Chemistry High School

how much heat is required to increase the temperature of 20 grams of water by 26 degrees celsius?

Answers

Answer 1

Answer: 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.

Explanation:

Given: Mass = 20 g

Change in temperature = [tex]26^{o}C[/tex]

The standard value of specific heat of water is [tex]4.184 J/ g^{o}C[/tex]

Formula used to calculate the heat energy is as follows.

[tex]q = m \times C \times \Delta T[/tex]

where,

q = heat energy

m = mass of substance

C = specific heat of substance

[tex]\Delta T[/tex] = change in temperature

Substitute the values into above formula as follows.

[tex]q = m \times C \times \Delta T\\= 20 g \times 4.184 J/g ^{o}C \times 26^{o}C\\= 2175.68 J[/tex]

Thus, we can conclude that 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.

Related Questions

i hate chemistry but someone help please, no links or you’ll be reported

Answers

Answer:

A, D, E

Explanation:

A greater force is required to move an object with a larger mass than one with a smaller
mass.

Answers

Answer:

Explanation:

what do u need to know

The greater the force that is applied to an object of a given mass, the more the object will accelerate. The greater the mass of an object, the less it will accelerate when a given force is applied. For example, doubling the mass of an object results in only half as much acceleration for the same amount of force. Hope this helps!

Si la masa de una muestra de un compuesto Y es de 196 gramos y contiene 2 mol, la masa molar de Y es

Answers

Answer:

98 g/mol

Explanation:

La masa molar de un compuesto es la cantidad de materia (medida como masa) que hay en 1 mol de dicho compuesto. Por lo tanto, puede calcularse como sigue:

masa molar = masa/número moles

Tenemos los siguientes datos del compuesto Y:

masa Y = 196 g

número de moles de Y = 2 mol

Entonces, podemos calcular la masa molar de Y de la siguiente manera:

masa molar Y = (masa Y)/(número de moles de Y) = 196 g/2 mol = 98 g/mol

What is a precipitation
reaction?

Answers

Answer:

A precipitation reaction is one in which substances in solution are mixed and an insoluble product is made. The insoluble product is called a precipitate and can be seen as a solid forming in the reaction mixture.

HELP!!! WILL MARK BRAINLIEST!!!
picture attached below

Answers

Answer:

0.2 cm

Explanation:

looking at the ruler, you can see that the diameter is 0.4 cm. to get the radius, just divide by two, which gets 0.2 cm as the radius

In order to expand agriculture and urban areas to meet increased demand for growing populations, water supplies often have to be diverted. In three to five sentences, construct a potential chain of consequences for what could happen when water is diverted from large bodies like lakes and rivers

Answers

Answer:

Decrease occur in the amount and flow of water bodies.

Explanation:

There is decrease in the amount and flow of water from water bodies such as rivers and lakes etc occur when the river is diverted from large water bodies because the water flows to the diverted sides and decrease occurs in the amount of water in the rivers and lakes. Those regions from where this river passes can also be negatively affected due to low amount of water they receives for their daily needs or for cultivation of crops so we can say that this diversion has adverse effect on other populations.

Ca(NO3)2 wht is the mass

Answers

Answer:

164.088 g/mol

Explanation: hope this helps

Answer:

Calcium nitrate

Explanation:

164.088 g/mol

give me the brainliest plss

which of the following is true about these diagrams

Answers

Answer:

N/A NO DIAGRAM

Explanation:

N/A NO DIAGRAM

N/A NO DIAGRAM N/A NO DIAGRAM

N/A NO DIAGRAM

N/A NO DIAGRAM N/A NO DIAGRAM

N/A NO DIAGRAM

How much water should be added to 5.00 g of KCl to prepare a 0.500 m
solution? *
Molality = moles of solute
Kg of solvent
100 g
38g
500 g
134 g
Other

Answers

Answer:133.4

Explanation: Explanation:

Molarity is number of moles of solute divided by number of litres of solution.

Rearrange for V to give

Number of moles of KCl is the mass divided by the molar mass of KCl which is 75.5 g/mol, so (5/75.5) = 0.0667 moles.

Now plug in the numbers:

0.0667

0.5

0.1334

litres

So you need to add 0.1334 litres of 133.4

of water.

(NB: symbol for molarity is upper case M. m is metres).

what is the physical change of a liquid to a solid by the removal of heat?

Answers

The addition or removal of heat can cause phase transition like freezing water to ice or melting ice to water or the operation water to vapor condensation vapor to water simulation ice to vapor and the depsition vapor to ice

Which statement explains why carbon-14 dating cannot be used to date ancient rocks?
O Carbon-14 decays at a varying rate.
O Carbon-14 decays quickly leaving the amount too small to measure.
O Carbon-14 can be used only to date the remains of organisms.
O Carbon-14 has a half-life that is much longer than potassium.

Answers

Answer: Carbon-14 decays quickly leaving the amount too small to measure.

Explanation:

Answer:

Explanation:

i did it

Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con 1 g de H2O.

Answers

Answer:

0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

[tex]Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3[/tex]

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

[tex]2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3[/tex]

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

How many grams of oxygen are present in 10g of H2 SO4?

