How do you factorise with letters and numbers please explain clearly example
7ab+14b how do I put that in brackets and what are the rules when factoring

Answer:

199 pages

Step-by-step explanation:

The average number of words on the page is 300.  Because there are 59,540 words and 59540/300 = 198.46 (approximately), there are 199 pages in the book (because the 0.46 pages would be the last page).

Answer:

54+456/79*78=5689

Step-by-step explanation:

maaf kalo salah

[tex]45 \times 456[/tex]

Answer:

5+h/n+3

Step-by-step explanation:

5+h is numerator

and n+3 is denominator

so you make it a fraction to get the quotient which is 5+h/n+3

Answer:7/97 or 0.072165

Step-by-step explanation:

Answer:

Its D

Step-by-step explanation:

i just guessed! but i think its D!<3

Answer:

0.0625

Step-by-step explanation:

Answer:

4 step by step explanation

The at {x} = 10, the value of the function remains +8.

A function is a relation between a dependent and independent variable. We can write the examples of functions as -

y = f(x) = ax + b

y = f(x, y, z) = ax + by + cz

Given is that the function f(x) is defined as -

f(x) = + 8

The given function is a constant function. This means that the value of the function remains the same irrespective of the value of {x} or the value in the function domain. So, at {x} = 10, the value of the function remains +8 only. This is true for all the values of {x}.

Therefore, the at {x} = 10, the value of the function remains +8.

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Answer:

[tex]\frac{14}{19}[/tex]

First:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

[tex]\frac{7}{4} \div \frac{19}{8}[/tex]

Applying the fractions formula for division:

[tex]= \frac{7 \times 8}{4 \times 19}[/tex]

[tex]= \frac{56}{76}[/tex]

Simplifying 56/76, the answer is:

[tex]\frac{14}{19}[/tex]

I hope this helps! :)

Answer:

the answer is 14/19

change the mixed numbers to improper fractions then that becomes 7/4 and 19/8 then multiply across 7x8=56 and 19x4=76 that gives you 56/76

Simplifying 56/76,=  14/19  

Hey there! I'm happy to help!

30% is the same thing as 0.3 because 0.3 is 30% of 1. If you multiply something by 1, it will just stay the same, so you need that percent of 1.

To convert a decimal to a percent, you move the decimal to the left two spaces.

Now, we simply multiply this by 930.

0.3×930=279

So, Kendra will receive a bonus of $279.

Have a wonderful day and keep on learning! :D

Answer:5 units

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Answer:

18 ft

Step-by-step explanation:

The circumference of a circle is given by

C = 2 * pi *r

113.04 = 2 ( 3.14) * r

113.04 = 6.28 r

Divide each side by 6.28

113.04/6.28 = 6.28r/6.28

18 =r

Answer:

a) Option A is correct.

b) Option B is correct.

Step-by-step explanation:

[tex]a) \: \: 5 \times a \\ = 5a[/tex]

[tex]b) \: \: b \times b \\ = {b}^{2} [/tex]

Answer:

n•√n

here is an accurate representation

Answer:

[tex]1\frac{1}{4}[/tex] cups

Step-by-step explanation:

3/4=3/5

3/4*1/3=3/5*1/3

1/4 = 1/5

1/4*5=1/5*5

5/4=5/5

5/4= 1 and 1/4 cups

Hope this helped! Please mark brainliest :)

~~ SUMMER ~~

Answer:

[tex]\frac{5+\sqrt{17}}{4}[/tex],      [tex]\frac{5-\sqrt{17}}{4}[/tex]

Step-by-step explanation:

One is asked to find the root of the following equation:

[tex]2x^2+1=5x[/tex]

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

[tex]ax^2+bx+c=0[/tex]

Change the given equation using inverse operations,

[tex]2x^2+1=5x[/tex]

[tex]2x^2-5x+1=0[/tex]

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

[tex]\frac{-b(+-)\sqrt{b^2-4ac}}{2a}[/tex]

[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}[/tex]

Simplify,

[tex]\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}[/tex]

[tex]\frac{5(+-)\sqrt{25-8}}{4}[/tex]

[tex]\frac{5(+-)\sqrt{17}}{4}[/tex]

Rewrite,

[tex]\frac{5(+-)\sqrt{17}}{4}[/tex]

[tex]\frac{5+\sqrt{17}}{4}[/tex],      [tex]\frac{5-\sqrt{17}}{4}[/tex]

Answer:

20000

Step-by-step explanation:

This is because when you round to the signifigant figure, you basically look at any digits at the start of the number, which isn't zero. In this case it would be in the ten thousand 19340. So you round 19340 to the nearest 10 thounsand, which, would be 20000

Hey there! I'm happy to help!

First of all, I would guide you to decipher clue 2 first. It is the only one that has just one shape, so then we can find the value of that shape.

To find what this circle is, we just divide 12 by three to see what 3 times the circle is!

12÷3=4

CIRCLE=4

-----------------------------------------------------------------

Now, let's look at clue one. This one only has two shapes, and it has the circle, which we already know.

We know that our circle is 4, so 5 circles will be 20.

This means that the diamond plus two will be 20, so let's just subtract 2 from 20!

20-2=18

DIAMOND=18

-----------------------------------------------------------------

Finally, let's look at the third one. This one is the trickiest. Two circles is eight, and that is going to be equal to our diamond (eighteen) and two triangles.

How is that going to work?

The triangles make us go backwards! Otherwise known as negative numbers!

To get from eighteen to eight, we have to go back ten. Ten is going to be made up of two triangles, so we just divide ten by two so each triangle gets an equal amount.

10÷2=5

TRIANGLE=5

-----------------------------------------------------------------

Have a wonderful day and keep on learning! :D

An equation is formed of two equal expressions. The value of the Circle, Diamond, and the triangle is 4, 18, and -5, respectively.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Let the circle be represented by C, the diamond be represented by D, and the triangle be represented by T.

Now, the clues can be rewritten as,

D + 2 = 5(C)

3(C) = 12

2(C) = D + 2(T)

Since the second clue has only one variable C, let's solve it first,

3(C) = 12

C = 12 / 3

C = 4

Further, the first clue has two variables C and D, and the value of C is already known, therefore, solve it second.

D + 2 = 5(C)

D + 2 = 5(4)

D + 2 = 20

D = 20 - 2

D = 18

Furthermore, by solving the last Clue we will get,

2(C) = D + 2(T)

Substitute the known values,

2(4) = 18 + 2(T)

8 = 18 + 2T

8 - 18 = 2T

-10 = 2T

T = -5

Hence, the value of the Circle, Diamond, and the triangle is 4, 18, and -5, respectively.

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Answer:

(- 1, - 3 )

Step-by-step explanation:

Substitute x = - 1 into the equation and evaluate for y

y = 4(- 1) + 1 = - 4 + 1 = - 3

solution is (- 1, - 3 )

Answer:

1024

Step-by-step explanation:

multiply 16 by 64

Answer:

2. ☑ A [tex]\displaystyle f(x) = tan\:\frac{1}{2}x[/tex]

☐ B [tex]\displaystyle f(x) = tan\:2x[/tex]

☐ C x = [tex]\displaystyle 2tan\:x[/tex]

1. ☐ A [tex]\displaystyle \frac{\pi}{2}[/tex]

☐ B [tex]\displaystyle \pi[/tex]

☑ C [tex]\displaystyle 2\pi[/tex]

Explanation:

[tex]\displaystyle \boxed{f(x) = -cot\:(\frac{1}{2}x - \frac{\pi}{2})} \\ \\ y = Acot(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\frac{\pi}{2}}{\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

OR

[tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

Here is all the information you will need. Now, what you need to know is that ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes. Also, keep in mind that although this IS the tangent graph, if you plan on writing your equation as a function of cotangent, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = cot\:\frac{1}{2}x,[/tex] in which you need to replase "tangent" with "cotangent", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the tangent graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cotangent graph [photograph on the right] is shifted [tex]\displaystyle \pi\:units[/tex] to the left, which means that in order to match the tangent graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \pi\:units,[/tex] which means the C-term will be positive, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\pi} = \frac{\frac{\pi}{2}}{\frac{1}{2}},[/tex] but we are NOT YET DONE. Although we shifted the graph back into position, remember, cotangent is graphed in REVERCE, so we need to insert a negative in front of the amplitude term, and with that, the cotangent graph of the tangent graph, accourding to the horisontal shift, is [tex]\displaystyle y = -cot\:(\frac{1}{2}x - \frac{\pi}{2}).[/tex] Now, with all that being said, we can move forward. To find the period in this case, you need to take a look at the distanse between each vertical asymptote. Now, accourding to this graph, the vertical asymptotes are [tex]\displaystyle -\pi = x\:and\:\pi = x.[/tex] From here, you will then find the distanse between these asymptotes by simply perfourming the operation of Deduction, and doing that will give you [tex]\displaystyle \boxed{2\pi} = \pi + \pi.[/tex] So, the period of this function is [tex]\displaystyle 2\pi.[/tex] Now, you will instantly get the jist of the horisontal shift by looking at the above formula. Just keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must pay cloce attention to what is given to you inside those parentheses. Finally, the midline is the centre of your graph, also known as the vertical shift, which in this case is at [tex]\displaystyle y = 0.[/tex]

Well, that just about wraps it up. Now that everything has been explained, you should understand it better. If you still have questions, do not hesitate to comment any you have.

I am delighted to assist you at any time.

Equations are represented with the = sign. It means both sides of the equation are equal. [tex]11=t+11.5-t[/tex] has no solution

Given that:

[tex]11=t+11.5-t[/tex]

Start by collecting like terms

[tex]11-11.5=t-t[/tex]

Evaluate like terms

[tex]-0.5 = 0[/tex]

-0.5 is not equal to 0.

Hence, the equation has no solution

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Answer:

30

Step-by-step explanation:

Another way to group the factor would be 3(2×5)

2 times 5 is 10 and then 10 times 3 is 30 so therefore, your answer is 30

Answer:

r = 6

Step-by-step explanation:

– 36 – 4r = -2(-6 + 6r)

+36               +36

----------------------------------

-4r = -12r + 48

+12r     +12r

----------------------------------

8r = 48

/8     /8

----------------------------------

r = 6

Answer:

r = 6

Step-by-step explanation:

– 36 – 4r = -2(-6 + 6r)

-36 - 4r = 12 - 12r

-48 - 4r = -12r

-48 = -8r

r = 6

Answer:

https://www.teachoo.com/3815/705/Example-35---Find-dy-dx--if-x--at2--y--2at---Class-12-CBSE-/category/Examples/

Answer:

a)

[tex] \frac{3.6}{1.5} = \frac{36}{15} = 2.4[/tex]

b)

[tex] \frac{42}{0.21} = \frac{4200}{21} = 200[/tex]

c)

[tex] \frac{200}{0.5} = \frac{2000}{5} = 400[/tex]

I hope I helped you^_^

Answer:

The correct answer is A.

Step-by-step explanation:

Answer:

im pretty sure its 250%

Step-by-step explanation:

Answer:

250%

Step-by-step explanation:

1 is 100% and double that is 200%

1/5 of 100% is 50%

200% + 50% = 250%

Hi ;-)

[tex]\text{x}=-1 \ \text{and} \ \text{y}=-4\\\\\dfrac{5x^2-y^2+3}{2x-4y}=\dfrac{5\cdot(-1)^2-(-4)^2+3}{2\cdot(-1)-4\cdot(-4)}=\dfrac{5\cdot1-16+3}{-2+16}=\boxed{-\frac{8}{14}}[/tex]