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WHAT IS THE OXIDATION NUMBER OF SULFUR IN THE S2O8 ION?
Answer: The Oxidation State Of Sulphur is +6
Explanation:
Question 8 of 10
Which of the following diagrams is the correct electron dot diagram for Al?
O A.
OB.
О с.
O D.
..
•Al:
:AI:
•AI.
:AI.
Please help I need it asap!!!
Answer:
The correct electron dot diagram for Al is option A:
•Al:
:AI:
Explanation:
what is the formula for co3+ and se2-?
The formula for Co3+ is Co3+ because it represents the ion of cobalt that has lost three electrons, leaving it with a 3+ charge.
What is chemical formula and how they are formed ?
A chemical formula is a symbolic representation of a chemical compound that shows the types of elements present in the compound and the relative number of atoms of each element. For example, the chemical formula for water is H2O, which indicates that it is made up of two hydrogen atoms and one oxygen atom.
Chemical formulas are formed by identifying the elements that make up a compound and determining the relative number of each element in the compound. The number of each element is represented by a subscript following the chemical symbol of the element. For example, the chemical formula for methane is CH4, which indicates that there is one carbon atom and four hydrogen atoms in each molecule of methane.
The formula for Se2- is Se2- because it represents the ion of selenium that has gained two electrons, giving it a 2- charge.
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Seventy five percent of a compound is carbon. If you have 250 grams of this particular compound, how much carbon is contained?
Answer:
The compound has 187.5 g. of Carbon
Explanation:
If the 100% of the compound is 250 gr, then you can calculate the 75% of it by multiplying:
Amount of Carbon = (75%) 250 g.
75%= 0.75
250 (0.75)
= 187.5 g.
A student sets up a titration with a * 1 point buret filled with 0.5 M NaOH. In the flask below they place the phenolphthalein indicator and 6.2 mL of the unknown acid. The solution in the beaker turns pink after exactly 24.8 mL of NaOH have been added. The student repeats this experiment but this time they do it with a buret filled with 1.0 M NaOH which is more concentrated than the original experiment. Would the solution in the test tube turn pink sooner, later, or around the same amount of added NaOH?
Answer:
The solution in the test tube would turn pink earlier with the more concentrated NaOH solution.
This is because the concentration of the NaOH solution is directly proportional to the number of moles of NaOH per unit volume of the solution.
So, with a more concentrated NaOH solution (1.0 M compared to 0.5 M), each mL of NaOH solution contains twice as many moles of NaOH.
Therefore, it would take half as much volume (i.e., 12.4 mL instead of 24.8 mL) of the 1.0 M NaOH solution to react with the same number of moles of the unknown acid as the 0.5 M NaOH solution.
Calculate the hydronium ion concentration, [H3O+], for a solution with a pH of 6.82.
[H₂0¹] =
M
The hydronium ion concentration, [H+] of a solution with a pH of 6.82 is 1.51 × 10-⁷ M.
How to calculate hydrogen ion concentration?The hydrogen or hydronium ion concentration of a solution can be calculated from the pH using the following formula;
pH = - log {H+}
[H+] = 10−pH
by exponentiating both sides with base 10, we can "undo" the common logarithm.
{H+} = 10-⁶.⁸²
{H+} = 0.000000151356
[H+] = 1.51 × 10-⁷ M
Therefore, the hydronium ion concentration with a pH of 6.82 is 1.51 × 10-⁷ M.
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is CF3Cl a polar or non-polar molecule?
Answer: Polar
Explanation: This is because if you look up the Lewis Dot structure of this specific molecule, it will have some net dipole moment, which makes it polar.
It can be considered that when a molecule does have some net dipole moment, it is polar.
So, yes CF3Cl is polar.
CF₃Cl, also known as chlorotrifluoromethane, is a polar molecule.
To determine the polarity of a molecule, consider the individual bond polarities and the molecular geometry.
In CF₃Cl, there is a difference in electronegativity between carbon (C) and chlorine (Cl), as well as between carbon and fluorine (F). Chlorine and fluorine are more electronegative than carbon, meaning they have a greater ability to attract electrons toward themselves.
The C-Cl bond and the C-F bonds in CF₃Cl are polar bonds due to the electronegativity difference. The Cl and F atoms pull the shared electrons towards themselves, creating partial negative charges on those atoms and partial positive charges on the carbon atom.
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Which of the following molecules is drawn in a conformation that has a proton and a leaving group anti-periplanar? H₂C, Br Ph. H CH3 Br H H₂C Br H₂C Ph H₂C CH3 H Ph H₂C, Br H Ph Save for Later CH3 CH3 CH3 CH3 CH3 Sul
The molecule that is drawn in a conformation that has a proton and a leaving group anti-periplanar is H₂C, Br.
The A, B, C, and D bond angles of a molecule are referred to as anti-periplanar, or antiperiplanar, in organic chemistry. The dihedral angles of the A–B and C–D bonds in this conformer are larger than +150° or less than 150°. In textbooks, the term "anti-periplanar" is frequently used to refer to a strictly anti-coplanar structure with a 180° AB CD dihedral angle. The anti-periplanar functional groups will be 180° apart from one another and in a staggered configuration in a Newman projection of the molecule.
Conformation is an essential factor in predicting reactivity in organic molecules. The anti-periplanar conformation of a molecule is one that occurs when two atoms in a molecule are in the same plane and are separated by 180 degrees. In this case, the proton and leaving group are placed in a perpendicular plane to the atoms directly in between them. This is the most stable conformer of the molecule. A significant factor in predicting reactivity in organic molecules is conformation. In this case, the molecule H₂C, Br is drawn in a conformation that has a proton and a leaving group anti-periplanar.
Therefore, the correct option is H₂C, Br.
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A chemist must dilute 93.1 mL of 7.79 of uM aqueous mercury (I) chloride solution until the concentration falls to 3.00 uM. She’ll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate the final volume in liters.
Taking into account the definition of dilution, if chemist must dilute 93.1 mL of 7.79 of uM aqueous mercury (I) chloride solution until the concentration falls to 3.00 uM, the final volume is 0.24175 L.
Definition of dilutionDilution is a procedure by which the concentration of a solution is lowered, usually with the addition of a diluent.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeFinal volumeIn this case, you know:
Ci= 7.79 uMVi= 93.1 mLCf= 3 uMVf= ?Replacing in the definition of dilution:
7.79 uM× 93.1 mL= 3 uM× Vf
Solving:
(7.79 uM× 93.1 mL)÷ 3 uM= Vf
241.75 mL= 0.24175 L = Vf (being 1000 mL= 1 L)
In summary, the final volume is 0.24175 L.
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Calculate Delta H r* n for Ca(s) + 1/2 * O_{2}(g) + C*O_{2}(g) -> CaC*O_{3}(s)
a. -813.4 kJ. enthalpy of the reaction is -813.4 kJ
One of the characteristics of a thermodynamic system is enthalpy, which is calculated by multiplying the internal energy of the system by the sum of its pressure and volume. The total enthalpy of a system cannot be directly calculated because the internal energy's components are either unknown, hard to access, or unimportant to thermodynamics.The overall reaction can be represented as: [tex]Ca(s) +\frac{ 1}{2}O_2(g) + CO2(g) \rightarrow CaCO_3(s).[/tex]
The reaction enthalpy [tex](\Delta H_{rxn})[/tex]is the result of adding the reaction's separate enthalpies.The enthalpy of each of the individual reactions is given as:
[tex]Ca(s) + \frac{1}{2}0_2(g) \rightarrow Cao(s) \Delta H_{rxn} = -635.1 kJ CaCO_3(s) \rightarrow Cao(s) + CO2(g) \Delta H_{rxn} = 178.3 kJ[/tex]
Therefore, the overall enthalpy change for the reaction is given as:
[tex]\Delta H_{rxn} = \Delta H_{rxn}(Ca(s) +\frac{ 1}{2}0_2(g) \rightarrow Cao(s)) +\Delta H_{rxn} (CaCO_3(s) \rightarrow Cao(s) + CO2(g))[/tex]
[tex]\Delta H_{rxn} = -635.1 kJ + 178.3 kJ \Delta H_{rxn} = -813.4 kJ[/tex]
Therefore,The reaction's enthalpy is -813.4 kJ.
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complete question:Calculate delta Hrxn for Ca(s) + 1/202(g) + CO2(g) => CaCO3(s) given the following set of reactions: Ca(s) + 1/202(g) => Cao(s) delta Hrxn = -635.1 kJ CaCO3(s) => Cao(s) + CO2(g) delta Hrxn = 178.3 kJ a. -813.4 kJ
b. -456.8 kJ
c. 813.4 kJ
d 456.8 kJ
e. None of these is within 5% of the correct answer.
