Identify The domain of the rational function, g(x)= 1/x+3
A (-∞, ∞)
B (-∞, 3)U(3, ∞)
C (-∞, -3]U[-3, ∞)
D (-∞, -3)U(-3, ∞)

Answers

Answer 1

Answer:

The domain is (-∞ , -3) ∪ (-3, ∞) D

Step-by-step explanation:

The domain of the rational fraction is the values of x which make the fraction defined. That means the domain does not contain the values of x which make the denominator equal to 0.

∵ g(x) = [tex]\frac{1}{x+3}[/tex]

The denominator = x + 3

→ Equate the denominator by 0

∵ x + 3 = 0

→ Subtract 3 from both sides

∴ x + 3 - 3 = 0 - 3

x = -3

→ That means the domain can not have -3 because it makes the denominator

   equal to 0

∴ The domain is all values of real numbers except x = -3

∴ The domain = {x : x ∈ R, x ≠ -3}

The domain = (-∞ , -3) ∪ (-3, ∞)


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Answer:

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Step-by-step explanation:

Given that a pack of 6 Gatorades costs 4.50, simply divide 4.50 by 6.

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Step-by-step explanation:

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Answers

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*How to solve*

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Step 2: Multiply by y

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Hope this helps comment below for more questions:)

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Answer:

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Step-by-step explanation:

!

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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≧◡≦

Mocha here! If this answer helped you, please consider giving it brainliest because I would appreciate it greatly. Have a wonderful day!

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

3

1

2

4

=

1

0

3x-1 \cdot \frac{2}{4}=10

3x−1⋅42​=10

Solve

1

Divide the numbers

3

1

2

4

=

1

0

3x-1 \cdot {\color{#c92786}{\frac{2}{4}}}=10

3x−1⋅42​=10

3

1

1

2

=

1

0

3x-1 \cdot {\color{#c92786}{\frac{1}{2}}}=10

3x−1⋅21​=10

2

Multiply the numbers

3

Add

1

2

\frac{1}{2}

21​

to both sides of the equation

4

Simplify

5

Divide both sides of the equation by the same term

6

Simplify

Solution

=

7

2

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Is the point (10,-2) a solution to the equation y = -2x + 16? Explain,
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Answers

Answer:

no

Step-by-step explanation:

y = -2x + 16

-2 = -2(10) + 16

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Plug the point (10,-2) into y = -2x + 16 and solve. If the equation is a true, then yes, it is a point on the equation.

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Now, solve.

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