How do I find x and y?

Answer:

BC = [tex]\frac{12}{13}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

BC² + AC² = AB²

BC² + ([tex]\frac{5}{13}[/tex] )² = 1²

BC² + [tex]\frac{25}{169}[/tex] = 1 ( subtract [tex]\frac{25}{169}[/tex] from both sides )

BC² = [tex]\frac{169}{169}[/tex] - [tex]\frac{25}{169}[/tex] = [tex]\frac{144}{169}[/tex] ( take square root of both sides )

BC = [tex]\sqrt{\frac{144}{169} }[/tex] = [tex]\frac{12}{13}[/tex]

Answer:

$2/ hat

Step-by-step explanation:

Find the unit rate:

$ to hats

8 to 4

Divide by four to get the unit rate; over 1

2 to 1

So, $2 per hat

Hope this helps!

Answer:

i think you just extend the coordinates to the side, except the right point, by 3, and then the bottom ones go down by 3, and the top one goes up by 3

Step-by-step explanation:

Answer:

-14, 9 and - 54/7

Step-by-step explanation:

Answer: [tex]9\sqrt{2}[/tex]

Step-by-step explanation:

Use the Pythagorean Theorem:

[tex]9^{2} +9^{2} =x^{2}\\x=\sqrt{9^{2} +9^{2}} =\sqrt{2(9)^{2} } =9\sqrt{2}[/tex]

Answer:

the missing values is 5

I hope it's helps you

Answer:

85 i guess

Step-by-step explanation:

The mean of the distribution is 70 and the standard deviation of the distribution is 4.

The shaded area in the distribution below represents approximately 95% of the data. This means that the shaded area is equal to 1.96 standard deviations from the mean.

The 68-95-99.7 rule states that 95% of the data in a normal distribution falls within 2 standard deviations of the mean. So, the shaded area in the distribution below represents the area between 1.96 standard deviations below the mean and 1.96 standard deviations above the mean.

The mean of the distribution is the center of the shaded area. The standard deviation of the distribution is the distance from the mean to the edge of the shaded area.

In this case, the mean of the distribution is approximately 70. The standard deviation of the distribution is approximately 4.

Here is a step-by-step explanation of how to find the mean and the standard deviation:

Identify the shaded area in the distribution.

Remember that the shaded area represents 95% of the data.

Use the 68-95-99.7 rule to determine that the shaded area is between 1.96 standard deviations below the mean and 1.96 standard deviations above the mean.

Find the mean by averaging the two points on the distribution that are 1.96 standard deviations from the mean.

Find the standard deviation by subtracting the mean from one of the points on the distribution that is 1.96 standard deviations from the mean.

Therefore, the mean of the distribution is approximately 70 and the standard deviation of the distribution is approximately 4.

To learn more about standard deviation here:

https://brainly.com/question/13498201

#SPJ2

Answer:

Step-by-step explanation:

[tex] {32}^{ \frac{1}{5} } [/tex]

[tex] = \sqrt[5]{32} [/tex]

[tex] = \sqrt[5]{2 \times 2 \times 2 \times 2 \times 2} [/tex]

= 2 (Ans)

Part 1

[tex]\left(\frac{g}{h}\right)(x) = \frac{g(x)}{h(x)}\\\\\left(\frac{g}{h}\right)(x) = \frac{3x-5}{-2x^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{3(3)-5}{-2(3)^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{4}{-11}\\\\\left(\frac{g}{h}\right)(3) = -\frac{4}{11}\\\\[/tex]

Answer:  -4/11

====================================================

Part 2

Set the denominator function equal to zero and solve for x to find which values to kick out of the domain.

[tex]h(x) = 0\\\\-2x^2+7 = 0\\\\7 = 2x^2\\\\2x^2 = 7\\\\x^2 = 7/2\\\\x^2 = 3.5\\\\x = \sqrt{3.5} \ \text{ or } x = -\sqrt{3.5}\\\\[/tex]

This shows that if x is equal to either of those values, then the denominator h(x) will be zero. These are the values to kick out of the domain to prevent a division by zero error. Any other value of x is valid in the domain.