Determine the pressure (in atm) of a 7.16-g sample of He gas at 692 K in a container with a volume of 55.9 L.
Answer:
1.82 atm
Explanation:
Ideal gas law
P=nRT/V
1) solve for n which is moles
7.16 / 4 = 1.79 mole He
2)
n=1.79
R=0.0821
T=692 K
V=55.9
P=1.79 X 0.0821 X 692 / 55.9 =1.82 atm
Choose the correct answer.
The correct reaction equation is; Sr(OH)2 ----> Sr + 2OH
How do you know a correct reaction equation?A correct chemical reaction equation must follow the law of conservation of mass, which states that matter cannot be created or destroyed, only transformed from one form to another. This means that the total number of atoms of each element on the reactant side of the equation must be equal to the total number of atoms of each element on the product side.
To ensure that an equation is correct, you should first check that the chemical formulas of the reactants and products are correct. You can then balance the equation by adjusting the coefficients in front of each chemical formula so that the number of atoms of each element is the same on both sides of the equation.
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add curved arrows to show the mechanism of the propagation steps to form each monochlorination product shown.
To form each of the monochlorination products shown, you will need to draw curved arrows that demonstrate the propagation steps. The first step is when a chlorine radical combines with the double bond to form a chlorine radical cation, which then donates an electron to the double bond.
This results in the formation of two radical chlorides, one on each carbon atom. These radicals then combine with two hydrogen atoms to form the monochlorination product, completing the reaction.The curved arrows for this process should be drawn as follows:
An arrow pointing from the chlorine radical to the double bond, representing the attack of the radical all arrows have been drawn, the monochlorination product has been formed. The mechanism of propagation steps to form each monochlorination product is shown in the following reaction:To represent this reaction, you can draw a curved arrow to show the movement of electrons from the bond to the chlorine. The arrow should start from the carbon-carbon double bond and point towards the chlorine.
Then, another curved arrow can be drawn to represent the formation of the C-Cl bond. The arrow should start from the chlorine and point towards the carbon with the unpaired electron.This process can be repeated to form the second monochlorination product. The following diagram shows the mechanism of the propagation steps:Here, you can see that the curved arrows are used to represent the movement of electrons during the reaction. The arrows point towards the atom that is gaining the electrons.
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which of the following is the correct electron configuration for tc? select the correct answer below: [kr]5s24d5 [kr]4d7 [kr]5s24d2 [kr]5s25d5
The correct electron configuration for Tc (technetium) is [Kr] 5s² 4d⁵. Therefore, the correct answer is: [kr]5s²4d⁵.
What is technetium?Technetium (Tc) is a radioactive chemical substance with the atomic number 43 and symbol Tc. It is a silvery-gray metal that belongs to the transition metals group on the periodic table. Technetium is the first element to be artificially produced, and all of its isotopes are radioactive, with no stable isotopes. It is a highly toxic and dangerous element, and therefore has no significant commercial applications. Technetium has many nuclear and medical applications due to its radioactivity, and is used in medical imaging, cancer treatment, and scientific research.
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Answer:
C
Explanation:
edg 2023
0.10 molL-1 NaCl solution contains 1.0 mole of NaCl
The volume of the 0.10 molL⁻¹ NaCl solution which contains 0.1 mole of sodium chloride, NaCl is 1 L
How do i determine the volume of the solution?Molarity of a solution is defined by the following formula:
Molarity = mole / volume
Cross multiply
Molarity × volume = Mole
Divide both sides by molarity
Volume = mole / molarity
With the above formula, we can obtain the volume of the solution. Details below:
Molarity of solution = 0.10 molL⁻¹Mole of NaCl = 0.1 moleVolume of solution =?Volume = mole / molarity
Volume of solution = 0.1 / 0.1
Volume of solution = 1 L
Thus, we can conclude that the volume of the solution is 1 L
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Complete question:
0.10 molL⁻¹ NaCl solution contains 1.0 mole of NaCl. What is the volume of the solution?
why can't the enthalpy of formation of calcium carbonate be determined directly?
The enthalpy change can not be measured directly because you have to take into account how much energy was put into the reaction in the first place.
Hope this helps!!! :)
The standard enthalpy of formation of all elements in their standard states are assumed to be zero. It is not possible to determine the enthalpy of formation of calcium carbonate as it is formed from other compounds.
What is enthalpy of formation?The standard enthalpy of formation of a compound can be defined as the enthalpy change accompanying the formation of one mole of the compound from its constituent elements, all the substances being in their standard states.
The standard enthalpy of formation is usually denoted as ΔfH⁰. For example the enthalpy of formation of CO₂ and CH₄ are -393.5 kJ mol⁻¹ and -74.8 kJ mol⁻¹ respectively.
Here CaCO₃ is formed by the reaction:
CaO + CO₂ → CaCO₃
The enthalpy change for the given reaction is not an enthalpy of formation of CaCO₃. Since CaCO₃ is not formed from its constituent elements.
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molarity of a solution that contains 29.4 grams of NaCl in 250 ml of water?
Answer:
2.16 M
Explanation:
The molarity of the solution is 2.16 M. To calculate the molarity, you need to first determine the number of moles: 29.4 grams of NaCl is equal to 0.737 moles. Then, divide the number of moles, 0.737, by the volume of the solution, which is 250 mL. Multiplying the result by 1000 gives the molarity, which is 2.16 M.
yw
When a mineral breaks along a weekly bonded plane it is called
Answer: Cleavage
Explanation:
When a mineral breaks along a weekly bonded plane it is called cleavage
Which of the following are volume ratios from this equation? Select all that apply.
2H2 + O2 --> 2H2O
The volume ratios from the equation 2H2 + O2 → 2H2O are:
2 L H2 : 1 L O2 (or 2 mol H2 : 1 mol O2)1 L O2 : 2 L H2O (or 1 mol O2 : 2 mol H2O)The coefficients in a balanced chemical equation give the ratio of moles of reactants and products. From the equation 2H2 + O2 → 2H2O, we can see that:
2 moles of H2 react with 1 mole of O2 to produce 2 moles of H2O.Therefore, the following volume ratios are valid:
2 L H2 : 1 L O21 L O2 : 2 L H2OWhat are the reactants?
The reactants are the substances that participate in a chemical reaction and are consumed to form new products. In the equation 2H2 + O2 → 2H2O, the reactants are hydrogen gas (H2) and oxygen gas (O2). These reactants undergo a chemical reaction to form water (H2O) as the product.
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For the partially completed Lewis structures, pick the correct Lewis structure.
How many Valence Electrons total overall?
The correct Lewis structures of the compounds that we have in the question have been shown in the images attached.
What is the Lewis structure?A Lewis structure is a diagram that shows the bonding between atoms in a molecule and the arrangement of electrons around the atoms. It is also known as a Lewis dot structure, Lewis dot diagram, or electron dot structure.
Lewis structures are useful in predicting the geometry of molecules and determining the polarity of molecules. They are also helpful in understanding the reactivity of molecules and how they interact with other molecules.
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Which of the following groups of substances involve the use of chemicals? Indicate all that apply
All of the groups of substances involve the use of chemicals from the question that we have here.
What are chemicals?Chemicals are essential to life and to many industries, including agriculture, medicine, manufacturing, and technology. They can be found in everyday objects such as food, clothing, electronics, and cleaning products.
Chemicals can be classified into various categories based on their properties, chemical structure, and uses. Some common categories of chemicals include:
Elements: Pure substances that cannot be broken down into simpler substances. Examples include carbon, oxygen, and gold.
Compounds: Substances composed of two or more elements chemically bonded together. Examples include water (H2O) and table salt (NaCl).
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Which of the following groups of substances involve the use of chemicals? Indicate all that apply.
Check all that apply.
Which of the following groups of substances involve the use of chemicals? Indicate all that apply.Check all that apply.
A light-weight bicycle frame, food packaging, a car exhaust catalytic converter
Soap, shampoo, washing powder
Antiseptic cream, pain killers, energy drinks
Paints, printer toner, food coloring
Computer displays, LED lights, barcode readers
Using C2H4 + 3 O2 -> 2 CO2 + 2 H2O. If 20 moles of fuel are combusted in the above equation, how many moles of O2 are consumed?
Answer:
Using C2H4 + 3 O2 -> 2 CO2 + 2 H2O. If 20 moles of fuel are combusted in the above equation, how many moles of O2 are consumed?
Explanation:
According to the balanced chemical equation:
1 mole of C2H4 reacts with 3 moles of O2
Therefore, for 20 moles of C2H4 combusted, we would need:
20 moles C2H4 × (3 moles O2 / 1 mole C2H4) = 60 moles O2
So, 60 moles of O2 are consumed in the combustion of 20 moles of C2H4.
How does a phase change affect a thermochemical equation?
