I need help whats the answer ?

Answer:

Step-by-step explanation:

1). WXYZ is a rectangle,

  Properties of a rectangle,

  i). Opposite sides are equal and parallel.

  ii). All interior angles measure 90°.

  iii). Diagonals are equal in measure.

a). WY = ZX = 30

 Therefore, ZT = [tex]\frac{1}{2}(ZX)[/tex]

                    [tex]ZT=15[/tex]

b). WY = ZX = 45

c). Since, WY = ZX,

    (4b - 16) = (3b + 5)

    4b - 3b = 16 + 5

     b = 21

2). GOAT is a rhombus and m∠OGA = 35°,

    a). m∠TGA = m∠OGA = 35°

    b). m∠GXO = 90°

    c). m∠GXT = 90°

    d). Since adjacent angles of a rhombus are supplementary,

         m∠OGT + m∠GTA = 180°

         70° + m∠GTA = 180°

         m∠GTA = 110°

         m∠GTO = [tex]\frac{1}{2}(m\angle GTA)[/tex]

                        = [tex]\frac{1}{2}(110^{\circ})[/tex]

                        = 55°

     e). Since, opposite angles of a rhombus are equal,

          m∠OGT = m∠OAT = 70°

     f). m∠GOA = m∠GTA = 110°

Answer:

x≠-7

Step-by-step explanation:

The function will be undefined when the denominator is zero

x+7≠ 0

x≠-7

Answer:

16

Step-by-step explanation:

8 questions

2 answers on each question

8*2=16

Answers:

t is the number of seconds after the rocket is released

V(r) is the volume of the ball with radius r.

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Explanation:

There isn't much to say in terms of explanation. These variables are simply definitions.

:) :) :) :) :) :) :) :) :) :) :) :) :)

Answer:

1 kg

Step-by-step explanation:

Number of chickadees = 100

Quantity of seed eaten = 100 kg

Number of days = 100

Quantity of seeds each chickadee eats per day =Number of chickadees ÷ Quantity of seed eaten ÷ Number of days

= 100 ÷ 100 ÷ 100

= 1 ÷ 100

= 0.01 kg of seed

How many kg of seeds can 10 chickadees eat in 10 days?

= Quantity of seeds each chickadee eats per day × number of chickadee × number of days

= 0.01 kg × 10 × 10

= 1 kg

10 chickadees eat 1 kg of seeds in 10 days

Answer:

x = -6

Step-by-step explanation:

cube each side :

3x + 7 = 2x + 1

solve for x:

x = -6

Common difference = 2nd term - first term = -22.5-(-18)= -22.5+18 = -4.5

Step-by-step explanation:

To evaluate the proposed, the comprehension of linear data is required,

Slope: The rise/run or the accumulative unit distance between two differentiated points on a linear.

X-intercept: The peculiar point in which the observed linear data intersects the x-axis.

Y-intercept: The peculiar point in which the observed linear data intersects the y-axis.

1. To solve the following systems, first convert the Slope-Intercept formatting to Standard (General) form:

y = -5/3x + 3

3(Y = -5/3x + 3) Product by the denominator to eliminate the fraction.

3y = -5x + 9. Add 5x to the other expression as in standard form, the slope must be positive.

5x + 3y = 9 <== Standard (General) Form.

Y = 1/3x - 3

3(y = 1/3x - 3). Product by the denominator to eliminate the fraction.

3y = x - 9. Subtract by x to place the slope within the other expression of the equation.

-1(-x + 3y = -9). Now, product by -1 to contribute to a positive slope.

X - 3y = 9 <=== Standard (General) Form.

2. To solve for the x and y values, utilize the system of substitution:

1(5x + 3y = 9)Multiply equations by opposite slope to the other, and a positive to other.

-5(X - 3y = 9)

Evaluate,

+ 5x + 3y = 9. Now, add the systems.

-5x + 15y = -45

——————————

18y = -36

Y = -2

Thus, now that y is equated to -2, substitute that to either equation.

X - 3y = 9

X - 3(-2) = 9

X + 6 = 9

X = 3

Thus, x = 3, y = -2. This is their intersection point.

To plot these lines on the graph, execute the following,

Y = -5/3 x + 3

Start with the y-intercept. Draw a point on number 3 on the y-axis (vertical).

Starting with that point, go down 5 units, right 3 units.

* Remember, if there is a negative rise, go down. Positive, go up. If there is a negative run, go left. Positive, go right.

* Keep going 5 units down, right 3 units, until the graph allows.

2. Y = 1/3 x - 3

Similarly, conduct the same steps:

Starting with the y-intercept, draw a point on -3 on the vertical, or y-axis.

Beginning on that point, go up 1 unit, right 3 units.

Keep going up 1 units and 3 units right until the graph permits.

*I hope this helps.

Answer:

First even = 24

Second even = 26

Step-by-step explanation:

let x be the first even integer.

let 2x be the second even integer.

[tex]x + 2x = 50[/tex]

[tex]x + x = 50 - 2 [/tex]

[tex]2x =48[/tex]

[tex] x = 24[/tex]

Therefore, The first even number is 24.

[tex]second \: \: number= 50 - x \\ = 50-24 \\ = 26[/tex]

Therefore, The second even number is 26.

Answer:

3 C

4 B

5 B

6C

Step-by-step explanation:

3. the negative of the functiin reflects the original function on the x axis

4. multiplying by a number greater than 1 increases the slop of the original function

5. subtracting from x translates the function to the right

6. subtracting from f(x) translates the function down

Answer:

s4 = 270

18+36+72+144 = 270

-- convergent sums to a single value

Step-by-step explanation:

Answer:

Step-by-step explanation:

The central angle is twice as big as any angle sharing the endpoints  with the central angle of a chord where the angle is not below the smaller sector.

2*62 = x

x = 124

Answer:welcome

Step-by-step explanation: sorry I jsit really needed the points

Answer:  Second row

The y intercept is 2

=============================================================

Explanation:

The y intercept always occurs when x = 0. Visually, the y intercept is the location where the graph crosses the y axis.

In the table, we see that x = 0 pairs up with y = f(x) = 2 in the second row. So we can say that the y intercept is 2.

Side note: the x intercept is 1 since it occurs when y = 0.

Answer:

[tex]{ \tt{ - 2 {x}^{2} + 5x - 3 = 0 }} \\ { \tt{2 {x}^{2} - 5x + 3 = 0}} \\ { \tt{(2x - 3)(x - 1) = 0}} \\ { \tt{x = \frac{3}{2} \: and \: 1}}[/tex]

Answer:

2 i think

Step-by-step explanation:

sorry if im wrong

Answer:

2779.2

Step-by-step explanation:

Answer:

td/(r+e) = a

Step-by-step explanation:

t           a

----  = -----

r+e      d

Using cross products

t*d = a(r+e)

Divide each side by (r+e)

td/(r+e) = a

Incomplete question

Let the area be = 100 square meter

Cost of plaster = Rs 315 per square meter

No of walls = 4

Total area = 400 square meter

Then cost = 400 × 315

= Rs 1,26,000

Answered by Gauthmath must click thanks and mark brainliest

[tex] \cos(45) = \frac{5 \sqrt{2} }{x} \\ \frac{1}{ \sqrt{2} } = \frac{5 \sqrt{2} }{x} \\ x = 10 \\ \\ \tan(45) = \frac{y}{5 \sqrt{2} } \\ 1 = \frac{y}{5 \sqrt{2} } \\ y = 5 \sqrt{2} [/tex]

I hope I helped you ^_^

Answer:

100

Step-by-step explanation:

0.2*500=100

Answer:

OA⊥OC

∴∠AOB+BOC= 90°

5x+8+6n-6=90

11x+2=90

x=90-2/11

x=88/11

x=8

∠BOC=6x-6

=6(8)-6

=48-6

∠BOC=42°

------------------------------

Hope it helps...

