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2.5 liters of water each day and 3 liters for adult

The area of this rectangular walk is 390[tex]ft^{2}[/tex]

A rectangle is a closed two-dimensional figure with four sides. The opposite sides of a rectangle are equal and parallel to each other and all the angles of a rectangle are equal to 90°.

The width of the walk is constant and is 2ft, length of the walk is determined by the part of the rectangular yard.

Area of walk = 3 x 27 +3x27 + 3 x 38 + 3 x 38 which is 390[tex]ft^{2}[/tex]

In conclusion the area of the walk is 390[tex]ft^{2}[/tex]

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Answer: 4/3

Step-by-step explanation:

The reciprocal of a/b is b/a.

The coordinates of the point after the two reflections are (0.3,-7/10).

A reflection is a mapping from an isometric hyperplane with a set of fixed points acting as the reflection's axis or plane from a Euclidean space to itself. A figure's reflection creates its mirror image of that figure in the plane or axis of the reflection.

Given that, the point (-0.3, 7/10) is reflected over the y-axis and then over the x-axis respectively.

The coordinates of the point after the reflection in the y-axis are:
(0.3, 7/10)

Now, the coordinates of the point after the reflection in the x-axis are:
(0.3, -7/10)

Hence, the coordinates of the point after the two reflections are (0.3,-7/10).

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Answer: false

Step-by-step explanation:

if the expected grade was 100 but passing was 80 then she couldn't have passes with a 48

Answer:

$23.55

Step-by-step explanation:

First we will need to determine the total amount of sales Ryan and Carlos made. To do that we will multiply the amount of products sold by the product cost.

$2.75 x 12 = $33

Now we need to deduct the cost of supplies they need to pay back from their profits.

$33- $9.45= $23.55

Now we are left with Ryan and Carlos' total profit, which is $23.55

Answer:

43x+3x+17y

Step-by-step explanation:

because 43x+17y+3x=43x+17y+3x

The domain and range of this square root function are: D: [–4, ∞) and R: [0, ∞).

In Mathematics, a domain can be defined as the set of all real numbers for which a particular function or relation is defined. This ultimately implies that, a domain is the set of all possible input values (x-values) for a function while a range is the set of all possible output values (y-values) of a function.

Based on the information provided, the function is represented as follows:

g(x) = √(x + 4)

Since a square root function doesn't exist for all negative values, the domain of this function is given by:

x + 4 ≥ 0

x ≥ -4

Domain = [-4, ∞]

Since we do not have a vertical translation, the range of this square root function is given by:

x ≥ 0

Range = [0, ∞]

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Answer:

[–4, ∞) and R: [0, ∞)

Step-by-step explanation:

I got it right on the test.

The area of the trapezoid is equal to 7 square units.

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the trapezoid in a two-dimensional plane is called the area of the trapezoid.

Given that the area of a trapezoid is given by the formula A = 1/2

h(b₁ + b₂). The given values are h = 2, b₁=3, and b₂=4.

The area of the trapezoid is calculated as,

Area = (1 / 2) x h(b₁ + b₂)

Area = (1 / 2 ) x 2 x ( 3 + 4 )

Area = 7

Area = 7 square units

Therefore, the area of the trapezoid is equal to 14 square units.

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Answer: It indicates that the quadratic has a repeated real number solution.

Step-by-step explanation:

The linear equations that represent the relationships in the question order are;

A linear equation is an equation of the form; y = m·x + c

The slope of the line is found as follows;

(-5 - (-21))/(-1 - (-5)) = 4

The equation is y - (-5) = 4·(x - (-1)) = 4·x + 4

y = 4·x + 4 - 5 = 4·x - 1

The y-intercept is (0, 4), the x-intercept is (4, 0)

The slope is therefore; (0 - 4)/(4 - 0) = -1

The equation is therefore; y - 0 = -1 × (x - 4) = -x + 4

The y-intercept is (0, -1), the x-intercept is (4, 0)

The slope is therefore; (0 - (-1))/(4 - 0) = 1/4

The equation is therefore; y - 0 = (1/4) × (x - 4) = x/4 - 4/4 =

The slope of the line is; [tex]\dfrac{-3\frac{3}{4} - \left(-\frac{3}{4}\right) }{4-1} = -1[/tex]

y - (-3/4) = -1 × (x - 1) = -x + 1

y = -x + 1 - (3/4) = -x + 1/4

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Using the par value method, the journal entry to record the treasury stock transaction is as follows:

Debit Treasury Stock $2,350

Debit Paid-in Capital in Excess of Par Value $1,880

Credit Cash $4,230

Treasury stock transactions can be recorded using the cost or the par value methods.

When the cost method is used, the Treasury Stock account is debited or credited with the cost (cash price paid or received).

When the par value method is used, the difference between the cash price or cost and the par value is recorded in the Paid-in Capital in Excess of the Par Value account.

The Treasury Stock account is then credited or debited with the par value.

Treasury Stock $2,350 (470 x $5) Paid-in Capital in Excess of Par Value $1,880 (470 x $9 - $5) Cash $4,230 (470 x $9)

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Journalize the treasury stock transaction using the par value method.

Answer:

Answer:

[tex]8\sqrt{11}[/tex]

Step-by-step explanation:

Given:

[tex]x+\dfrac{1}{x}=\sqrt{11}[/tex]

Sum of two squares

[tex]\boxed{a^2+b^2=(a+b)^2-2ab}[/tex]

[tex]\textsf{Let}\; a = x[/tex]

[tex]\textsf{Let}\; b = \dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}x^2+\dfrac{1}{x^2}&=\left(x+\dfrac{1}{x}\right)^2-2x\left(\dfrac{1}{x}\right)\\\\&=\left(\sqrt{11}\right)^2-2\\\\&=11-2\\\\&=9\end{aligned}[/tex]

Sum of two cubes

[tex]\boxed{a^3+b^3=(a+b)(a^2-ab+b^2)}[/tex]

[tex]\textsf{Let}\; a = x[/tex]

[tex]\textsf{Let}\; b = \dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}x^3+\dfrac{1}{x^3}&=\left(x+\dfrac{1}{x}\right)\left(x^2-x\left(\dfrac{1}{x}\right)+\left(\dfrac{1}{x}\right)^2\right)\\\\ &=\left(x+\dfrac{1}{x}\right)\left(x^2-1+\dfrac{1}{x^2}\right)\\\\&=\left(x+\dfrac{1}{x}\right)\left(x^2+\dfrac{1}{x^2}-1\right)\\\\&=\sqrt{11}\left(9-1\right)\\\\&=8\sqrt{11}\end{aligned}[/tex]

Answer:

find p (A or ),given that A and B are independent

The graph of the inequality is plotted using the below points.

Graph:

In math, graph show you information as a visual image or picture.

Given,

Here we need to find the graph of the given inequality.

To graph an inequality:

To graph the related boundary line. We have to replace the <, >, ≤ or ≥ sign in the inequality with = to find the equation of the boundary line.

Now, we have to identify at least one ordered pair on either side of the boundary line and substitute those (x, y) values into the inequality.

Then shade the region that contains the ordered pairs that make the inequality a true statement.

Here if points on the boundary line are solutions, then use a solid line for drawing the boundary line. This will happen for ≤ or ≥ inequalities.

Where as if points on the boundary line are not solutions, then use a dotted line for the boundary line. This will happen for < or > inequalities.

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Answer:

Separating the variables , using equality symbol , drawing boundary line in XY plane , shading the area are the four steps in graphing linear inequalities

Step-by-step explanation:

Mathematical expressions known as linear inequalities compare two expressions using the inequality symbol. The expression may be either a numerical or an algebraic expression, or it may be both.

Step 1: Always start by separating the variable y from the left side of the inequality.

Step 2: The equality symbol should be used in place of the inequality symbol

Step 3: Draw the boundary line from step 2 in the XY plane.

Step 4: The last step is to partially or completely shade the border line.

Separating the variables , using equality symbol , drawing boundary line in XY plane , shading the area are the four steps in graphing linear inequalities

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Question 1

Since the x-coordinates are the same, the line is vertical. Therefore, the slope is undefined.

Question 2

Since the y-coordinates are the same, the line is horizontal. Therefore, the slope is zero.

Answer:

A

Step-by-step explanation:

Fill in X and Y for each of the equations until you find one that fits

The equation of the line y=2x+3 passes through the (1,4) point only.
The line gave y=2x+3.

In order to check whether the line passes through the points the following steps are:

A) (1,4)

Here x=1 , y=4.

We will put these values in the line y=2x+3.

4= 2(1)+3

4=4
As L.H.S=R.H.S, therefore this point (1,4) passes through the line.

B) (-1,4)

Here x=-1 , y=4.

We will put these values in the line y=2x+3.

4= 2(-1)+3

4= -2+3
4 [tex]\neq[/tex] 1
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (1,4) does not pass through the line.

C) (2,3)

Here x=2 , y=3.

We will put these values in the line y=2x+3.

3= 2(2)+3

3= 4+3
3 [tex]\neq[/tex] 7
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (2,3) does not pass through the line.

D) (3,2)

Here x=3 , y=2.

We will put these values in the line y=2x+3.

2= 2(3)+3

2= 6+3
2 [tex]\neq[/tex] 9
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (3,2) does not pass through the line.

Only (1,4) point passes through the line.

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The comparison of the terms are:

From the question, we have the following equation:

-4x + 11 = -10x + 17

The variable terms are terms that have the variable x represented

In this case, the variable terms are

Left-hand side = -4x

Right-hand side = -10x

When -4x and -10 are compared, we can conclude that

-4x is greater than -10x

From the question, we have the following equation:

-4x + 11 = -10x + 17

The constant terms are terms that do not have the variable x represented

In this case, the constant terms are

Left-hand side = 11

Right-hand side = 17

When 11 and 17 are compared, we can conclude that

11 is less than 17

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You can occasionally start by isolating and replacing a variable that is squared in both equations if you're required to solve a system of equations without a starting linear equation.

If there isn't a linear equation to begin with, you can pick out and use a squared variable in both equations.

Start by dividing both sides of the supplied nonlinear equation by the variable's coefficient, for instance.

After you've done that and isolated a variable, carry on with the problem-solving by adding that variable to the other equation.

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Answer:

[tex]2 \sqrt[3]{3} [/tex]

Step-by-step explanation:

[tex]24 {}^{ \frac{1}{3} } [/tex]

[tex] \sqrt[3]{24} [/tex]

[tex] \sqrt[3]{8 \times 3} [/tex]

[tex] \sqrt[3]{8} \times \sqrt[3]{3} [/tex]

[tex] \sqrt[3]{2 {}^{3} } \times \sqrt[3]{3} [/tex]

[tex]2 \times \sqrt[3]{3} [/tex]

[tex]2 \sqrt[3]{3} [/tex]

Answer:

30 tadpoles

Step-by-step explanation:

the 3 part of the ratio relates to the number of swans, that is 18 , then

18 ÷ 3 = 6 ← value of 1 part of the ratio

Then

number of tadpoles = 5 × 6 = 30

Using the rate, the number of book Mason reads per month is 2 books.

Mason read 4 books in 2 months. Mason reads at a constant rate. The number of books he reads each month can be calculated as follows;

The number of books he reads is at a constant rate. The rate formula can be used to find the number of book Mason read each month.

rate = number of books read / number of month

Therefore,

number of books read = 4 books

number of month = 2 month

Hence,

rate  = 4 / 2

rate = 2 books per month

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The test that Joan can use to determine if husbands earn more is the t test.

A t test is a statistical test used to compare two groups' means. It is frequently used in hypothesis testing to determine whether a process or treatment has an effect on the population of interest, or whether two groups differ. A t-test is an inferential statistic that is used to determine whether or not there is a significant difference in the means of two groups and how they are related.

The Independent Samples t Test compares the means of two independent groups to see if there is statistical evidence that the associated population means differ significantly. This can be utilized by Joan.

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The common denominator of the complex fraction is (1/a - 1/b)/(1/a + 1/b) is a²b² which is option D.

The provided complex fraction is  (1/a - 1/b)/(1/a + 1/b).

Now, to find the common denominator,

Solving this complex fraction.

First multiplying each component of every bracket to every component of the other bracket,

= 1/a² + 1/ab - 1/ab - 1/b²

Now, simplifying the equation,

= 1/a² + 1/b²

= (a²+b²)/a²b²

The denominator is the lower part of the fraction.

Hence, the common denominator of the complex fraction is a²b².

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Complete question - What is the common denominator of 1/a + 1/b in the complex fraction (1/a - 1/b)/(1/a + 1/b)?

A)a2 b2

B)a – b

C)a + b

D)ab

Charmaine sends 34 message, Jose send 75 texts and Shen send 25 messages.

What is linear equation?

An equation is a mathematical statement, which has an equal sign (=) between the algebraic expression. Linear equations are the equations of degree 1. It is the equation for the straight line.

Let C be charmaine text, S be shen text, J be jose text.

C +J+ S=134

Shen send 9 messages fewer than charmine .

S = C -9

C = S+9

And Jose sent 3 times more then shen

J =3S

We get,

S+9+3S+S=134

5S +9 = 134

5S = 134 -9

5S = 125

S = 25

C = 25 +9

= 34

J= 75

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Assuming [tex]\overline{BC}[/tex] is a diameter, minor arc [tex]AB[/tex] has a measure of [tex]180^{\circ}-108^{\circ}=72^{\circ}[/tex].

Using the inscribed angle theorem, [tex]36=x+3 \implies x=\boxed{33}[/tex].

The function has the end behavior f(x) → -∞  as , x → -∞ as f(x) → +∞ , x → +∞

Since,  The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity.

The degree and the leading coefficient of a polynomial function determine the end behavior of the graph.  And, if the function has  positive leading coefficient with odd degree then its end behavior is    f(x) → -∞  as , x → -∞ as f(x) → +∞ , x → +∞

Here, The given function has positive leading coefficient with odd degree.

Therefore,  by the definition of end behavior of a function,

The function has the end behavior f(x) → -∞  as , x → -∞ and, f(x) → +∞ , x → +∞

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The mistakes that Cindy made include:

The answer for Cindy's monthly car payments would be $609.63

To find the monthly payment. first convert the APR to a monthly rate and the number of years to months.

Monthly rate:

= 4% / 12

= 1 / 3%

Number of months:

= 4 x 12 months

= 48 months

The monthly payments is an annuity as it is constant and periodic. The monthly payment for Cindy's car can be found as:

= Cost of car / Present value of annuity factor, 1/3%, 48 months

= 27, 000 / 44.288833874953

= $609.63

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Factor the expression using the GCF 24y+88x

24y+88x

GCF is 8:

8(3y + 11x)