I want to create water out of 45.4 Liters of Oxygen at STP. How much water will I produce?
STP: Standard Temperature and Pressure
72g H2O
36g H20
9g H20
18g H20

Answers

Answer 1

Answer:

72.96 of water produce by 45.4 L of oxygen at STP.

Explanation:

[tex]H_2+\frac{1}{2}O_2\rightarrow H_2O[/tex]

1 mole of oxygen=22.4 L at STP

[tex]\frac{1}{2}[/tex]\mole of oxygen=22.4/2=11.2 L

11.2 L of oxygen required to produce water=1 mole

1 L of oxygen required to produce water=1/11.2 mole

45.4 L of oxygen required to produce water=[tex]\frac{1}{11.2}\times 45.4[/tex]

45.4 L of oxygen required to produce water=[tex]\frac{45.4}{11.2}[/tex]moles

1 mole of water=18 g

[tex]\frac{45.4}{11.2}[/tex]moles of water=[tex]18\times \frac{45.4}{11.2}[/tex]

[tex]\frac{45.4}{11.2}[/tex]moles of water=72.96 g

Hence, 72.96 of water produce by 45.4 L of oxygen at STP.


Related Questions

Which one of the following reactions is NOT balanced?

2 CO + O2 + 2 CO2
2 SO2 + O2 +2 SO3
2 KNO3 + 10 K 5 K20 + N2
SF4 + 3 H2O → H2SO3 + 4HF

Answers

Answer:

co+ o2+ 2co2 is not balanced reaction

100.0 mL of a 0.780 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the solution?

Answers

5 times dilution
0.780M x 1/5 = 0.156M
Hope this help.

1. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:
a) -CH3 b) -CH2OH c) -CH2NH2 d) -CH2BR
2. Arrange the following groups in order of decreasing priority that would allow you to determine E/Z, or R/S. Provide a string of letters (e.g. abcd) as an answer with the highest priority listed first, lowest priority last:
a) -F b) -CH2OH c) -CHO d) -CH3

Answers

1. dcba
2. acbd

Good luck

Regards
BLACKSHARK

1) The order of decreasing priority would allow determining E/Z or R/S is "dbca".

2)  The order of decreasing priority would allow determining E/Z or R/S is "acbd".

What is absolute configuration?

Absolute configuration can be described as to the spatial arrangement of atoms within a chiral molecular entity. Absolute configuration in organic molecules, where carbon is bonded to four different substituents.

The absolute configuration has used a set of rules to describe the relative positions around the chiral center atom. The most common labeling method is the descriptors R or S where R and S refer to Rectus and Sinister.

The group with the highest atomic number will get the highest priority and the group with the lowest atomic number substituents will get the lowest priority. Therefore, the order of priority is -CH₂Br > -CH₂OH > -CH₂NH₂ > -CH₃.

Therefore, the order of priority for the second part is -F > -CHO > -CH₂OH > -CH₃.

Learn more about absolute configuration, here:

https://brainly.com/question/14365822

#SPJ5

Which of the following is the correct way to balance the following chemical question:
2SnO2 + 4H2 -> 2Sn + 4H2O
SnO2 + 2H2 -> Sn + 2H2O
a. Both equation I and II are balanced, but equation I is the correct way to write the balanced equation.
b. Can you divide equation II by another factor and still have it be correct? Why or why not?
c. In a complete sentence, write down a method you could use to determine if an equation is written in the correct way.

Answers

Answer:

i have no answer for part A

part B

the one that has a 4 can be divided by 2 because reducing

part c

you can determine if an equation is written in the correct way by balancing the equation as if it had not been done already.

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving some urea () in of . This solution boils at . Calculate the mass of that was dissolved. Round your answer to significant digits.

Answers

This question is incomplete, the complete question is;

A certain liquid X has a normal boiling point of 150.4 °C and a molar boiling point elevation constant kb is 0.60 °Ckgmol⁻¹.

A solution is prepared by dissolving some urea (NH22CO) in 750 g of X. This solution boils at 150.9 °C . Calculate the mass of urea that was dissolved. Round your answer to 3 significant digits.

