (1/4) · (x + 2)²How to determine the standard equation of the parabola

In this question we have four case of parabolas with vertical axes of reference, whose standard formula is:

[tex]y - k = \frac{1}{4\cdot p}\cdot (x-h)^{2}[/tex]     (1)

Where:

(h, k) - The vertex of the parabola.p - Least distance between the vertex and the focus of the parabola.

Please notice that p < 0 when the directrix is above the focus, otherwise p < 0. The vertex is the midpoint of line segment between the directrix and the focus.

Now we proceed to derive the standard equations of the parabola:

1) Vertex:

(h, k) = 0.5 · (- 6, 4) + 0.5 · (- 6, - 3)

(h, k) = (- 6, 0.5)

Least distance:

p = - 3.5

y + 6 = - (1/14) · (x + 6)²

2) Vertex:

(h, k) = 0.5 · (0, - 4) + 0.5 · (0, - 5)

(h, k) = (0, - 4.5)

Least distance:

p = 0.5

y = (1/2) · (x + 4.5)²

3) Vertex:

(h, k) = 0.5 · (2, 3) + 0.5 · (2, 7)

(h, k) = (2, 5)

Least distance:

p = 2

y - 5 = - (1/8) · (x - 2)²

4) Vertex:

(h, k) = 0.5 · (- 2, - 6) + 0.5 · (- 2, - 4)

(h, k) = (- 2, - 5)

Least distance:

p = 1

y + 5 = (1/4) · (x + 2)²

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Can someone help me with these questions pls

Answers

8. ionic bond because lithium is a metal and oxygen is a non metal.

9. covalent bond because sulfur and oxygen are both non metals.

10. covalent

11. ionic

How do you find mass in physics

Answers

Density times volume

please watch this video, hope it helps

An impulse of 12.2kg m/s is delivered to an object whose initial momentum is 4.5kgm/s. What is the object's final momentum?

Answers

Answer:

Object's final momentum = 16.7 kg-m/s

Explanation:

Given that,

Impulse, J = 12.2 kg-m/s

Initial momentum, [tex]P_i=4.5\ kg-m/s[/tex]

We need to find the object's final momentum. We know that the impulse is equal to the change in momentum. So,

Impulse = change in momentum

[tex]J=P_f-P_i\\\\P_f=J+P_i\\\\P_f=12.2+4.5\\\\P_f=16.7\ kg-m/s[/tex]

So, the object's final momentum is 16.7 kg-m/s.

The final momentum of the object will be "16.7 kg-m/s".

Given:

Impulse, [tex]J = 12.2 kg-m/s[/tex]Initial momentum, [tex]P_i = 4.5 \ kg-m/s[/tex]

We know the relation,

→ [tex]Impulse = Change \ in \ momentum[/tex]

or,

→ [tex]J = P_f-P_i[/tex]

then,

→ [tex]P_f = J+P_i[/tex]

By substituting the values,

        [tex]= 12.2+4.5[/tex]

        [tex]= 16.7 \ kg-m/s[/tex]

Thus the above answer is right.      

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Why is it important for body cell to have twice and many chromosomes as sex cells?

Answers

Answer:

Why sex cells only need half the number of chromosomes compared to other cells in the body?  As gametes are produced, the number of chromosomes must be reduced by half. Why? The zygote must contain genetic information from the mother and from the father, so the gametes must contain half of the chromosomes found in normal body cells.

Explanation:

Brainliest Plzz

Answer:

During Mitosis, the chromosomes split at G2 Phase.

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