Identify the slope and y-intercept: y = -x + 13 y help mee please​

Answer:

12,490

+ 3,941

16431

Step-by-step explanation:

Answer:

[tex]x^{\frac{3}{2} } p^{6}[/tex]

Step-by-step explanation:

Answer:

cos N = 7/25 =.28

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj side / hypotenuse

cos N = MN/ LN

We need to find the ad

Using the Pythagorean theorem

a^2+b^2 = c^2

MN^2 + 48^2 = 50^2

MN^2 + 2304 =2500

MN^2 = 2500-2304

MN^2 =196

Taking the square root

MN =14

cos N = MN/ LN

cos N = 14/50

cos N = 7/25

Answer: CosN (0.28)

A²+B²=C²

In this case we are trying to find the base so

C²-A² = B²

So 50² subtract 48²= B²

2,500 subtract 2,304 = 196

Square root of 196 = 14

Now we have all 3 sides of the triangle we find

Soh Cah Toa

Cah means Cos=Adjacent / hypotenuse

First we identify the Angle before we can decide which of the sides is labelled opposite anx adjacent

We have Angle N and we know our hypotenuse (The longest side of the triangle)

The opposite of the angle would be our opposite and the one thats niether our opposite or hypotenuse is our adjacent

In this cse the angle we solved for B²= 14

Again back "Cah" Cos= Adjacent/hypotenuse

So, 14/50 = 0.28

Step-by-step explanation:

This can be interpreted as Tamika bought 9 gallons of milk and no toilet paper

From the graph given, we can see that the line touches the x-axis at (9, 0). Hence the x-intercept of the line is at (9, 0).

Since x represents gallons of milk and y represents the packages of toilet paper, therefore from the coordinate x = 9 and y = 0. This can be interpreted as Tamika bought 9 gallons of milk and no toilet paper

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Answer: a rectangular poster has an area of 260 square inches.the width of the poster is greater than 10 inches and is a prime number

Step-by-step explanation: a rectangular poster has an area of 260 square inches.the width of the poster is greater than 10 inches and is a prime number.what is the width

Answer:

10

Step-by-step explanation:

1) The vector CD is equal to (X-(-14); 13-6)= (x+14; 7)

2) The module of the vector CD is equal to diatance CD=25. It is equal to

 sqrt ((x+14)(x+14)+7*7) from the formula of module (with coordinates).

25= sqrt ((x+14)(x+14)+7*7)

625= (x+14)*(x+14)+49

625= x^2+28x+196+49

X^2+28X-380=0

a=1 b=28 c=-380

D= b*b-4ac= 28*28-4*1*(-380)= 784+1520= 2304

sqrt D= sqrt2304=48

x1= (-28-48)/2= -38

x2= (-28+48)/2= 10

But x1<0 it is negative and it is not suitable, x2>0 it is positive, so answer is 10.

Answer:

Step-by-step explanation:

25*-30= -$750

Second: He sells 22 of those calculators for $35 each, so he is making money.

22*35= $770

Third: With the remaining three calculators, he must pay $2 each for returned calculators, so he is losing money again.

3*-2= -6

Add all the costs and sales together, and you get 770-750-6= $14 profit

However, the problem does not say if he gets his money back for the 3 returned calculators. In that case if he did, you would add the cost of each of those calculators to his profit. 30*3= 90

$90+$14= $104 profit

here u go

Answer: y/y+x

Step-by-step explanation: Reduce the fraction at the bottom (1 - x/y) (1 + x/y) = 1 + x/y = simplify and you get y/y+x

Answer:

25%

Step-by-step explanation:

1 dozen = 12

3 out of 12

3/12

Simplify

1/4

Multiply top and bottom by 25 to get a denominator of 100

25/100

25%

Answer:

12 mathletes is needed to solve 30 problems in 5 minutes

Step-by-step explanation:

8 athletes can solve 20 problems in 10 minutes

30-20=10

now we need 10 more problems to be solved so

20/2=10. 8/2=4 so we need more 4 mathletes to solve all the problems

Hi there!

