If a conductor is in electrostatic equilibrium near an electrical charge i.e. the correct option is, B) The electric field inside the conductor must be zero.
Because charge carriers can freely move within a conductor, when a charged or uncharged conductor is exposed to an external electric field, charge will flow until a steady state is reached, at which point the net flow of charge will cease. This state is known as electrostatic equilibrium. If the conductor is charged, the charges within it are rearranged, resulting in a zero net electric field inside the conductor. The net field inside the conductor again becomes zero if the conductor is polarized after being neutral.A neutral or charged conductor will typically achieve electrostatic equilibrium with a net zero electric field inside of it when it is kept close to an electric charge.The conductor in electrostatic equilibrium has characteristics such as a zero electric field inside and excess charges that are located on the surface. Therefore, the conductor's internal electric field must be zero.
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A certain 50.0-Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 13.0 kV/m. (a) What is the wavelength of this very low frequency electromagnetic wave? (b) What is its maximum magnetic field strength?
An electromagnetic wave radiating from a specific 50.0-Hz AC power line has a maximum electric field strength of 13.0 kV/m. This extremely low frequency electromagnetic pulse has a wavelength of 6.00 x [tex]10^{6}[/tex]m.
An electromagnetic wave is what?A sinusoidal graph illustrates electromagnetic waves. It is made up of time-varying electric and magnetic fields that are perpendicular to each other and to the direction that waves travel.
How do wavelength and frequency relate to one another?Inverse proportionality describes the relationship between frequency and wavelength. Longer wavelengths are correlated with lower frequency, and vice versa. The fact that a wave's speed is equal to the product of its frequency and wavelength helps to explain how these two properties are related.
Briefing:
Given that,
Frequency of the power line, f = 50.0 Hz
Value of maximum electric field strength of 13.0 kV/m
The wavelength of this very low frequency electromagnetic wave is given by using relation as:
[tex]c = f[/tex]λ
λ [tex]= \frac{c}{f}[/tex]
λ [tex]= \frac{3.8 * 10^{8} m/s }{50}[/tex]
λ = 6 x [tex]10^{6}[/tex] m
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A 50 gg mass rotates in a vertical plane--call it the xy-plane with the y-axis pointing up--at the end of a 75-cmcm-long, massless, rigid rod. The other end of the rod is attached to a frictionless pivot at the origin.
What is the gravitational torque about the pivot when the mass is 60 ∘∘ above the +x-axis? Give your answer using unit vectors.
The gravitational torque about the pivot when the mass is 60 ∘∘ above the +x-axis is (0.1838 Nm)k
What is torque?Torque is the turning effect of a force which causes rotation. It is given by τ = F × d where
F = force and d = perpendicular distance of force from point of action.What is the gravitational torque about the pivot when the mass is 60° above the +x-axis?Since a 50 g mass rotates in a vertical plane--call it the xy-plane with the y-axis pointing up--at the end of a 75-cm-long, massless, rigid rod.
The gravitational torque is given by τ = F × d where
F = component of weight perpendicular to rod = -(mgcosФ)j where m = mass, g = acceleration due to gravityФ = angle between rod and x axis and d = length of rodSo, τ = F × d
= -(mgcosФ)j × di
= mgdcosФ(-j × i)
= -mgdcosФ(j × i)
= -mgdcosФ(-k)
= (mgdcosФ)k
Given that
m = 50 g = 0.05 kgg = 9.8 m/s²,d = 75 cm = 0.75 m and Ф = 60°Substituting the values of the variables into the equation, we have
τ = (mgdcosФ)k
= (0.05 kg × 9.8 m/s² × 0.75 m × cos60°)k
= (0.05 kg × 9.8 m/s² × 0.75 m × cos60°)k
= (0.3675 kgm²/s² × 0.5)k
= (0.18375 kgm²/s²)k
= (0.18375 Nm)k
≅ (0.1838 Nm)k
So, the torque is (0.1838 Nm)k
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A single loop of copper wire lying flat in a plane, has an area of 7.80 cm^2 and a resistance of 2.70 Ω A uniform magnetic field points perpendicular to the plane of the loop. The field initially has a magnitude of 0.500 T, and the magnitude increases linearly to 3.50 T in a time of 1.10 s. What is the induced current (in mA) in the loop of wire over this time?
