Answer:
44.62 kJ
Explanation:
Firstly, we calculate the energy needed to heat the liquid (ethyl alcohol) by using the formula:
Q = m × c × ∆T
Where;
Q = Amount of heat (J)
m = mass (g)
c = specific heat of ethyl alcohol = 2.138 J/g°C
∆T = change in temperature (°C)
According to the information given in this question;
Q = ?, m = 50.0g, ∆T = (78.4°C - 60°C) = 18.4°C
Therefore, using Q = mc∆T
Q = 50 × 2.138 × 18.4
Q (amount of energy needed to heat ethyl alcohol) = 1966.96 J
Next, we calculate and add the amount of heat needed to vaporize by using the formula;
How many kilojoules of energy are required to heat 50.0 g of ethyl alcohol from 60.0 °C to 78.4 °C and vaporize it? The specific heat of ethyl alcohol is heat of vaporization is 853 J/g.
Generally the ionization potential in a period increases, but there are some exceptions. The one which is not an exception is
1) Be & B 2) N & O 3) Mg & Al 4) Na & Mg
Answer:
Generally, the first ionisation energy increases along a period. But there are some exceptions one which is not an exception
A mixture of He, Ar, and Xe has a total pressure of 2.40 atm. The partial pressure of He is 0.300 atm, and the partial pressure of Ar is 0.250 atm. What is the partial pressure of Xe?
Express your answer to three significant figures and include the appropriate units.
The partial pressure of Xe in the mixture is 1.850 atm. (partial pressure of Xe = Total pressure - Partial pressure of He - Partial pressure of Ar = 1.850 atm).
To find the partial pressure of Xe, we need to subtract the partial pressures of He and Ar from the total pressure.
Total pressure = partial pressure of He + partial pressure of Ar + partial pressure of Xe
Given:
Total pressure = 2.40 atm
Partial pressure of He = 0.300 atm
Partial pressure of Ar = 0.250 atm
Let's solve for the partial pressure of Xe:
Partial pressure of Xe = Total pressure - Partial pressure of He - Partial pressure of Ar
Partial pressure of Xe = 2.40 atm - 0.300 atm - 0.250 atm
Partial pressure of Xe = 1.850 atm
Therefore, the partial pressure of Xe in the mixture is 1.850 atm.
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7.In the oxidation of ethane: 2 C2H6 + 7 02 + 4CO2 + 6H2O how many
liters of O2 are required to react with 90 grams of ethane?
Answer:
If reaction is taking place at room temperature and pressure(rtp)
= 360 litres of O₂ at rtp
If reaction is taking place at standard temperature and pressure(stp):
= 336 litres of O₂ at stp
Explanation:
2C₂H₆ + 70₂ → 4CO₂ + 6H₂O
1 mole of C₂H₆ = (12 × 2) + (1 × 6) = 24 + 6 = 30g
2 moles of C₂H₆ = 30 × 2 = 60g
From the equation:
1 mole of 0₂ reacts with 2 moles of C₂H₆
1 mole of 0₂ reacts with 60g of C₂H₆
? moles of 0₂ react with 90g of C₂H₆
[tex]\frac{90}{60}[/tex]= 1.5 moles of O₂
Considering condition of reaction taking place whether room temperature and pressure(rtp) or standard temperature and pressure(stp)
If room temperature and pressure(rtp):
1 mole of 0₂ occupies 24 liters/24000 cm³/ 24 dm³ of O₂
1.5 moles of O₂ occupies (24 × 1.5) litres of O₂
= 360 litres of O₂ at rtp
If standard temperature and pressure(stp):
1 mole of 0₂ occupies 22.4 liters/22400 cm³/ 22.4 dm³ of O₂
1.5 moles of O₂ occupies (22,4 × 1.5) litres of O₂
= 336 litres of O₂ at stp
WILL GIVE BRAINLIEST!!!
Answer:
The answer is B
Explanation:
The answer is B because representative particles can only be atoms.
What is the mass of 4.76 moles of Na3Po4?
SHOW WORK PLEASE - NO LINKS OR FILES(I will not open them)
( btw if your user is Alexgrelli do not answer , I have already reported your account )
Answer:
780 g
Explanation:
Step 1: Given data
Moles of sodium phosphate: 4.76 moles
Step 2: Calculate the mass corresponding to 4.76 moles of sodium phosphate
To convert moles to mass, we need a conversion factor. In this case, we will use the molar mass of sodium phosphate, which is 163.94 g/mol.
