How do I solve this problem?

Step-by-step explanation:

+ Both equations

You will get : 5x=13 ; x=13/5

and put x to the first equation

2*13/5-y=4

y=6/5

(13/5;6/5)

Answer is C

Answer:

9/8 = n

Step-by-step explanation:

9 = 8n

Divide each side by 8

9/8 = 8n/8

9/8 = n

Step-by-step explanation:

The answer is mentioned above.

Hope it helps.

Answer:

[tex]2^{\frac{1}{6} }[/tex]

Step-by-step explanation:

(2^1/3)^1/2 = 2^(1/3 x 1/2) =2^1/6

Answer:

D. Range

Step-by-step explanation:

The definition of range is as the question says, and we can also use the process of elimination to make sure it's not the others.

A mean is the average of a data set.

A mode is the item that appears the most times.

And a median is the middle number.

As you can see, A, B, C all don't fit the given statement in the question, so it is D. Range.

I hope this helped! :D

Answer: x=-3

Step-by-step explanation:

2(x)-39=5(x+2x)

2x-39=5(3x)

2x-39=15x

-39=13x

-39/13=-3

Answer:

(1, 3)

Step-by-step explanation:

Since up and down are opposites, the point didn't move at all.

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

100000 = 8 (4) ^t

Step-by-step explanation:

We are multiplying by 4 each time

y = a (4)^t

The initial amount is 8

y = 8 (4)^t

We want to get to 100000

100000 = 8 (4) ^t

Answer:

B

8 ⋅ 4^t  = 100,000

Step-by-step explanation:

[tex]\\ \sf\longmapsto 41sin\Theta=40[/tex]

[tex]\\ \sf\longmapsto sin\Theta=\dfrac{40}{41}[/tex]

Now

[tex]\boxed{\sf cos\Theta=\sqrt{1-sin^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\left(\dfrac{40}{41}\right)^2}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{1-\dfrac{1600}{1682}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{1681-1600}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\sqrt{\dfrac{81}{1681}}[/tex]

[tex]\\ \sf\longmapsto cos\Theta=\dfrac{9}{41}[/tex]

We know

[tex]\boxed{\sf tan\Theta=\dfrac{Sin\theta}{Cos\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{tan\Theta}{1-tan^2\Theta}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{sin\Theta}{cos\Theta}}{1-\dfrac{sin^2\Theta}{cos^2\Theta}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{\left(\dfrac{40}{41}\right)}{\left(\dfrac{9}{41}\right)}}{1-\dfrac{\left(\dfrac{40}{41}\right)^2}{\left(\dfrac{9}{41}\right)^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{{40}}{{9}}}{1-\dfrac{{40}^2}{{9}^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{9^2-40^2}{9^2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{81-1600}{81}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{\dfrac{40}{9}}{\dfrac{-1519}{81}}[/tex]

[tex]\\ \sf\longmapsto {\dfrac{40}{\cancel{9}}}\times \dfrac{\cancel{81}}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{40\times 9}{(-1519)}[/tex]

[tex]\\ \sf\longmapsto - \dfrac{360}{1519}[/tex]

Answer:

0 is the answer . The explanation is in the attachment .

A midpoint is a point that divides a given line into two equal halves.The answers to the questions are:

1. BC = 89

b. AB = 45

c. AC = 44

2. The coordinate of I is 2.5

3. J = 19

4. MQ = 32

5. NO = 13

6. NO = 23

b. MN = 25

A line segment can be divided into different fractions. Where the point that divides the line segment into equal parts is the midpoint. however, number line is a system that shows the location or positions of all directed numbers.

The given questions can be solved as follows:

1. Given that point A is between BC and AB = 4x -3, BC = 7x + 5, AC = 5x - 16

But,

BC = AB + AC

7x + 5 = (4x -3) + (5x - 16)

          = 9x - 19

7x + 5 = 9x - 19

19 + 5 = 9x - 7x

24 = 2x

x = [tex]\frac{24}{2}[/tex]

x = 12

So that;

a. BC = 7x + 5

         = 7(12) + 5

BC = 89

The value of BC is 89.

b. AB = 4x -3

         = 4(12) - 3

AB = 45

Thus AB has a value of 45.

c.  AC = 5x - 16

          = 5(12) -16

 AC = 44

The value of AC is 44.

