how do you write in numerals

Answer:

should be (5y-2)y = 72

Step-by-step explanation:

since the product of the two is 72, it's true that xy = 72. and it is also true that x is equal to five times y minus 2, so you can rewrite x as 5y-2. plug that in for x in the first equation, and you're set. hope this helps :)

Answer:

$196.28

Step-by-step explanation:

Original cost: 39 × $8 = $312

Revenue: 32 × $16.19 = $518.08

Return charge: 7 × $1.4 = $9.8

$312 + $9.8 = total cost, which is $321.8

$518.08 - $321.8 = profit

Profit = $196.28

Answer:

The answer is the third one below

Answer:  Choice D.  (-7, 14)

Work Shown:

[tex](x,y) \to (x-3, y+7)\\\\(-4,7) \to (-4-3, 7+7)\\\\(-4,7) \to (-7, 14)\\\\[/tex]

The point has moved 3 units to the left and 7 units up. See the diagram below.

Answer:

Slope = 2

Step-by-step explanation:

To find the slope of the line, you need to plot two points

My own two points will be: [tex](1,2)[/tex] and [tex](2,4)[/tex]

Now use the Slope-Formula to identify the slope of the line

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{4-2}{2-1}[/tex]

[tex]m=\frac{2}{1}[/tex]

[tex]m=2[/tex]

so the slope of the line in simplest form will be 2.

Answer:

2w<23

Step-by-step explanation:

The product of w and 2 mean that w multiplied by 2

Answer:

The second number is 100.

Step-by-step explanation:

Let the first integer be x.

Then since the five integers are consecutive, the second integer will be (x + 1), the third (x + 2), fourth (x + 3), and the fifth (x + 4).

They total 505. Hence:

[tex]\displaystyle x+(x+1)+(x+2)+(x+3)+(x+4)=505[/tex]

Solve for x. Combine like terms:

[tex]5x+10=505[/tex]

Subtract 10 from both sides:

[tex]5x=495[/tex]

And divide both sides by five. Hence:

[tex]x=99[/tex]

Thus, our sequence is 99, 100, 101, 102, and 103.

The second number is 100.

Answer:

1. -6x + 14 < -28

6x<42

x<7

2.  3x + 28 < 25

3x < -3

x<-1

Hope This Helps!!!

Answer:

I think the answer is 100 because nothing greater than 200 if its rounded hope this helped if not sorry

Let the <C=x

We know in a triangle

☆Sum of angles=180°

[tex]\\ \sf\longmapsto 51+26+x=180[/tex]

[tex]\\ \sf\longmapsto 77+x=180[/tex]

[tex]\\ \sf\longmapsto x=180-77[/tex]

[tex]\\ \sf\longmapsto x=103°[/tex]

Answer:

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive

Step-by-step explanation:

Let

Set A={a,b,c}

Now, define a relation R on set A is given by

R={(a,a),(a,b),(b,a),(b,b)}

For reflexive

A relation is called reflexive if (a,a)[tex]\in R[/tex] for every element a[tex]\in A[/tex]

[tex](c,c)\notin R[/tex]

Therefore, the relation R is  not reflexive.

For symmetric

If [tex](a,b)\in R[/tex] then [tex](b,a)\in R[/tex]

We have

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

Hence, R is symmetric.

For transitive

If (a,b)[tex]\in R[/tex] and (b,c)[tex]\in R[/tex] then (a,c)[tex]\in R[/tex]

Here,

[tex](a,a)\in R[/tex] and [tex](a,b)\in R[/tex]

[tex]\implies (a,b)\in R[/tex]

[tex](a,b)\in R[/tex] and [tex](b,a)\in R[/tex]

[tex]\implies (a,a)\in R[/tex]

Therefore, R is transitive.

Yes, it is possible to have  a relation on the set {a, b, c} that is both symmetric and transitive but not reflexive.

Answer:

0.025 = 2.5% probability that a given class period runs between 51.25 and 51.5 minutes.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value between c and d is:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

Uniformly distributed between 47.0 and 57.0 minutes.

This means that [tex]a = 47, b = 57[/tex]

Find the probability that a given class period runs between 51.25 and 51.5 minutes.

[tex]P(c \leq X \leq d) = \frac{51.5 - 51.25}{57 - 47} = 0.025[/tex]

0.025 = 2.5% probability that a given class period runs between 51.25 and 51.5 minutes.