Answer: [tex]x = \sqrt{3.5} \text{ and } x = -\sqrt{3.5}\\\\[/tex]

Answer:

[tex]55[/tex]

Step-by-step explanation:

We'll be using case-work to solve this problem. Let's call the ones digit of the telephone number [tex]B[/tex] and the tens digit [tex]A[/tex]. Each telephone number can be represented as [tex]AB[/tex].

Since the question states that numbers that are smaller when their digits are reversed are not used, we have the following inequality:

[tex]B\geq A[/tex]

This is because if [tex]A>B[/tex], the number would become smaller when [tex]A[/tex] and [tex]B[/tex] are switched in [tex]AB[/tex]. However, if [tex]A=B[/tex] or [tex]B>A[/tex], the number will not become smaller.

Let's work our way up starting with [tex]A=0[/tex]. If [tex]A=0[/tex], there are 10 other numbers (0-9) that we can choose for [tex]B[/tex] that adhere to the condition [tex]B\geq A[/tex]:

[tex]0B,\\01, 02, 03,...[/tex]

Therefore, there are 10 possible telephone numbers when the tens digit is 0.

Repeat the process, now assigning [tex]A=1[/tex]. Now, we only have the digits 1-9 to choose from for [tex]B[/tex], since [tex]B[/tex] needs to be greater than or equal to A. Therefore, there are 9 possible telephone numbers when the tens digit is 1.

This pattern continues. As we work our way up through the cases (when increasing [tex]A[/tex] by 1), the number of possible telephone numbers decreases by 1, since there becomes one less option for [tex]B[/tex].

The last case would be [tex]A=9[/tex] in which case there would only be one option for [tex]B[/tex] and that would be 9.

Since there are 10 cases (0-9), add up the possible telephone numbers for each case:

[tex]\displaystyle \sum_{n=1}^{10}n=1+2+3+4+5+6+7+8+9+10=\boxed{55}[/tex]

Alternatively, recall that the sum of this series can be found using [tex]\frac{n(n+1)}{2}[/tex], where [tex]n[/tex] is the number of values in the set. In this case, [tex]n=10[/tex], and we have:

[tex]1+2+3+4+5+6+7+8+9+10=\frac{10(11)}{2}=\frac{110}{2}=\boxed{55}[/tex]

Answer:

18.45

Step-by-step explanation:

I used a calculator

Answer:

3744.64

Step-by-step explanation:

To know the answer to this question you need to know the formulas to find the volume of the cylinder and the rectangular prism. The volume of a cylinder is pi*r^2*h while the volume of the rectangular prism is l*w*h. The cylinder is 1808.64 cubic in while the rectangular prism is 1936 cubic. Together, they are 3744.64 cubic in.

Answer:

cylinder= A=πr²h

=3.14×4²×9

=452.16

rectangle=A=l×w×h

=19×11×11

=2299

total area=452.16+2299

=2751.16

Step-by-step explanation:

Answer:

[tex]V=90[/tex]

Step-by-step explanation:

Step 1:  Find the volume of the cone

[tex]V = \frac{\pi *r^{2}*h}{3}[/tex]

Plug in the values

[tex]V = \frac{\pi *3^{2}*10}{3}[/tex]

Simplify and Solve

[tex]V = \frac{\pi *9*10}{3}[/tex]

[tex]V = \frac{90\pi }{3}[/tex]

[tex]V = \frac{90*3 }{3}[/tex]

[tex]V=90[/tex]

Answer:  [tex]V=90[/tex]

Answer:

It is over 7 days

hope it helps

Answer: B

Step-by-step explanation:

Its written in slope intercept form not standard

Answer:

-1

Step-by-step explanation:

