how do i do 3 5/6 - 2 7/15?

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The correct Choice is ~ D

a || b by the converse of the same side interior angles

Answer:

The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity

Step-by-step explanation:

hope this help

dont know if this is correct

The end behavior of the polynomial function is as x -> ∞, y -> -∞

From the graph of the polynomial, we have the following highlight:

The above highlights mean that:

As x -> ∞, y -> -∞

Hence, the end behavior of the polynomial function is as x -> ∞, y -> -∞

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Answer:

7 boys to 10 all children

Answer:

x= - 3/5y +4/5

Step-by-step explanation:

isolate x:

5x+ 3y= 4

5x= -3y+ 4

x= -3/5y +4/5

Step-by-step explanation:

(10+5)³-1 = 3375-1 = 3374.

Answer:

[tex]t_4 = 20[/tex]

Step-by-step explanation:

The base case in the recursive function are:

[tex]t_1 = 1[/tex]

[tex]t_2 = 2[/tex]

The recursive case is equal to:

[tex]t_n = 2t_{n-1} + 3t_{n-2}[/tex]

So replace [tex]t_n[/tex] for [tex]t_4[/tex]:

[tex]t_4 = 2t_{3} + 3t_{2}[/tex]

In the new expression [tex]t_2[/tex] is a base case so you don't have to worry for that part, but [tex]t_3[/tex] is still the recursive case so evaluate again in [tex]t_n[/tex]

[tex]t_3 = 2t_{2} + 3t_{1}[/tex]

[tex]t_2[/tex] and [tex]t_1\\[/tex] are define as base cases so you replace for it's numbers:

[tex]t_3 = 2(2) + 3(1) = 7[/tex]

Now return to [tex]t_4[/tex] and replace for the new values:

[tex]t_4 = 2(7) + 3(2) = 14 + 6 = 20[/tex]

So the final answer is 20

The simplified form of the function is [tex]f(x) = \frac{x+3}{x}[/tex]

Given the following function as shown:

[tex]f(x)=\frac{x^2-9}{x^2-3x}[/tex]

This can be factorized as:

[tex]f(x)=\frac{x^2-3^2}{x(x-3)}\\f(x)= \frac{(x+3)(x-3)}{x(x-3)} \\[/tex]

Cancel out the common terms:

[tex]f(x) = \frac{x+3}{x}[/tex]

Hence the simplified form of the function is [tex]f(x) = \frac{x+3}{x}[/tex]\

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Hi Phoenix! :)

I'm much late lol.

Answer:

[tex]\boxed{ \cfrac{x + 3}{x}} [/tex]

Step-by-step explanation:

Given:

[tex] \cfrac{x {}^{2} - 9}{x {}^{2} - 3x } [/tex]

Solution:

[Here the best option is to factorise the expression.]

Rewrite the numerator of the expression as

[tex] \cfrac{x {}^{2} - 3 {}^{2} }{x {}^{2} - 3x} [/tex]

It can be seen that the numerator is like an algebraic identity:

> a² - b² = (a+b)(a-b)

ATP, numerator : a = x² and b = 3²

Now in the denominator take x common:

(x-3) in the denominator and (x-3) in the numerator gets canceled.

Welp,Done, that's it! :D

Answer:

Step-by-step explanation:

the answer is 1.1324

[tex] \red{ \rule{40pt}{555555pt}}[/tex]

Answer:

32 qt = 8 gal

Step-by-step explanation:

1 qt x 32 = 1/4 gal x 32

32 qt = 32/4 gal

32 qt = 8 gal

Answer: [tex]x^{2/5}[/tex][tex]y[/tex]

Step-by-step explanation:

([tex]x^{2}[/tex][tex]y^{5}[/tex])^[tex]^{1/5}[/tex]

= [tex]x^{2/5}[/tex][tex]y[/tex]

Answer:

she would have 3ft. 10 inches of board

Step-by-step explanation:

Answer:

3ft and 10inches

Step-by-step explanation:

so 6ft 8 in minus 10in is 5ft 10 in

then 5ft minus 2ft is 2ft the rest is a piece of cake

Step-by-step explanation:

10 1

20 miles car travel 65t hb

Answer: 12 x 8

Step-by-step explanation: The other three are not the basic multiplication facts from 0 - 12.

Step-by-step explanation:

option c is correct answer

Answer:

A) -11/-4

Step-by-step explanation:

-11/-2=11/4

Rewrite the fraction.

-(-11/4)

=11/4

Hope this helps :)

cyclist a speed is d = v × t

so you can find velocity of a and b.

then compare them both.

5 bombas deben trabajar durante 4 dias para llenar la piscina.

Cada bomba trabaja a un rate (razon de trabajo) R.

Sabemos que 3 bombas, trabajando 5 horas diarias por 10 días (un total de 50 horas), llena una piscina, entonces:

(3R)*50 horas= 1 piscina.

R = (1 piscina)/(150 horas).

Es decir, una sola bomba tarda 150 horas en llenar una piscina.

En el caso de que 5 bombas trabajen, tenemos que para llenar una piscina tienen que trabajar un tiempo T.

5*((1 piscina)/(150 horas))*T = 1 piscina.

(1 piscina)/(30 horas)

Resolviendo para T, obtenemos:

T = 1 piscina*(30 horas)/(1 piscina) = 30 horas.

Y sabemos que trabajan 8 horas diarias, es decir, las bombas deben trabajar durante:

30/8 = 3.75 ≈ 4 días.

5 bombas deben trabajar durante 4 dias para llenar la piscina.

Sí quieres aprender más sobre razones de trabajo.

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Answer:

A

Step-by-step explanation:

5 times 10= 50

5 times -5= -25

50-25=25

Answer:

Hello!

Judging by the link you provided I have come up with the correct solution:

x= 61°

y= 29°

Step-by-step explanation:

I will link my work below:

The first step to finding the two solutions it to first identify one of them.

I chose to identify x first.

To identify the value of x in this problem you have to notice that the x value corresponds with the value "29°" to form a perfect right angle, being 90°.

Thus you can simply find the value of x by doing this formula:

x+29°=90°

You then subtract 29° from both sides to simplify, and you come up with the solution

x=61°

Now we need to find the value of y.

To find the value of y I noticed that again, like x, y corresponds with another variable (being x) to form a perfect right angle (90°).

The way I realized this is a perfect right angle is because, as you can see in the picture you provided, the y+x angle are alternate exterior angles with another angle that is 90°.

Thus you can assume that:

x+y=90°

x= 61°

61°+y=90°

You then subtract 61° from both sides to get:

y=29°

Answer:

it would be c because its moved 2x up

Step-by-step explanation:

Answer:

It'll be B.10

Step-by-step explanation:

Rectangles always have 2 side lower than the other2 . BC and AD are same length so they are both 13. BA and CB are the same length to It has to be 10.

Hope this helps :)

[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{-2}-\underset{x_1}{(-4)}}}\implies \cfrac{-1}{-2+4}\implies \cfrac{-1}{2}\implies -\cfrac{1}{2}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{-\cfrac{1}{2}}[x-\stackrel{x_1}{(-4)}] \\\\\\ y-6=-\cfrac{1}{2}(x+4)\implies y-6=-\cfrac{1}{2}x-2\implies \underset{\textit{slope-intercept form}}{y=-\cfrac{1}{2}x+4}[/tex]

Answer:

Step-by-step explanation:

55.345 is rounded off two places therefore, the hundreths place

the number next to 4 is 5 in the thousandths place. 5 is high and therefore 4 is changed to 5 and makes it 53.35

The area of the rectangular field is 0.07 square kilometers (km²).To find the area of the rectangular field in square kilometers, we need to convert the given dimensions from meters to kilometers.

To find the area of the rectangular field in square kilometers, we need to convert the given dimensions from meters to kilometers and then calculate the area.

Given:

Length of the field = 350 meters

Width of the field = 200 meters

To convert from meters to kilometers, we divide the measurements by 1000, since there are 1000 meters in a kilometer.

Length in kilometers = 350 meters / 1000 = 0.35 kilometers

Width in kilometers = 200 meters / 1000 = 0.2 kilometers

Now that we have the dimensions of the field in kilometers, we can calculate the area.

Area of the field = Length in kilometers * Width in kilometers

Area of the field = 0.35 kilometers * 0.2 kilometers

Multiplying the values, we get:

Area of the field = 0.07 square kilometers

Therefore, the area of the rectangular field is 0.07 square kilometers.

It's important to include the correct unit in the answer, which is "square kilometers" (km²). This represents the unit for measuring the two-dimensional area. In this case, the area of the field is 0.07 km².

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Answer:

9 mm

Step-by-step explanation:

90*0.1=9

Answer:

Step-by-step explanation:

Initial class size = 30 students

Class size now is 40% larger:

First let's find larged amount

[tex]\\ \sf\longmapsto 40\%\:of\:30[/tex]

[tex]\\ \sf\longmapsto 0.4(30)[/tex]

[tex]\\ \sf\longmapsto 12[/tex]

Class size=30+12=42students

[tex] \frac{1}{2} \: to \: the \: power \: of \: 5 \: is \: \frac{1}{32} or \: 0.03125 [/tex]

Answer:

[tex] \ {\boxed{ \tt ( \frac{1}{2}) ^{5} = \frac{1}{32} }}[/tex]

Step-by-step explanation:

[tex] \\ \tt( \frac{1}{2} )^{5} [/tex]

[tex] \\ \tt= \frac{ {1}^{5} }{ {2}^{5} } [/tex]

[tex] \\ \tt = \frac{1 \times 1 \times 1 \times 1 \times 1}{2 \times 2 \times 2 \times 2 \times 2} [/tex]

[tex] \\ \tt = \frac{1}{32} [/tex]

Answer:

The correct answer is 66,045