Answer:

he rate it 16%

Step-by-step explanation:

64-80\100=16

Answer:

[tex]C = 48.6[/tex]

Step-by-step explanation:

Given

[tex]Area= 4.5m^2[/tex]

[tex]a =4[/tex]

[tex]b = 3[/tex]

Required

Find angle C

The area of the triangle will be calculated using:

[tex]Area = \frac{1}{2}ab \sin C[/tex]

So, we have:

[tex]4.5= \frac{1}{2} * 4 * 3 * \sin C[/tex]

[tex]4.5= 6 * \sin C[/tex]

Divide both sides by 6

[tex]0.75= \sin C[/tex]

Take arc sin of both sides

[tex]\sin^{-1}(0.75)= C[/tex]

[tex]48.6 = C[/tex]

[tex]C = 48.6[/tex]

Answer:

50 dozen total

Step-by-step explanation:

8/12 & 10/12.... average 9/12

11/12 - 9/12 =

2/12x = 100

2x = 1200

x = 600/12

50 dozen total

Answer:

First Example: 3 1/2 + 4 3/4, Second Example: 6 3/8 + 7 9/15

Extra Example: 8 4/20 + 3 5/10

Step-by-step explanation:

First Example:

1/2 + 3/4

1/2 is equal to 2/4 so it is now compatible to be added to 3/4.

2/4 + 3/4

= 5/4

Now for the mixed numbers since its 3 and 4, 3 + 4 = 7.

Final answer is 7 5/4.

Second Example:

3/8 + 9/15

9/15 can be reduced to 3/5

Now the equation is 3/8 + 3/5

= 15/40 + 24/40 is an equivalent equation

15/40 + 24/40  

= 39/40

Now for the mixed numbers since its 6 and 7, 6 + 7 = 13

Final answer is 13 39/40.

I am going to include one last example just in case you need one:

Third Example:

4/20 + 5/10

We can reduce these to

1/5 + 1/2

= 2/10 + 5/10 is the equivalent equation

2/10 + 5/10

= 7/10

Now for the mixed numbers since its 8 and 3, 8 + 3 = 11.

Final answer is 11 7/10.

I Hope this helps!

Answer:

14) 4x+10=8x-26 (corresponding angles are equal)

4x-8x=-26-10

-4x=-36

x= -36/-4= 9

x=9

15) perimeter of rectangle= 2(l+b)

2( l+ [tex]\frac{2l}{3}[/tex]) = 40m

2l+ [tex]\frac{4l}{3}[/tex] =40

Take LCM as 3

[tex]\frac{2l}{1}[/tex] * [tex]\frac{3}{3}[/tex] + [tex]\frac{4l}{3}[/tex] =40

[tex]\frac{6l+4l}{3}[/tex] = 40

[tex]\frac{10l}{3}[/tex] = 40

10l=40*3

10l = 120

l= 120/10 =12 cm

l=12cm

b= 2/3 *12 = 8cm

16) 2:3:4

It can be written as 2x+3x+4x

sum of angles of a triangle =180 degree

so 2x+3x+4x=180

9x=180

x=180/9=20 degree

1st angle=2x=2*20= 40 degree

2nd angle= 3x=3*20 =60 degree

3rd angle= 4x=4*20= 80 degree

17) sum of interior angles of a pentagon is 540 degree

so, 125+88+128+60+x=540 degree

401 +x= 540 degree

x=540-401= 139 degree

Hope this helps

Please mark me as brainliest

Answer:

The answer is $1.50/bottle.

Step-by-step explanation:

To get the unit price, you need to divide the total by the amount of bottles.

[tex]9.00/6=1.50[/tex]

Answer:

Hence,

a) The probability that the sample average would be less than 90 pounds is 0.0210.

b) The probability that the sample average would be between 98 and 105 pounds is 0.5045.

c) The probability that the sample average would be less than 112 pounds is 0.9935.

d) The probability that the sample average would be between 93 and 96 pounds is 0.1341.

Step-by-step explanation:

a) [tex]P(X < 90) = P(Z < (90 - 99.9) / (30\sqrt(38)))[/tex]

                     = P(Z < -2.03) = 0.0210

b )[tex]P(98 < x <105) = P((98 -99.9) / (30 \sqrt(38)) < Z < (105 -99.9) / (30 \sqrt(38)))[/tex]

                              = P(-0.39 < Z < 1.05) = 0.5045

c ) [tex]P(X < 112) = P(Z < (112 - 99.9) / (30\sqrt(38)))[/tex]

                        = P(Z < 2.49) = 0.9935

d )[tex]P(93 < x < 96) = P((93 -99.9) / (30 \sqrt(38)) < Z < (96 -99.9) / (30 \sqrt(38)))[/tex]

                            = P( -1.42 < Z < -0.8 )

                            = 0.2119 - 0.0778 = 0.1341

Answer:

Step-by-step explanation:

a)

zo=(89.0-92.2)/sqrt((1.5/15)+(1.2/20))

zo=-8.00

p-value=0.0000

Reject the null hypothesis.

b)

95% confidence interval for difference

=(89-92.2)+/-1.96*sqrt((1.5/15)+(1.2/20))

=-3.2+/-0.78

=(-3.98, -2.42)

Answer:

The measure of the angle is 55º.

Step-by-step explanation:

Complement of angle x:

If two angles are complementary, the sum of their measures is of 90º. Thus, the complement of an angle x is 90 - x.