4.76 mol × 163.94 g/mol = 780 g
what's the relation between Kp and Kc
Answer:
the relation between Kp and Kc is
[tex] \colorbox{red}Kp=Kc{[RT]}^{∆n}[/tex]
where
∆n=no.of moles of gaseous product - no.of moles of gaseous reactant in the balanced chemical equation.
R=universal gas constant
T=temperature.
Balance the equation ___ CaCO3 -> ____ CaO + ____ CO2
Answer:
CaCO3 -> CaO + CO2
Explanation:
Woahhhh, did you balance it yourself just then?
The Swedish chemist Karl Wilhellm was the first to produce chlorine in the lab
2NaCl + 2H2SO4 + MnO2 -----> Na2SO4 + MnSO4 + H2O + Cl2
If Dr. Wilhellm started with 50.0 g of each reactant, which reactant is the limiting reactant?
Answer:
Explanation:
Remark
Interesting que8stion. You have to figure out how many mols are present in each reactant. Since all periodic tables are different, I'm going to use rounded numbers. If it is too close, I will go further.
NaCl
Na = 23
Cl = 35.5
1 mol = 58.5 grams
given = 50.0 grams
Mols for the reaction = 50/58.5 = 0.855
H2SO4
H2 = 2*1 2
S = 1 * 32 32
O4 = 4*16 64
1 mol = 98 grams
mols present = 50/98 = 0.510
MnO2
Mn = 1 * 55 = 55
O2 = 2*16 = 32
1 mol = 87 grams
mols available = 50/87 = 0.5747
Discussion
Na Cl and H2SO4 both require 2 moles for every mol of Cl2 produces.
H2SO4 has 0.51 mols available for a reaction
NaCl has 0.855 moles available for a reaction
MnO2 has 0.575 moles available for a reaction.
Given those numbers 0.510 mols of H2SO4 will only produce 0.255 mols of chlorine and the rest will be reduced in a similar manner. H2SO4 is the limiting reagent (reactant).
In other words only 0.510 moles of NaCl will be used and 0.855 - 0.510 moles will be left over on the reactants side.
only 0.575 moles of MnO2 will be used and 0.065 moles will be left over.
The oddity in the result shows up because the balance numbers in the equation give a ratio of 2 to 1 for H2SO4 and NaCl The 2 belongs to the reactants and the 1 for the chlorine.
(b) How many moles of hydrogen are needed to make 30 moles of Fe?
PLEASE HELP ASAP
Answer:
1 mole of Fe is 55.85 g per mole
Explanation:
hope it helps
The moles of hydrogen that are needed to make 30 moles of Fe is 45 moles.
What are moles?Moles is a measurement unit. It is the quantity amount of substance.
The balanced equation is
Fe2O3 + 3H2 ---> 2Fe + 3H2O
Given the moles of iron is 30
To find the moles of hydrogen is?
According to the given balanced equation, the ratio of moles of hydrogen and iron is 3 : 2
To produce 30 moles of Fe
30 x 3 / 2 = 45 moles.
Thus, the number of moles of hydrogen is 45 moles.
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Your question is incomplete. Your most probably complete question is given below:
One way to change iron are, Fe2O3, into metallic iron is to heat it together with hydrogen:
Fe2O3 + 3H2 ---> 2Fe + 3H2O
The mass of an atom of element x is equivalent to the total mass of 7 hydrogen atoms
Answer: I'm not sure what your question is but i'll answer as best as I can.
Explanation:
Since X is equal to 7 H and we know that H is equal to 1.008, we can just do 7x1.008 = 7.056 g. I hope i helped and please clarify more in the future.
The atomic mass of an element is given by the sum of the mass of protons and neutrons. The element X is lithium as it has a mass of 6.941 u.
What is atomic mass?Atomic mass is the sum of the masses of the isotopes of that element and is given by adding the masses of the number of protons and neutrons of the elemental atom.
The atomic mass of one hydrogen atom is 1.008, so seven hydrogens will be, 7 x 1.008 = 7.056 g. Now, from the periodic table, it can be seen that an atomic mass of 7.056 g is closest to the atomic mass of a lithium atom (6.941 u).
From the mass, it can be said that seven hydrogen atom has an equivalent mass as that of one lithium atom in the periodic table. The lithium atom has atomic number 3 and an atomic mass of 6.941 g/mol.
Therefore, element X is lithium.
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What is the correct definition of temperature
Answer:
i'm pretty sure its the last answer and if not its the 2nd one
2 Which of the gases in air are elements? Explain how you can tell.
Answer:
I'll explain.