[3-4(-1)^4]^3

=>(3-4)^3

=>(-1)^3

=>-1

Answer From Gauth Math

Answer:

-1

Step-by-step explanation:

[tex][3-4*(3-4)^4]^3[/tex]        

[tex](3-4)^4= 1\\Therefore, [3-4*1]^3= -1^3\\So, -1^3= -1\\\\[/tex]

Cube of any negative integer will be negative, or, a negative integer raised to any odd number will be negative. Likewise, a negative integer raised to an even number will be positive.

they don't share any points

that's one thing, but I don't know what your options are of course.

see screenshot for illustration of the inequalities

Answer:

There are sixteen lines.

Answer:

7

Step-by-step explanation:

[tex]s = {a}^{2} \: thus \: a = \sqrt{s } = \sqrt{49} = 7[/tex]

Answer:

120.40 per payment

Step-by-step explanation:

Subtract the down payment

642 - 160.40

481.60

Divide this by 4

481.60 / 4

120.40

Answer:

Step-by-step explanation:

(√63 + 144)/5 = (3√7 + 144)/5 = 0.6√7 + 28.8

Answer:

A = 49/pi

Step-by-step explanation:

C = 2 * pi *r

14 = 2 * pi *r

Divide each side by 2 pi

14/2pi = r

7/pi = r

The area is given by

A = pi r^2

A = pi ( 7/ pi)^2

A  = pi * 49 / pi^2

A = 49/pi

Answer:

[tex]area = {15.61m}^{2} [/tex]

explanation is attached to the picture

Hope this helps you

Answer:

The center is (9,-8) and the diameter is 8

Step-by-step explanation:

(x − 9)^2 + (y + 8)^2 = 16

A circle is in the form

(x − h)^2 + (y -k)^2 = r^2  where (h,k) is the center and r is the radius

(x − 9)^2 + (y -  -8)^2 = 4^2  

The center is (9,-8) and the radius is 4

The diameter is 2 times the radius so the diameter is 8

The center is (9,-8) and the diameter is 8

Given:

The data set is:

0, 1, 1, 1, 2, 3, 4, 4, 6, 6, 9

To find:

The correct statement that represents the box plot of the data correctly.

Solution:

We have,

0, 1, 1, 1, 2, 3, 4, 4, 6, 6, 9

Divide the data in 2 equal parts.

(0, 1, 1, 1, 2), 3, (4, 4, 6, 6, 9)

Divide each parenthesis in 2 equal parts.

(0, 1), 1, (1, 2), 3, (4, 4), 6, (6, 9)

Here,

Minimum value = 0

First quartile = 1

Median = 3

Third quartile = 6

Maximum value = 9

A number line goes from 0 to 10. The whiskers range from 0 to 9, and the box ranges from 1 to 6. A line divides the box at 3.

Therefore, the correct option is D.

Answer:

its d

Step-by-step explanation: my yt Tray Clayps

Answer:

3/2

Step-by-step explanation:

if u divide two fractions, it is same as multiplying with its reciprocal

Answer:

12lb and 7oz

Step-by-step explanation:

you can just add it together and get an answer

Answer:

11 lbs 17oz

Step-by-step explanation:

In this question, a piece-wise function is asked to be graphed.

Piece-wise function:

A piece-wise function is a function that has different definitions, depending on the input.

In this question, the function has three different definitions:

For x between -1(inclusive) and 0, y takes a constant value of -1.

For x between 0(inclusive) and 1, y takes a constant value of -2.

For x between 1(inclusive) and 2, y takes a constant value of -3.

Additionally:

At the inclusive points, the interval is circled, and thus, the graphic is given at the end of this answer.

For another example of the graphic of a piece-wise function, you can check https://brainly.com/question/16855064

Answer:

Step-by-step explanation:

1. (1, 3); (2, 3)

2. (0, 0) (1, 0)

3. (-1, 1) (0,0)