The induced current in the loop of the copper wire is found to be 7.85 mA.
The single loop of the copper wire is lying in flat plane and the magnetic field is pointing perpendicular to the plane of the loop. The area of the loop is given to be 7.8cm²
The magnetic field initially has a magnitude of 0.500 Tesla and it finally increases manner to grow to a magnitude of 3.50 Tesla in a time 1.10 seconds.
The induced EMF in the circuit will be given by the relation,
E = A∆B/∆T
Where,
B is magnetic field,
A is the area and T is the time taken.
Putting all the values,
E = 0.00078×(3.5-0.5)/1.1
E = 21.2mV.
The resistance in the copper loop is given to be 2.7 ohm.
Now, the induced current in the circuit will be given by the relation,
I = E/R
Putting all the values
I = 21.2/2.7
I = 7.85 mA.
So, the induced current in the wire is 7.85 milliamps.
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five coins are stacked in the smooth plastic container. if each coin weighs 0.0235 lb, determine the normal reactions of the bottom coin on the container at points a and b.
The smooth plastic jar has five pennies placed inside of it. The normal reactions of the bottom coin on the container at locations a and b will be 0.0705 lb and 0.1175 lb respectively if each coin weighs 0.0235 lb.
What does normal force mean?A contact force, the normal force is often referred to as the normal reaction force. On two surfaces that are not attached to one another, a normal force cannot be applied.
What normal force is present during deceleration?The body's weight determines the usual deceleration force. A body's position relative to the ground tells us when it is about to fall. The normal force is the portion of a force that is perpendicular to any contact surface.
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Two blocks, with masses indicated in the figure above, are at rest on a horizontal surface and connected by a string of negligible mass and a compressed spring. There is negligible friction between the blocks and the surface. The string is cut, and the spring pushes the blocks away from each other. Which of the following statements are true about the motion of the blocks immediately after the string is cut? select two answers.
1. The velocity of the center of mass of the two-block system is zero.
2. The magnitude of the acceleration of the left block is greater than that of the right block.
The center of mass, or balancing point, of a distribution of mass in space is the only location where the total of the weighted relative positions of the distributed mass equals zero. In order to accelerate linearly without also accelerating angularly, a force might be applied at this moment. Using the center of mass as a reference point simplifies calculations in mechanics quite a bit. To imagine how an object would move, one can imagine a hypothetical location where the object's total mass is concentrated. To apply Newton's equations of motion to a particular object, the center of mass is the particle equivalent of that thing.
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Field poles are electromagnets whose ____ change as the flow of current alternates in the field windings.
Field poles are electromagnets whose polarities change as the flow of current alternates in the field windings.
An electromagnet is a sort of magnet wherein the magnetic area is produced with the aid of an electric current. Electromagnets generally encompass cord wounds into a coil. A cutting edge through the wire creates a magnetic discipline that is focused inside the hole in the middle of the coil.
Electromagnets create a magnetic discipline through the application of power. When you introduce the modern, either from a battery or any other supply of strength, it flows through the wire. This creates a magnetic discipline around the coiled cord, magnetizing the metal as though it were a permanent magnet.
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In a diffraction experiment, a coherent light source illuminates a pair of identical slits in a barrier, and the resulting pattern is projected on a screen that is separated from the barrier by 2.05 m. A student sketches the pattern that appears on the screen. The locations of the centers of the bright and dark fringes are accurate, but the shading is only qualitative. The color chosen may not be an ideal match to the actual light source. TITUTE THI HT -50.0 -40.0 -30.0 -20.0 -10.0 0.0 10.0 20.0 30.0 40.0 50.0 y (cm) * 25% Part (a) Enter the ratio of the slit separation, d, to the slit width, D, as a whole number. d = D TT 7 8 9 HOME E 4 5 6 sino cos tan cotano asin acos atan acotan sinh cosho tanh) cotanh O Degrees Radians 1 2 3 + 0 END . VO BACKSPACE DE CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. A 25% Part (b) Calculate and enter the ratio of the slit width to the wavelength of the light source. A 25% Part (C) If the slit separation is 17 um, then calculate and enter the wavelength, in nanometers, of the light source. 25% Part (d) What is the slit width, in micrometers?