Explanation:
The molecules of two different elements, nitrogen and oxygen, make up about 99 percent of the air. The rest includes small amounts of argon and carbon dioxide. Oxygen is the life-giving element in the air. You can tell because they're on the periodic table which is a table for elements.
Explanation:
nitrogen and oxygen are the gases in the air which are elements you can simply say it by looking the periodic table
what element in magma is most abundant
Answer:
Oxygen and Silicon
Explanation:
Oxygen and Silicon are the most abundant elements in magma, SiO₂
-TheUnknownScientist
un MODELO ATÓMICO es:
a. Una esfera con partículas positivas y negativas
b. La estructura mínima de la materia.
c. Una serie de descubrimientos.
d. La representación de un átomo donde se explica su comportamiento y características.
Answer:
Creo que es D pero no tan segura
Explanation:
Match the element with its oxidation number (charge).
1. +1 O
2. -1 Ca
3. -3 Si
4. -2 Al
5. +2 N
6. +3 Na
7. +/- 4 F
Answer:
The answer is in the problem
Explanation:
As general rule of number of oxygen is -2:
O → -2
Alkali metals (Li, Na, K) are always +1
Na → +1
Alkali earth methals (Be, Mg, Ca...) are always +2
Ca → +2
The halogen group (F, Cl, Br...) is always -1
F → -1
The oxidation number of Si (+/- 4)
Aluminium is, usually +3
And to complete the octet rule in nitrogen, 3 electrons are required. That means:
N → -3
The x-intercept shows us where the temperature can be no lower, defined as absolute zero. Absolute zero is 0 K. Look at the graph.
Did the line reach (0,0)? If not, how close to absolute zero was the line?
Answer:
someone please answer!:(
Answer:
No, it was 130k way from (0,0).
Explanation:
You and several novice researchers decide to set up some experiments in an attempt to explain why potassium reacts with oxygen to form a superoxide. One of your team members proposes that potassium's capacity to form a superoxide compound is related to a low value for the first ionization energy. If you wanted to validate this hypothesis, indicate two metals other than potassium (in order of increasing atomic number) that you could examine to see if they also form superoxides when reacted with oxygen gas.
Required:
Express your answers as chemical symbols separated by a comma.
Answer:
Rubidium and cesium
Explanation:
It is noteworthy to say here that larger cations have more stable superoxides. This goes a long way to show that large cations are stabilized by large cations.
Let us consider the main point of the question. We are told in the question that the reason why potassium reacts with oxygen to form a superoxide is because of its low value of first ionization energy.
The implication of this is that, the other two metals that can be examined to prove this point must have lower first ionization energy than potassium. Potassium has a first ionization energy of 419 KJmol-1, rubidium has a first ionization energy of 403 KJ mol-1 and ceasium has a first ionization energy of 376 KJmol-1.
Hence, if we want to validate the hypothesis that potassium's capacity to form a superoxide compound is related to a low value for the first ionization energy, we must also consider the elements rubidium and cesium whose first ionization energies are lower than that of potassium.
PLZ HELP "NO LINKS"
A vessel of volume 22.4 dm3 contains 2.0 mol H2(g) and 1.0 mol N2(g) at 273.15 K.
(a) Calculate the mole fractions of each component.
H2:
N2:
(b) Calculate the partial pressures of each component.
H2:
N2:
(c) Calculate the total pressure.
Thanks!
Answer: (a) Mole fraction of [tex]H_{2}[/tex] is 0.66.
Mole fraction of [tex]N_{2}[/tex] is 0.33
(b) The partial pressure of [tex]H_{2}[/tex] is 1.98 atm.
The partial pressure of [tex]N_{2}[/tex] is 0.99 atm.
(c) The total pressure is 3.0 atm
Explanation:
Given: Volume = [tex]22.4 dm^{3}[/tex] (1 [tex]dm^{3}[/tex] = 1 L) = 22.4 L
Moles of [tex]H_{2}[/tex] = 2.0 mol
Moles of [tex]N_{2}[/tex] = 1.0 mol
Total moles = (2.0 + 1.0) mol = 3.0 mol
Temperature = 273.15 K
Now, using ideal gas equation the total pressure is calculated as follows.[tex]PV = nRT\\[/tex]
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
[tex]PV = nRT\\P \times 22.4 L = 3.0 mol \times 0.0821 L atm/mol K \times 273.15 K\\P = 3.0 atm[/tex]
The mole fractions of each component:The mole fraction of [tex]H_{2}[/tex] is calculated as follows.