Answers

H2SO4 molecular weight is 98g/mol.

out of 98g 64g is due to oxygen

one mole of oxygen is 32g

Then 2moles of oxygen in H2SO4.

If you want to know the mass percent of a substance in a compound.

Simple formula:

Mass percent=Mass of the substance×100/Total mass of the compound

Ex:

Mass percent of oxygen in H2SO4=mass of the oxygen ×100/Total mass of the H2SO4

(i.e 16×4×100/98=65.3061%)

Here oxygen mass is multipled by 4 because there are 4 Oxygen atoms in H2SO4.

*
14. An AREA which drains into a common river system.
watershed
tributary
drainage divide
riparian zone

Answers

Watershed
A watershed is an entire river system of an area drained by a river and its tributaries

What is the purpose of a buffer?

Answers

The main purpose of a buffer solution is just to resist the change in pH so that the pH of the solution won't be much affected when we add an acid or base into it. The added acid or base is neutralized.

Answer: A buffer solution is a solution made to prevent the pH level of something from changing when you add a base or an acid to it. For example, if you put a buffer solution in a pool, and then you put chlorine in it, the chlorine's effect on the PH level will be suppressed.

9.49.8 grams of Kl is dissolved in 1.00 kg of solvent. What is the molality?

Answers

Answer:

Molality = 9.498 mol k g − 1

Explanation:

A final way to express the concentration of a solution is by its molality. The molality ( m ) of a solution is the moles of solute divided by the kilograms of solvent. A solution that contains 1.0 mol of NaCl dissolved into 1.0 kg of water is a “one-molal” solution of sodium chloride.

molality = number of moles of solute/ mass of solvent in kg

number of moles of KI = mass of KI / molar mass of KI

number of moles of KI = 9.49.8 g / 1.00 g m o l − 1

number of moles of KI = 9.498 moles

molality = 9.498 moles / 1kg

molality = 9.498 mol k g − 1

What three temperature measurements Inust you make to calculate the specific heat of a sample using a calorimeter?

Answers

Answer:

Explanation:

Heat and temperature are two different but closely related concepts. Note that they have different units: temperature typically has units of degrees Celsius ( ∘ C ^\circ\text C ∘Cdegrees, start text, C, end text) or Kelvin ( Kstart text, K, end text), and heat has units of energy, Joules ( Jstart text, J, end text).

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O How many moles of oxygen gas (O2) are needed to create EXACTLY 6 moles of Carbon dioxide(CO2)?.

Answers

صاحي يخي ب فاق . فخذ بريعهح زين

Sample A has a mass of 40g and a volume of 10cm^3. Sample B has a volume of 15cm^3 and a mass of 45g. Which sample has a greater density? Show your work.

Answers

The Answer Is Sample A

Density -

[tex]density = \frac{mass}{volume} [/tex]

Input The Formula For Both Equations To Find Density.

Sample A -

[tex]d = \frac{40}{10} [/tex]

[tex]d = 4[/tex]

Sample B -

[tex]d = \frac{45}{15} [/tex]

[tex]d = 3[/tex]

Which two moon phases can occur while the
relative positions of the sun, Earth, and moon
form a straight line?

Answers

Answer:

its the lunar and solar eclipse

Explanation:

the solar eclipse happens when the moon is in between the sun and earth

If 4.04g of h2 gas react with oxygen gas to create 36.36g of water, how many grams of oxygen reacted?

Answers

Answer:

gO₂ = 32.32 g

Explanation:

In this case, let's write the general equation:

2H₂ + O₂ -------> 2H₂O

In this case, we can use the 1° law, which is mass conservation. If the product has 36.36 g of water, then in the reactants we should have the same 36.36 g.

According to this, we already have 4.04 of hydrogen, then the remaining to reach the 36.36 g would be:

gO₂ = 36.36 - 4.04

gO₂ = 32.32 g

Hope this helps

Consider the following balanced equation:
3 H2 + N2 --> 2 NH3
What volume of hydrogen gas will react in a perfect ratio
with 3 liters of nitrogen gas?

Answers

Answer:

[tex]from \: avogadros \: hypothesis \\ 1 \: mole \: of \: nitrogen \: reacts \: with \: 3 \: moles \: of \: hydrogen \\ 3 \: litres \: of \: nitrogen \: react \: with \: ( \frac{3 \times 3}{1} ) \\ 9 \: litres \: of \: hydrogen[/tex]

Please answer all of the examples below!

Answers

Answer:

The first one is balanced. The second one is not.

Explanation:

The first one is balanced because there are the same amount of elements on the reactant side as there are on the product side. The second one is not balanced because there are not the same amount of elements on the reactant side as there are on the product side. Therefore, it is not balanced

More Detailed: first example

Reactant side (left of arrow)

H: 2

C: 1

O: 3

Product side (right of arrow)

H: 2

C: 1

O: 3

More detailed: second example

Reactant side:

Na: 1

O: 1

H: 1

C: 1

Product side:

Na: 2

O: 4

H: 2

C: 1

the variables needed to balance this equation is 2,1, 1, 1.

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