O It alters the products.
O It alters the moles of reactants.
O It affects the balance of the equation.
O It can affect the AH value.
The correct answer is option D, It can affect the AH value.
What is a phase change?A phase change is a physical change in a substance in which the substance's state of matter is changed, such as from a gas to a liquid or from a liquid to a solid. It is also known as a phase transition.
Phase changes also involve changes in energy, temperature, and pressure. For example, when a solid melts to become a liquid, it absorbs energy and the temperature rises. When a liquid boils to become a gas, energy is released and the temperature decreases. Similarly, when a gas condenses to become a liquid, energy is released and the pressure increases.
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Cryolite, Na3AlF6(s),
an ore used in the production of aluminum, can be synthesized using aluminum oxide.
equation:
Al2O3(s)+6NaOH(l)+12HF(g)⟶2Na3AlF6+9H2O(g)
If 10.3 kg of Al2O3(s),
55.4 kg of NaOH(l),
and 55.4 kg of HF(g)
react completely, how many kilograms of cryolite will be produced?
mass of cryolite produced:
The mass (in kilograms) of Cryolite, Na₃AlF₆ produced, given that 10.3 Kg of Al₂O₃, 55.4 Kg of NaOH, and 55.4 Kg of HF react completely is 42.4 Kg
How do i determine the mass of Na₃AlF₆ produced?The mass of Na₃AlF₆ produced from the reaction can be obtained as follow:
Al₂O₃(s) + 6NaOH(l) + 12HF(g) ⟶ 2Na₃AlF₆ + 9H₂O(g
Molar mass of Al₂O₃ = 102 g/molMass of Al₂O₃ from the balanced equation = 1 × 102 = 102 g = 102 / 1000 = 0.102 KgMolar mass of Na₃AlF₆ = 210 g/molMass of Fe from the balanced equation = 2 × 210 = 420 g = 420 / 1000 = 0.420 KgFrom the balanced equation above,
0.102 Kg of Al₂O₃ reacted to produce 0.420 Kg of Na₃AlF₆
Therefore,
10.3 Kg of Al₂O₃ will react to produce = (10.3 × 0.420) / 0.102 = 42.4 Kg of Na₃AlF₆
Thus, from the above calculation, it is evident that the mass of Na₃AlF₆ produced is 42.4 Kg
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Need BIO help with both questions
Answer:
6. The light being reflected off changes the color shown
7. The bottom, the sugar looses its positive charge
Explanation:
draw a mechanism showing the penta-coordinate intermediate and the formation of the phosphorylated intermediate (which is an anhydride)
The formation of the phosphorylated intermediate (an anhydride) involves the formation of a penta-coordinate intermediate. This intermediate is formed by a nucleophilic attack of the sulfur on the phosphorus atom of the phosphate group.
In this mechanism, the sulfur atom of the sulfate group nucleophilically attacks the phosphorus atom of the phosphate group to form a penta-coordinate intermediate. This intermediate then rearranges to form a phosphorylated intermediate, which is an anhydride.
Mechanism showing the penta-coordinate intermediate and the formation of the phosphorylated intermediate are given as follows:
Step 1: Alkyl Phosphate Formation : The first step of the mechanism includes the formation of an alkyl phosphate. A proton is abstracted by OH− from the phosphate group to create the alkyl phosphate. The base catalyzes this step.
Step 2: Binding to Mg2+After the alkyl phosphate is created, the magnesium ion binds to it.
Step 3: Nucleophilic attack: Following that, the nucleophilic attack happens, with the nucleophile being the water molecule. It is coordinated with the magnesium ion. It occurs at phosphorus, causing it to be phosphorylated. It results in the creation of a pentacoordinate intermediate.
Step 4: Release of Orthophosphate: Orthophosphate is released as a result of the reaction between pentacoordinate intermediate and water. It results in the creation of a diester intermediate.
Step 5: Subsequent Hydrolysis: In the final step, the intermediate diester is hydrolyzed to form orthophosphate and the final product. This is accomplished via nucleophilic substitution.
The end result is a free phosphate group that is bound to the alcohol's oxygen. A phosphate anhydride is formed in the process.
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how many different alkenes result when 2-bromooctane is treated with a strong base? select answer from the options below
Strong bases like sodium ethoxide (NaOEt) or sodium hydroxide (NaOH) are used to treat 2-bromooctane, which then goes through an elimination process (also known as dehydrohalogenation) to produce various alkenes.