(a) The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width, in micrometers;
d = 20.5 µm
(a) We know that Fringe width is given by,
[tex]\beta =\frac{D\lambda}{d}[/tex]
Where,
D = slit to screen distance
λ = wavelength
d = slit width
Given in the question,
D = 2.05 m
[tex]\beta =4 cm=0.04m[/tex]
Now,
[tex]\frac{d}{D} =\frac{\lambda}{\beta } =\frac{400*10^{-9} }{0.04}[/tex]
d/D = 0.0001
Hence,
The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b) Ratio of d & λ,
[tex]\frac{d}{\lambda} =\frac{D}{\beta }[/tex]
[tex]\frac{d}{\lambda}=\frac{2.05}{0.04}[/tex]
[tex]\frac{d}{\lambda}=51.25[/tex]
Hence,
The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength of the light source,
[tex]\lambda=\frac{D\beta }{d}[/tex]
[tex]\lambda=\frac{17*10^{-6} *0.04}{2.05}[/tex]
[tex]\lambda=331.7nm[/tex]
Hence,
The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width,
[tex]d =\frac{D\lambda}{\beta }[/tex]
[tex]d=\frac{400*10^{-9} *2.05}{0.04}[/tex]
[tex]d=20.5 \mu m[/tex]
Hence,
The slit width, in micrometers;
d = 20.5 µm
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in the figure, light is incident at angle on a boundary between two transparent materials. some of the light travels down through the next three layers of transparent materials, while some of it reflects upward and then escapes into the air.
(a) θ5 in the air is 56.9° and (b) θ4 in the bottom material 35.30°. Normally, a light beam that strikes an angle on a prism's refracting face emerges from the opposite face.
How to calculate?(a) Approximating n=1 for air, we have
n1. sinθ1 = (1)sinθ5 ⇒56.9°=θ5
and with the more accurate value for n air in Table below, we obtain 56.80.(b) Equation n1 sinθ c =n2 sin 90° leads to,
n1 sinθ 1=n2 sinθ2 =n3 sinθ 3 =n4 sinθ 4
so that. θ4 =sin −1( n1/n4.sinθ 1 )=35.30° .
What does angle of incidence mean?The angle of incidence is formed by a line drawn perpendicular to the reflecting barrier and the wave's direction of motion.
Is the incidence angle of refraction?Refraction Depending on the Refractive Indices in the Two Media and the Angle of Incidence. Snell's law states that the angle of incidence, I and the proportion of the refractive indices of the two media that make up the interface determine the angle of refraction, r.
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umama wants to enable user experience virtualization (ue-v) by configuring group policy settings. two important settings that she needs to configure are the setting storage location and settings template catalog location. which of the following is true of this scenario?
Correct. When new user profiles are created, the default profile is utilised. Umama wants to configure Group Policy settings to enable User Experience Virtualization (UE-V).
UEV policy settings: What are they?You can enable or disable User Experience Virtualization using this Group Policy setting (UE-V). Only versions of UE-V 2.x and earlier are affected by this setting. Use the Enable UE-V setting in Wind ows 10, version 1607, for UE-V. The location of the settings template catalogue and the location of the settings storage location are two crucial settings that she must set up.
Microsoft User Experience Virtualization: What is it?A programme called Micro soft UE-V (User Experience Virtualization) enables users to switch between Wind ows devices while keeping their current operating system (OS) and application settings.
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A uniform plane wave with parallel polarization is propagating in a lossless dielectric medium (l is € 1), and is incident obliquely onto a plane boundary with another lossless dielectric medium (u 2, E 2). (30%) (a) Derive the Snell's laws of reflection and refraction in terms of the refractive indices and angles. (b) Derive the general expressions for the reflection and the transmission coefficients of the EM field. Find such expressions in terms of the refractive indices if both media are nonmagnetic, i.e., M F M 240. (c) Derive the general expression for the Brewster angle. Find such an expression in terms of the refractive indices if both media are nonmagnetic. (d) Prove that, under the condition of no reflection, the sum of the Brewster angle and the angle of refraction is 90° if both media are nonmagnetic. (e) For total reflection to occur, find the condition for the medium property and the critical angle.
Transmission coefficients are used in physics and electrical engineering when considering wave propagation in discontinuous media. The snells law is n₁sinθ1 = n₂sinθ2
The transmission coefficient describes the amplitude intensity or total power of the transmitted wave relative to the incident wave. The transmission coefficient is defined as the ratio of the transmitted particle flux to the incident particle flux and depends on the incident energy.
The sum of the reflected and transmitted energy must equal the total incident energy, so the transmission coefficient is calculated simply by subtracting the reflection coefficient. The ratio of the reflected wave amplitude to the incident wave amplitude is called the reflection coefficient.
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for a severe supercell ts to form over the great plains, one would expect the 5,000 agl wind to be group of answer choices 360/10 kt 200/15 240/90 190/45
Note that for a severe supercell ts to form over the great plains, one would expect the 5,000 AGL wind to be 190/45kts (Option D)
What is a supercell?A supercell thunderstorm is distinguished by the presence of a mesocyclone, which is a deep, continually revolving updraft. As a result, these storms are sometimes known as spinning thunderstorms.
Supercells are storms that have updrafts that spin along a vertical axis and are generally but not always thunderstorms. This rotation is caused by shear in the environmental wind field (a change in wind direction and/or speed with height) that surrounds the storm as it grows.
Supercell thunderstorms are intense, long-lived storms that are characterized by strong wind shear and rotational dynamics.
The wind shear, or the change in wind speed and direction with height, is a key factor in the development and maintenance of supercell thunderstorms.
Note that AGL means Above Ground Level; while
KTS means Knots. Knots are a unit measurement of speed. I nautical mile is usually equated to one knot.
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apply the loop rule to loop 2 (the smaller loop on the right). sum the voltage changes across each circuit element around this loop going in the direction of the arrow. remember that the current meter is ideal.express the voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.
The voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.ΣΔV = 0 = I3 ⋅ R3 - I2 ⋅ R2.
When applying Kirchhoff's second rule the loop rule we need to identify closed loops and decide whether to loop clockwise or counterclockwise. For example, in Figure 3 the loop was traversed in the same direction as the current.
Loop 1 is the full loop and Loop 2 is the small loop on the right. To apply the loop rule, add all those voltage changes. Kirchhoff's Second Law, also known as Kirchhoff's Voltage Law states that the sum of all voltages around the closed loop of any circuit must be zero. This is a result of charge conservation and energy conservation.
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The smoke from the Old Man’s furnace travels up from the basement at a velocity of |.5 meters per second. Ralphie is sitting in the kitchen above and can smell the smoke within 6 seconds. What is the approximate distance that the smoke travels up from the furnace?
The approximate distance that the smoke travels up from the furnace is 9metres.
What is distance?Distance is described as a numerical or occasionally qualitative measurement of how far apart objects or points are. In the field of physics or everyday usage, distance is usually referred to a physical length or an estimation based on other criteria.
Parameters given:
Velocity = 1.5
time = 6 seconds
We know that distance = speed x time
Hence, distance = 1.5 x 6 seconds
distance = 9 meters.
Distance is a scalar quantity that refers to how much ground an object has covered in the course of its motion while we can describe displacement as a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
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During the heating season, a damper in the bypass duct is closed to prevent air from passing through the humidifier. Electronic humidistats are equipped with solid-state sensors in place of a hygroscopic element. Evaporative humidifiers contain an element that is kept damp. False
This statement is False because Solid-state sensors are used in place of a water - absorbing element in electronic humidistats. A damper in the bypassed duct is closed during the summer period to stop airflow.
What is hygroscopic and example?Hygroscopy - A material is said to be hygroscopic if it has the capacity to adsorb and retain water or water from its immediate surroundings. Examples include ethanol, glycerin, concentrated sulfuric acid, honey, silica gel, and methanol.
How hydroscopic is water?Around the soil particles, some water in the soil creates an incredibly thin, firmly held layer. It's referred to as hydroscopic water. A little amount of water in the soil is chemically linked to soil components in the soil. We refer to it as mixed water.
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A pulley system is used to lift up a 90N boulder. What is the mechanical advantage if you only need to use 15N of force to lift the boulder?
By simply creating more loops or pulleys, the pulley system's mechanical advantage can be accomplished.
Equation:
It is known that a pulley system can lift a crate with 90 newtons of force. Finding the pulley system's mechanical advantage is important if the input force is 15 newtons.
The force makes the distance longer as though it were working. Mechanical advantage is not greatly affected by the number of pulleys. This is only based on the amount of weight that needs to be lifted.
Therefore,
F1/F2 = 90/15
F1/F2 = 6
Given that the crate's weight is 90 N and the input force is 15 N, this makes sense.
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One of the most controversial ideas to come out of instinct theories of aggression was Lorenz's proposal that society provide acceptable ways of permitting , or the process of discharging built-up aggressive energy.
The general instinct hypothesis, which contends that people are physiologically predisposed to or possess inclinations for violent behaviours, is known as the instinct theory of aggression in psychology.
This theory is more focused on aggression. The instinct theory of aggressiveness holds that human aggression is akin to sex and hunger, and that it can only be regulated rather than eradicated.In an effort to understand why we become aggressive and whether that behaviours can be altered, psychologists have developed three primary theories of aggression. Although many hypotheses have been put out, these three have proven most reliable and are crucial to comprehending the origins of violence. These hypotheses comprise as,
Adversity theory based on instinctTheory of Frustration and AggressionTheory of Social LearningTo know more about theory of aggression
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what should be the value of 'x' such that the mass то exerts a force of mg on the inclined surface at P. (N=mg)
The value of 'x' such that the mass то exerts a force of mg on the inclined surface at P. (N=mg) is given by
x = N / (mg cos θ)
What is value of 'x'?Generally, To determine the value of 'x', you need to know the angle of inclination of the surface and the mass of the object. The force of gravity (N) acting on the object is equal to the mass of the object (m) multiplied by the acceleration due to gravity (g). The force of gravity is also equal to the normal force (N) exerted by the surface on the object, which is perpendicular to the surface.
If the surface is inclined at an angle θ with respect to the horizontal, the normal force will be equal to the component of the force of gravity along the surface. This component can be calculated using the formula N = mg cos θ, where θ is the angle of inclination and m is the mass of the object.
Therefore, to determine the value of 'x', you need to solve the equation N = mg cos θ for 'x'. To do this, you can rearrange the equation to solve for x:
x = N / (mg cos θ)
Substituting the values of N, m, and θ into this equation will give you the value of 'x' that you are looking for.
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A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -40 cm are 160 cm apart. A 2.5 cm-tall object is 60 cm in front of the converging lens.
Calculate the image position. cm in front of the second lens.
Calculate the image height.
1.25 cm is the height of the image. 160 cm separates a converging lens with such a 40 cm focal length from a diverging lens with the a -40 cm focal length. The converging lens is 60 cm away from a 2.5 cm tall item.
What does a converging or diverging lens mean?A lens that conforms a parallel source beam of light is known as a converging lens. One kind of converging lens is a double convex lens. Converging Lens A lens that separates a parallel light beam is known as a diverging lens. Diverging lenses include those that are double concave.
For the diverging lens, this image height corresponds to object height. We obtain h ′D=(20cm40cm)(5.0cm)=1.25cm again for diverging lens as a result.
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- A basketball strikes the rim of the basket. Explain each force in the force pair.
A basketball experiences four forces as it soars through the air. The ball is being pulled down to the Earth by gravity, being propelled upward by buoyancy, and slowed down due to the drag force created by the air it collides with.
What is force ?A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
For instance, a basketball will strike the ground hard when it is dribbled. The ground's force on the ball is balanced by this force of the ball on the ground. The ball is sent upwards by the second force since it acts in the opposite direction. There are numerous characteristics of motion that depend on this interaction.
Thus, A basketball experiences four forces as it soars through the air.
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for the circuit below all values are rms with a source frequency of 60 hertz. the generator impedance is negligible (0 w). calculate the value of ib and and determine the value of vb-n. now, calculate the rms values of apparent, real and reactive power of zb. (show units for all)
The reactive power of the branch (Qb) can be calculated from its voltage and current 676.16 VA.
What is reactive power?Reactive power is the power in an AC circuit that is required to establish and maintain a voltage across a load. It is associated with the storage and release of energy in the form of electric and magnetic fields. Reactive power does not contribute to the actual work output of a system and is measured in Volt-amperes reactive (VARs). Power factor is a measure of reactive power relative to the total power in a system.
Source frequency = 60 Hz
Generator impedance = 0 W
Circuit:
Vg = 170 V
R1 = 10 Ω
R2 = 20 Ω
Zb = 20 + j10 Ω
The current flowing through the generator (Ig) and the branch (Ib) can be calculated from Ohm's Law:
Ig = Vg/R1 + Vg/R2 = 170/10 + 170/20 = 17 A
Ib = Ig - Vg/Zb = 17 - 170/(20 + j10) = 17 - 16.4 + j4.4 = 0.6 + j4.4 A
Since Ib is a complex number, we can find its magnitude (|Ib|) and angle (θ):
|Ib| = √(0.6² + 4.4²) = 4.46 A
θ = tan⁻¹(4.4/0.6) = 80.16°
The voltage across the branch (Vb-n) can be calculated using Ohm's Law:
Vb-n = Ib × Zb = (0.6 + j4.4) × (20 + j10) = -8.4 + j74.4 V
The apparent power of the branch (Sb) can be calculated from its voltage and current:
Sb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = -45.48 + j367.04 VA
The real power of the branch (Pb) can be calculated from its voltage and current:
Pb = Vb-n × Ib = (-8.4 + j74.4) × (0.6 + j4.4) = -45.48 - j367.04 W
The reactive power of the branch (Qb) can be calculated from its voltage and current:
Qb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = 676.16 VA
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Suppose a rocket is fired vertically upward from the surface of the earth with one-half of the esacpe speed. How far from the center of the earth will it reach vefore it begins to fall back?
(let g = 9.8 m/s^2 and Re = 6370 km)
A. 1.3 * 104 km
B. 8.5 * 103 km
C. 9.6 * 103 km
D. 2.6 * 104 km
E. 1.9 * 104 km
The correct answer: B.
I do not understand why I am not getting the correct answer.
The distance before it falls back to the earth is 8.5 * 103 km. Option B
What is the escape velocity?We know that the escape velocity has to do with the velocity that has to be supplied to a material so that the material can be able to escape from the earth's gravitational pull. Let us recall that the whole earth is a large gravitational field. If we throw an object up then the object would have to certainly fall doen to the ground under the influence of gravity.
It is therefore clear that gravity is the force that draws any object that goes upwards down back to the ground. Given that we have been told here that the speed is one-half of the escape speed, then then the magnitude of the speed is 5590.3 m/s.
Given that;
v^2 = u^2 - 2gh
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = height
Then;
u^2 = 2gh
h = u^2/2g
h = ( 5590.3)^2/2 * 9.8
= 8.5 * 103 km
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A rod has a length 2.0000m at 20.0C. The length of the rod increases to 2.0005
5.00 × 10-3/K is the coefficient of thermal expansion of the material from which the rod is made as it increases its length to 2.0005m
What is the purpose of the thermal expansion coefficient?The coefficient of thermal expansion explains how an object's size varies when temperature changes. In particular, it measures the fractional size change per degree change in temperature at constant pressure, where lower coefficients denote a reduced propensity for size change.
What does thermal expansion mean?The propensity of matter to alter shape, volume, and area in reaction to a change in temperature is known as thermal expansion. The average molecular kinetic energy of a substance has a monotonic relationship with temperature.
How is thermal expansion calculated?Use the equation for linear thermal expansion ΔL=αLΔT Δ L = α L Δ T to calculate the change in length, ΔL .
