how do i solve this ?

Given:

ABC is an isosceles triangle in which AC =BC.

D and E are points on BC and AC such that CE=CD.

To prove:

Triangle ACD and BCE are congruent​.

Solution:

In triangle ACD and BCE,

[tex]AC=BC[/tex]                  (Given)

[tex]AC\cong BC[/tex]

[tex]\angle C\cong m\angle C[/tex]                  (Common angle)

[tex]CD=CE[/tex]                  (Given)

[tex]CD\cong CE[/tex]

In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.

[tex]\Delta ACD\cong \Delta BCE[/tex]           (SAS congruence postulate)

Hence proved.

Answer:

Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD

∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)

Then BE−DE=CD−DE

ORBC=CE......................................(2)

In ΔABD and ΔACE

∠ABD=∠ACE ( From 1)

BC=CE (from 2)

AB=AC ( GIven)

∴ΔABD≅ΔACE

So AD=AE [henceproved]

Answer:

what????????????????????

Answer:

I think 1 is the correct answer

Answer:

answer is 36 centimeter

Step-by-step explanation:

volume of a cylinder=πr^2h

1696=3.14*r^2*15

1696=47.1=r^2

1696-47.1=r^2

1648.9=r^2

[tex]\sqrt{1648.9}[/tex] =r

40.60 =r

here according to the question and option given 40.60 is closest to 36 centimeters.so answer is option d.

Answer:

The transformation is right 4

Step-by-step explanation:

Since the transformation occurred inside the absolute value function, this means there will be a horizontal shift. Therefore, the transformation is right 4.

Observe the graph to view the transformation.

Answer:

Option c (Upper tailed) is the correct choice.

Step-by-step explanation:

Given that:

The average attendance is:

= 74,900

We will have to test:

⇒ [tex]H_0:\mu \leq \mu_0[/tex]

or,

   [tex]H_0: \mu \leq 74,900[/tex]

Verses,

⇒ [tex]H_1: \mu> \mu_0[/tex]

or,

    [tex]H_1: \mu >74,900[/tex]

The other given alternatives aren't connected to the given scenario. So the above is the correct one.

Answer:

parallel

Step-by-step explanation:

the slope of each line is 5/6 which means the lines are parallel

Using translation concepts, it is found that the equation that represents this transformation is given by:

A. [tex]g(x) = (x - 3)^4 - 1[/tex]

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the parent function is given by:

[tex]f(x) = x^4[/tex].

Then:

Hence, the equation that represents the transformation is given by:

[tex]g(x) = (x - 3)^4 - 1[/tex]

Which means that option A is correct.

More can be learned about translation concepts at https://brainly.com/question/4521517

#SPJ1

Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Exact Form:

x = 2 √ 2 − 1 3 , − 2 √ 2 − 1 3

Decimal Form:

x = 2.49509379 , − 3.16176045

Step-by-step explanation:

Simplify the decimals as needed

Answer:

3408

Step-by-step explanation:

9514 1404 393

Answer:

  (b)  (x – 4)^2 + (y – 6)^2 = 16

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

  (x -h)^2 +(y -k)^2 = r^2

You want the equation for a circle with center (4, 6) and radius 4. That equation is ...

  (x -4)^2 +(y -6)^2 = 16

Answer:

B; (x – 4)2 + (y – 6)2 = 16

Step-by-step explanation:

correct on edge

Answer:

the coordinates of pre - image point H is (3,2)

Answer:

c time for learning

Step-by-step explanation:

Answer:

The volume increases at 35.71cm^3/min

Step-by-step explanation:

Given

[tex]PV^{1.4} = C[/tex]

[tex]V = 400cm^3[/tex]

[tex]P =80kPa[/tex]

[tex]\frac{dP}{dt} =-10kPa/min[/tex]

Required

Rate at which volume increases

[tex]PV^{1.4} = C[/tex]       [tex]V = 400cm^3[/tex]       [tex]P =80kPa[/tex]

Differentiate: [tex]PV^{1.4} = C[/tex]  

[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = \frac{d}{dt}C[/tex]

By differentiating C, we have:

[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = 0[/tex]

Rewrite as:

[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} + V^{1.4}*\frac{dP}{dt} = 0[/tex]

Solve for [tex]\frac{dV}{dt}[/tex]

[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} =- V^{1.4}*\frac{dP}{dt}[/tex]

[tex]\frac{dV}{dt} =- \frac{V^{1.4}*\frac{dP}{dt} }{P*(1.4)*V^{0.4}}[/tex]

Substitute values

[tex]\frac{dV}{dt} =- \frac{400^{1.4}*-10 }{80*(1.4)*400^{0.4}}[/tex]

[tex]\frac{dV}{dt} =\frac{400*10 }{80*1.4}[/tex]

[tex]\frac{dV}{dt} =\frac{4000 }{112}[/tex]

[tex]\frac{dV}{dt} =35.71cm^3/min[/tex]

9514 1404 393

Answer:

  ΔWZT ~ ΔWXY

Step-by-step explanation:

Angle XWY and angle ZWT are vertical angles, so congruent.

