I neeed help , can somebody please tell the answer . ?

Answer: The last score must be 92%

Step-by-step explanation: To find the average, you add all the terms, then divide by the number of terms.

Answer:

2

Step-by-step explanation:

because 8 and 4 to get the shape smaller you divide it by 2 so you times 1 *2 to get the bigger one

Answer:

d. $13.35

Step-by-step explanation:

subtract

i am so sorry if this is wrong! hope this helps:)

Answer:

17x-7y

Step-by-step explanation:

Im assuming you need to simplify it.

combine 13x and 4x

17x-7y

Answer:

18

3+x (x=15)

so

3+15 =

18

Step-by-step explanation:

Answer: 18

Step-by-step explanation:

Answer:

Step-by-step explanation:

to find out you will

250*56/100=140 this is the discount

250-140=110 you will pay for membership

Answer: 110 %

Step-by-step explanation:

Answer:

35 miles per hour.

Step-by-step explanation:

140÷4=35

!75÷5=35

210÷6=35

Answer:

❌23 miles per hour

✅35 miles per hour

❌42 miles per hour

❌53 miles per hour

Go follow me on T I k T o k  aiyana_parker

Answer:

I have one below (It's kind of simple though..)

Step-by-step explanation:

Harry Had 5 Potions he made in Potions Class. He would like to share the 5 potions with his 2 friends, Ron and Hermione. How many potions do they each get? Write the equation for how many each person gets in fractional form

(This is a simple one I don't have a complicated one..)

Given:

[tex]\tan \theta > 0[/tex] and [tex]\sec \theta <0[/tex].

To find:

The quadrant.

Solution:

We know that,

In I quadrant, all trigonometric ratios are positive.

In II quadrant, only [tex]\sin \theta, \text{cosec}\theta[/tex] are positive and others are negative.

In III quadrant, only [tex]\cot \theta, \tan\theta[/tex] are positive and others are negative.

In IV quadrant, only [tex]\cos \theta, \sec\theta[/tex] are positive and others are negative.

We have,

[tex]\tan \theta > 0[/tex] and [tex]\sec \theta <0[/tex].

Here, [tex]\tan \theta[/tex] is positive and [tex]\sec \theta[/tex] is negative. So, [tex]\theta [/tex] lies in the III quadrant.

Therefore, the correct option is C, i.e., III.

Answer:

4x-1

Step-by-step explanation:

The working is shown in the above photo

Answer:

see explanation

Step-by-step explanation:

Given f(x) then the derivative f'(x) is

f'(x) = lim ( h tends to zero ) [tex]\frac{f(x+h)-f(x)}{h}[/tex]

      = lim ( h to 0 ) [tex]\frac{2(x+h)^2-(x+h)-(2x^2-x)}{h}[/tex]

     = lim ( h to zero ) [tex]\frac{2(x^2+2hx+2h^2)-x-h-2x^2+x}{h}[/tex]

     = lim ( h to zero ) [tex]\frac{2x^2+4hx+2h^2-h-2x^2}{h}[/tex]

     = ( lim h to 0 ) [tex]\frac{4hx+2h^2-h}{h}[/tex]

     = ( lim h to 0 ) [tex]\frac{2h(2x+h)-h}{h}[/tex]

     = lim ( h to 0 ) [tex]\frac{2h(2x+h)}{h}[/tex] - [tex]\frac{h}{h}[/tex] ← cancel h on numerator/ denominator of both

     = lim( h to 0 ) 2(2x + h) - 1 ← let h go to zero

f'(x) = 4x - 1

Step-by-step explanation:

Remember the Difference of Squares:

a² - b² = (a + b)(a - b)

Therefore (√20 - √3)(√20 + √3)

= (√20)² - (√3)² = 20 - 3 = 17. (C)

Answer:

we could migrate here

Step-by-step explanation:

Answer:

I feel like I answered this before

Step-by-step explanation:

Answer:

I can explain. look at variables (letters) ..7,2,3 in back of numbers. With this numbers it's an x. In front of 7x its a - or +. It tells you to either subtract or add...7x°-2x°+2x°-3. Start with 7x minus 2°, minus 2°, plus two & at end subtract 3

Answer:

1) 3x+8

2) -2y+3x

Step-by-step explanation:

thats the answer! hope it helps :)

Answer:

I'm doing this project rn I'll help you as soon as I'm done! Did you do the other sections already?

Step-by-step explanation:

Step-by-step explanation:

f(x) = x² - 3x + 2 = (x - 2)(x - 1).

When f(x) = 0, (x - 2)(x - 1) = 0.

=> x = 2 or x = 1.

Answer:

[tex]g(f(x)) = g(2x - 3) = {(2x - 3)}^{2} \\ =\boxed{4 {x}^{2} - 12x + 9}[/tex]

Answer:

the desired solution is (2, 2)

Step-by-step explanation:

Solve this using elimination by add'n/subtr'n.

