Answer: it would stop producers from producing food.
Explanation: why? Without the action of the producers to turn sunlight into food, the producers would die, and consumers that rely on them would lose their food source and die too.
Answer:
It would stop producers from producing food
Explanation:
Producers would die, and if producers died, consumers would die too.
Hope this helps
Which is the weakest type of intramolecular force/bond?
a. Polar covalent b. Ionic c. Metallic d. Nonpolar covalent
Answer:
Non polar covlant
Explanation:
A patient is prescribed 100mg/day of antibiotic for 2 weeks. The antibiotic is available in vials that contain 20mg/vial of the drug. How many vials are necessary for the entire treatment?
Give an example of chemical reaction that occurs in everyday life
Answer: metal and salt water
Explanation: salt starts to brake down metal and metal is everywhere in the ocean hope this helps
Answer:
baking a cake.
Explanation:
baking a cake is an example of a chemical reaction that happens daily because a new substance is forming when the cake is being baked. hope this helps! :)
Give the IUPAC name for each compound.
Answer:
a. 1-fluoro-3,3,4-trimethyl-pentane.
b. 1-iodo-3-ethyl-2-methyl-hexane.
c. 1,3-dichloro-5-dimethyl-hexane.
d. 1-bromo-3-methyl-cyclopentane.
Explanation:
Hello!
In this case, according to the IUPAC rules for the listed alkyl halides, we first need to name the halogens (considering periodic order) then alkyl radicals and finally the parent chain; thus, the names are given below:
a. 1-fluoro-3,3,4-trimethyl-pentane.
b. 1-iodo-3-ethyl-2-methyl-hexane.
c. 1,3-dichloro-5-dimethyl-hexane.
d. 1-bromo-3-methyl-cyclopentane.
e. 5-chloro-1-bromo-1,1,5-trimethyl-pentane (radicals are not clear).
Best regards!
What is a molecule contains the genetic instructions for the development and functioning of all living organisms found in the nucleus of a cell
(1) Phosphorus silicon is a semi-conductor
When Silicone is altered with Phosphorus, 4 of its electrons form covalent bonding and the 5th electron becomes delocalized and thus it increases electrical conduction
Answer:
blue blah blue blah
Explanation:
An isotope has three forms. 30% have a mass of 4 amu, 20% have a mass of 5 amu and
50% have a mass of 3 amu, Average atomic mass will be closest to
The average atomic mass will be 3.70 amu
We have to obtain the average atomic mass by multiplying the mass of each isotope in amu by the relative abundance of the given isotope as contained in the data of the question.
Hence;
Average atomic mass;
(0.30 * 4) + (0.20 * 5) + (0.50 * 3)
= 1.20 + 1.00 + 1.50
= 3.70 amu
https://brainly.com/question/13292428
How many milliliters of 60% carbonic acid must be mixed with how many milliliters of 15% carbonic acid to make 650 milliliters of a 38% carbonic acid solution
Answer:
348.9 mL of the 60% solution and 251.1 mL of the 15% solution.
Explanation:
First, we calculate how many mililiters of pure carbonic acid are there in 650 mL of a 38% solution:
650 mL * 38/100 = 247 mLThen we can express the sum of both initial solutions as:
1) x * 60/100 + y * 15/100 = 247for the volume of carbonic acid; and
2) x + y = 600 mLFor the volume of the solutions.
We now have a system of two equations and two unknowns (x is the volume of the 60% solution and y is the volume of the 15% solution).
We express x in terms of y in equation 2):
x = 600 - yAnd replace x in equation 1):
(600 - y) * 60/100 + y * 15/100 = 247360 - 0.6y + 0.15y = 247-0.45y = -113y = 251. 1 mLFinally we calculate x using equation 2):
x + 251.1 = 600x = 348.9 mLWill give brainliest
The order is Solumedrol 3 mg/kg for a child weighing 20 kg. Solumedrol is available as 125 mg/2ml. How many ml will be given
Answer:
0.96mL must be given
Explanation:
First, we need to obtain the mass of Solumedrol required for the child by using its mass. Then, with this mass we can solve the volume that must be administered:
Mass of solumedrol required:
20kg * (3mg / kg) = 60mg of solumedrol are required.
Volume given:
60mg Solumedrol * (2mL / 125mg) =
0.96mL must be given
CHEMISTRY HELP
Once the following equation is balanced, what is the correct coefficient for Z₂?
Answer:
The coefficient of Z₂ is 1.
Explanation:
From the question given above:
X + ZY —> XY + Z₂
Next, we shall balance the equation to obtain the coefficient of Z₂. This can be obtained as follow:
X + ZY —> XY + Z₂
There is 1 atom of Z on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of ZY as shown below:
X + 2ZY —> XY + Z₂
There are 2 atoms of Y on the left side and 1 atom on the right side. It can be balance by putting 2 in front of XY as shown below:
X + 2ZY —> 2XY + Z₂
Now, we have 1 atom of X on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of X as shown below:
2X + 2ZY —> 2XY + Z₂
Now the equation is balanced.
Thus, the coefficient of Z₂ is 1.
How do sound waves travel? PLEASE HELP IF YOU WANT BRAINLEIST AND ME TO LIKE URE COMMENT!!
A. Sound causes the air near it to vibrate inwards.
B. waves radiate outward from a central point.
C. Sound moves randomly in different directions.
D. Sound transforms waves into different frequencies.
The answer is A. The vibration caused by the waves through the air eventually weaken, which is why sound diminishes easily over distance.
Which word describes the amount of matter an object contains?
altitude
density
mass
pressure
Answer:
Mass
Explanation:
Answered this question multiple times and got it correct
Hope this helped!
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What carpet Burns in a deficiency of O2 a mixture of CO and CO2 forms.Carbon Burns in excess O2 to form only CO2 and CO Burns in excess O2 to form only CO2. Calculate ΔH for C(graphite +1/2O2) →CO(g).
Answer:
Explanation:
From the combustion of carbon, the reactions occurring in limited oxygen conditions are:
[tex]C(graphite) + \dfrac{1}{2}O_{2(g)} \to CO_{(g)}[/tex]
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex]
If it occurs in excess, then any leftover CO changes to CO2. i.e.
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex] ---- (1)
[tex]CO_{(g)} + \dfrac{1}{2}O_{(g)} \to CO_{2(g)}[/tex] ----- (2)
From (1), the enthalpy change is:
[tex]\Delta H_{rxn1} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{f C(graphite)}+ \Delta H^0_{fCO_2(g)}[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol -(0+0)[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol[/tex]
From (2), the enthalpy change is:
[tex]\Delta_{rxn2} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{fCO(g)} + \dfrac{1}{2} \Delta H^0_{fO_2(g)})[/tex]
[tex]\Delta_{rxn2} = -393.5 \ kJ/mol -(-110.5 + \dfrac{1}{2}(0))[/tex]
[tex]\Delta_{rxn2} = -283.0 \ kJ/mol[/tex]
Subtracting (2) from (1), we get:
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)} \ \ \ \Delta H_{rxn} = -393.5 \ kJ/mol}[/tex]
[tex]CO_{(g)} + \dfrac{1}{2} O_2(g) \to CO_{2(g)}} \ \ \ \Delta H _{rxn2} = -283.0 \ kJ/mol[/tex]
[tex]C(graphite) + O_{2(g)} \to CO (g) + \dfrac{1}{2}O_{2(g)} \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
[tex]C(graphite) + \dfrac{1}{2} O_{2(g)} \to CO (g) \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
The enthalpy change ΔH of the reaction = -110.5 kJ/mol
