How many joules of heat energy are required to raise the temperature of 100.0 g of aluminum by 120.0°C? The specific heat of aluminum is 0.897 J/g.°C. 2 3

Answer:

Exothermic

1771 g

Explanation:

Step 1: Write the balanced thermochemical equation

2 S(s) + 3 O₂(g) ⇒ 2 SO₃(g)   ΔH° = -791.4 kJ

Since ΔH° < 0, the reaction is exothermic.

Step 2: Calculate the moles of SO₃ produced when 8753 kJ of energy are released

According to the thermochemical equation, -791.4 kJ are released every 2 moles of SO₃ that are formed.

-8753 kJ × 2 mol/(-791.4 kJ) = 22.12 mol

Step 3: Calculate the mass corresponding to 22.12 moles of SO₃

The molar mass of SO₃ is 80.06 g/mol.

22.12 mol × 80.06 g/mol = 1771 g

Answer:

The solubility of the gaseous solute decreases

Explanation:

As we know, pressure decreases with altitude. This means that, at higher altitudes, the pressure is much lower than it is at sea level.

The solubility of a gas increases with increase in pressure and decreases with decrease in pressure.

Hence, in Denver, Colorado where the elevation is about 5,280 feet above sea level, a gaseous solute is less soluble than it is at sea level due to the lower pressure at such high altitude.

Answer:

V = 365.54 mL

Explanation:

Given that,

The density of chloroform, d = 1.48 g/mL

The mass of chloroform, m = 541 g

We need to find the volume of chloroform.

We know that,

Density = mass/volume

So,

[tex]V=\dfrac{m}{d}\\\\V=\dfrac{541\ g}{1.48\ g/mL}\\\\=365.54\ mL[/tex]

So, the volume of chloroform is 365.54 mL.

Answer:

My nettttttworkkkk is slowww

Answer:

the TWO characteristics of an effective collision are:

1.Molecules collide with sufficient energy

2.Molecules collide with the proper orientation.

Answer:

The reaction rate increases in direct proportion to the concentration of the reactant in solution - second order reaction

The reaction rate is constant regardless of the amount of reactant in solution - zero order reaction

An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially - first order reaction

Explanation:

In a second order reaction, the rate of reaction is directly proportional to the concentration of reactants. This implies that, reaction rate varies as the concentration of the reactant in solution varies.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactants in solution. This means that reaction rate is constant regardless of the amount of reactant in solution.

For a first order reaction, the rate of reaction varies exponentially as the concentration of reactants. Hence, an increase or decrease in the concentration of the reactant in solution causes the reaction rate to increase or decrease exponentially.

Answer:

No, the correct empirical formula is [tex]C_3H_7[/tex].

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us to bear to mind the fact that empirical formulas must not be expressed in decimal numbers, for that reason, we need to multiply the given empirical formula by 2 to get the correct one:

[tex]C_3H_7[/tex]

Which is now possible.

Regards!

Answer:

0.0457 M

Explanation:

Concentration is the amount of a substance in a predefined volume of space. The basic measurement of concentration in chemistry is molarity or the number of moles of solute per liter of solution. What is the molarity of a solution containing 9.478 grams of RuCl₃, in enough water to make 1.00 L of solution?

Step 1: Given data

Step 2: Calculate the moles corresponding to 9.478 g of RuCl₃

The molar mass of RuCl₃ is 207.4 g/mol.

9.478 g × 1 mol/207.4 g = 0.04570 mol

Step 3: Calculate the molarity of the solution

We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.04570 mol / 1.00 L = 0.0457 M

Answer:

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Answer:

See Explanation

Explanation:

Rate of reaction refers to how quickly or slowly a reaction proceeds. The rate of reaction depends on certain factors.

Two among the factors that affect the rate of reaction are the concentration of reactants and the surface area of reactants.

The more the concentration of reactants, the faster the rate of reactants because there is a high possibility of collision between reactants. Also, the higher the surface area of reactants, the greater the rate of reaction.

In flour mills and coal mines where there is a large amount (concentration) of combustible materials and the particles are powdered (high surface area), there is a greater risk of explosion due to a high rate of reaction owing to a combination of the two factors discussed above.