2. Given that H is the mid point of GI, and G = 8, I = -3.

Then;

I = 2.5

The coordinate of I is 2.5

3. A midpoint is a point that divides a line segment in to two equal halves. Given that J is the midpoint of KL. KL = 38

J = [tex]\frac{KL}{2}[/tex]

  = [tex]\frac{38}{2}[/tex]

J = 19

The value of the midpoint J is 19.

4. It can be deduced from the conditions given in the question that:

  MQ = MN + NO + OP + PQ

          = 8 + 8 + 16      (NB: OP + PQ = 16)

MQ = 32

Thus, value of MQ is 32.

5. Since P is the mid point of NQ, and OP = 11, OQ = 35

 Then;

PQ  = OQ - OP

      = 35 - 11

PQ = 24

Since, PQ = NP =24

Then;

NO = NP - OP

      = 24 - 11

NO = 13

NO has a length of 13.

6. NO = 2y + 11, OP = 3y - 2, NP = 6y + 3 and MP = 64.

But,

NO + OP = NP

(2y + 11) + (3y - 2) = 6y + 3

5y + 9 = 6y + 3

9 - 3 = 6y - 5y

y = 6

So that;

a. NO = 2y + 11

          = 2(6) + 11

NO = 23

Here, the value of NO is 23.

b. MN = MP - NP

But,

NP = 6y + 3

     = 6(6) + 3

NP = 39

Then;

MN = 64 - 39

MN = 25

So that MN has a value of 25.

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Answer:

.71

Step-by-step explanation:

We only need to look at the brown eyes row

2+2+10 =14

Brown hair is 10

P(brown hair) = brown hair / total

                        =10/14 =5/7 = .714285714

Answer:

48.5 and 34.5

Step-by-step explanation:

83 divided by 2 and then subtract 7

Answer:

45 and 38 equal 83 and 45 is 7 more than 38

Answer:

[tex]x^{\frac{3}{2} } p^{6}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

25*-30= -$750

Second: He sells 22 of those calculators for $35 each, so he is making money.

22*35= $770

Third: With the remaining three calculators, he must pay $2 each for returned calculators, so he is losing money again.

3*-2= -6

Add all the costs and sales together, and you get 770-750-6= $14 profit

However, the problem does not say if he gets his money back for the 3 returned calculators. In that case if he did, you would add the cost of each of those calculators to his profit. 30*3= 90

$90+$14= $104 profit

here u go

Answer:

1) a³b⁴/ ab³ = a²b

2)2 (x³ )² = 2x^6

3)3x*2x³ y² = 6x⁴y²

Answer:

Therefore 3/10 is closer to ½

Step-by-step explanation:

We've to get the difference:

» with 3/10 :

[tex] \frac{1}{2} - \frac{3}{10} = { \boxed{\frac{1}{5} }}[/tex]

» with 5/7

[tex] | \frac{1}{2} - \frac{5}{7} | = { \boxed{ \frac{3}{14} }}[/tex]

but:

[tex] \frac{3}{14} > \frac{1}{5} [/tex]

Among both the given fractions, the one that is closer to a ½ is 3/10.

A number that is stated as a quotient in mathematics, when the numerator and denominator are split in half. Both are integers in a straightforward fraction. In the numerator or denominator of a complex fraction is a fraction.

An element of a whole or, more broadly, any number of equal pieces, is represented by a fraction. When used in conversational English, a fraction indicates the number of components of a particular size, as in one-half, eight-fifths, and three-quarters.

A fraction is a number that represents a portion of a whole. In order to evaluate it, a whole is divided into a number of components.  A correct fraction has a numerator that is lower than its denominator.

Required calculations are done with both the fractions,

1/2 - 3/10 = 1/5

1/2 - 5/7 = 3/14

3/14 ≥ 1/5

Therefore, among both the given fractions, the one that is closer to a ½ is 3/10.

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Answer:

Option D, 52

Answered by GAUTHMATH

Answer:

13 and 17 units

Step-by-step explanation:

explaination is in pic.

The length of the diagonals of the quadrilateral AC and BD are 13 units and 17 units respectively, as per length between two points.

The length between two given points (x₁, y₁) and (x₂, y₂) will be:

√[(x₂ - x₁)² + (y₂ - y₁)²] units

Given, the vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).