[tex]\large\boxed{y = \frac{x + 4}{7}}[/tex]

f(x) = 7x - 4

Rewrite f(x) with y:

y = 7x - 4

Swap the x and y variables:

x = 7y - 4

Solve for y:

x + 4 = 7y

y = (x + 4)/7

Answer:

jejejjejejr

Step-by-step explanation:

uejejjejejjsjs

I would go with C as a first step

The correct answer is C (that is equating f(x) and g(x))

A quadratic polynomial has highest degree 2 and a linear polynomial has highest degree 1.

In geometric sense, solving them means finding the point of intersection of curves:

In X-Y plane, these polynomials can be written as:

[tex]y=-x^{2} +2x+3\\y=-2x+3[/tex]

Taking the value of y from second equation and substituting it in first equation we get,

[tex]-x^{2} +2x+3=-2x+3[/tex]

Therefore, with the above procedure, we got the first step of solving the equations with the help of substitution.

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Answer:

O I, II, and III only

Step-by-step explanation:

x-3 < 2

Add 3 to each side

x-3+3< 2+5

x<5

-3 is less than 5

0 is less than 5

2 is less than 5

5 is not less than 5

I , II , II are true

Answer:

x > 5

Step-by-step explanation:

-5-7x < -40

Add 5 to each side

-5+5-7x < -40+5

-7x < -35

Divide by -7, remembering to flip the inequality

-7x/-7 > -35/-7

x > 5

Open circle at 5, going to the right

Answer:

1) a³b⁴/ ab³ = a²b

2)2 (x³ )² = 2x^6

3)3x*2x³ y² = 6x⁴y²

Answer:

-19 = b

Step-by-step explanation:

76 = -4b

Divide each side by -4

76/-4 = 4-b/-4

-19 = b

Answer:

b = -19

Step-by-step explanation:

76 = -4b

shift -4 to the left hand side and when you shift -4 divides 76

76/-4 = b

-19 = b

Answer:

Therefore 3/10 is closer to ½

Step-by-step explanation:

We've to get the difference:

» with 3/10 :

[tex] \frac{1}{2} - \frac{3}{10} = { \boxed{\frac{1}{5} }}[/tex]

» with 5/7

[tex] | \frac{1}{2} - \frac{5}{7} | = { \boxed{ \frac{3}{14} }}[/tex]

but:

[tex] \frac{3}{14} > \frac{1}{5} [/tex]

Among both the given fractions, the one that is closer to a ½ is 3/10.

A number that is stated as a quotient in mathematics, when the numerator and denominator are split in half. Both are integers in a straightforward fraction. In the numerator or denominator of a complex fraction is a fraction.

An element of a whole or, more broadly, any number of equal pieces, is represented by a fraction. When used in conversational English, a fraction indicates the number of components of a particular size, as in one-half, eight-fifths, and three-quarters.

A fraction is a number that represents a portion of a whole. In order to evaluate it, a whole is divided into a number of components.  A correct fraction has a numerator that is lower than its denominator.

Required calculations are done with both the fractions,

1/2 - 3/10 = 1/5

1/2 - 5/7 = 3/14

3/14 ≥ 1/5

Therefore, among both the given fractions, the one that is closer to a ½ is 3/10.