Answer:

the mass of urea that was dissolved is 37.5 g

Explanation:

Given the data in the question;

normal boiling point of X; Tb⁰ = 150.4 °C

boiling point of solution Tb = 150.9 °C

Change in boiling point Δt = Tb - Tb⁰  = 150.9 °C - 150.4 °C = 0.5 °C

Kb = 0.6 °C.kg.mol⁻¹

V = 750 g

Now, we know that

Δt = Kb × molality

so

0.5 = 0.6 × molality

molality = 0.5 / 0.6

molality = 0.833

we know that molar mass of urea is 60 g/mol

so

molality = mass × 1000 / molar mass × volume( g )

we substitute

0.833 = ( mass × 1000 ) / ( 60 × 750 )

0.833 = ( mass × 1000 ) / 45000

0.833 × 45000 = mass × 1000

mass = ( 0.833 × 45000 ) / 1000

mass = 37485 / 1000

mass = 37.485 ≈ 37.5 g   { 3 significance figure }

Therefore, the mass of urea that was dissolved is 37.5 g

A structural model of retinol is shown below. How many carbon atoms are in
retinol?
А. 14
В. 28
С. 20
D. 5

Answers

Answer:

The answer is 20

Explanation:

Platinum is one of the most dense elements (d = 21.5 g/cm3). What is the volume of a 10.0 g sample of the metal?

Answers

Answer:

0.465

Explanation:

To find the volume of a substance, divide the mass by the density.

M/D = V

10.0 / 21.5 = 0.4651163

Then round to 3 significant figures: and the density is 0.465

A solution of hydrochloric acid had a hydrogen ion concentration of 1.0 mol/dm3
Water was added to hydrochloric acid until the ph increased by 1
What was the hydrogen ion concentration of the hydrochloric acid after had been added?

Answers

Answer:

pH = -log[H+]

Where [H+] = Hydrogen ion concentration

In this case,

[H+] = 1 × 10^(-2) = 10^(-2)

log{10^(-2)} = -2

-log{10^(-2)} = -(-2) = 2

pH = -log{10^(-2)} = 2

and hi.!!!

Answer:

0.1

Explanation:

Hydrogen ion concentration can be calculated using the formula [H+] = 10^-pH

pH can be concentrated using ph = -log[H+]

let's calculate the initial pH before anything was added: pH = -log(1) = 0

it increased by 1 so the final pH is 1.

Now we'll find the [H+] of a solution with a pH of 1:

concentration = 10^(-1) = 0.1

Assign oxidation state to each atom in each element ion or compound.
a. Ag
b. Ag+
c. CaF2
d. H2S
e.CO3
f. CrO4
g. Cl2
h. Fe
i. CuCl2
j. CH4

Answers

Answer:

a. [tex]Ag^0[/tex]

b. [tex]Ag^{+}[/tex]

c. [tex]Ca^{2+}F_2^-[/tex]

d. [tex]H_2^+S^{2-}[/tex]

e. [tex](C^{4+}O_3^{2-})^{-}[/tex]

f. [tex](Cr^{6+}O_4^{2-})^{2-}[/tex]

g. [tex]Cl_2^0[/tex]

h. [tex]Fe^0[/tex]

i. [tex]Cu^{2+}Cl_2^-[/tex]

j. [tex]C^{4-}H_4^+[/tex]

Explanation:

Hello there!

In this case, according to the concept of charge balance, which tell us that the overall charge is zero for any compound, except ions, it turns out possible to proceed as follows:

a. [tex]Ag^0[/tex]

b. [tex]Ag^{+}[/tex]

c. [tex]Ca^{2+}F_2^-[/tex]

d. [tex]H_2^+S^{2-}[/tex]

e. [tex](C^{4+}O_3^{2-})^{-}[/tex]

f. [tex](Cr^{6+}O_4^{2-})^{2-}[/tex]

g. [tex]Cl_2^0[/tex]

h. [tex]Fe^0[/tex]

i. [tex]Cu^{2+}Cl_2^-[/tex]

j. [tex]C^{4-}H_4^+[/tex]

Keep in mind lonely elements have 0 as their oxidation state.

Regards!

The shape of the sulfur dioxide molecule, where sulfur is the central atom is

bent.
linear.
trigonal planar.
tetrahedral.

Answers

Answer:

bent

Explanation:

The molecular formula of sulfur dioxide is written as SO₂

The molecular geometry of sulfur dioxide can be determined using the Lewis structure.

The Lewis structure shows the distribution of electrons around the atoms of a given compound such as sulfur dioxide (SO₂).

In this compound, sulfur is the central atom with 6 valence electrons.

The sulfur is bonded covalently with two oxygen atoms, each with 6 valence electrons. Oxygen contributes 2 lone pairs while sulfur which is the central atom contributes 1 lone pair of electrons in the bond.

The bond angle between the two oxygen atoms and the central sulfur atom is approximately 120⁰, as a result of the bent shape of the molecular structure.

PLEASE HELP!!

How does temperature, agitation, and particle size affect solubility?

Answers

Answer:

At higher temperatures, particles move faster and collide more, increasing solubility rates.

Agitation increases solubility rates as well, by bringing fresh solvent into contact with the undissolved solute

The smaller the particle size, the higher (faster) solubility rate. Vice versa, the bigger the particle size, the lower (slower) solubility rate.

Explanation:

g Arrange the following compounds in order of acidity (highest to lowest): H2O, H3O , HCl A. CH3COOH > HCl > H2O B. H2O > CH3COOH > HCl C. HCl > H2O > CH3COOH D. HCl > CH3COOH > H2O

Answers

Answer:

Arrange the following compounds in order of acidity (highest to lowest): H2O, CH3COOH , HCl

A. CH3COOH > HCl > H2O

B. H2O > CH3COOH > HCl

C. HCl > H2O > CH3COOH

D. HCl > CH3COOH > H2O

Explanation:

The given substances are acetic acid, hydrochloric acid, and water.

Since HCl is a strong acid and it undergoes complete ionization.

CH3COOH acetic acid is a weak acid and it undergoes partial dissociation in water.

Pure water is a neutral substance.

Hence, the order of acidity is shown below:

HCl > CH3COOH > H2O.

Among the given options, option D is the correct answer.

Diethyl ether (C2H5 )2O vaporizes at room temperature. If the vapor exerts a pressure of 233 mm Hg in a flask at 25 °C, what is the density of the vapor?​

Answers

Answer: The density of the given vapor is 0.939 g/L.

Explanation:

Given: Pressure = 233 mm Hg (1 mm Hg = 0.00131579 atm) = 0.31 atm

Temperature = [tex]25^{o}C[/tex] = (25 + 273) K = 298 K

According to the ideal gas equation,

[tex]PV = \frac{m}{M}RT[/tex]

where,

P = pressure

V = volume

m = mass

M = molar mass

R = gas constant = 0.0821 L atm/mol K

T = temperature

This formula can be re-written as follows.

[tex]PM = \frac{m}{V}RT[/tex]    (where, [tex]Density = \frac{mass (m)}{Volume (V)}[/tex] )

Hence, formula used to calculate density of diethy ether (molar mass = 74.12 g/mol) vapor is as follows.

[tex]d = \frac{PM}{RT}[/tex]

Substitute values into the above formula as follows.

[tex]d = \frac{PM}{RT}\\= \frac{0.31 atm \times 74.12 g/mol}{0.0821 L atm/mol K \times 298 K}\\= \frac{22.9772}{24.4658}\\= 0.939 g/L[/tex]

Thus, we can conclude that the density of the given vapor is 0.939 g/L.

CAN YOU PLEASE HELP ME
When Pt electrodes are used in the electrolysis of Kl(aq), a number of reactions are possible at the electrodes. Using a standard reduction potentials table predict which reaction is most likely to occur at the anode​

Answers

anode is oxidation

so look at the reduction potential for Pt and Kl

the one with the smaller reduction potential will undergo oxidation

the one with the larger reduction potential will undergo reduction

you have to flip the equation that undergoes oxidation because the reduction table always gives reduction equations

Draw the Lewis structure for the polyatomic hydronium H3O cation. Be sure to include all resonance structures that

Answers

Answer:

 Lewis structure of Hydronium ion is shown below :                          

Explanation:

Lewis structure : It is a representation of valence electrons on the atoms in a molecule

Here , Hydronium ion is given , which contains 1 atom of oxygen and 3 atoms of hydrogen .

Oxygen has a total of 6 valence electrons and hydrogen contains 1 valence electron .

Oxygen share its 3 valence electrons with 3 hydrogen atoms and left with 3 valence electrons. From these three valence  electrons of oxygen atom  two electrons will be shown as a pair of electrons on oxygen atom but a single electron can not be shown . So , to simplify this, one positive charge is shown overall .  

Resonance structure will be same as the hybrid structure because all  three atoms are same , that is hydrogen .

It takes to break a carbon-hydrogen single bond. Calculate the maximum wavelength of light for which a carbon-hydrogen single bond could be broken by

Answers

The question is incomplete, the complete question is;

It takes 412. KJ/mol to break a carbon-hydrogen single bond. Calculate the maximum wavelength of light for which a carbon-hydrogen single bond could be broken by absorbing a single photon. Round your answer to significant digits.

Answer:

289 nm

Explanation:

The energy of the photon = 412 × 10^3/6.02 × 10^23 = 6.84 × 10^-19 J

From;

E = hc/λ

h= Plank's constant

c= speed of light

λ = wavelength

λ = hc/E

λ = 6.6 × 10^-34 × 3 × 10^8/6.84 × 10^-19

λ = 2.89 × 10^-7 m

λ = 289 nm

Which of the following is true for balancing equations?
A. There must be an equal number of atoms of each element on both sides of the equation.

B. The number of products should be equal to the number of reactants

C. The properties of products should be the same as the properties of the reactants

D. There must be an equal number of compounds on both sides of the equation

Answers

Answer:

A.

Explanation:

An equation with the equal amount and proportion of atoms of each element on both sides of the reaction is commonly referred to as a balanced chemical equation.

The law of conservation of matter asserts that no observable and empirical change in the amount of matter occurs within a conventional chemical process. As a result, each element in the product would have the same equal amount or numbers of atoms as the reactants.

What is the product of the following reaction? K OC(CH3)3

Answers

Answer:

See explanation and image attached

Explanation:

The reaction is an E2 reaction. It is a synchronous reaction.

The base KOC(CH3)3 abstracts a proton as the bromide ion leaves in a single step.

This yields the product as shown in the image attached.

Acetic acid and water react to form hydronium cation and acetate anion, like this:

HCH3CO2(aq) + H2O → H3O+(l)(aq) + CH3CO2^-(aq)

Imagine 226 mmol of CH3CO2- are added to a flask containing a mixture of HCH3CO2, H2O, H3O + and CH3CO2- at equilibrium.

Required:
What is the rate of the reverse reaction before any CH3CO2^- has t:een added to the flask?

Answers

Answer:

The rate of the reverse reaction before any addition of CH3CO2- is zero

Explanation:

When the reaction is in equilibrium:

HCH3CO2(aq) + H2O ⇄ H3O+(l)(aq) + CH3CO2^-(aq)

The reaction quotient, Q = Ka and no more products or reactants are produced because their concentrations are in the right proportion.

Now, as no reaction occurs,

The rate of the reverse reaction before any addition of CH3CO2- is zero

Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant k at 25.0 celsius for the following reaction.
6Cl2(g)+2Fe2O3(s)----->4FeCl3(s)+3O2
Round answer to 2 significant digits.

Answers

Answer:

Explanation:

From the given reaction:

[tex]6Cl_{2(g)}+2Fe_2O_{3(s)} \to 4FeCl_{3(s)}+3O_2[/tex]

From the Gibbs Free Energy table at standard conditions, the value of each compound is as follows:

[tex]G_f^0 \ of \ Cl_2 = 0 \ KJ/mol[/tex]                       [tex]G_f^0 \ of \ Fe_2O_3 = -742.24 \ KJ/mol[/tex]

[tex]G_f^0 \ of \ Fe_2Cl_3 = -334.05 \ KJ/mol[/tex]      [tex]G_f^0 \ of \ O_2 = 0 \ KJ/mol[/tex]

Now, the standard Gibb's Free energy for the given reaction can be estimated as follows:

[tex]\mathtt{\Delta G^0 = (4 *G_f^0(FeCl_3) +3*G_f^0(O_2)) - (6*G_f^0 (Cl_2) +2*G_f^0(Fe_2O_3))}[/tex]

[tex]\mathtt{\Delta G^0 = (4 *(-334.05) +3*(0)) - (6(0) +2(-742.24))}[/tex]

[tex]\mathtt{\Delta G^0 = 148.28 \ kJ/mol}[/tex]

using the following formula:

[tex]\mathtt{\Delta G^0 =-RTIn K_{eq}}[/tex]

the equilibrium constant can  be determined as:

[tex]\mathtt{ In K_{eq} =\dfrac{\Delta G^0 }{-RT}}[/tex]

[tex]\mathtt{ In K_{eq} =\dfrac{148.28*10^3 J/mol }{-(8.314 \ J/k mol )*298 \ K}}[/tex]

[tex]\mathtt{ In K_{eq} =-59.85}[/tex]

[tex]\mathtt{ K_{eq} =e^{-59.85}}[/tex]

[tex]\mathtt{ K_{eq} =1.0*10^{-26}}[/tex] to 2 significant figures.

How many hydrogen atoms are in 3.90 mol of ammonium sulfide?

Answers

Answer:

First, the number of ammonium sulfide molecules should be calculated:

N = NA × n,

where NA - the Avogadro number, n - number of moles.

N (ammonium sulfide) = 6.022 × 1023 × 8.5 mol = 51.187 × 1023.

The moelcular formula of ammonium sulfide is (NH4)2S. It means that each molecule contains 8 hydrogen atoms.

As a result, 8.5 mol of (NH4)2S contain:

51.187 × 1023 × 8 = 41 × 1024 hydrogen atoms.

Answer: 41 × 1024 hydrogen atoms

If the volume of the gas is increased to 9.6 L , what will the pressure be?

Answers

The pressure will be 438 mm Hg

According to the kinetic-molecular theory, gas molecules have
ANSWER:
Part
A. Less energy than molecules of a solid.
B. strong interactions between molecules.
C. little distance between molecule
D. weak interactions between molecules.

Answers

Answer:

The choose ( D )

weak interactions between molecules.

Answer:

Explanation:

el     a  

3)O que são políticas públicas?​

Answers

Answer:

azertyuiopazertyuiiop

Question 9
2 pts
How many milliliters of 1.0 M HCl needs to be diluted to make 200 mL of a 0.1 M solution?
O 0.2 mL
O 0.02 mL
O 20 mL
2 mL
2 nts

Answers

Answer: There are 20 milliliters of 1.0 M HCl is required to be diluted to make 200 mL of a 0.1 M solution.

Explanation:

Given: [tex]M_{1}[/tex] = 1.0 M,    [tex]V_{1}[/tex] = ?

[tex]M_{2}[/tex] = 0.1 M,    [tex]V_{2}[/tex] = 200 mL

Formula used is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute values into the above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\1.0 M \times V_{1} = 0.1 M \times 200 mL\\V_{1} = \frac{0.1 M \times 200 mL}{1.0 M}\\= 20 mL[/tex]

Thus, we can conclude that there are 20 milliliters of 1.0 M HCl is required to be diluted to make 200 mL of a 0.1 M solution.

A 2,31M solution of trans-4-methyl-2-pentene (C6H12, 85mL) is combined with 7,5mL of 3,55M elemental bromine to form an addition product. With an expectation of 100% yield, more than 25mmols of elemental bromine would be consumed during this chemical process.
a. True
b. False

Answers

Answer:

The statement is false

Explanation:

Number of moles of alkene = 2.31 × 85/1000 = 0.196 moles

Number of moles of Br2 = 3.55 × 7.5/1000 = 0.0266 moles

Given that the reaction is 1:1

1 mole of alkene reacts with 1 mole of bromine

0.196 moles of alkene should react with 0.196 moles of bromine

Hence, to achieve 100%yield, 0.196 moles of bromine and not 25mmols of elemental bromine

Which equation was used by Albert Einstein to explain the photoelectric effect? [E = energy, h= planck's constan, and v = frequency]

Answers

Answer:

E = hv

Explanation:

Energy = planck constant × frequency

Linoleic acid is a polyunsaturated fatty acid found, in ester form, in many fats and oils. Its doubly allylic hydrogens are particularly susceptible to abstraction by radicals, a process that can lead to the oxidative degradation of the fat or oil.

a. True
b. Flase

Answers

Answer:

True.

Explanation:

The information presented in the question above regarding linoleic acid is true. Linoleic acid is, in fact, found in many oils and fats in the ester form. In addition, linoleic acid is considered a polyunsaturated fatty acid, due to the presence of two unsaturations in its composition. Its chemical formula is CH3-(CH2)4-CH=CH-CH2-CH=CH-(CH2)7COOH and it is an essential fatty acid for the human body, as it is essential in the composition of arachidonic acid that is responsible for building muscle, managing body fat thermogenesis, and regulating core protein synthesis.

how to separate and purify the Flufenamic acid from the aqueous layer​

Answers

Answer:

Explanation:

H

Enough of a monoprotic acid is dissolved in water to produce a 1.211.21 M solution. The pH of the resulting solution is 2.882.88 . Calculate the Ka for the acid.

Answers

Answer:

1.44 × 10⁻⁶

Explanation:

Step 1: Given data

Concentration of the acid (Ca): 1.21 MpH of the solution: 2.88

Step 2: Calculate the concentration of H⁺ ions

We will use the definition of pH.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -2.88 = 1.32 × 10⁻³ M

Step 3: Calculate the acid dissociation constant of the acid (Ka)

For a weak monoprotic acid, we will use the following expression.

Ka = [H⁺]²/Ca

Ka = (1.32 × 10⁻³)²/1.21 = 1.44 × 10⁻⁶

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