Identify the transformation that occurs to create the graph of m(x)
m(x)=f(5x)

Answer:

The answer for both linear equations is A. x = 2, y = 7

Step-by-step explanation:

First start by plugging in the variables with the given numbers (2,7). We'll start with 6x + 3y = 33.

6x + 3y = 33

6 (2) + 3 (7 )= 33 <--- This is the equation after the numbers are plugged in.

12 + 10 = 33

33 = 33 <---- This statement is true, therefore it is the correct pair.

Now we are not done, to confirm that this pair works with both equations we need to solve for 4x + y = 15 to see if it works. Linear Equations must have the variables work on both equations.

4x + y = 15 <----- We are going to do the exact same thing to this equation.

4(2) + 7 = 15

8 + 7 = 15

15 = 15  <-- 15=15 is a true statement therefore this pair works for this equation.

Therefore,

A. x = 2, y = 7 is the correct answer

Sorry this is a day late, I hope it helps.

Answer:

3.15 seconds is the answer.

Explanation

when the ball touches the ground, h =0

hence,

0=255-21t-16t²

16t²+21t-225=0

here a=16 ,b=21, c= -225

[tex]t= \frac{ - b± \sqrt{ {b }^{2} - 4ac} }{2a} \\ \\ t= \frac{ - 21± \sqrt{ {21}^{2} - 4 \times 16 \times - 225} }{2 \times 16} \\ = \frac{ - 21 ± \sqrt{441 - ( - 14400)} }{32} \\ = \frac{ - 21± \sqrt{14841} }{32} \\ = \frac{ - 21±121.82}{32} \\ \\ t = \frac{ - 21 + 121.82}{32} \: or \: \: t = \frac{ - 21 - 121.82}{32} \\ t = 3.15 \: \: or \: \: t = - 4.46[/tex]

time cannot be negative, hence t = -4.46 can be avoided

The ball takes 3.15 seconds to hit the ground.

Answer:

$138.72

Step-by-step explanation:

(1-0.999578)*$240,000 = $101.28

$240 - $101.28 = $138.72

Answer:

what is the question

pls mark me as brainlist

Thank you for the points

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

Given:

First lamp rating

Power (P) = 100W

Voltage (V) = 110V

Second lamp rating

Power (P) = 100W

Voltage (V) = 220V

Source

Voltage = 220V

i. Get the resistance of each lamp.

Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e

P = [tex]\frac{V^2}{R}[/tex]

Make R subject of the formula

⇒ R = [tex]\frac{V^2}{P}[/tex]             ------------------(i)

For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)

R₁ = [tex]\frac{110^2}{100}[/tex]

R₁ = 121Ω

For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)

R₂ = [tex]\frac{220^2}{100}[/tex]

R₂ = 484Ω

ii. Get the equivalent resistance of the resistances of the lamps.

Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e

R = R₁ + R₂

R  = 121 + 484

R = 605Ω

iii. Get the current flowing through each of the lamps.

Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e

V = IR [From Ohm's law]

I = [tex]\frac{V}{R}[/tex]

I = [tex]\frac{220}{605}[/tex]

I = 0.36A

iv. Get the power consumed by each lamp.

From Ohm's law, the power consumed is given by;

P = I²R

Where;

I = current flowing through the lamp

R = resistance of the lamp.

For the first lamp, power consumed is given by;

P = I²R           [Where I = 0.36 and R = 121Ω]

P = (0.36)² x 121

P = 15.68W

For the second lamp, power consumed is given by;

P = I²R           [Where I = 0.36 and R = 484Ω]

P = (0.36)² x 484

P = 62.73W

Therefore;

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

Answer:

the correct answer is 3

hope it helps

have a nice day

12.8, pythagorean theorem.

Answer:

0.1357 = 13.57% probability that the proportion of flops in a sample of 572 released films would be greater than 6%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

A film distribution manager calculates that 5% of the films released are flops.

This means that [tex]p = 0.05[/tex]

Sample of 572

This means that [tex]n = 572[/tex]

Mean and standard deviation:

[tex]\mu = p = 0.05[/tex]

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.05*0.95}{572}} = 0.0091[/tex]

What is the probability that the proportion of flops in a sample of 572 released films would be greater than 6%?