Multiply the first equation by 2, obtaining the equivalent set of equations:

2x - 2y = 0

3x + 3y = 10

Combining like terms, we get 5x = 10, and thus x must be 2.

Subbing 2 for x in the first equation yields 2 - y = 0, or y = 2.

Then the desired solution is (2, 2).

Answer:

1. independent: months , x axis

2. dependent: frogs , y axis

Step-by-step explanation:

plato

Answer:

Hope this helps!

Step-by-step explanation:

2L + 3S = 83

4L + 8S = 197

Multiplies the top equation by -2.

-4L + -6S = -166

4l  + 8S = 197

Adding them together...

2S = 31

S = 31/2 = 15.5

Plugging into the first equation:

 2L + 3S = 83

 2L + 3(15.5) = 83

2L + 46.5 = 83

2L = 83 - 46.5

2L = 36.5

L = 36.5/2 = 18.25

check:

2L + 3S = 2(18.25) + 3(15.5) = 36.5 + 46.5 = 83

4L + 8S = 4(18.25) + 8(15.5) = 73 + 124 = 197

The Large box weighs 18.25

The small box weighs 15.5

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Answer:

your answer would be 6

Step-by-step explanation:

(3)4-6

12-6

6

Answer:

I think it would be 18

Step-by-step explanation:

3 x 4 =12

12 + 12= 24

24 -6=18

9514 1404 393

Answer:

  1. yes

  2. no

Step-by-step explanation:

We can label the equations [1] and [2] to make the transformations to the equivalent system easier to describe.

1. The equivalent system is [1] +[2] and 2×[1]. Both of these are described as allowed transformations.

  [1] +[2] is (-x +2y) +(-3x +9y) = (10) +(-15)  ⇒  -4x +11y = -5

  2×[1] is 2(-x +2y) = 2(10)  ⇒  -2x +4y = 20

These resulting equations match the ones proposed for the equivalent system.

  yes, the systems are equivalent

__

2. The first equation of the proposed "equivalent" system is [1] +[2]. The second equation has no relation to the equations of the given system.

  [1] +[2] = (-2x +3y) +(-11x -13y) = (14) +(-6)  ⇒  -13x -10y = 8

  no, the systems are not equivalent

(This is also shown in the attached graph. The original system is in red; the "equivalent" system is in green. Equivalent systems have the same solution. These do not.)

Answer:

[tex]AB=2\sqrt{ab}[/tex]

Step-by-step explanation:

From figure,

[tex]OA=a, \quad \quad O'B=b\\\Rightarrow OO'= (a+b) \quad \quad \text{and}\quad OD=(a-b)[/tex]

In triangle [tex]OO'D[/tex]

  [tex](OO')^2=(OD)^2+(O' D)^2[/tex]

[tex]\Rightarrow (a+b)^2=(a-b)^2+(O' D)^2\\\Rightarrow a^2+b^2+2ab-a^2-b^2+2ab=(O' D)^2\\\Rightarrow 4ab=(O' D)^2\\\Rightarrow O'D=2\sqrt{ab} \\\Rightarrow O' D=2\sqrt{ab}=AB \quad \quad [\because O' DAB\;\; \text{is a rectangle.}][/tex]

Hence, [tex]AB=2\sqrt{ab}[/tex]

Answer:

The answer is 19.25

Step-by-step explanation:

Key skills needed: Fraction operations, decimal conversion

1) We are given the hint to use 9 as "b", and we get:

---> [tex]a = \frac{16}{8}(9) + \frac{10}{8}[/tex]  

Let's do  [tex]\frac{16}{8}(9)[/tex]

--> [tex]\frac{16}{8}[/tex] is the same as [tex]16[/tex] ÷ [tex]8[/tex]

16 divide by 8 is 2.

2) This means that it would be  ---> [tex]2(9)[/tex]  which is simply 2 times 9.

2 times 9 = 9 + 9 = 18

3) With that result, it would be  ---> [tex]a = 18 + \frac{10}{8}[/tex]

Now, do [tex]\frac{10}{8}[/tex] (10 divided by 8)  ---> Get 1.25

4) 18 + 1.25 = 19.25, so --> [tex]a = 19.25[/tex] is the answer

Hope you understood and have a nice day!!   :D

Answer:

Th answer is x = (c - ab) / a

Step-by-step explanation:

The steps are :

a(x + b) = c

ax + ab = c

ax = c - ab

x = (c - ab) / a

Answer:

x=(c-ab)/a

this s answer

Answer: You are correct, the solution is:

-2 + (-4) + 2 = -4

Step-by-step explanation:

We start at position -2, then we get 4 in the first dice, the first dice tell us how many units we move to the left, and at the left we have the negative side of the numberline then we need to subtract 4 to the starting position. This is:

-2 - 4

Or we can rewrite this as:

-2 + (-4)

Now we got a 2 in the second dice, this dice tell us how many units we move to the right, and we know that the right is the positive side of the numberline, then we need to add 2.

The equation becomes:

-2 + (-4) + 2 = -4

So you are correct.