i need helpp !!!!!!!!!!!

Hi there I hope you are having a great day :) I am pretty sure that you do 280 degrees around angle so i would say you would add 63 + 73 + 83 = 219 then you would take away it 280 - 219 =  61 so y must equal to 61 this is because we can see a z shape and a z shape adds up to 280.

Hopefully that helps you.

Answer:

No solution

Step-by-step explanation:

5x+10y=3 equation 1

10x+20y=8 equation 2

-2(5x+10y)=-2(3) multiply equation 1 by -2 to eliminate x

-10x-20y=-6 equation 1 multiplied by -2

10x+20y=8 equation 2

0  +  0  =2. Add above equations

    0      =2  

no solution

Answer:

yes

Step-by-step explanation:

the answer is c well thats what my teacher said

Answer:

B

Step-by-step explanation:

using sine rule

[tex] \frac{y}{sin \: 45} = \frac{5}{sin \: 45} \\ y = 5[/tex]

using sin rule

[tex] \frac{x}{sin \: 90} = \frac{5}{sin \: 45} \\ \\ 5sin90 = xsin45 \\ \\ x = \frac{5 \: sin \: 90}{sin \: 45} \\ x = \frac{5}{0.7071} \\ x = 7.071[/tex]

x=5√2

Answer:

17

Step-by-step explanation:

So, this is a percentage problem.

Start off by finding how many students 0.28% is:

If 100% = 5780

0.01% = 0.578                          

Now:

0.01% = 0.578

0.28% = 16.184

The exercise tells you to round for a whole person, so 16.184 turns 17

And that's the answer!

Answer:

The unlimited mileage plan would save money for Lia from 410 miles onwards.

Step-by-step explanation:

Since Lia can rent a van for either $ 90 per day with unlimited mileage or $ 50 per day with 250 free miles and an extra 25 ¢ for each mile over 250, to determine for what number of miles traveled in one day would the unlimited mileage plan save Lia money, the following calculation must be performed:

90.25 - 50 = 40.25

40.25 / 0.25 = 161

161 + 250 = 411

Therefore, the unlimited mileage plan would save money for Lia from 410 miles onwards.

Answer:

3/1 : 1/3

Step-by-step explanation:

Just simplify it.

9514 1404 393

Answer:

  B. only (-2, 9)

Step-by-step explanation:

A graph of the equation makes it easy to see that (-2, 9) is a solution and (2, -9) is not.

You can try these values of x in the equation to see what the corresponding y-values are.

  y = -2{-2, 2} +5 = {4, -4} +5 = {9, 1}

Points on the line are (-2, 9) and (2, 1).

(2, -9) is not a solution.

Answer:

B

Step-by-step explanation:

I know it is B. I know it because I put b in and I got it right on khan academy

Answer:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

( − ∞ , ∞ )

Set-Builder Notation:

{ x | x ∈ R }

Step-by-step explanation:

hope that helps bigger terms

Answer:

Some demerits of classical probability are provided throughout the following portion.

Step-by-step explanation:

Answer:

The correct answer is 3x-2

Step-by-step explanation:

It gives you the expression for JM and LM, and it asks for JL. Therefore, if you take away LM from JM, you are left with JL. You must subtract 2x-6 from 5x-8.

∴5x-8-(2x-6)

Do not forget to distribute the negative since you are subtracting, so instead of subtracting 6 from 8, you will be adding 6 to 8 because two negatives make a positive.

2x^2 + 8x - 12 = 0..divide by 2

x^2 + 4x - 6 = 0

x^2 + 4x = 6...add 4 to both sides of the equation

x^2 + 4x + 4 = 6 + 4

(x + 2)^2 = 10....<== ur constant is 10

x + 2 = (+-)sqrt 10

x = -2 (+ - ) sqrt 10

x = -2 + sqrt 10

x = -2 - sqrt 10

Answer:

the volume = 1152cm^2

Step-by-step explanation:

> The volume of cylinder =4 spheres

> Volume of sphere = v= 4/3πr³

> radius =6cm

volume of 4 spheres =

[tex]v \: = 4 \times \frac{4}{3} \times \pi \times {6}^{3} \\ \\ v = 1152cm {2} [/tex]

Answer:

the unused volume is 18095,57cm cubed

Answer:

ΔEFG ~ ΔRPQ - Angle Angle Angle Theorem

ΔEFG ~ ΔRFQ - Side Side Side Proportional Theorem

Step-by-step explanation:

First set : using triangle sum theory to find missing angle. Letters should match congruent angles when creating statement.