1 subtracted by the p-value of Z when X = 0.06. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.06 - 0.05}{0.0091}[/tex]

[tex]Z = 1.1[/tex]

[tex]Z = 1.1[/tex] has a p-value of 0.8643

1 - 0.8643 = 0.1357

0.1357 = 13.57% probability that the proportion of flops in a sample of 572 released films would be greater than 6%

Answer:

[tex]x=6\\y=4[/tex]

Step-by-step explanation:

Elimination method:

[tex]x+5y=26[/tex]

[tex]-x+7y=22[/tex]

Add these equations to eliminate x:

[tex]12y=48[/tex]

Then solve [tex]12y=48[/tex] for y:

[tex]12y=48[/tex]

[tex]y=48/12[/tex]

[tex]y=4[/tex]

Write down an original equation:

[tex]x+5y=26[/tex]

Substitute 4 for y in [tex]x+5y=26[/tex]:

[tex]x+5(4)=26[/tex]

[tex]x+20=26[/tex]

[tex]x=26-20[/tex]

[tex]x=6[/tex]

{ [tex]x=6[/tex] and [tex]y=4[/tex] }    ⇒ [tex](6,4)[/tex]

hope this helps...

Answer:

x = 6, y = 4

Step-by-step explanation:

x + 5y = 26

- x + 7y = 22

_________

0 + 12y = 48

12y = 48

y = 48 / 12

y = 4

Substitute y = 4 in eq. x + 5y = 26,

x + 5 ( 4 ) = 26

x + 20 = 26

x = 26 - 20

x = 6

Answer:

37

Step-by-step explanation:

7 + (5×6)

= 7 + 30

= 37

.................

Answer:

37

Step-by-step explanation:

First Step: Multiply

5x6=30

Second Step: Add

30+7=37

Therefore your answer is 37

Hope this helps and if it does, don't be afraid to give my answer a "Thanks" and maybe a Brainliest if it's correct?  

Answer:

The motion of the particle describes an ellipse.

Step-by-step explanation:

The characteristics of the motion of the particle is derived by eliminating [tex]t[/tex] in the parametric expressions. Since both expressions are based on trigonometric functions, we proceed to use the following trigonometric identity:

[tex]\cos^{2} t + \sin^{2} t = 1[/tex] (1)

Where:

[tex]\cos t = \frac{y-3}{2}[/tex] (2)

[tex]\sin t = x - 1[/tex] (3)

By (2) and (3) in (1):

[tex]\left(\frac{y-3}{2} \right)^{2} + (x-1)^{2} = 1[/tex]

[tex]\frac{(x-1)^{2}}{1}+\frac{(y-3)^{2}}{4} = 1[/tex] (4)

The motion of the particle describes an ellipse.

Answer:

The function that passes through (0, 0) is [tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} - \frac{1}{6}[/tex].

Step-by-step explanation:

Firstly, we integrate the function by algebraic substitution:

[tex]\int {x^{2}\cdot e^{2\cdot x^{3}}} \, dx[/tex] (1)

If [tex]u = 2\cdot x^{3}[/tex] and [tex]du = 6\cdot x^{2} dx[/tex], then:

[tex]\int {e^{2\cdot x^{3}}\cdot x^{2}} \, dx[/tex]

[tex]\frac{1}{6}\int {e^{u}} \, du[/tex]

[tex]f(u) = \frac{1}{6}\cdot e^{u} + C[/tex]

[tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} + C[/tex]

Where [tex]C[/tex] is the integration constant.

If [tex]x = 0[/tex] and [tex]f(0) = 0[/tex], then the integration constant is:

[tex]\frac{1}{6}\cdot e^{2\cdot 0^{3}} + C= 0[/tex]

[tex]C = -\frac{1}{6}[/tex]

Hence, the function that passes through (0, 0) is [tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} - \frac{1}{6}[/tex].

Answer:

Where is the diagram though..

Step-by-step explanation:

Answer:

[tex]\implies \dfrac{2}{10}< \dfrac{3}{10} [/tex]

Step-by-step explanation:

We need to compare the given two fractions .The given fractions are ,

[tex]\implies \dfrac{3}{10} [/tex]

[tex]\implies \dfrac{1}{5} [/tex]

Firstly let's convert them into like fractions . By multiplying 1/5 by 2/2 . We have ,

[tex]\implies \dfrac{1}{5} =\dfrac{1*2}{5*2}=\dfrac{2}{10} [/tex]

Now on comparing 2/10 and 3/10 we see that ,

[tex]\implies 2< 3 [/tex]

Therefore ,

[tex]\implies \dfrac{2}{10}< \dfrac{3}{10} [/tex]

Answer:

2x 2 - y + 5 + 3

Step-by-step explanation:

2ggfdfguutffyreryyrrrrrrrr

Answer:

y = 26.3x² - 116.9x + 109.6

Step-by-step explanation:

Given the data ;

Year Period Users (Millions)

2004 1 1

2005 2 5

2006 3 11

2007 4 58

2008 5 145

2009 6 359

2010 7 607

2011 8 846

A quadratic regression model can be obtained using a quadratic regression calculator ; The quadratic regression modeled obtained is in the form :

y = Ax² + Bx + C

y = 26.3x² - 116.9x + 109.6

Answer:

D. It will increase by 1%.

Step-by-step explanation:

Given

[tex]u_1 = 5\%[/tex] --- initial rate

[tex]u_2 = 3\%[/tex] --- final rate

Required

The effect on the GDP

To calculate this, we make use of:

[tex]\frac{\triangle Y}{Y} = u_1 - 2\triangle u[/tex]

This gives:

[tex]\frac{\triangle Y}{Y} = 5\% - 2(5\% - 3\%)[/tex]

[tex]\frac{\triangle Y}{Y} = 5\% - 2(2\%)[/tex]

[tex]\frac{\triangle Y}{Y} = 5\% - 4\%[/tex]

[tex]\frac{\triangle Y}{Y} = 1\%[/tex]

This implies that the GDP will increase by 1%

Answer: A. It will increase by 7%.

Step-by-step explanation: I took this course!

Answer:

0.5759

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

the sum of 8,5,15,12,10 is 50 and there are 5 numbers so 50 divided by 5 is 10 and it's mean is also 10

hope this helps !

9514 1404 393

Answer:

  (c)  x = 12.5

Step-by-step explanation:

  -0.2(x -4) = -1.7

  -0.2x +0.8 = -1.7 . . . eliminate parentheses using the distributive property

  -0.2x = -2.5 . . . . . . subtract 0.8

 x = 12.5 . . . . . . . . divide by -0.2

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that [tex]P(A) = 0.8[/tex]

If you have passed subject A, the probability of passing subject B is 0.8.

This means that [tex]P(B|A) = 0.8[/tex]

Find the probability that the student passes both subjects?

This is [tex]P(A \cap B)[/tex]. So

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

[tex]P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64[/tex]

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

[tex]p = P(A) + P(B) - P(A \cap B)[/tex]

Considering [tex]P(B) = 0.7[/tex], we have that:

[tex]p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86[/tex]

0.86 = 86% probability that the student passes at least one of the two subjects

Answer:

50,000 : 0.01

multiply by 100...

5000000 : 1

 1:5,000,000

Step-by-step explanation:

Answer:

x P(x)

0 0.4167

1 0.5

2 0.0833

3 0

Step-by-step explanation:

The speedometers are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this question:

7 + 2 = 9 speedometers, which means that [tex]N = 9[/tex]

2 are not correctly calibrated, which means that [tex]k = 2[/tex]

3 are chosen, which means that [tex]n = 3[/tex]

Complete the probability distribution table.

Probability of each outcome.

So

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,9,3,2) = \frac{C_{2,0}*C_{7,3}}{C_{9,3}} = 0.4167[/tex]

[tex]P(X = 1) = h(1,9,3,2) = \frac{C_{2,1}*C_{7,2}}{C_{9,3}} = 0.5[/tex]

[tex]P(X = 2) = h(2,9,3,2) = \frac{C_{2,2}*C_{7,1}}{C_{9,3}} = 0.0833[/tex]

Only 2 defective, so [tex]P(X = 3) = 0[/tex]

Probability distribution table:

x P(x)

0 0.4167

1 0.5

2 0.0833

3 0

Hello!

(6a/8+3) + 7a/8 =

= 6a/11 + 7a/8 =

= 125/88 × a

Good luck! :)

Answer:

y= (-6/5)x+3

Step-by-step explanation:

6x+5y=15

Divide everything by 5

(6/5)x + y = 3

Move (6/5)x to the other side of the = sign by subtracting

y= (-6/5)x + 3

That's your answer!

Hope it helps!

Answer:

[tex]\frac{(2/36)}{(1-(28/36))} = 1/4[/tex]

Step-by-step explanation: