With each amplitude change, 3 bits can be broadcast across 8 frequencies, including 000,001,010,011 and 100,101,110,111.
What function does amplitude serve?With the use of group analytics, Amplitude, a platform of product analytics, enables businesses to track visitor activity. The platform uses behavioral reports to understand how people interact with products and provides insights to accelerate work in real-time.
What is an illustration of amplitude?It refers to the greatest departure an item in periodic motion can make from equilibrium. As an illustration, consider a pendulum that swings through its market equilibrium (straight down), then swings to the furthest point from the center.
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do i need to adjust the tension on my elna super sewing machine when using denim fabric and 100/16 needles?
A tension of 3.5 to 4.5 is advised when sewing tough fabric, such denim or leather. This allows you to effortlessly maintain neatness across the fabric when sewing through it. Before starting to sew any thick material, check the attachments on your sewing machine and adjust the tension.
Depending on the thickness of the denim, I use a straight-stitch length between 3.0 mm and 4.0 mm. I also increase the tension on my machine to 4.6 (up from 4.0 for lightweight woven fabrics). If my denim has spandex in it, I use a stretch stitch, such as a narrow zigzag.
Linen, cotton and denim: These fabrics hold wrinkles well, so they require the highest heat, from 150 to 200 degrees. If needed, you may also use steam or spray water from a bottle or your iron.
The longer the stitch length, the easier and faster it will be to pull the fabric along the gathering threads. However, the shorter the stitch length, the easier it will be to achieve even gathers. We find a 4.5 mm setting to be a good compromise, but it's always a good idea to test and see what you prefer.
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how fast would she have to be running for her race to appear to her to be only 91 yd long? give your answer in terms of c.
1.81*10^8m/s is the speed with which she have to be running for her 100m race to appear to be only 91 yard long.
What is the Speed?The rate at which an object's location changes in any direction is what is known as speed. The distance traveled in relation to the time it took to travel that distance is how speed is defined. The Speed just has a direction and does not have magnitude hence, speed is a scalar quantity.Solution:Given:
Race length=100M=L
she has to appear=91yd
to find this we need to
[tex]L_{o}[/tex]=100M
1 yard =0.9144 meter
hence, L=91yard*0.9144/1
[tex]L_{o[/tex]=83.2104m
now do as follows:
L=[tex]L_{o}[/tex][tex]\sqrt{1-\frac{v^{2} }{c^{2} } }[/tex]
Solving the equation we get
v=2*9.88^8*[tex]\sqrt{\frac{83.21^{2} }{100^{2} } }[/tex]
v=1.81*10^8m/s
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The complete question is:
How fast would she have to be running for her 100m race to appear to be only 91 yard long? give your answer in terms of c.
Between which two points on the heating curve is the substance melting
The Curve horizontal or plateaued lines represent the change in the sample's states. The first plateau is a symbol of melting and the second one is a symbol of boiling (or transition from liquid to gas).
What does a heating curve's melting point represent?Phase changes are another name for the plateaus. Melting is the initial state shift (section BC) (changing from a solid to a liquid). While a substance melts, the temperature remains constant. This temperature is 0°C for water as that is also its melting point.
What does a substance's heating curve look like?A heating curve is a plot or graph that charts the increase in temperature of a substance over time to determine
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WILL GIVE BRAINLY IF RIGHT
what would happen if you dropped, at the same time, particles of different shapes from a boat into still water
Explanation:
If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.
11. Mac and Tosh are arguing in the cafeteria. Mac says that if he flings the Jell-O with a
greater speed it will have a greater inertia. Tosh argues that inertia does not depend
upon speed, but rather upon mass. Who do you agree with? Explain why.
I agree with Tosh because inertia depends on mass. So Mac is wrong.
What is Newton's first law of motion?Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.
Newton's first law of motion is also called the law of inertia because it depends on the mass of the object.
Inertia is the reluctance of an object at rest to start moving or the relictance of an object in motion to stop moving. The greater the mass of an object, the greater the inertia of the object.
Thus, Mac is wrong while Tosh is right because inertia does not depend on the speed of an object rather, it depends on the mass of the object.
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Question 8 of 20
You heat a pot of water on a gas stove. Not all the energy from the
combustion of the gas is transformed into thermal energy. What happens to
the rest of the energy released when the gas burns?
OA. It is transformed into light energy.
OB. It is transformed into chemical energy.
C. It is transformed into electrical energy.
OD. It is transformed into nuclear energy.