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Answer:

yes it is the 10th term in the series

Step-by-step explanation:

The nth term of a geometric sequence is

[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]

where a₁ is the first term and r the common ratio

Here a₁ = 7 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{14}{7}[/tex] = 2 , then

[tex]a_{n}[/tex] = 7 [tex](2)^{n-1}[/tex]

Equate [tex]a_{n}[/tex] to 3584 and solve for n

7 [tex](2)^{n-1}[/tex] = 3584 ( divide both sides by 7 )

[tex]2^{n-1}[/tex] = 512 , that is

[tex]2^{n-1}[/tex] = [tex]2^{9}[/tex]

Since the bases on both sides are equal, both 2 , then equate the exponents

n - 1 = 9 ( add 1 to both sides )

n = 10

3584 is the 10th term in the series

Answer:

Option D, 52

Answered by GAUTHMATH

Answer:

73

Step-by-step explanation:

Answer:

[tex]h^{-1}[/tex] (t) = [tex]\frac{7-t}{6}[/tex]

Step-by-step explanation:

let y = h(t) and rearrange making t the subject

y = - 6t + 7 ( add 6t to both sides )

6t + y = 7 ( subtract y from both sides )

6t = 7 - y ( divide both sides by 6 )

t = [tex]\frac{7-y}{6}[/tex]

Change y back into terms of x with t = [tex]h^{-1}[/tex] (t)

[tex]h^{-1}[/tex] (t) = [tex]\frac{7-t}{6}[/tex]

Answer:

126 was removed.

Step-by-step explanation:

The total before division took place was

Total = mean * 14

mean = 49

Total = 49 * 14

Total = 685

Now you subtract x from the total

685 - x

And divide by 13 [one number is missing]

(685 - x)/13

and the result = 43

(685 - x ) / 13 = 43                Multiply both sides by 13

685 - x  = 43 * 13

685 - x = 559                       Subtract 685 from both sides

- x = - 126                             Multiply by - 1

x = 126

Answer:

f(9) = - 59

Step-by-step explanation:

Substitute x = 9 into f(x) , that is

f(9) = - (9)² + 9 + 13

     = - 81 + 22

    = - 59

Answer:

-59

Step-by-step explanation:

f(x) =-x^2+x+13

Let x = 9

f(9) = - (9)^2 +9+13

       = -81 +9+13

      = -59

Answer:

4746

Step-by-step explanation:

Answer:

x = 46

Step-by-step explanation:

Assuming DE is an angle bisector , then it divides the opposite side into segments that are proportional to the other 2 sides, that is

[tex]\frac{HD}{DG}[/tex] = [tex]\frac{EH}{EG}[/tex] , substitute values

[tex]\frac{x+4}{58}[/tex] = [tex]\frac{55}{63.8}[/tex] ( cross- multiply )

63.8(x + 4) = 3190 ( divide both sides by 63.8 )

x + 4 = 50 ( subtract 4 from both sides )

x = 46

The steps to create attached screenshot of the inscribed circle of triangle ΔABC using GeoGebra tools includes;

1) Clicking on the Geometry link, under Powerful Math Apps group

2) On the opened Geometry page click on the Polygon icon and follow the instructions that come up, which is Select all vertices and then the first vertex (selected) again (a second time)

3) Once the triangle is created, select the Angle Bisector icon, under the Construct group; A message will appear, asking to Select three points or two lines, select three vertex, of the triangle created with a mouse click, with the vertex A in the center, such as BAC, or CAB a straight line representing the angle bisector of angle ∠A is created

4) Repeat the above to create the angle bisector of angle ∠B

5) Click on the Point button under the Basic Tools group, then click on the intersection of the two angle bisectors created above, the point will be automatically labelled point D

6) Click on the Perpendicular Line, icon under the Construct group, then click on point D, and then the line AB to draw the perpendicular from D to AB

7) Click on the point Point icon and then the intersection point of the perpendicular from D and AB to label the point E

8) Click on the Circle with Center basic tool and then points D and E above, to create the inscribed circle of triangle ΔABC

9) Select the Segment tool, then select the center of the circle and a point

on the circumference. Click on the label, from the pop up options, select

the label option AA then change the label of the segment created to Radius

and select Show Label and Show Value. The inscribed circle of ΔABC created with GeoGebra tools is attached

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Answer:

Step-by-step explanation: from edmentum