If (93 × p) + 84 = 8593 times p plus 84 equals 85, then p equals:.

Answers

Answer 1

The solutions of  (93 × p) + 84 = 8593 times p plus 84 equals 85 yields  p =  84/8500 or 1/8593.

We can write the equation as follows;

(93 × p) + 84 = (8593  × p) + 84 = 85

We can solve the equation in parts as follows;

(93 × p) + 84 = (8593  × p) + 84

93p + 84 = 8593p

93p - 8593p = -84

-8500p = -84

p = 84/8500

Also;

(8593  × p) + 84 = 85

8593p + 84 = 85

p = 85 - 84/8593

p = 1/8593

Hence p = 84/8500 or 1/8593

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Answer:

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Hence, a product comprises the finished goods that gives satisfaction to a customer's needs and wants.  

A product mix is also referred to as product portfolio or product assortment and it can be defined as a complete set of products that are being offered by a business firm, for sale to consumers.

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The second detail "He knew he had the courage to blast through tacklers and the toughness to work all day in the beetroot fields, but this seemed harder" indicates that the author's intention is to entertain, as it uses descriptive language to create a sense of drama and tension.

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Answer:

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Answers

Answer:

0.8041

Explanation:

0.8041

We know that  

μ=72  and  σ=5

and P(65<X<78)

We can determine the Z value as (X-μ)/σ

P( 65<X<78 )=P( 65-72< X-μ<78-72)

P((65-72)/5 < Z < (78-72)/5)P((65−72)/5<Z<(78−72)/5)

P(65 < X < 78 )=P(-1.4 < Z < 1.2)P(65<X<78)=P(−1.4<Z<1.2)

To fine the Z values:

P (-1.4 < Z < 1.2 )=P ( Z < 1.2 )-P (Z < -1.4 )P(−1.4<Z<1.2)=P(Z<1.2)−P(Z<−1.4)

From the standard normal tables:

P (Z < 1.2 )=0.8849P(Z<1.2)=0.8849

to find P ( Z<-1.4)

P ( Z < -a)=1-P ( Z < a )P(Z<−a)=1−P(Z<a)

From the standard normal tables:

P ( Z < -1.4)=1-P ( Z < 1.4 )=1-0.9192=0.0808P(Z<−1.4)=1−P(Z<1.4)=1−0.9192=0.0808

Therefore

P(-1.4 < Z < 1.2 )=0.8041P(−1.4<Z<1.2)=0.8041

P (65 < X < 78)=0.8041P(65<X<78)=0.8041

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