[tex]Mole fraction = \frac{moles of H_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{2.0 mol}{(2.0 + 1.0) mol}\\= 0.66[/tex]
The mole fraction of [tex]N_{2}[/tex] is as follows.
[tex]Mole fraction = \frac{moles of N_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{1.0 mol}{(2.0 + 1.0) mol}\\= 0.33[/tex]
The partial pressures of each component:Partial pressure of [tex]H_{2}[/tex] are as follows.
[tex]P_{H_{2}} = P_{total} \times mole fraction of H_{2}\\= 3.0 atm \times 0.66\\= 1.98 atm[/tex]
Partial pressure of [tex]N_{2}[/tex] are as follows.
[tex]P_{N_{2}} = P_{total} \times mola fraction of N_{2}\\= 3.0 atm \times 0.33\\= 0.99 atm[/tex]
What is the molarity of a solution that contains 224 grams of KOH in 2
liters of solution?
Answer:
[tex]\boxed {\boxed {\sf 2 \ M \ KOH}}[/tex]
Explanation:
Molarity is a measure of concentration in moles per liter.
1. Grams to MolesThe first step is to convert the amount of grams given to moles. The molar mass is used. This found on the Periodic Table and it's the same value as the atomic mass, but the units are grams per mole.
We have 224 grams of KOH. Look up the molar masses for the individual elements.
Potassium (K): 39.098 g/mol Oxygen (O): 15.999 g/mol Hydrogen (H): 1.008 g/molSince the compound's formula has no subscripts, 1 formula unit has 1 atom of each element. We can simply add the molar masses together to find KOH's molar mass.
KOH: 39.098 + 15.999 + 1.008=56.105 g/molUse this number as a ratio.
[tex]\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}[/tex]
Multiply by the value we are converting: 224 g KOH
[tex]224 \ g \ KOH *\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}[/tex]
Flip the ratio so the units of grams KOH cancel.
[tex]224 \ g \ KOH *\frac {1 \ mol \ KOH}{56.105 \ g\ KOH}[/tex]
[tex]224 *\frac {1 \ mol \ KOH}{56.105}[/tex]
[tex]\frac {224}{56.105} \ mol \ KOH[/tex]
[tex]3.992514036 \ mol \ KOH[/tex]
2. Calculate MolarityRemember molarity is moles per liter.
[tex]molarity = \frac{moles}{liters}[/tex]
We just calculated the moles and we know there are 2 liters of solution.
[tex]molarity = \frac{ 3.992514036 \ mol \ KOH}{ 2 \ L}[/tex]
[tex]molarity= 1.996257018 \ mol \ KOH/ L[/tex]
3. Round and Convert UnitsFirst, let's round. The original values have 3 and 1 significant figures. We go with the lowest number: 1. For the number we found, that is the ones place.
1.996257018The 9 in the tenths place tells us to round to 1 up to a 2
[tex]2 \ mol \ KOH/ L[/tex]
Next, convert units. 1 mole per liter is equal to 1 molar or M.
[tex]2 \ M \ KOH[/tex]
The molarity of the solution is 2 M KOH
Answer:
2M of KOH
Explanation:
224 g of KOH in 2 liters of KOH
? of KOH in 1 liters of KOH
[tex]\frac{224}{2} = 112g of KOH[/tex]
1 mole of KOH = 39 + 16+ 1 = 56g
?mole of KOH = 112g
[tex]\frac{112}{56}[/tex]moles of KOH = 2 moles/1liter of KOH
written as 2M KOH
Which of the following regions has an economy based on processing food and consumer goods?
A. Western Europe
B. Eastern Europe
C. northern Europe
D. southern Europe
No links plz
Answer:
B. Eastern Europe
Explanation:
The economy of Eastern Europe depends on producing foods. For example, Poland and Belarus are two countries in Eastern Europe, and they both produce chocolates. Producing foods isn't the only detrimental part of the region's economic data. The other half depends on consumer goods. For example, Estonia and Latvia are good countries in packaging food. The answer to the question is B.
Select the TRUE statements below regarding the coordination compound prepared in lab. Group of answer choices The coordination compound contained a complex ion that was covalently bonded to sulfate. The ligand must have at least one unshared pair of valence electrons in order to covalently bond with transition metal in the coordination compound. Ethanol was used during crystallization of the coordination compound because the compound is soluble in ethanol. The ammonia is covalently bonded to the transition metal. The colors of many coordination compounds are the result of light absorption by the d electrons on the transition metal.
Answer: Hello the compound is missing but I was able to get the Full question and missing compound . ( compound = copper sulfate )
answer : statement ; 2 , 3 and 5
Explanation:
The true statements regarding the coordination compound ( copper sulfate ) are :
The ligand must have at least one unshared pair of valence electrons in order to covalently bond with transition metal in the coordination compound ( statement 2 )Ethanol was used during crystallization of the coordination compound because the compound is soluble in ethanol ( statement 3 ) The colors of many coordination compounds are the result of light absorption by the d electrons on the transition metal ( statement 5 )During the coordination of compounds dative bonds exits between the transition metals and the Ligands molecules
Determine the number of moles of CH3Br in 47.5 grams of CH3Br?
Show Work please - NO LINKS
Answer:
0.500 moles
Explanation:
In order to convert grams of any given substance into moles, we need the substance's molar mass:
Molar Mass of CH₃Br = Molar Mass of C + (Molar Mass of H)*3 + Molar Mass of BrWe can find the molar masses of each element in the periodic table:
Molar Mass of CH₃Br = 94.94 g/molNow we can divide the given mass by the molar mass in order to calculate the number of moles:
47.5 g ÷ 94.94 g/mol = 0.500 molesplease help i don’t know this:(
Answer:
29.5 days
Explanation:
orginally 27.3 days but 29.5 days is also correct
When H2(g) reacts with F2(g) to form HF(g) , 542 kJ of energy are evolved for each mole of H2(g) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.
Answer:
H₂(g) + F₂(g) ⇒ 2 HF(g) ΔH°rxn = -542 kJ
Explanation:
Let's consider the unbalanced equation that occcurs when H₂(g) reacts with F₂(g) to form HF(g).
H₂(g) + F₂(g) ⇒ HF(g)
In order to get the balanced equation, we will multiply HF(g) by 2.
H₂(g) + F₂(g) ⇒ 2 HF(g)
To convert a balanced equation into a thermochemical equation, we need to add the standard enthaply of the reaction, considering that 542 kJ of energy are evolved for each mole of H₂(g) and there is 1 mole of H₂(g) in the balanced equation. By convention, when energy is released, it takes a negative sign. The thermochemical equation is:
H₂(g) + F₂(g) ⇒ 2 HF(g) ΔH°rxn = -542 kJ
how a scientist might use a graph of the
relationship between population growth and time to identify
a trend
PLEASE HURRY!!!
It took Mrs. Murphy 5.5 hours traveling at a rate of 113 km/hr to finally reach her parents house.
How far did she travel?
Use the crisscross method to find the chemical formula for the ionic compound formed by aluminum (Al) and sulfur (S). A. Al₂S2 B. AlzS3 C. Al3S2 D. Als
Answer:Al2s3
Explanation:
Just took quiz
What is the best way to reduce water pollution
Answer: Pick up litter and throw it away in a garbage can.
Blow or sweep fertilizer back onto the grass if it gets onto paved areas. ...
Mulch or compost grass or yard waste. ...
Wash your car or outdoor equipment where it can flow to a gravel or grassed area instead of a street.
Don't pour your motor oil down the storm drain.
HOPE THIS HELPS
4NH3 + 502 - 6H20 + 4NO
How many grams of O2 are required to produce 0.3 mol of H20?
4NH3 + 5O2 --> 6H2O + 4NO
How mant grams of NO are produced from 1.55 mol of NH3?
4NH3 + 5O2 --> 6H2O + 4NO
How many grams of NO is produced if 12g of 02 is combined with ammonia?
Explanation:
4NH3 + 502 - 6H20 + 4NO
How many grams of O2 are required to produce 0.3 mol of H20?
4NH3 + 5O2 --> 6H2O + 4NO
How mant grams of NO are produced from 1.55 mol of NH3?
4NH3 + 5O2 --> 6H2O + 4NO
How many grams of NO is produced if 12g of 02 is combined with ammonia?
If 6.75 g of NaOH are dissolved in 50.00 g of water and the temperature increases
from 20.5°C to 47.8 °C.
a. Is this an example of an endothermic or exothermic reaction?
b. What is the q for the reaction? (Remember since the NaOH dissolves in water add the
masses to get the m)
C. How many moles of NaOH are dissolved?
d. What is the AH for the reaction?
Answer: THE STANDARD HEAT OF SOLUTION OF SODIUM HYDROXIDE IN WATER IS -7.68 KJ PER MOLE.