Solution :

  Term                                                                      Best description

Eriochrome Black T                                                          EBT

Starting color, before titration                               Pale purple-pink color

Molecule that has a high affinity for metal ions       Chelating agent

Ethylenediaminetetracetic acid                                    EDTA

Color at the completion of titration                           Blue-gray color    

Answer:

1.75L

Explanation:

Reaction of decomposition is:

2KClO₃(s) →  2KCl(s) + 3O₂(g)

We determine moles of salt:

4.35 g . 1 mol /122.55 g = 0.0355 moles

Ratio is 2:3. 2 moles of salt can produce 3 moles of oxygen

Then, our 0.0355 moles of chlorate may produce (0.0355 . 3)/ 2 = 0.0532 moles.

We have determined, moles of gas and we have data of pressure and temperature. To find out the volume, we apply the Ideal Gases Law:

We convert T° from °C to K → 27°C + 273 = 300K

P . V = n . R . T

0.75 atm . V = 0.0532 mol . 0.0821 L.atm/mol.K . 300K

V = (0.0532 mol  . 0.0821 L.atm/mol.K . 300K) / 0.75 atm

V  = 1.75 Liters

Answer:

1. Write the balanced chemical equation for the reaction

2. Identify all important information provided in the word problems or data table.

3. Solve for the theoretical yield of the reaction, following all the steps of a stoichiometry calculation organizer. Use two calculations if both reactants are provided.

4. Use the percent yield equation to calculate the percent yield of the reaction.

Explanation:

its comes right from the 5.06 lesson

Answer:

D. amine and alcohol

Explanation:

Organic compounds are identified using the functional group they contain. The functional group defines their peculiarity and chemical identity. For example, alkenes are identified by a double bond functional group (=), alcohols are identified by an hydroxyl functional group (OH) etc.

According to this question, a compound was given as an attached image. The compound posseses:

- an hydroxyl group (OH) indicating that it has an ALCOHOL functional group

- an N-H group indicating that it has an amine functional group

Answer:

0.186 moles

Explanation:

In order to convert grams of PCl₅ into moles, we need to use its molar mass:

Then we proceed to calculate the number of moles:

In the given question Phosphorus pentachloride is used as a catalyst for certain chemical reaction. 38.7 g of [tex]\rm PCl_5[/tex], there are 0.186 moles of [tex]\rm PCl_5[/tex].

A catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy required for the reaction to occur.

To calculate the number of moles in 38.7 g of [tex]\rm PCl_5[/tex], we need to divide the given mass of [tex]\rm PCl_5[/tex] by its molar mass.

The molar mass of [tex]\rm PCl_5[/tex] can be calculated by adding the atomic masses of one phosphorus atom and five chlorine atoms:

Molar mass of  [tex]\rm PCl_5[/tex] = (1 x atomic mass of P) + (5 x atomic mass of Cl)

= (1 x 30.97 g/mol) + (5 x 35.45 g/mol)

= 208.22 g/mol

Now, we can calculate the number of moles of  [tex]\rm PCl_5[/tex]:

Number of moles = mass / molar mass

= 38.7 g / 208.22 g/mol

= 0.186 moles

Therefore, there are 0.186 moles of  [tex]\rm PCl_5[/tex] in 38.7 g of  [tex]\rm PCl_5[/tex].

Learn more about catalyst here:

https://brainly.com/question/24430084

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Answer: The pH of the resulting solution will be 3.60

Explanation:

Molarity is calculated by using the equation:

[tex]\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}[/tex] ......(1)

We are given:

Molarity of formic acid = 0.100 M

Molarity of potassium formate = 0.100 M

Volume of solution = 420 mL = 0.420 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

[tex]\text{Moles of formic acid}=(0.100mol/L\times 0.420L)=0.0420mol[/tex]

[tex]\text{Moles of potassium formate}=(0.100mol/L\times 0.420L)=0.042mol[/tex]

Molarity of KOH = 1.00 M

Volume of solution = 7 mL = 0.007 L

Putting values in equation 1, we get:

[tex]\text{Moles of KOH}=(1mol/L\times 0.007L)=0.007mol[/tex]

The chemical equation for the reaction of formic acid and KOH follows:

                 [tex]HCOOH+KOH\rightleftharpoons HCOOK+H_2O[/tex]

I:                   0.042     0.007       0.042

C:                -0.007    -0.007     +0.007

E:                  0.035         -           0.049

Volume of solution = [420 + 7] = 427 mL = 0.427 L

To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:

[tex]pH=pK_a+ \log \frac{\text{[conjugate base]}}{\text{[acid]}}[/tex] .......(2)

Given values:

[tex][HCOOK]=\frac{0.049}{0.427}[/tex]

[tex][HCOOH]=\frac{0.035}{0.427}[/tex]

[tex]pK_a=3.75[/tex]

Putting values in equation 2, we get:

[tex]pH=3.75-\log \frac{(0.049/0.427)}{(0.035/0.427)}\\\\pH=3.75-0.146\\\\pH=3.60[/tex]

Hence, the pH of the resulting solution will be 3.60

Answer:

Concentration C = 0.0189 mol/L

Explanation:

From the given information:

Let consider the formula used in calculating the concentration according to Beer's law:

[tex]\mathtt{A =\varepsilon \times L \times C}[/tex] --- (1)

here;

A = absorbance

ε = coefficient of molar absorptivity

L = path length

C = concentration (mol/L)

Also, from Beer law plot:

y = mx+b

where,

y represent absorbance A

b represents intercept

m represents the coefficient of molar absorptivity ε

and x represents the concentration(C).

replacing the substituted entities

A = ε × C + b ---- (2)

Making the concentration the subject of the above formula:

[tex]C = \dfrac{A-b}{\varepsilon}[/tex]----(3)

From y = 11.589x - 0.0002

A = 11.589 *C - 0.0002

Given that:

A = 0.219

∴

0.219 = 11.589 *C - 0.0002

0.219 + 0.0002 =  11.589 *C

C = 0.2192/11.589

C = 0.0189 mol/L

Answer:

HCl  is a acid

Explanation:

NaOH is base

Nacl is salt

Answer:

(E)-1-phenylbut-1-ene

Explanation:

2-phenyl-4 bromobutane is an amphetamine that contains a phenyl group. It forms a major stable product with other reacting agents.

The major organic product that is obtained from the sequence of the reactions of the 2-phenyl-4 bomobutane when it reacts with [tex]NaN_3[/tex] is the (E)-1-phenylbut-1-ene.

Thus the answer is 2-phenyl-4 bromobutane is an amphetamine that contains a phenyl group. It forms a major stable product with other reacting agents.

The major organic product that is (E)-1-phenylbut-1-ene.

Answer:

the amount of a substance that will dissolve in a given amount of solvent.

Explanation:

Solubility is a term used to describe how readily a substance can be dissolved in a solvent to form a solution. Thus, a substance is said to be soluble if it dissolves completely in a solvent and insoluble if it doesn't dissolve or only dissolves partially.

For example, sodium chloride (NaCl) when mixed with water dissociates into sodium and chloride ions. Thus, salt (sodium chloride) is said to be soluble because it dissolves completely in water.

Furthermore, a compound that dissolves completely in water to produce an aqueous solution is said to be soluble in water.

In conclusion, solubility is simply the amount of a substance such as salt, that will dissolve in a given amount of solvent. A solvent is any liquid such as water, coffee, tea, etc., that dissolves a liquid, gaseous, or solid solute to produce a solution.

Answer:

Below

Explanation:

Got it right

Check the periodic table, then click electrons

Answer:

Amount of reactant after four hours = 4,26 grams

Explanation:

Suppose y denotes the amount of reactant at the time (t)

The given function:

[tex]\dfrac{dy}{dt} = -0.7 y[/tex]

[tex]\dfrac{dy}{y} = -0.7 dt[/tex]

Taking integral on both sides

㏑(y) = -0.7t + c¹

[tex]e^{In(y)}= e^{-0.7t + c^1}[/tex]

[tex]y(t) = Ce ^{-0.7t}[/tex]

At t = 0 ; y (t) = 70

∴

[tex]70 = Ce^{-0.7(0)}[/tex]

C = 70

As such; [tex]\mathtt{y(t) = 70 e^{-0.7*t}}[/tex]

After four hours, the amount of the reactant is:

[tex]\mathtt{y(t) = 70 e^{-0.7*4}}[/tex]

[tex]\mathtt{y(t) = 70 e^{-2.8}}[/tex]

[tex]\mathtt{y(t) = 4.26}[/tex]

Amount of reactant after four hours = 4,26 grams

Answer:

2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)

Explanation:

Rubidium has a more negative reduction potential (-2.98 V) compared to strontium (-2.89 V).