The sides on either side of those angles are proportional:

  WZ/WX = WT/WY

  11/22 = 10/20 = 1/2

so, we can claim similarity by the SAS Theorem.

  ΔWZT ~ ΔWXY

Answer:

Suppose you have a fair coin: this means it has a 50% chance of landing heads up and a 50% chance of landing tails up. Suppose you flip it three times and these flips are independent. What is the probability that it lands heads up, then tails up, then heads up? So the answer is 1/8, or 12.5%.

Answer:

x = 25

Step-by-step explanation:

Given a line parallel to a side of the triangle and intersecting the other 2 sides then it divides those sides proportionally, that is

[tex]\frac{40}{24}[/tex] = [tex]\frac{x}{15}[/tex] ( cross- multiply )

24x = 600 ( divide both sides by 24 )

x = 25

Answer:

nnn bjbjjjjjnn

Step-by-step explanation:

Answer:

c. 108

Step-by-step explanation:

do 12×12 and get 144 then do 6×6 to get 36 then do 144-36 and you get 108. hope this helps mate.

Answer:

Please find the complete question in the attached file.

Step-by-step explanation:

For point 1:

At this point we make up triangles for the first one makes up by 3 matches figure 2 make up by 5 matches figure 3 makes up by 7 matches.

For point 2:

 [tex]4 \ \ 5\ \ 6\ \ 7\ \ 8[/tex]  you can try to  

[tex]9 \ \ 11\ \ 13 \ \ 15 \ \ 17[/tex] draw to find  values  

For point 3:

number of matches[tex]= 1+2 \times \ figure\ number\\\\[/tex]

For point 4:

[tex]1+2 \times 9=19 \ \ (use \ law \ of\ (iii)) \\\\1+2 \times 17=35[/tex]

Answer:

13122

Step-by-step explanation:

a(n) = 6 * 3^(n -1)

a(8) = 6* 3^7

3^7 = 2187

a(8) =6 * 2187

a(8) = 13122

Answer:

y = 2/5x + 1/5

Step-by-step explanation:

First, plug in the slope.

y = mx+b

y = 2/5x + b

Then, plug in the point given, in order to find b.

-1 = 2/5(-3) + b

-1 = -6/5 + b

1/5 = b

So the final equation is:

y = 2/5x + 1/5

Answer:

Base: 7

Height:10

BH divided by two so

7 times 10 = 70 divided by two 35

Base: 7 yd

Height: 10 yd

Area: 35 square yd

         ([tex]A=\frac{h_{b}b }{2}[/tex] = [tex]\frac{10*7}{2}[/tex] = 35)

hope this helps....

Answer:

10 square inches

Step-by-step explanation:

that is the procedure above

Answer:

Area=10.167=10.2

Step-by-step explanation:

Area=1/2ab sin c

area= 1/2(7)(9.4)sin18

area = 10.167=10.2

this is for delta math

Answer:

"fair" srry im only in 8th so im d.u.m

Step-by-step explanation:

Answer:

d) 0.383

Step-by-step explanation:

For each sample, there are only two possible outcomes. Either they contain the pollutant, or they do not. The probability of a sample containing the pollutant is independent of any other sample. Thus, the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

30% chance of containing a particular organic pollutant.

This means that [tex]p = 0.3[/tex]

Next 10 samples

This means that [tex]n = 10[/tex]

Probability that two or less contain the pollutant.

This is:

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.028[/tex]

[tex]P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.121[/tex]

[tex]P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.233[/tex]

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.028 + 0.121 + 0.233 = 0.382[/tex]

A little rounding difference, but the correct answer is given by option d.

9514 1404 393

Answer:

Step-by-step explanation:

Parallelogram PTSR is divided into two equilateral triangles by diagonal RT. All of the acute angles in that quadrilateral are 60°, and the obtuse angles are 120° (2×60° and also the supplement of 60°).

Triangle PTQ is an isosceles right triangle, so its acute angles are 45°.

  ∠PTQ = 45°

  ∠QTR = ∠PTR -∠PTQ = 60° -45°

  ∠QTR = 15°

  ∠PTS = 120° . . . . . . obtuse angle in PTSR; sum of ∠PTR and ∠RTS