Second set :

[tex]\frac{EG}{RQ}[/tex] = [tex]\frac{10}{12}[/tex] =  [tex]\frac{5}{6}[/tex]

[tex]\frac{EF}{RF}[/tex] =  [tex]\frac{15}{18}[/tex] =  [tex]\frac{5}{6}[/tex]

[tex]\frac{FG}{FQ}[/tex] =  [tex]\frac{20}{24}[/tex] =  [tex]\frac{5}{6}[/tex]

Answer:

[tex] g(x)=-8|x |+1. = 9552815 \geqslant 6[/tex]

Answer: 36in2

Step-by-step explanation:

A= base *height

=12*3

=36

The Area of the figure is 36 in².

The area of a parallelogram refers to the total number of unit squares that can fit into it and it is measured in square units (like cm2, m2, in2, etc). It is the region enclosed or encompassed by a parallelogram in two-dimensional space.

The area of a parallelogram can be calculated by multiplying its base with the altitude. The base and altitude of a parallelogram are perpendicular to each other. The formula to calculate the area of a parallelogram can thus be given as,

Area of parallelogram = b × h square units

where,

b is the length of the base

h is the height or altitude

Given:

base= 12 in

height= 3 in

Area of parallelogram,

= base * height

=12* 3

= 36 in²

Learn more about Area of parallelogram here:

https://brainly.com/question/16052466

#SPJ2

Answer:

D

Step-by-step explanation:

So a Quadratic function,A quadratic function is one of the form f(x) = ax2 + bx + c, where a, b, and c are numbers with a not equal to zero

Answer:

[tex]791.7\:\mathrm{ft^3}[/tex]

Step-by-step explanation:

The volume of a cylinder with radius [tex]r[/tex] and height [tex]h[/tex] is given by [tex]A_{cyl}=r^2h\pi[/tex].

By definition, all radii of a circle are exactly half of all diameters of the circle. Therefore, if the diameter of the circular base of the cylinder is 6 feet, the radius of it must be [tex]6\div 2=3\text{ feet}[/tex].

Now we can substitute [tex]r=3[/tex] and [tex]h=28[/tex] into our formula [tex]A_{cyl}=r^2h\pi[/tex]:

[tex]A=3^2\cdot 28\cdot \pi,\\A=9\cdot28\cdot \pi,\\A=791.681348705\approx \boxed{791.7\:\mathrm{ft^3}}[/tex]

Answer:

your can only divide then up in that specific sequence one time

MODE IS THE NUMBER THAT IS REPEATED THE HIGHEST TIME..

HERE, IN YOUR QUESTION 5CAME 2 TIMES i.e. it is repeated highest time .so mode=5....

Answer:

D

Step-by-step explanation:

i think it's correct if not I'm sorry

Answer:

There are 824 deer in the preserve.

Step-by-step explanation:

Since to determine the number of deer in a game preserve, a conservationist catches 412 deer, tags them and lets them loose, and later, 316 deer are caught, 158 of them are tagged, to determine how many deer are in the preserve you must perform the following calculation:

316 = 100

158 = X

158 x 100/316 = X

50 = X

50 = 412

100 = X

824 = X

Therefore, there are 824 deer in the preserve.

Answer: hello your question was poorly written but i was able to the get missing parts online which enabled me resolve your question

answer:

a) a = 0.1096

b) 1.89 watts

Step-by-step explanation:

Std of output voltage = 0.25 volt

H0 : μ = 5 volts

Ha : μ ≠ 5 volts

n = 16

a) Acceptance region = 4.9 ≤ X ≤ 5.1  

Determine the value of a

value of a = 0.0548 + 0.0548

                 = 0.1096

attached below is the reaming solution

note : a is a type 1 error

b) power of test

True mean output voltage = 5.1 volts

P = - 1.89 watts

power cant be negative hence the power of the test  = 1.89 watts

Answer:

$15,540

Step-by-step explanation:

I DONT KNOW IF ITS RIGHT THO BUT

9% = 1,800

Answer:

Step-by-step explanation:

I don't think so. This equation has but one definite answer and the left and right sides don't produce the same result.

subtract 5m from both sides

6 = 4m - 5m

6 = - m                 Multiply both sides by - 1

-6 = m

An identity is something like 4x + 5x = 9x

It doesn't matter what x is. Any value of x will make the right side = to the left side. This becomes more important when you will study trigonometry.

here you go it's too easy

Step-by-step explanation:

Explanation is in the attachment .