Therefore, the diagonals of the quadrilateral will be AC and BD.

The coordinates of the diagonal AC are (4, - 3) and (- 8, 2).

Now, the length of the diagonal AC will be:

= √[(-8 - 4)² + (2 - (- 3))²] units

= √[(- 12)² + (5)²] units

= √[144 + 25] units

= √(169) units

= 13 units                                  (length can't be negative)

Similarly, the coordinates of the diagonal BD are (7, 10) and (- 1, - 5).

Now, the length of the diagonal BD will be:

= √[(-1 - 7)² + (- 5 - 10)²] units

= √[(- 8)² + (- 15)²] units

= √[64 + 225] units

= √(289) units

= 17 units                                  (length can't be negative)

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Answer:

C(x)=40x+14, 6 days

Step-by-step explanation:

C(x)= payment per day*x + initial payment. the payment per day is $40 while the initial payment is $14. so C(x)=40x+14.

C(x)=254=40x+14, 40x=240, x=6

Answer:

[tex]8 \times \frac{15}{5} - (5 + 9) \\8 \times 3 - (14) \\ 24 - 14 \\ = 10[/tex]

I hope I helped you^_^

Answer:

x=14.2

Step-by-step explanation:

AC = BD

The diagonals of a rectangle are equal

7x-9 =  2x+62

Subtract 2x from each side

7x-9-2x = 2x+62-2x

5x-9 = 62

Add 9 to each side

5x-9+9 = 62+9

5x= 71

Divide by 5

5x/5 = 71/5

x=14.2

I 7X + 5 I = I 3X- 13I

7×+5 = 3x +13

7X-3x = 13-5

4x = 8

X= 8/4

X=2

The answer is : [tex]\left(m+n^2\right)\left(m-n^2\right)[/tex]

Here are the steps below to help you! ^^

Answer:

x=6, y=4, z=8

I hope this is helpful!

Answer:

x = 4.98

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 50 = x/6.5

6.5 sin 50 =x

x=4.97928

x = 4.98

Answer:

See below

Step-by-step explanation:

Okay so...I might be interpreting the question wrong-if I am please comment! I'll fix it to the best of my ability.

A) Plug in -5 to all x values

   f(-5)=10(-5)-3

          ==50-3

    f(-5)= -53

B) f(0)=10(0)-3

    f(0)= -3

C) f(7)=10(7)-3

         =70-3

    f(7)=67

D) f(t^2+2)=10(t^2+2)-3

                 =10t^2+20-3

     f(t^2+2)=10t^2+17

E) f(12-x)=10(12-x)-3

              =120-10x-3

    f(12-x)=117-10x

F) f(x+h)=10(x+h)-3

             =10x+10h-3

Answer:

B = 64°

AB = 33.378

BC = 14.632

Step-by-step explanation:

Given the right angled triangle ;

Angle B = 180 - (90 + 26) (sum of angles in a triangle)

Angle B = 180 - 116

Angle B = 64°

Side AB = c

Using trigonometry :

Sin B = opposite / hypotenus

Sin 64 = 30/AB

AB = 30 / Sin64

AB = 33.378

Side BC ;

Sin A = BC / AB

Sin 26 = BC / 33.378

BC = 33.378 * Sin 26

BC = 14.632

Answer:

(x, y) → (y, -x)

Step-by-step explanation:

The coordinates of the vertices of parallelogram ABCD are; A(2, 5), B(5, 4), C(5, 2), and D(2, 3)

The coordinates of the vertices of parallelogram A'B'C'D' are; A'(5, -2), B'(4, -5), C'(2, -5), and D'(3, -2)

The rule that escribes the transformation of the rotation of parallelogram ABCD to create the image A'B'C'D' is presented, by observation, is therefore;

(x, y) → (y, -x)

The resulting transformation used will be (x, y) -> (y, -x)

Transformation are rules applied to an object to change its orientation

For the given parallelogram, in order to know the rule used, we need the coordinate of the image and preimage

The coordinate of A is (2, 5) while that of A' is (5, -2).

From both coordinates, you can see that the coordinate was switched and the resulting y coordinate negated.

Hence the resulting transformation used will be (x, y) -> (y, -x)

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