Hence, in a redox reaction involving rubidium and strontium, rubidium will be oxidized while strontium is reduced.

The balanced redox reaction equation is obtained from;

Oxidation half equation;

2Rb(s) ---->2Rb^+(aq) + 2e

Reduction half equation;

Sr^2+(aq) + 2e ----> Sr(s)

Overall reaction equation;

2Rb(s) + Sr^+(aq) → 2Rb^+ (aq) + Sr(s)

Answer:

Compound A and compound B are constitutional isomers with molecular formula C3H7Cl.

When compound A is treated with sodium methoxide, a substitution reaction predominates. When compound B is treated with sodium methoxide, an elimination reaction predominates.

Explanation:

Constitutional isomers are the one which differs in the structural formula.

When compound A is treated with sodium methoxide, a substitution reaction predominates.

That means sodium methoxide is a strong base and a strong nucleophile.

But when it reacts with primary alkyl halides it forms a substitution product and when it reacts with secondary alkyl halide it forms mostly elimination product.

The reaction and the structures of A and B are shown below:

Answer:

In a combination redox reaction, two or more reactants, at least one of which is a(n) element, form a(n) compound. General Reaction: X + Y > Z

In a decomposition redox reaction, a(n) compound forms two or more products, at least one of which is a(n) element. General Reaction: Z>X+Y

In double-displacement (metathesis) reactions, such as precipitation and acid-base reactions, atoms (or ions) of two compounds exchange places; these reactions are not redox processes. General Reaction: AB+CD>AD+CB

In solution, single-displacement reactions occur when a(n) atom of one element displaces the atom of another. Since one of the reactants is a(n) element, all single-displacement reactions are redox processes. General Reaction: X+YZ>XY+Z

Explanation:

In a combination redox reaction, two or more reactants, at least one of which is a(n) element, form a(n) compound.

General Reaction: X + Y > Z

In the reaction scheme above, X combines with Y to give Z as a product.

In a decomposition redox reaction, a(n) compound forms two or more products, at least one of which is a(n) element.

General Reaction: Z>X+Y

In the reaction scheme above, Z decomposes to X and Y

In double-displacement (metathesis) reactions, such as precipitation and acid-base reactions, atoms (or ions) of two compounds exchange places; these reactions are not redox processes since there are no changes occurring in the oxidation number of the atoms (or ions) involved.

General Reaction: AB+CD>AD+CB

In the reaction scheme above, B and D exchange places in their respective compounds

In solution, single-displacement reactions occur when a(n) atom of one element displaces the atom of another. This type of reaction is due to the difference in the reactivities of the elements. The more reactive atom of one element displaces the least reactive atom of another element from its solution.

Since one of the reactants is a(n) element, all single-displacement reactions are redox processes.

General Reaction: X+YZ>XY+Z

In the reaction scheme above, X displaces Z from the compound YZ.

Answer:

Compare the solubility of silver chloride in each of the following aqueous solutions:

a. 0.10 M AgNO3 More soluble than in pure water.

b. 0.10 M NaCI Similar solubility as in pure water

c. 0.10 M KNO3 Less soluble than in pure water.

d. 0.10 M NH4CH3COO

Explanation:

This is based on common ion effect.

According to common ion effect, the solubility of a sparingly soluble salt decreases in a solution containing common ion to it.

The solubility of AgCl(s) is shown below:

[tex]AgCl(s) <=> Ag^{+}(aq)+Cl^-(aq)[/tex]

So, when it is placed in:

a. 0.10 M AgNO3

Due to common ion effect Ag+, its solubility is less in this solution than in pure water.

b. 0.10 M NaCI :

Due to common ion effect Cl-, its solubility is less in this solution than in pure water.

c. 0.10 M KNO3 :

In this solution there is no presence of common ion.

So, the solubility of AgCl in this solution is similar to that of pure water.

d. 0.10 M NH4CH3COO:

In this solution, AgCl forms a precipitate.

So, the solubility of AgCl is more in this solution compared to pure water.

Answer:

The answer is cell wall

Explanation:

Because it is