In this question:

Angle is 120 less than 5 times its own complement, so:

[tex]x = 5(90 - x) - 120[/tex]

We have to solve for x

[tex]x = 450 - 5x - 120[/tex]

[tex]6x = 330[/tex]

[tex]x = \frac{330}{6}[/tex]

[tex]x = 55[/tex]

The measure of the angle is 55º.

Answer:

Step-by-step explanation:

If X is a normal random variable with a mean of 6 and a standard deviation of 3.0, then find the value x such that P(Z>x)is equal to .7054.

-----

Find the z-value with a right tail of 0.7054

z = invNorm(1-0.7054) = -0.5400

x = zs+u

x = -5400*3+6 = 4.38

Answer:

The measure of the smallest angle is 30º

Step-by-step explanation:

Let the angles be:

[tex]x \to[/tex] the first angle (the smallest)

[tex]y \to[/tex] the second angle

[tex]z \to[/tex] the third angle

So, we have:

[tex]y = 2x[/tex]

[tex]z=x + 60[/tex]

Required

Find x

The angles in a triangle is:

[tex]x + y +z = 180[/tex]

Substitute values for y and z

[tex]x + 2x +x + 60 = 180[/tex]

[tex]4x + 60 = 180[/tex]

Collect like terms

[tex]4x = 180-60[/tex]

[tex]4x = 120[/tex]

Divide by 4

[tex]x = 30[/tex]

Answer:

0.14

Step-by-step explanation:

P(A|B) asks for the probability of A, given that B has happened. This is equal to the probability of A and B over the probability of B (see picture)

Here, the question is asking if someone is taking the bus given that they are a senior.

The probability of someone being a senior and taking the bus is 5/100, or 0.05 . The probability of someone being a senior is 35/100, or 0.35

Our answer is then 0.05/0.35 = 1/7 = 0.14

Answer:

[tex](5xy + 7)(5xy-7) = 25x^2 y^2 - 49[/tex]

Step-by-step explanation:

[tex](a - b)(a +b ) = a^2 - b^2 \\\\From \ given \ expression \ a = 5xy \ , \ b = 7\\\\Therefore , (5xy + 7 )(5xy - 7 ) = ( 5xy)^2 - ( 7)^2 \\[/tex]

                                             [tex]= 25x^2 y^2 - 49[/tex]

Answer:

25x²y² - 49

Step-by-step explanation:

We can do this by using the a+b formula:

(a+b)(a-b)= a² - b²

So,

(5xy+7)(5xy-7)

=(5xy)² - 7²

= 25x²y² - 49

Another way we can do this by expanding the algebraic expression:

(5xy+7)(5xy-7)

= 5xy(5xy-7) + 7(5xy-7)

= 25x²y² - 35xy + 35xy - 49

= 25x²y²- 49

[tex]\huge{\boxed{\boxed{ Solution ⎇}}} \ [/tex]

[tex] - 3x \times (2x + 5) \\ = - 3x \times 2x + - 3x \times 5 \\ = - 6x ^{2} - 15x[/tex]

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꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

[tex] - 3x \times (2x + 5) \\ = - 3x \times 2x + - 3x \times 5 \\ = - 6x ^{2} - 15x [/tex]

Answer ⟶ - 6x² - 15x

Answer:

Total earning last month with x articles is:

This is same amount as 2000

The equation is:

Answer:

Approximately [tex]4.75[/tex].

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] are equal.

[tex]{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}[/tex]

Since [tex]\rm CH_3COONa[/tex] is a salt soluble in water. Once in water, it would readily ionize to give [tex]\rm CH_3COO^{-}[/tex] and [tex]\rm Na^{+}[/tex] ions.

Assume that the [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] ions in this solution did not disintegrate at all. The solution would contain:

[tex]0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol[/tex] of [tex]\rm CH_3COOH[/tex], and

[tex]0.06\; \rm mol[/tex] of [tex]\rm CH_3COO^{-}[/tex] from [tex]0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol[/tex] of [tex]\rm CH_3COONa[/tex].

Accordingly, the concentration of [tex]\rm CH_3COOH[/tex] and [tex]\rm CH_3COO^{-}[/tex] would be:

[tex]\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}[/tex].

[tex]\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}[/tex].

In other words, in this buffer solution, the initial concentration of the weak acid [tex]\rm CH_3COOH[/tex] is the same as that of its conjugate base, [tex]\rm CH_3COO^{-}[/tex].

Hence, once in equilibrium, the [tex]\rm pH[/tex] of this buffer solution would be the same as the [tex]{\rm pK}_{a}[/tex] of [tex]\rm CH_3COOH[/tex].

Calculate the [tex]{\rm pK}_{a}[/tex] of [tex]\rm CH_3COOH[/tex] from its [tex]{\rm K}_{a}[/tex]:

[tex]\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}[/tex].