Hope it is helpful to you ❣️☪️❇️

Answer:

The remainder is 3x - 4

Step-by-step explanation:

[Remember] [tex]\frac{Dividend}{Divisor} = Quotient + \frac{Remainder}{Divisor}[/tex]

So, [tex]Dividend = (Quotient)(Divisor) + Remainder[/tex]

In this case our dividend is always P(x).

Part 1

When the divisor is [tex](x - 1)[/tex], the remainder is [tex]4[/tex], so we can say [tex]P(x) = (Quotient)(x - 1) + 4[/tex]

In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x - 1) = 0[/tex]

When solving for [tex]x[/tex], we get

[tex]x - 1 = 0\\x - 1 + 1 = 0 + 1\\x = 1[/tex]

When [tex]x = 1[/tex],

[tex]P(x) = (Quotient)(x - 1) + 4\\P(1) = (Quotient)(1 - 1) + 4\\P(1) = (Quotient)(0) + 4\\P(1) = 0 + 4\\P(1) = 4[/tex]

--------------------------------------------------------------------------------------------------------------

Part 2

When the divisor is [tex](x + 3)[/tex], the remainder is [tex]104[/tex], so we can say [tex]P(x) = (Quotient)(x + 3) + 104[/tex]

In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x + 3) = 0[/tex]

When solving for [tex]x[/tex], we get

[tex]x + 3 = 0\\x + 3 - 3 = 0 - 3\\x = -3[/tex]

When [tex]x = -3[/tex],

[tex]P(x) = (Quotient)(x + 3) + 104\\P(-3) = (Quotient)(-3 + 3) + 104\\P(-3) = (Quotient)(0) + 104\\P(-3) = 0 + 104\\P(-3) = 104[/tex]

--------------------------------------------------------------------------------------------------------------

Part 3

When the divisor is [tex](x^2 - x + 1)[/tex], the quotient is [tex](x^2 + x + 3)[/tex], and the remainder is [tex](ax + b)[/tex], so we can say [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

From Part 1, we know that [tex]P(1) = 4[/tex] , so we can substitute [tex]x = 1[/tex] and [tex]P(x) = 4[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

When we do, we get:

[tex]4 = (1^2 + 1 + 3)(1^2 - 1 + 1) + a(1) + b\\4 = (1 + 1 + 3)(1 - 1 + 1) + a + b\\4 = (5)(1) + a + b\\4 = 5 + a + b\\4 - 5 = 5 - 5 + a + b\\-1 = a + b\\a + b = -1[/tex]

We will call [tex]a + b = -1[/tex] equation 1

From Part 2, we know that [tex]P(-3) = 104[/tex], so we can substitute [tex]x = -3[/tex] and [tex]P(x) = 104[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

When we do, we get:

[tex]104 = ((-3)^2 + (-3) + 3)((-3)^2 - (-3) + 1) + a(-3) + b\\104 = (9 - 3 + 3)(9 + 3 + 1) - 3a + b\\104 = (9)(13) - 3a + b\\104 = 117 - 3a + b\\104 - 117 = 117 - 117 - 3a + b\\-13 = -3a + b\\(-13)(-1) = (-3a + b)(-1)\\13 = 3a - b\\3a - b = 13[/tex]

We will call [tex]3a - b = 13[/tex] equation 2

Now we can create a system of equations using equation 1 and equation 2

[tex]\left \{ {{a + b = -1} \atop {3a - b = 13}} \right.[/tex]

By adding both equations' right-hand sides together and both equations' left-hand sides together, we can eliminate [tex]b[/tex] and solve for [tex]a[/tex]

So equation 1 + equation 2:

[tex](a + b) + (3a - b) = -1 + 13\\a + b + 3a - b = -1 + 13\\a + 3a + b - b = -1 + 13\\4a = 12\\a = 3[/tex]

Now we can substitute [tex]a = 3[/tex] into either one of the equations, however, since equation 1 has less operations to deal with, we will use equation 1.

So substituting [tex]a = 3[/tex] into equation 1:

[tex]3 + b = -1\\3 - 3 + b = -1 - 3\\b = -4[/tex]

Now that we have both of the values for [tex]a[/tex] and [tex]b[/tex], we can substitute them into the expression for the remainder.

So substituting [tex]a = 3[/tex] and [tex]b = -4[/tex] into [tex]ax + b[/tex]:

[tex]ax + b\\= (3)x + (-4)\\= 3x - 4[/tex]

Therefore, the remainder is [tex]3x - 4[/tex].