How much money will there be in an account at the end of 10 years if $4000 is deposited at 6% compounded quarterly

Answer:

1.328

Step-by-step explanation:

Given :

Sample size, n = 20.

Degree of freedom, df = n - 1

df = 20 - 1 = 19

α = 0.2

Using the T-distribution calculator :

Since it is two - tailed:

Tα/2 ; 19 = T0.2/2 ; 19 = T0.1, 19 = 1.3277 = 1.328

Using a t-distribution calculator, it is found that the t-value is of t = 1.328.

In a calculator, these following inputs are needed:

In this problem, inputting the data given in a calculator, it is found that the t-value is of t = 1.328.

More can be learned about the t-distribution at https://brainly.com/question/13873630

Answer:

The endpoints of the latus rectum are [tex](12, -7)[/tex] and [tex](-8, -7)[/tex].

Step-by-step explanation:

A parabola with vertex at point [tex]C(x, y) = (h,k)[/tex] and whose axis of symmetry is parallel to the y-axis is defined by the following formula:

[tex](x-h)^{2} = 4\cdot p \cdot (y-k)[/tex] (1)

Where:

[tex]y[/tex] - Independent variable.

[tex]x[/tex] - Dependent variable.

[tex]p[/tex] - Distance from vertex to the focus.

[tex]h[/tex], [tex]k[/tex] - Coordinates of the vertex.

The coordinates of the focus are represented by:

[tex]F(x,y) = (h, k+p)[/tex] (2)

The latus rectum is a line segment parallel to the x-axis which contains the focus. If we know that [tex]h = 2[/tex], [tex]k = -2[/tex] and [tex]p = -5[/tex], then the latus rectum is between the following endpoints:

By (2):

[tex]F(x,y) = (2, -2-5)[/tex]

[tex]F(x,y) = (2,-7)[/tex]

By (1):

[tex](x-2)^{2} = -20\cdot (-7+2)[/tex]

[tex](x-2)^{2} = 100[/tex]

[tex]x - 2 = \pm 10[/tex]

There are two solutions:

[tex]x_{1} = 2 + 10[/tex]

[tex]x_{1} = 12[/tex]

[tex]x_{2} = 2-10[/tex]

[tex]x_{2} = -8[/tex]

Hence, the endpoints of the latus rectum are [tex](12, -7)[/tex] and [tex](-8, -7)[/tex].

Answer:

Option C

Step-by-step explanation:

Step 1:  Find the correct method

Option A is incorrect because we don't have m + 6 and 5m - 2

Option B is incorrect because that wouldn't show us the correct value

Option C is correct, once we solve for v, we can plug in v and get the value of m.  For example:  v + 6 = 5v - 2 → v + 8 = 5v → 8 = 4v → 2 = v.  Then we plug it into the other equation m = 2 + 6 → m = 8

Option D is incorrect because that wouldn't show us the correct value.

Answer: Option C

Answer:

not enough information

Step-by-step explanation:

jill could have 2*2*2*2*2*2

and Jamal 113*113*113

but if Jill's number is made from all high primes and Jamals from low ones, it's vice versa

Answer:

In 2025, t=30. so D=418*30+6000 = 18540

Answer:

B

Step-by-step explanation:

In a triangle, the sum of any two sides must be bigger than the third.

For the first one, 10+20=30 is not greater than 30, so this is not correct.

For B, 122+137 = 259 > 257, 257+137>122  , and 257 + 122 > 137. This works

For C, 8.6 + 2.7 = 11.3 < 12.2, so this does not work

For D, 1/6 + 1/5 = 5/(6*5) + 6/(6*5) = 5/30 + 6/30 = 11/30 < 1/2 = 15/30, so this does not work

Answer:

[tex]\frac{2}{5}^{-3}[/tex]×[tex]x=\frac{1}{2}^{4}[/tex]

[tex]x=\frac{2}{5} ^{3} \\[/tex]×[tex]\frac{1}{2}^{4}[/tex]

(negative in the exponent means reciprocal of the fraction)

x= [tex]\frac{1}{250}[/tex]

Brainliest please

[tex] \frac{dw}{dt} = \frac{dx}{dt} \times \frac{dw}{dx} + \frac{dy}{dt} \times \frac{dw}{dy} + \frac{dz}{dt} \times \frac{dw}{dz} \\ \frac{dw}{dt} = 3t ^{2} \times {e}^{ \frac{y}{z} } + - t \times \frac{x {e}^{ \frac{y}{z} } }{z} + 4 \times - \frac{xy {e}^{ \frac{y}{z} } }{ {z}^{2} } \\ \frac{dw}{dt} = \frac{ {e}^{ \frac{y}{z} } (3 {t}^{2} {z}^{2} - tzx - 4xy)}{ {z}^{2} } [/tex]

Answer:

1 hr , 18 mins

Step-by-step explanation:

that is the procedure above

Answer:

Hello,

Answer A (-4,0) and (0,0)

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}y&=&x^2+4x\\y+x^2&=&-4x\\\end{array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&x^2+4x\\y&=&-x^2-4x\\\end{array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&x^2+4x\\x^2+4x&=&-x^2-4x\\\end{array} \right.\\\\\\\left\{\begin{array}{ccc}2*x^2+8*x&=&0\\y&=&x^2+4x\\\end{array} \right.\\\\\\\left\{\begin{array}{ccc}x(x+4)&=&0\\y&=&x^2+4x\\\end{array} \right.\\\\\\[/tex]

[tex]\left\{\begin{array}{ccc}x&=&0 \\y&=&0\\\end{array} \right. \ or\ \left\{\begin{array}{ccc}x&=&-4 \\y&=&0\\\end{array} \right.[/tex]

Step-by-step explanation:

Ten pairs of points yielded a correlation coefficient r of 0.790. If a =0.05, which of the following statements is correct if H.: P = 0? (Do not calculate a t-value.) A) Because 0.790 is greater than 0.632, the nullliy pothesis is not rejected. Because 0.790 is greater than 0.602, che null hypothesis is not rejected. Because 0.790 is greater than 0.632, che null hypothesis is rejected. OD) There is no correlation between the variables

9514 1404 393

Answer:

  f(x) = 3

Step-by-step explanation:

Replace sin(x) with 0 and you will have it.

  f(x) = 12·0 +3

  f(x) = 3

Answer:

y= 3

Step-by-step explanation:

I took the test

Answer:

x=2    x=-1

Step-by-step explanation:

f(x) = x^2 - X - 2

0= x^2 -x-2

Factor

0 =(x-2)(x+1)

Using the zero product property

x-2 =0   x+1 =0

x=2    x=-1

Answer:

x=2, -1

Step-by-step explanation:

Hi there!

We want to find the zeros of this function: f(x)=x²-x-2

The zeros are the values of x that will make f(x)=0

So that means in order to find the zeros, set f(x) as 0

In that case,

x²-x-2=0

Now let's solve the quadratic equation

We can do it by factoring

-x is the sum of two numbers, while -2 is the product of those two same numbers

Now think: which two numbers add up to -1, but multiply to get -2?

Those numbers are -2 and 1

Now factor the polynomial by FOIL:

(x-2)(x+1)=0

Split and solve

x-2=0

x=2

x+1=0

x=-1

The zeros are x=2, -1

Hope this helps!

Answer:

B. 11.5

Step-by-step explanation:

That missing length can be solved via the equation a^2+b^2=c^2, where the hypotenuse is c. We know A and B, which is 7 and 9.

7^2+9^2=130

sqrt 130 is 11.4017543

Here, you kinda have to break the rules of rounding to say that it is B.

There could be a more efficient route for resolving this answer, but this is the method that I was taught.

The segment XT splits the trapezoid exactly in half. The average of RS and Q will give us XT because of the properties of a trapezoid.

We find the area of a trapezoid by averaging the bases as well.

RS + Q / 2 = XT

RS + 26 / 2 = 22

RS + 26 = 44

RS = 18

Hope this helps!

Answer:

5 ft

Step-by-step explanation:

The formula for Volume is V=lwh, or Volume = length x width x height.

The equation would be:

[tex]180=l(4)(9)[/tex]

or

[tex]180=36l[/tex]

To find the answer, divide by 36.

[tex]\frac{180}{36} =\frac{36l}{36}[/tex]

[tex]5=l[/tex]

Answer:The first would taste more like oranges

Step-by-step explanation:

That's a question about exponentiation.

Answer:

Kenji is wrong because he does not aply the porperty correctly.

Step-by-step explanation:

A exponetiation has this form:

[tex]\boxed{a^b}[/tex]

a is the base

b is the power or exponent

To understand that situation it's important to know a property about exponentiation. When we have a multiplication with the same exponent and diferent bases, the result is the multiplication of the bases with the same exponent. Let's see this above, in mathematical language:

[tex]\boxed{a^b \cdot c^b = (a\cdot c) ^b}[/tex]

Examples:

Now, we can say why Kenji is wrong. It's easy simplify [tex]3^5 \cdot 4^5[/tex]! We know that the result is [tex](3 \cdot 4) ^5 = 12^5[/tex], but Kenji multiplied the bases and added the exponents, that's why he is wrong.

I hope I've helped. ^^

Enjoy your studies! \o/

2 Answers:

z = 1 + i   and   z = -1 - i

========================================================

Explanation:

We want z to be a complex number in the form z = a+bi, where a,b are real numbers and [tex]i = \sqrt{-1}[/tex] is imaginary.

Let's plug that into the equation your teacher gave you

[tex]z^2 = 2i\\\\(a+bi)^2 = 2i\\\\(a+bi)(a+bi) = 2i\\\\a(a+bi)+bi(a+bi) = 2i\\\\a^2+abi+abi+b^2*i^2 = 2i\\\\a^2+2abi+b^2*(-1) = 2i\\\\a^2+2abi-b^2 = 2i\\\\(a^2-b^2)+2abi = 0+2i\\\\[/tex]

You could use the FOIL rule to take a shortcut. I'm deciding to be a bit more wordy to show a further breakdown how everything is multiplying out.

Notice that the real part a^2-b^2 must be 0 so that it matches the real part on the right hand side.

a^2-b^2 = 0

(a-b)(a+b) = 0 .... difference of squares rule

a-b = 0 or a+b = 0

a = b or a = -b

So whatever solution z = a+bi is, it must have either a = b or a = -b.

--------------------------------

If a = b, then the 2abi portion on the left side turns into 2a^2*i

Set this equal to 2i on the right hand side and isolate 'a'

[tex]2a^2*i = 2i\\\\2a^2 = 2\\\\a^2 = 1\\\\a = 1 \text{ or } a = -1\\\\[/tex]

So a = 1 leads to b = 1

Or a = -1 leads to b = -1

Two complex solutions so far are:   z = 1 + i   and   z = -1 - i  based on those two cases above.

--------------------------------

Now consider the case that a = -b

We'll effectively have the same steps as the previous section, but the equation to solve now is [tex]-2a^2*i = 2i\\\\[/tex]

The only difference is that negative is out front. You should find that it leads to a^2 = -1, but this has no solutions because we stated earlier that a,b were real numbers.

So if a = -b, then it concludes with a,b being nonreal numbers. Ultimately we rule out the case that a = -b is possible.

Put another way, note how -2a^2 is always negative which clashes with the idea that the right hand side is positive (ignore the 'i' portions). This contradiction means that no real values of 'a' will make the equation [tex]-2a^2*i = 2i\\\\[/tex] to be true.

--------------------------------

To wrap things up, we only have two solutions and they are  

z = 1 + i   and   z = -1 - i

You can use a tool like WolframAlpha to confirm this.

Answer: x = 2

Step-by-step explanation:

P-----------------------T----------------------Q

         (3x-3)                   (5x-7)

Since T is the midpoint we know that PT and TQ are equal

Just solve the equation: 3x-3 = 5x-7

[tex]3x-3 = 5x-7[/tex]

now move the x to one side

[tex]-3 = 2x-7[/tex] (I subtracted the 3x)

then get the 2x by itself

[tex]4=2x[/tex]

lastly, divide by 2 to get x by itself

[tex]x=2\\[/tex]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that [tex]p = 0.16[/tex]

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136 [/tex]

0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

[tex]E = \frac{n}{p}[/tex]

In this question, [tex]n = 1, p = 0.16[/tex]. So

[tex]E = \frac{1}{0.16} = 6.25[/tex]

The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

Recall that [tex]\log 10 = 1[/tex] so we can rewrite the equation above as

[tex]\log 10 + \log 2 = \log (x + 1)[/tex]

Also recall that [tex]\log(ab) = \log a + \log b[/tex] so the left-hand side becomes

[tex]\log [(10)(2)] = \log (x + 1)[/tex]

or

[tex]20 = x + 1 \Rightarrow x = 19[/tex]

Answer:

The point at the bottom has to move over 2 to the left to be aligned with the point at the top however they will have a 3 space in between the 2 same for the point at the top, the top point moves over 2 to the right to be aligned with the bottom point, then they will have a 3 square space between each other.

Answer:Around 3 spaces between?

Step-by-step explanation:

Answer:

The second car traveled 280 miles farther than the first car.

Step-by-step explanation:

Car A: 50 mi/1 hr for 4 hrs

Car B: 60 mi/1 hr for 8 hrs

Solve for Car A:

50 mi/1 hr × 4 hrs

50 × 4

200 miles

Solve for Car B:

60 mi/1 hr × 8 hrs

60 × 8

480 miles

Find the difference between Car A and Car B:

480 miles - 200 miles

280 miles

Answer:

a. 0.042 = 4.2% probability that the chosen applicants are either all managers or all engineers.

b. 0.2398 = 23.98% probability that the number of managers is the same as the number of engineers on the task force.

c. The expected number of engineers chosen is 4.

d. 0.958 = 95.8% probability that at least one manager is chosen for the task force.

Step-by-step explanation:

The positions are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

5 + 10 = 15 applicants, which means that [tex]N = 15[/tex]

10 are engineers, which means that [tex]k = 10[/tex]

Six members are chosen, which means that [tex]k = 6[/tex]

a. What is the probability that the chosen applicants are either all managers or all engineers?

Not possible having all managers(five applicants are manager, while there are 6 open positions), so this is P(X = 6), that is, all engineers.

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 6) = h(6,15,6,10) = \frac{C_{10,6}*C_{5,0}}{C_{15,6}} = 0.042[/tex]

0.042 = 4.2% probability that the chosen applicants are either all managers or all engineers.

b. What is the probability that the number of managers is the same as the number of engineers on the task force?

3 engineers, so this is P(X = 3).

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 3) = h(3,15,6,10) = \frac{C_{10,3}*C_{5,3}}{C_{15,6}} = 0.2398[/tex]

0.2398 = 23.98% probability that the number of managers is the same as the number of engineers on the task force.

c. What is the expected number of engineers chosen?

The expected value of the hypergeometric distribution is:

[tex]E(X) = \frac{nk}{N}[/tex]

So

[tex]E(X) = \frac{6(10)}{15} = 4[/tex]

The expected number of engineers chosen is 4.

d. What is the probability that at least one manager is chosen for the task force?

At most five engineers, which is:

[tex]P(X \leq 5) = 1 - P(X = 6)[/tex]

Since in item a. we already have P(X = 6).

[tex]P(X \leq 5) = 1 - 0.042 = 0.958[/tex]

0.958 = 95.8% probability that at least one manager is chosen for the task force.

Answer:

The population is the population of 3521 people who made credit card purchases.

The sample is the 172 people who returned the survey form.

Step-by-step explanation:

Department mails customers satisfactions forms to those who make credit cards purchase at the store, totaling 3521 people. Thus, the population is the population of 3521 people who made credit card purchases.

Surveys are mailed to 278 of these people, chosen at random, and 172 people return the survey form.

Thus the sample, that is, those from whom the data will be taken and expanded to the rest of the population, is the 172 people who returned the survey form.

The population is all 3521 people who made credit card purchases.

The sample is the 172 people who returned the survey form.

The question is incomplete. The complete question is :

An automobile assembly line operation has a scheduled mean completion time, μ, of 15.5 minutes. The standard deviation of completion times is 1.7 minutes. It is claimed that, under new management, the mean completion time has decreased. To test this claim, a random sample of 90 completion times under new management was taken. The sample had a mean of 15.4 minutes. Can we support, at the 0.1 level of significance, the claim that the mean completion time has decreased under new management?

Solution :

The given data :

n = 90

μ = 15.5

σ = 1.7

[tex]$\overline x$[/tex] = 15.4

So, the null hypothesis is : [tex]$H_0: \mu = 15.5$[/tex] is been tested against

Alternate hypothesis : [tex]$H_1 : \mu < 15.5 $[/tex]   (one-tailed test)

Since, the sample size is sufficiently large and the sample deviation is known, we use the Z-test.

Under this test, the test statistic is given as :

[tex]$Z=\frac{\overline x - \mu}{\sigma/\sqrt{n}} \sim N(0,1)$[/tex]

Under [tex]H_0[/tex], we have

[tex]$Z_0=\frac{\overline x - \mu}{\sigma/\sqrt{n}} $[/tex]

[tex]$Z_0=\frac{15.4-15.5}{1.7/\sqrt{90}} $[/tex]

[tex]$Z_0=-0.56$[/tex]

The critical value for the test is [tex]$Z_{\alpha} = Z_{0.1} = -1.28$[/tex]

We observe that (-0.56 > -1.28), and so we fail to reject the null hypothesis.

No, there is no evidence to support the claim that the mean completion time has decreased.

Thus, we conclude that the mean completion time is 15.5 minutes.

Answer:

u still doing school :)

Step-by-step explanation: