Answer:
37x - 13
Step-by-step explanation:
Hello!
The product of 37 and x mean multiply so we can write it as
37x
13 less means subtract so we put that at the end
37x - 13
The answer is 37x - 13
Hope this helps!
Answer:
37 * x - 13
This answer is here according to your question It said that 37*x - 13 Please mark this answer The brainliest one
Please answer question
Answer:
87.6yd²
Step-by-step explanation:
Base: =1/2bh
=1/2(6)(5.2)=15.6
Sides: =1/2bh
=1/2(6)(8)=24 (3 of them)
15.6+24+24+24=87.6yd²
What expression has the same value as -3/2-(2-3/8)+3/2
Answer:
[tex]\dfrac{-3}{2}-(2-\dfrac{3}{8})+\dfrac{3}{2}=\dfrac{-13}{8}[/tex]
Step-by-step explanation:
We need to find the value of expression [tex]\dfrac{-3}{2}-(2-\dfrac{3}{8})+\dfrac{3}{2}[/tex].
Firstly solving the second term as :
[tex](2-\dfrac{3}{8})=\dfrac{16-3}{8}=\dfrac{13}{8}[/tex]
Now the above expression becomes,
[tex]\dfrac{-3}{2}-(2-\dfrac{3}{8})+\dfrac{3}{2}\\=\dfrac{-3}{2}-\dfrac{13}{8}+\dfrac{3}{2}[/tex]
-3/2 and +3/2 equals 0.
It means that, [tex]\dfrac{-3}{2}-(2-\dfrac{3}{8})+\dfrac{3}{2}=\dfrac{-13}{8}[/tex]
need help please. Will give you 5-stars and a big thank you comrades
Answer:
first answer
Step-by-step explanation:
(8x³ - 22x² - 4) / (4x - 3)
when you do long division you get the first answer
PLEASE HELP! 17 points! Use the right-hand rule for magnetic force to determine the charge on the moving particle. This is a _____ charge.
Answer: Positive Charge
Answer:
negative
Step-by-step explanation:
When using the Right-Hand Rules, it is important to remember that the rules assume charges move in a conventional current (the hypthetical flow of positive charges). In order to apply either Right-Hand Rule to a moving negative charge, the velocity (v) of that charge must be reversed--to represent the analogous conventional current.
The opposite charge is a negative charge.
find the area of a rhombus with a 120 degree angle and sides 10 cm
Answer:
A = 50√3 cm²Step-by-step explanation:
[tex]A=s^2\cdot \sin\alpha\\\\s=10\\\alpha=120^o\\\\A=10^2\cdot\sin(120^o)=100\sin(180^o-60^o)=100\sin(60^o)=100\cdot\frac{\sqrt3}2=50\sqrt3[/tex]
27 – 4 + 2a = 4a + 10 what is the answer
Answer:
13/2 = a
Step-by-step explanation:
27 – 4 + 2a = 4a + 10
Combine like terms
23 +2a = 4a +10
Subtract 2a from each side
23+2a-2a = 4a-2a +10
23 = 2a+10
Subtract 10 from each side
23-10 = 2a+10-10
13 = 2a
Divide by 2
13/2 = a
Answer: a = 13/2
I assume you don't need a step - by - step, you're just asking for the answer. Hope this helps!
In a college test, students receive 4 points for every question answered correctly and loses 7 points for every question answered incorrectly. On this particular test, Terry answered 87 questions correctly and 46 questions incorrectly. What is his score for the test?
Answer:Her score is 26
Step-by-step explanation:
To find the answer, we must deduct the total amount of points that are answered correctly
By the total amount of points that are answered incorrectly.
Because = 1 answered correctly = 4 points
= 1 answered incorrectly = deduct 7
points
So= 87 answered correctly × 4 points
= 348 points
So= 46 answered incorrectly × 7 points
=deduct 322 points
Then the answer will be= 348 - 322= 26
Hope this helps!
) What should be subtracted from -5/3 to get 5/6?
Answer:
[tex]-\frac{5}{2}[/tex]
Step-by-step explanation:
Step 1: Put this into an equation
[tex]-\frac{5}{3} - x = \frac{5}{6}[/tex]
Step 2: Solve for x
[tex]-x = \frac{5}{6} + \frac{5}{3}[/tex]
[tex]-x = \frac{5}{2}[/tex]
[tex]x =- \frac{5}{2}[/tex]
Therefore you need to subtract [tex]-\frac{5}{2}[/tex] from [tex]-\frac{5}{3}[/tex] to get [tex]\frac{5}{6}[/tex]
Answer:i don’t know
Step-by-step explanation:I’m sorry dude I have no idea I tried doing it in the browser and I could not find an answer sorry
i need to know the area
Answer:
I got option 1.
Step-by-step explanation:
See pictures
If v=5 and w=24, what is 5v+w?
Answer:
49
Step-by-step explanation
5v + w
5(5) + 24
25 + 24
49
First you have to substitute the variables with numbers given (v=5 ; w=24)
Start with multiplying 5*5 which equals 25, then finish off with adding the two numbers.
Answer:
5v+w = 5(5)+24 = 49
Step-by-step explanation:
As you can see we have two variables
v & w
And we have no coefficient to w but we do to v which is...
5
So... we must replace the variables (v & w) replacing them with the numbers you gave us, 5 for v and 24 for w.
The sentence is
5v+w= ?
If you replace v with 5 it becomes...
5(5)+w
When seeing a number & a variable or numerous variables that placed right next to each other, it means that the number and the variable(s) are to be multiplied together.
So now we have 5(5)+w meaning 5 times 5 plus the variable w
The second value you gave us is 24 which is supposed to be subbed in for w.
So... when we replace w with 24 we get...
5(5)+24
Now we evaluate the expression.
According to PEMDAS... since we have no parenthesis or exponents we do m, multiplication first. 5*5=25
We are now left with...
25+24
25 + 24 = 49.
So...
5v+w is now 5(5)+24 which is equal to...
49
Hopefully this helped you!
Have a good day!
A portion of the Quadratic Formula proof is shown. Fill in the missing reason. A: Multiply the fractions together on the right side of the equation? B: Subtract 4ac on the right side of the equation? C: Add 4ac to both sides of the equation? D: Add the fractions together on the right side of the equation?
Answer:
Combine numerators over the common denominator to make one term
Step-by-step explanation:
Answer:
D: Add the fractions together on the right side of the equation
Step-by-step explanation:
Let's finish this proof:
Add the fractions together on the right side of the equation
[tex]$x^2+\frac{b}{a} x+\left(\frac{b}{2a} \right)^2=\frac{b^2-4ac}{4a^2} $[/tex]
[tex]\text{Consider the discriminant as }\Delta[/tex]
[tex]\Delta=b^2-4ac[/tex]
Once we got a trinomial here, just put in factored form:
[tex]$\left(x+\frac{b}{2a}\right)^2=\frac{\Delta}{4a^2} $[/tex]
[tex]$x+\frac{b}{2a}=\pm\frac{\Delta}{4a^2} $[/tex]
[tex]$x+\frac{b}{2a}=\pm \sqrt{\frac{\Delta}{4a^2} } $[/tex]
[tex]$x=-\frac{b}{2a}\pm \sqrt{\frac{\Delta}{4a^2} } $[/tex]
[tex]$x=-\frac{b}{2a}\pm \frac{ \sqrt{\Delta} }{2a} $[/tex]
[tex]$x= \frac {-b\pm \sqrt{\Delta}}{2a} $[/tex]
[tex]$x= \frac {-b\pm \sqrt{b^2-4ac}}{2a} $[/tex]
A can do a piece of work in 10 days and B in 12 days.
With the help of C they can finish the work in 4 days. How
long will C take to do it alone?
a) 12 days b) 15 days c) 18 days d) 20 days
Answer:
B. 15 days
Step-by-step explanation:
A=10=1/10 of the job
B=12=1/12 of the job
A+B+C=4=1/4 of the job
A+B
=1/10 + 1/12
=10+12/120
=22/120
=11/60
(A+B+C) - (A+B)
=1/4 - 11/60
=5 - 11/60
=4/60
=1/15
It would take C alone 15 days to finish the job
Simplify to create an equivalent expression.
5(10k + 1) + 2(2+8k)
Answer:
66k+9
Step-by-step explanation:
Let's simplify step-by-step.
5(10k+1)+2(2+8k)
Distribute:
=(5)(10k)+(5)(1)+(2)(2)+(2)(8k)
=50k+5+4+16k
Combine Like Terms:
=50k+5+4+16k
=(50k+16k)+(5+4)
=66k+9
Answer:
=66k+9
HOPE THIS HELPS!!!!!! :)
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What is the area of this composite figure?
Answer:
C.) 7.14 in²
Step-by-step explanation:
The figure is made up of a square and a circle. The circle is divided in half and each piece is set on one side of the square. This means that the diameter of the circle is equal to the length of the sides of the square, 2 inches.
The area of the square can be found by multiplying length times the width:
[tex]2*2=4[/tex]
The area of the square is 4 inches, and since we multiplied two lengths, we square the value:
A=4in²
Now find the area of the circle using the formula:
[tex]A=\pi r^2[/tex]
The radius is half of the diameter, so the radius is 1. Insert values and solve:
[tex]A=\pi *1^2\\\\A=\pi *1\\\\A=\pi[/tex]
The area of the circle is equal to π. Add the values together:
[tex]4+\pi =7.14[/tex]
The area of the figure is 7.14 in²
:Done
help me im dangered plzzzzzzzzzzzzzzzzzzzz
Answer:
A
Step-by-step explanation:
Hi!
An exponent is the same thing as just multiplying the expression by itself the number of times the exponent says. So we need to multiply 1/3 by itself three times.
1/3 * 1/3 * 1/3 = 1/27
HELP ASAP!!!! URGENT!!! LOOK AT SCREENSHOT! Identify all points and line segments in the picture below. This image has the potential for visual bias, so there is no alternative text. Select one: a. Points: A, B Line segments: bar(AB) b. Points: A, B, C, D Line segments: bar(AB) c. Points: A, B, C, D Line segments: bar(AB), bar(BC), bar(CD), bar(AD), bar(BD), bar(AC) d. Points: A, B, C, D Line segments: bar(AB), bar(AC), bar(BD)
Answer:
the answer is D
stagg high school has a rectangular swiming pool the area of the water in the pool is 1,800 meters squared the length is twice the width what is the perimeter of the pool find the length and width. SHOW WORK
Step-by-step explanation:
L*b=1800m^2
L=2b
2b*b=1800
2b^2=1800
b^2=900
b=30m
L=2*30
=60m
Perimeter=2(l+b)
=2(60+30)
=2*90
=180m
solve 2(1/9)× = 2/81 for x
Answer: x=1/9
Step-by-step explanation:
[tex]2\left(\frac{1}{9}\right)x=\frac{2}{81}[/tex]
[tex]\frac{2}{9}x=\frac{2}{81}[/tex]
multiply both sides by 9
[tex]9\cdot \frac{2}{9}x=\frac{2\cdot \:9}{81}[/tex]
[tex]2x=\frac{2}{9}[/tex]
divide 2 on both sides
[tex]x=\frac{1}{9}[/tex]
4/5x - 1/10 = 3/10
what is the value of x ?
Answer:
x = 1/2Step-by-step explanation:
[tex]\frac{4}{5}x-\frac{1}{10}=\frac{3}{10}\\\\\mathrm{Add\:}\frac{1}{10}\mathrm{\:to\:both\:sides}\\\\\frac{4}{5}x-\frac{1}{10}+\frac{1}{10}=\frac{3}{10}+\frac{1}{10}\\\\\frac{4}{5}x=\frac{2}{5}\\\\\mathrm{Multiply\:both\:sides\:by\:}5\\\\5\times \frac{4}{5}x=\frac{2\times \:5}{5}\\\\4x=2\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\\\frac{4x}{4}=\frac{2}{4}\\\\x=\frac{1}{2}[/tex]
Answer:
1/2
Step-by-step explanation:
isolate variable
solve
how to find the theta with side lengths of a triangle
Step-by-step explanation:
Hello, there!!!
I hope you mean the question is like the above problem in picture.
so, let's simply work with it.
here, we may use cosine rule,
so, according to cosine rule,
[tex] {c}^{2} = {a}^{2} + {b}^{2} - 2ab.cosc[/tex]
so, just put value of formulae here,
we get;
5^2 = 3^2 + 4^2 - (2×3×4) . cos thita
or, 25 = 9 + 16 -24 cos thita.
or, 24 cos thita = 0
or, cos thita = 0/25
or, cos thita = 0
now, taking cos to right side we get,
[tex] {cos}^{ - 1 } (0)[/tex]
now, after typing cos ^-1 (0) we get angle as 90°.
(note: in step {cos thita = 0} you couold directly write like; cos thita = cos 90°. and cos would be cancelled in it as cos 90°=0. but it is only applied in particular angle like 0°,30°,60°,..... which are identified or if you don't know you must use the method above using calculator and remember to put inverse {cos^-1}).
so, In this way we find angle.
I hope it helps....
a man stride is 7/8 metre long. how many strides does he take in walking a distance of 98m
Answer:
112
Step-by-step explanation:
To find the number of strides, divide the distance by the distance per stride:
(98 m)/(7/8 m/stride) = (98)(8/7) strides = 112 strides
He takes 112 strides in walking 98 m.
Find f(x) and g(x) so the function can be expressed as y = f(g(x)). (1 point) [tex]y=\frac{7}{x^{2} } +10[/tex]
Answer:
The functions are [tex]f(x) = 7\cdot x+10[/tex] and [tex]g(x) = \frac{1}{x^{2}}[/tex], respectively.
Step-by-step explanation:
Let suppose that [tex]g(x) = \frac{1}{x^{2}}[/tex], then [tex]f(g(x))[/tex] is:
[tex]f(g(x)) = 7\cdot \left(\frac{1}{x^{2}} \right) + 10[/tex]
[tex]f(g(x)) = 7\cdot g(x) + 10[/tex]
Thus,
[tex]f(x) = 7\cdot x + 10[/tex]
The functions are [tex]f(x) = 7\cdot x+10[/tex] and [tex]g(x) = \frac{1}{x^{2}}[/tex], respectively.
Please help me!!! I need this ASAP!!!
Answer:
number ten: x=5
number two: x=5³/5
Step-by-step explanation:
number ten:
4x + 3x - 9 = 26
4x + 3x = 26+9
7x = 35
x = 5
number two:
3x + 2x - 8 = 20
3x + 2x = 20+8
5x = 28
x = 5³/5
HELP ASAP ITS SO HARD! Kelsey did the following division problem. Her teacher says that the quotient she found is wrong. −2 5/6 ÷ 1 1/3 −17/6 ÷ 4/3 −6/17• 3/4 −6×3 divided by 17×4 −18/68 −9/34 A. Identify what Kelsey did wrong in her calculations. B. Find the correct quotient, showing all of your calculations.
Part A
Her steps were
[tex]-2 \frac{5}{6} \div 1 \frac{1}{3}\\\\-\frac{17}{6} \div \frac{4}{3}\\\\-\frac{6}{17} \times \frac{3}{4}\\\\-\frac{6\times 3}{17\times4}\\\\-\frac{18}{68}\\\\-\frac{9}{34}\\\\[/tex]
Kelsey made a mistake on line 3. Note how the 17/6 flips to 6/17. This is not correct. You keep the first fraction the same, but you do flip the second fraction. This only applies when you divide two fractions.
The third step should look like [tex]-\frac{17}{6}\times \frac{3}{4}[/tex]
=======================================================
Part B
Here's what she should have written
[tex]-2 \frac{5}{6} \div 1 \frac{1}{3}\\\\-\frac{17}{6} \div \frac{4}{3}\\\\-\frac{17}{6} \times \frac{3}{4}\\\\-\frac{17\times 3}{6\times 4}\\\\-\frac{51}{24}\\\\-\frac{17}{8}\\\\[/tex]
If you want to convert that improper fraction to a mixed number, then you could do something like this
[tex]-\frac{17}{8} = -\frac{16+1}{8}\\\\-\frac{17}{8} = -\frac{16}{8}-\frac{1}{8}\\\\-\frac{17}{8} = -2 \frac{1}{8}\\\\[/tex]
Or you could divide 17 over 8 using long division to get 2 remainder 1. The 2 is the quotient that goes to the left of the 1/8. The remainder of 1 is the numerator of 1/8.
Find the missing probability: P(B)=7/20, P(A|B)=1/4, P(A∩B)=?
Answer:
P(A∩B) = 7/80
P(A∩B) = 0.0875
Step-by-step explanation:
Given
P(B)=7/20
P(A|B)=¼
Required
P(A∩B)=?
The given probability shows conditional probability and the relationship between the given parameters is as follows.
P(A∩B) = P(B) * P(A|B)
Substitute ¼ for P(A|B) and 7/20 for P(B)
The expression
P(A∩B) = P(B) * P(A|B) becomes
P(A∩B) = 7/20 * ¼
P(A∩B) = 7/80
P(A∩B) = 0.0875
Hence, the calculated P(A∩B) is 7/80 or 0.0875
How many solutions does this system of inequalities have graphed below
Answer:
There is only one solution set.
Step-by-step explanation:
The set can contain any number of solutions or none.
This is all I know, hope it helps.
I also need to know this one pretty soon pleaseee
Answer:
128
Step-by-step explanation:
Simplify the following: (74) (6/4)
Answer:
111
Step-by-step explanation:
Reducing the given expression:
74(6) 37(6) 111
--------- = ---------- = ---------- = 111
4 2 1
Answer:
[tex] \boxed{111}[/tex]Step-by-step explanation:
[tex] \mathsf{(74) \times ( \frac{6}{4} )}[/tex]
To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.
⇒[tex] \mathsf{ \frac{74 \times 6}{4 \times 1} }[/tex]
⇒[tex] \mathsf{ \frac{444}{4} }[/tex]
⇒[tex] \mathsf{111}[/tex]
[tex] \mathrm{Hope \: I \: helped !} [/tex]
[tex] \mathrm{Best \: regards !}[/tex]
1. Escribe las razones de los siguientes enunciados: a. En una clase de un colegio cada pelota es utilizada por cada equipo de cinco niños, o sea que tenemos cinco alumnos por cada pelota de fútbol. b. En un estacionamiento hay coches de fábricas asiáticas y de fábricas americanas. En total hay 3060 coches, de los cuales, 1740 son de fabricación asiática y el resto, 1320, son de fabricación americana. (es urgentee.. Es para una tarea)
Answer:
a. 5 n/p o 1 p/ 5n
b. 1720 autos asia/3060 autos, o 1320 autos USA/3060 autos
Step-by-step explanation:
Se entiende como razón a la fracción que compara dos elementos entre sí.
Por ejemplo en una clase de 24 alumnos donde 15 son mujeres y 9 son varones, podemos decir que:
- Por cada 15 mujeres hay 9 varones 9/15
- Por cada 9 varones hay 15 mujeres, 15/9
Para el ejercicio a. nos cuentan que 1 pelota es utilizada cada 5 niños, por lo que la razón la podemos escribir como 1/5, 1 pelota cada 5 o directamente 5, ya que por cada 5 alumnos, tenemos 1 pelota.
El ejercicio b es más fácil: ya tenemos el total de autos, 3060. Entonces:
- Cada 3060 autos, 1720 son asiáticos
- Cada 3060 autos, 1320, son americanos
A sequence of transformations is described below. A reflection over a line \overleftrightarrow{PQ} PQ P, Q, with, \overleftrightarrow, on top A rotation about the point PPP Another reflection over \overleftrightarrow{PQ} PQ P, Q, with, \overleftrightarrow, on top A rotation about the point QQQ Which of the following must be preserved under this sequence of transformations? Choose 1 answer: Choose 1 answer: (Choice A) A Angle measures only (Choice B) B Segment lengths only (Choice C) C Both angle measures and segment lengths (Choice D) D Neither angle measures nor segment lengths
Answer:
The correct option is;
(Choice C) Both angle measures and segment lengths
Step-by-step explanation:
The given transformations are;
The reflection over the line, [tex]\overleftrightarrow{PQ}[/tex], with, A rotation about the point P. Another reflection over [tex]\overleftrightarrow{PQ}[/tex]. A rotation about the point Q, we have;
The transformations involve changes only in the orientation and location of the pre-image, which remain rigid, therefore, there are no changes in the segment lengths or angle dimensions
Therefore, the correct option is, both angle measures and segment lengths.
(Choice C) C Both angle measures and segment lengths