SUBMIT
Answer:
None of the choices you provided are correct. When a gas burns, it releases energy in the form of heat and light. Some of this energy is transferred to the pot of water, increasing its temperature, but some of the energy is also released as light. However, the rest of the energy is not transformed into chemical, electrical, or nuclear energy. Instead, it is lost to the environment in the form of waste heat. This is why gas stoves can become hot to the touch - they are releasing excess energy in the form of heat that is not being used to heat the pot of water.
Explanation:
Three point charges are arranged in a straight line. The point charges are q1 = 10.0 μC, q2 = –40.0 μC, and q3 = –30.0 μC. Charge q1 is 10.0 cm from charge q2, and charge q3 is 20.0 cm from charge q2. Determine the magnitude of the net electric force on charge q1.
Let us find first the forces at 1, 2 & 3 points.
We know that ke= 8.99 * 109N.m2 / C2
The forces are: -
F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2
F1 = 359.6 N
F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2
F2 = 29.96 N
F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2
F3 = 269.7 N
Now,
The net force on q1 is F1 – F2,
i.e. F1 + F2 = 359.6 + 29.96
F(q1) = 389.56 N to the left
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find the maximum transverse speed of a point on the string. (f) what would be the equation y1x, t2 for this string if it were vibrating in its eighth harmonic?
In a one-dimensional string, a harmonic wave has a maximum transverse velocity and maximum transverse acceleration of 1ms-1 and 1ms-2, respectively.
What is maximum transverse speed of a point on the string?We have attached a harmonic wave with a frequency of 80 Hodge to the string. Additionally, a positive extraction travels at a speed of 12 m/s with an amplitude of 0.025 m. Next, we must create a proper wave function for this wave in the first. In light of this.
we have established that the frequency F is the hurt amplitude is 0.025 m, and the speed is 12 m/s. As a result, given that we are aware of the wave function's writing, we may determine whether or not the sign K x minus omega T applies. Omega, which equals two pi into, is the angular frequency in this case. Thus, we can say that this word has been introduced. 80 is to be purchased That makes 160 by, too.
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x-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequency. suppose an x-ray camera uses x-rays with a wavelength of 4.04. calculate the frequency of the x-rays.
If an X-ray camera uses X-rays with a wavelength of 4.04. the frequency of the x-rays is 36.9 PHz.
Compared to ultraviolet rays and gamma rays, X-rays have a wavelength of 0.01–10 nm, which corresponds to frequencies in the range of 3×10⁻¹⁶–3×10⁻¹⁹ Hz and energies in the range of 100 eV to 100 keV.
using, C=Lf,
Where C is the speed of light,
L stands for wavelength
Given,
C= 8.13 nm = 8.13* 10-9 m
f=C/L
f= (3x108m/s) / (8.13^ 10-9 m)
f= 3.69 x1016Hz (10 PHz = 1016Hz)
hence frequency, f= 36.9 PHz
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sir lancelot, who weighs 800 n, is assaulting a castle by climbing a uniform ladder that is 5.0 m long and weighs 180 n. the bottom of the ladder rests on a ledge and leans across the moat in equilibrium against a frictionless, vertical castle wall. the ladder makes an angle of 53.1 deg with the horizontal. lancelot pauses one third of the way up the ladder. (a) find the normal force and friction forces on the base of the ladder. (b) find the minimum coefficient of static friction needed to prevent slipping at the base. (c) find the magnitude and direction of the contact force on the base of the ladder. (that is, the vector sum of the forces at the base.)
(a) The normal force is 267.7 N and frictional force is 980 N.
(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.
(c) The direction of the contact force is 1016 N.
∈(t) = 0
N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )
N₂ = 267.7 N
(a) Normal force F(d) = N₂ = 267.7 N
Frictional force N = 800 + 180
N = 980 N
(b) The minimum coefficient of static friction,
F(d) = μ N₁
μ = F / N₁
μ = 267.7 / 980
μ = 0.27
(c) The direction of the contact force,
R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]
R = 1016 N
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what is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then released from rest, and whose period is 0.66 s ? assume that the displacement at the start of the motion is positive.
Answer:
x = A cos ω t at t = zero, x displacement equals amplitude
x = .088 m cos ω t describes the motion
We need yet to find ω in terms of P which is given
ω = √(k / m)
P = 1 / f and f = ω / (2 π)
Thus ω = 2 π f = 2 π / P since 1 / f = P
This gives us
x = .088 m cos 2 π / .66 * t
A student is investigating inertia and acceleration. The data the student collects is shown in the table.
Force (N) Mass (kg) Acceleration (m/s²)
10
10
20
20
1
2
1
2
b
Oc
Od
Assuming the force acting on the objects is constant, which claim about inertia and acceleration is supported by the data?
0.1
0.2
Next Page
0.05
0.1
An object with a lower mass has less inertia which causes it to speed up less quickly.
An object with a higher mass has more inertia which causes it to speed up less quickly.
An object with a higher mass has less inertia which causes it to speed up more quickly.
An object with a lower mass has more inertia which causes it to speed up more quickly.
Back
Assuming the force acting on the objects is constant, a claim about inertia and acceleration which is supported by the data include the following: B. An object with a higher mass has more inertia which causes it to speed up less quickly.
What is Newton's First Law (Inertia)?Newton's First Law of Motion is also referred to as Law of Inertia and it states that an object in motion would continue in its state of motion at continuous velocity (same speed and direction) or if at rest, it will remain at rest unless it is acted upon by an external force.
This ultimately implies that, the amount of net force keeping a physical object moving at a constant speed and in a specific direction is always equal to zero (0) newton in accordance with Newton's First Law of Motion.
In this context, we can reasonably infer and logically deduce that a physical object that has a higher mass would have more inertia, which causes it to either experience a slower motion or speed up less quickly.
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Answer: its c
Explanation: i took the test
if a river has an average width of 20 m, an average depth of 2 m, and is flowing with a velocity of 3 m/s, what is its discharge? give your answer in cubic meters/second.
answer is 120 cubic meters/second
Briefing
if a river has an average width of 20 m,Width (W)= 20 m
width of 20 m,Depth (D)= 2 m
flowing with a velocity of 3 m/s, Velocity(V)= 3m/s
Discharge = V x D x W
Discharge = 20 × 2 × 3 =120 m3/s
Discharge is 120 cubic meters/second
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if the minute hand has a mass of 130 kg, what is the torque being applied by the mass of the minute hand itself?
The torque being applied by the mass of the minute hand itself is 3470.303N-m. if it has mass of 130kg.
In material science and mechanics, torque is a standard mechanical amount, what might be compared to direct force.[1] It is likewise alluded to as the snapshot of power (likewise shortened to second). It addresses the capacity of a power to deliver change in the rotational movement of the body. The idea began with the examinations by Archimedes of the use of switches, which is reflected in his well known expression: "Give me a switch and a spot to stand and I will move the Earth". The law of preservation of energy can likewise be utilized to grasp force. The image for force is ordinarily , the lowercase Greek letter tau. While being alluded to as snapshot of power, it is normally signified by M.
Torque is given by the formula=r×F
or Torque=rFsinθ
Now,we have r=6meter,F=130 ˣ 9.8=1274N,θ=27°,sin27°=0.453
So,Torque=6 ˣ 1274ˣ0.453
=>Torque=3470.303N-m.
Hence,torque applied by the mass is 3470.303N-m.
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(Complete question) is:
if the minute hand has a mass of 130 kg, what is the torque being applied by the mass of the minute hand itself?length of minute hand is 6 meters long,and angle made by minute hand is 27 degrees.
9. A piece of iron with a mass of 9.8 g has an initial temperature of 32.6°C. As it is heated, it absorbs 365J of energy. What is the final temperature of the iron? (The specific heat of iron is .46 J/g °C)
The final temperature of the piece of iron with the mass of 9.8 grams on the absorption of 365J of energy is 113.56°C.
What is Specific heat capacity?
The specific heat capacity of a material can be defined as the quantity of heat energy (J) which is absorbed per unit mass (kg) of the material when its temperature is increased by 1 K (or 1 °C). The SI unit of specific heat capacity is J/(kg K) or J/(kg °C).
The specific heat capacity of a material can be calculated by the formula:
Q = m × c × ΔT
where, Q = heat energy,
m = mass of the material,
c = specific heat capacity,
ΔT = change in temperature
The final temperature of the piece of iron can be calculated by the formula:
Q = m × c × ΔT
ΔT = (Final temperature - initial temperature)
365J = 9.8 × 0.46 × ΔT
365J = 4.508 × ΔT
ΔT = 80.96
ΔT = Final temperature = initial temperature
ΔT = (T - 32.6)
80.96 = (T - 32.6)
T = 80.96 + 32.6
T = 113.56°C
Therefore, the final temperature of the piece of iron is 113.56°C.
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a system releases heat to the surroundings and no work is done on or by the system. what are the signs of qsystem and wsystem?
Heat that is emitted into the environment is harmful. The system's work output is zero.
The movement of mechanical energy from one item to another is referred to as work. Work is measured in the same units as energy since it is a movement of energy: joules (J). The total energy of an object will change as a force is applied to it across a distance. The object's kinetic energy will vary as a result of either acceleration or deceleration. Its potential energy will change, for instance, if it is raised up to a given height while being pulled by gravity.
Hence, sign are used based on the release and absorbed.
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when you look at a single slit diffraction pattern produced on a screen by light of a single wavelength, you see a bright central maximum and a number of maxima on either side, their intensity decreasing with distance from the central maximum. if the wavelength of the light is increased:_____.
The pattern gets bigger as the light wave length gets longer. other maxima are further from the central one and are wider.
What wavelength does it have?A wavelength is the distance between two identical locations (adjacent crests) in successive cycles in a waveform signals that is transmitted by a wire or in space. Typically, this length is expressed in feet (m), millimeters (cm), or millimeters (mm) in wireless systems (mm).
What do wavelengths and frequencies refer to?The distance that separates two wave crests is known as the wavelength, and it also applies to troughs. The number of vibrations that pass across a certain area in a second, or 60hz (Hz), is the unit of measurement for frequency (Hertz).
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a simple harmonic oscillator takes 11.5 s to undergo five complete vibrations. (a) find the period of its motion. s (b) find the frequency in hertz. hz (c) find the angular frequency in radians per second. rad/s
The required values are a) T = 2.3 seconds, b) f = 0.434 Hz, c) ω = 2.7 rd/s.
Which of the following motions is simply harmonic?Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.
According to question:Given,
Time = 11.5 seconds to five complete vibrations.
a) Time period is time taken to complete one vibration,
So T = 11.5/5 = 2.3 seconds
b) Frequency(f) = 1/T
f = 1/2.3 = 0.434 second inverse.
c) By using formula of angular frequency ω = 2π/T
ω = 2π/2.3 = 2.7 hz
Thus, final values are a) T = 2.3 seconds, b) f = 0.434 second inverse, c) ω = 2.7 rd/s.
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a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?
The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.
To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.
Now, we know that momentum =mass × velocity
So, initial momentum of first object=6.2×3=18.6Kg-m/sec
Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec
Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg
Now, both objects are moving with common velocity, so assume both have velocity v
=>So, final momentum of both objects is =14.2×v
according to law of conservation of momentum
=>18.6+25=14.2v
=>43.6=14.2v
=>v=43.6/14.2
=>v=3.07m/sec
Hence, final velocity of objects are 3.07m/sec.
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b) how far will the cart move in the 4.5 s if the shopper places a(n) 84 n child in the cart before pushing it? answer in units of m.
The cart of the supermarket will move 3.99 m if the shopper places an 84 N child in cart and is pushing.
Given that,
Mass of the cart = 25.1 kg
Horizontal force = 13.3 N
It is pushed for 3.6 sec
Mass of the cart and child = Total force/ Acceleration = (25.1* 9.8 + 84)/9.8 = 33.67 kg
From the equations of motion, we know,
Initial velocity = 0
Time t = 4.5 s
Distance s = ut + 1/2* a* t² = 0 + 1/2* (13.3/33.67)* (4.5)² = 3.99 m
Thus, the cart will move for 3.99 m after placing the child.
The question is incomplete. The complete question is 'A shopper in a supermarket pushes a loaded cart with a horizontal force of 13.3 Newtons. The cart has a mass of 25.1 kg and is pushed for 3.60 seconds, starting from rest.'
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there must be equal amounts of mass on both side of the center of mass of an object.T/F
An object's centre of mass must be surrounded by an equal amount of mass on both sides. It is untrue.
Does an object's centre of mass have to be located there?The centre of mass of an item typically, but not always, sits within the thing itself. For instance, a ball's centre of mass is located in its exact centre, while a book's centre of mass is located in its middle.
When two masses are equivalent, what happens?When two objects of equivalent mass and speed approach one another, they stay together. After staying together, the two surfaces come to rest while retaining motion but losing kinetic energy. several of the energy of motion gets converted to thermal energy, or heat.
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let's say you see a comet's nebulous (meaning `cloudy-looking') tail stretching across the sky, and it's several million kilometers long. how big is the solid object that has developed this tail, and what's it made of?
The solid object that created the comet's nebulous tail is likely the nucleus of the comet, which is typically made of ice, dust, and rocky material.
What is comet?Comet is a web application development technique that enables web applications to send and receive data from a server asynchronously without the need for a browser page refresh. It creates an interactive user experience by enabling a continuous connection between the client and server so that data can be exchanged in both directions. This type of communication is also known as a bi-directional, full-duplex connection. Comet is an umbrella term for several techniques for achieving this kind of communication.
The nucleus of a comet can range in size from a few hundred meters to tens of kilometers, though their average size is typically around 5 kilometers. As the comet approaches the Sun, its frozen material turns to gas, which is pushed away from the Sun by the solar wind and forms the nebulous tail that stretches millions of kilometers across the sky.
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a 1,402-kg car rounds an unbanked curve with a radius of 53 m at a speed of 9.9 m/s. what minimum coefficient of friction must exist between the road and tires to prevent the car from slipping?
To keep the car from slipping, the road and tires need to have a minimum coefficient of friction of 0.188.
The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, but it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible. Yes. Because the adhesive forces between molecules are stronger when the contact surface is substantially polished, frictional force increases. In this situation, the friction coefficient will be higher than one.
Here m= 1402 kg
r=53
v= 9.9 m/s
g=9.8
coefficient = (v^2) / rg
coefficient = (9.9^2) / (53*9.8)
coefficient = 98.01/519.4
coefficient = 0.188
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A fast ride at Six Flags makes a circular loop. If the tangential speed of the cart as it moves around the loop is 10 m/s, and the radius of the loop is 5 m, what is the centripetal acceleration of the cart as it moves around the loop?
The centripetal acceleration of the Cart is 20 m/s2.
What is centripetal acceleration?Centripetal acceleration is a change in velocity that points toward the center of a circular path. It is the acceleration an object experiences when its velocity changes direction, but its speed remains constant. It is always directed toward the center of the circle and is caused by a force, such as gravity or friction. The magnitude of the centripetal acceleration is equal to the square of the object's velocity divided by the radius of the circle. Examples of centripetal acceleration include the motion of a satellite orbiting the Earth, a car rounding a curve, and a roller coaster car making a loop.
Given that,
Speed of the Cart = 10m/s
Radius of the loop = 5m
We know that the acceleration of the car can be computed as follows:
a = v2/R
a = (10.0 m/s)2/(5.0 m)
a = 20.0 m/s2
Thus, the centripetal acceleration of the Cart is 20 m/s2
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a motorcyclist moves at a constant speed down one hill and up another hill along the smooth curved surface. when the motorcyclist reaches the lowest point of the curve its velocity and acceleration directions are: (a) (b) (c) (d) 5. a car moves along the curved track. what is the apparent weight of the driver when the car reaches the lowest point of
At the lowest point of the curve, the motorcyclist's velocity would be tangential to the curve.
Motorcyclists' velocity would be parallel to the surface of the road. The acceleration of the motorcyclist would be directed opposite the direction of the velocity, meaning it would be directed uphill.
At the lowest point of the curve, the direction of the net force on the driver, Fn, would be directed towards the center of the curve. This is because the velocity of the driver is tangential to the curve, and the centripetal force is directed toward the center of the curve to provide the necessary acceleration to keep the driver on the curve.
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Can someone please help me with this calculation? It's a bit confusing for me.
You are calculating the average speed, velocity, and acceleration of a toy car.
I'm not sure what the speed of the toy car was or the acceleration. I only have the times of the meters.
first meter: 2.00, second meter: 4.00, third meter: 6.20, fourth meter: 8.01, fifth meter: 10:13, sixth meter: 12:13, seventh meter: 14:13, eighth meter: 16:14, ninth meter 18:18 and tenth meter: 20:00.
Answer the following questions.
Did the car travel at a constant speed? (Hint: you must calculate the speed at every meter)
What was the average speed of the car?
Describe the overall motion of the car.
What are some practical applications for determining the motion of an object?
Answer: See Explanation
Explanation:
Did the car travel at a constant speed?
This means "Is the speed at each interval the same?"
There are 10 intervals for which to calculate from.
For each one, the speed is the distance traveled divided by the time.
Each interval is 1 meter long (distance).
1st: 1 meter / 2.00 s = 0.5 m/s
2nd: 1 meter / (4.00 - 2.00) s = 0.5 m/s
3rd: 1 meter / (6.2 - 4.0) s = 0.454 m/s
Right here you can see that the speed is different, NO is the answer.
Average Speed = total distance divided by total time
v = d / t v = (10 m) / (20:00 s) = 0.5 (m/s)
Describe the overall motion: (continue on with step one to see the total motion over the 10 meters)
4th: 0.552
5th: 0.472
6th: 0.5
7th: 0.5
8th: 0.4975
9th: 5.39
10th: 0.55
Overall motion stayed steady from 0-2 meters, slowed for the 3rd meter, sped up for the 4th, slowed down the 5th, stayed steady until slowing down in the 8th meter, then increased speed til the 10th meter.
Races would be practical applications to see where people/cars pace themselves, push themselves, etc.
imagine that five 10.0-ohm resistors are connected in parallel. what is the effective resistance of this combination of resistors?
The effective resistance of five 10.0-ohm resistors is
Resistance is property of a material to measure the amount of restriction provided to the charge particles during the current flow.
Its SI unit is ohm, represented by a Greek symbol 'Ω'.According to the Ohm's law, resistance can be defined as the ratio of voltage to the current supplied in the circuit.Mathematically R = (V/I)R1 = 10 Ohms
R2 = 10 Ohms
R3= 10 Ohms
R4 = 10 Ohms
R5 = 10 Ohms
Re = Effective Resistance = ?
Since they are in parallel connections, the equivalent resistance (Re) can be calculated as follows :
1/Re = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5
1/Re = 1/10 + 1/10 + 1/10 + 1/10 + 1/10
1/Re = ( 1+1+1+1+1)/10
1/Re = 5/10
1/Re = 1/2
Cross multiply to express in linear form
Re = 0.5 ohms
Therefore the equivalent resistance of this combination of resistors is 0.5 ohms.
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which deductible level would result in the lowest premium for automobile insurance?
The deductible level that would result in the lowest premium for automobile insurance is from $250 or $500
Is a greater or lower deductible preferable?For those who anticipate needing expensive medical care or continuous medical treatment, a plan without a deductible typically offers good coverage and is a wise decision.
In most circumstances, a plan's premium will be lower the larger its deductible. You save money on what you pay each month when you're willing to pay more up front when you need care.
The typical range for a comprehensive deductible suggested by insurance agents is between $100 and $500. It makes sense to have a smaller deductible for comprehensive claims because they often involve less damage than collision claims.
High-deductible health plans typically have cheaper premiums but need greater upfront payments before insurance will cover medical expenses. Meanwhile, higher premiums are typically associated with health insurance plans with lower deductibles since they provide more predictable expenses and frequently more robust coverage.
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A 20 kg wagon is pulled along the level ground by a rope inclined 30 degrees above the horizontal (friction is
negligible) (A) How large is the pulling force is the wagon accelerates of .40 m/s²? (B) What is the normal force of
the wagon?
Answer:
(A) 9.2 Newtons
(B) 200.8 Newtons
Explanation:
Attached is the free body diagram I drew along with some of the work/formulas I used. Please ask me any questions you have in the comments about my diagram/work. I'd be happy to walk you through it.
The adjacent figure shows a solid 'S' of weight 15N connected to a thread and put on an inclined plane. 1) a-Is the weight of solid 'S' a contact force or a force acting from a distance? b- List the characteristics of the weight of solid 'S'. Thread Inclined plane c- Represent the weight of solid 'S' by a vector. Choose a convenient scale. 2) a- Name the other forces acting on solid 'S' and indicate their types. b- Represent each force by a vector without respecting a scale. c- List the characteristics of each of the above forces. (Without the magnitude) 3) The thread is cut and solid 'S' moves as shown in the adjacent figure a- Name the new force that acts on solid 'S' and indicate its type. b- List the characteristics of this force.(scale 1cm-1.3N). Thread Inclined plane Solid 'S' Solid 'S'
Answer:
Here is answer
Explanation:
a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.
b) The characteristics of the weight of solid 'S' are:
It acts in the downward direction.
It is a gravitational force that is exerted by the Earth on the solid 'S'.
It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).
c) The weight of solid 'S' can be represented by a vector as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
[/asy]
a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.
b) These forces can be represented by vectors as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));
label("$N$", (7.5sqrt(2),7.5), NE);
draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));
label("$F_f$", (-7.5sqrt(2),-7.5), SW);
[/asy]
c) The characteristics of these forces are:
The normal force acts perpendicular to the surface of the inclined plane.
The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.
The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.
The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.
a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.
b) The characteristics of the gravitational force are:
It acts in the downward direction.
It is a force that is exerted by the Earth on the solid 'S'.
Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):
[asy]
unitsize(1cm);
draw((0,0)--(0,-1.3),Arrow(6));
label("$W$", (0,-0.65), S);
[/asy]