Which 4 alkenes are there?Ethene, propene, butene, and pentene are the first four alkenes.
Alkenes are a group of unsaturated hydrocarbons (i.e., molecules with solely carbon and hydrogen) that include at least one double bond from carbon to carbon. Olefins is a different name for alkenes. Due to the double bond, alkenes are more reactive than alkanes.
Both the hydrocarbons alkene and alkyne are unsaturated.
Whereas two Carbon atoms in Alkyne are joined by a triple bond, two Carbon atoms in Alkene only have a double bond.
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Consider a 0.238 M aqueous solution of sodium hydroxide, NaOH.
How many grams of NaOH are dissolved in 23.46 mL?
Answer:
0.2237 grams of NaOH
Explanation:
To calculate the grams of NaOH dissolved in 23.46 mL of a 0.238 M solution of NaOH, we can use the formula:
mass = molarity x volume x molar mass
where mass is the mass of NaOH dissolved in grams, molarity is the concentration of NaOH in moles per liter, volume is the volume of the solution in liters, and molar mass is the molar mass of NaOH in grams per mole.
First, we need to convert the volume of the solution from milliliters to liters:
volume = 23.46 mL / 1000 mL/L
volume = 0.02346 L
The molar mass of NaOH is 40.00 g/mol.
Now we can plug in the values and solve for mass:
mass = 0.238 M x 0.02346 L x 40.00 g/mol
mass = 0.2237 g
Therefore, there are 0.2237 grams of NaOH dissolved in 23.46 mL of a 0.238 M solution of NaOH.
Identify the Lewis acid and the Lewis base in each the following reactions. (Omit states of matter.) a. B(OH)2(aq) + H2O(l) + B(OH)4 - (aq) + H+ (aq) Acid: Base: b. H2O(1) + CN- (aq) + HCN(aq) + OH- (aq) Acid: Base: C. HgI,(s) +21+ (aq) → Hg1,2(aq) Acid: Base:
Base: Water, b. [tex]HCN[/tex] Acid Base [tex]OH-[/tex] , c. Base: I- Acid:[tex]HgI2[/tex] . Chemical substances known as acids have the ability to donate a proton [tex](H+)[/tex] to a base or another molecule.
Chemical substances known as acids have the ability to donate a proton [tex](H+)[/tex] to a base or another molecule. They have a sour flavour, have the power to dissolve metals, and can make litmus paper turn red. On the pH scale, where 7 is neutral and lower numbers indicate higher acidity, acids have a pH below 7. Hydrochloric acid, sulfuric acid, and acetic acid are a few typical examples of acids. Acids are essential for many chemical processes, such as digestion, the creation of energy, and the synthesis of numerous significant chemicals. Also, they are employed in a number of sectors, such as industry, food production, and agriculture.
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3. Draw a Lewis dot structure for the fictitious molecular ion [ZO2]-1. Assume that the central Z atom is bonded to each of the outer O atoms by a single bond. What is the formal charge on the Z atom?
The formal charge on the Z atom in the [ZO2]-1 ion is +1.
The Lewis dot structure for the [ZO2]-1 molecular ion is:
O
|
Z === O
|
O-
1. Determine the total number of valence electrons in the ion by adding the valence electrons of each atom and the charge of the ion.
Z has 4 valence electrons, while each O atom has 6 valence electrons.The ion has an overall negative charge of 1, so there is one extra electron.Total number of valence electrons = 4 + 6 + 6 + 1 = 172. Connect the Z atom to each O atom with a single bond, which uses up 2 electrons.
We now have 15 electrons left to distribute.3. Add the remaining electrons in pairs as lone pairs to each atom until all valence electrons are used up.
Each O atom needs 2 lone pairs (4 electrons).Z needs 2 lone pairs (4 electrons).4. Draw the Lewis dot structure.
The Lewis dot structure for [ZO2]-1 is:O
|
Z === O
|
O-
5. Calculate the formal charge on the Z atom using the formula:
Z has 4 valence electrons.Z has 2 lone pairs (4 electrons) and 2 bonding electrons (1 bond to each O).Formal charge = valence electrons - (number of lone pair electrons + 1/2 x number of bonding electrons)
Formal charge = 4 - (2 + 1/2 x 2) = 4 - 3 = +1
Therefore, the formal charge on the Z atom in the [ZO2]-1 ion is +1.
What is valence electron?
A valence electron is an electron in the outer shell associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed.
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