Have a great day!!

Answer:

[tex]<BOC = 42[/tex]

Step-by-step explanation:

In this problem, it is given that lines (AO) and (OC) are perpendicular. This means that when the lines intersect, the four angles formed each have a measure of (90) degrees. As per the given diagram, angles (<AOR) and (<ROC) add up to make (<AOC). Thus, one can form the following equation and solve for (x).

[tex](<AOR) + (<ROC) = (<AOC)[/tex]

Substitute,

[tex](6x-6)+(5x+8)=90[/tex]

Simplify,

[tex]11x+2=90[/tex]

Inverse operations,

[tex]11x+2=90[/tex]

[tex]11x=88\\\\x=8[/tex]

Substitute this into the equation for the measure of angle (<BOC) to find the numerical angle measure:

[tex]<BOC = 6x-6\\x = 8\\\\= 6(8)-6\\\\=48-6\\\\=42[/tex]

Answer:

Does the answer help you?

9514 1404 393

Answer:

  (a) All three pyramids have the same volume

Step-by-step explanation:

The triangular base has an area of ...

  B = 1/2bh . . . . where b is the base of the triangle and h is its height.

The volume of the pyramid is ...

  V = 1/3BH . . . . where B is the area of the base, and H is the height of the pyramid.

Combining these equations gives ...

   V = 1/3(1/2bh)H = 1/6bhH

__

Pyramid 1 volume

  V1 = 1/6(12 m)(2 m)(10 m) = 40 m³

Pyramid 2 volume

  V2 = 1/6(6 m)(4 m)(10 m) = 40 m³

Pyramid 3 volume

  V3 = 1/6(12 m)(4 m)(5 m) = 40 m³

All three pyramids have the same volume.

Answer:

875.018

Step-by-step explanation:

To solve this, we must plug in 6 for our t value. So, we have the equation:

-4.982 - 20(6) + 1000

Following the rules of PEMDAS, we have:

-4.982 - 120 + 1000 = 875.018

There are infinitely many rational no.s between two no.s

one rational number between 1 and 2 is

11/10

Answer:

a=1/10, b=17/6

Step-by-step explanation:

IF you mean the points (9,a), (b,3) lie on the line y=2/(3x-7),

then a=2/(3*9-7)=1/10;

3=2/(3b-7)

b=17/6

Answer:

Remember that a triangle rectangle of length L and width W has an area:

A = W*L

In our rectangle, we have two sides along the x and y axes.

So one of the vertices of our triangle rectangle is the point (0, 0)

And the other vertex, is along the line:

y = -4x + 20

So, if the opposite vertex is at the point:

(x₁, y₁)

We can define the length as the difference between the x-values of each vertex.

L = (x₁ - 0) = x₁

And the width, similarly, as:

W = (y₁ - 0) = y₁

Such that the point (x₁, y₁) is a solution for the equation y = -4x + 20, then we have:

y₁ = -4x₁ + 20

Then we can rewrite the width as:

W = -4x₁ + 20

Now, we can write the area of our rectangle as:

A = (x₁)*(-4x₁ + 20)

A = -4*x₁^2 + 20*x₁

Now we want to maximize the area, notice that the area is given by a quadratic equation with a negative leading coefficient.

Thus, the maximum will be at the vertex of that quadratic equation.

Remember that for a general quadratic equation:

y = a*x^2 + b*x + c

The x-value of the vertex is:

x = -b/(2*a)

so, in our case, the x-value of the vertex will be:

x₁ = -20/(-4*2) = 20/8 = 5/2

Now we can evaluate this in our area equation:

A = -4*(5/2)^2 + 20*(5/2)  = 49.36

This is the maximum area of the rectangle.