How many liters of hydrogen can be produced at a pressure of 2 atm and a temperature of 298 K?

How Many Liters Of Hydrogen Can Be Produced At A Pressure Of 2 Atm And A Temperature Of 298 K?

Answers

Answer 1

Answer: A volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.

Explanation:

Given: Mass of Mg = 2.3 g

Pressure = 2 atm

Temperature = 298 K

The reaction equation is as follows.

[tex]Mg + 2HCl \rightarrow MgCl_{2} + H_{2}[/tex]

This shows that 1 mole of Mg gives 1 mole of [tex]H_{2}[/tex].

Hence, moles of Mg for the given mass is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{2.3 g}{24.30 g/mol}\\= 0.095 mol[/tex]

Hence, 0.095 moles of Mg will give 0.095 moles of [tex]H_{2}[/tex].

Formula used to calculate volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into the above formula as follows.

[tex]PV = nRT\\2 atm \times V = 0.095 mol \times 0.0821 L atm/mol K \times 298 K\\V = \frac{0.095 mol \times 0.0821 L atm/mol K \times 298 K}{2 atm}\\= 1.16 L[/tex]

Thus, we can conclude that a volume of 1.16 L hydrogen is produced at a pressure of 2 atm and a temperature of 298 K.


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1) O - 88.10/16,      H - 11.190/1

  O - 5.5,               H - 11.19

  O - 5.5/5.5,        H - 11.19/5.5

  O -  1,                 H - 2

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2) C - 41.368/12  H - 8.101/1,   N - 32.162/14,   O - 18.369/16

   C - 3,               H - 8,           N - 2,                  O - 1

   C - 3/1,            H - 8/1          N - 2/1                 O - 1/1

    C - 3,             H - 8,           N - 2,                   O - 1

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To obtain the molecular formula where n = number of atoms of each element;

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[ 3(12) + 8(1) + 2(14) + 16]n = 174

n= 174/88

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[C3H8N2O]2

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    C - 2,                H - 7,            N -  3,                 O - 2

    C - 2/2,            H - 7/2,         N -   3/2,             O - 2/2

    C - 1,                H - 4,            N -  2,                  O - 1

Empirical formula - CH4N2O

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Answer:

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Answer:

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Answers

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Answers

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Answers

Answer:

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Answers

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