How to solve?Get your rod hot enough to achieve, say, 1% linear thermal expansion.
The rod's dimension has increased to 1.01 units.
The rod is 1.030301 times its original size, or 1.013 larger than it was before heating.
This equals 1.03 when rounded to three major figures. In other words, its volume is 3% higher than that of the cold specimen.
The linear expansion is tripled, or 3%, by the volumetric expansion.
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Complete question:
A rod has a length 2.0000 m at 20.0°C. The length of the rod increases to 2.0005 m when the temperature increases to 40.0°C. What is the coefficient of thermal expansion of the material from which the rod is made?
A toy spacecraft is launched directly upward. When the toy reaches its highest point, a spring is released and the toy splits into two parts with masses of 0.01 kg and 0.09 kg, respectively. Immediately after the separation, the 0.01 kg part moves horizontally due east. Air resistance is negligible. True statements about the 0.09 kg part include which of the following? I. It could move north immediately after the spring is released. II. It takes longer to reach the ground than does the 0.01 kg part. III. It strikes the ground closer to the launch point than does the 0.01 kg part. (A) I only (B) III only (C) I and II only (D) II and III only (E) I, II, and III
Air resistance is hardly noticeable. true regarding the 0.09-kilogram component. This causes 0.01kg to land farther from the launch site than 0.09kg did.
0.09kg will move to the west due to momentum conservation (opposite of 0.01 kg). Additionally, since both are at the same height above the ground, it will take them equal amounts of time to descend to the ground.
Allowing v to be the speed of 0.01 kg, which means that the speed of 0.09kg will be smaller than 0.01 kg,
0.01v - (0.09)V = 0
V = 0.01 v/ 0.09 = 0.111v
The speed of 0.09 kg = 0.111v
The speed of 0.09 kg is less than 0.01kg.
Because of this, 0.01kg hits the ground farther from the launch point than 0.09kg did.
The amount of resistance in an electrical circuit represents the resistance to current flow. The Greek letter omega (), which represents resistance, represents ohms. German physicist Georg Simon Ohm (1784–1854), who investigated the connection between voltage, current, and resistance, is the name given to the unit of resistance known as an ohm.
Resistance measurements are typically performed in order to evaluate the health of a component or a circuit.
Current flow is inversely correlated with resistance. Conductor damage from corrosion or burning could be one of several potential causes if it is extremely high.
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A wire is formed into a circle having a diameter of 20.0 cm and placed in a uniform magnetic field of 2.50 mT. The wire carries a current of 5.00 A.
(a) Find the maximum torque on the wire.
_____ µN·m
(b) Find the range of potential energies of the wire-field system for different orientations of the circle.
minimum
_____µJ
maximum
_____ µJ
The maximum torque on the wire is 392.3 µN·m and the range of potential energy is -392.3µN·m(minimum) to +392.3µN·m(maximum)
Torque: Torque is a measure of the force that can cause an object to rotate about an axis. It is a vector quantity.
Given that,
diameter D=20cm
Radius r =10cm
magnetic field B =2.5mT
current I=5A
Torque= n×B
=nBsinФ
torque=nB= NIAB
= 1×5×π×[tex]10^{2}[/tex]×[tex]10^{-4}[/tex]×2.5×[tex]10^{-3}[/tex]
= 39.23×[tex]10^{-5}[/tex]
= 392.3µN·m
minimum potential energy= -nB= -392.3µN·m
maximum potential energy =+nB= +392.3µN·m
Therefore the maximum torque on the wire is 392.3 µN·m when is placed in an uniform magnetic field of 2.50mT and the range of potential energy is -392.3µN·m(minimum) to +392.3µN·m(maximum)
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A taxi company is trying to decide whether to purchase brand A or brand B tires for its fleet of taxis. To estimate the difference in the two brands, an experiment is conducted using 12 of each brand. The tires are run until they wear out. The results are Brand A: \overline{x}_1 = 36. 300 x
1
=36.300 kilometers, s_1s 1
= 5000 kilometers. Brand B: \overline{x}_2 = 38. 100 x
2
=38.100 kilometers, s_2 = 6100s 2
=6100 kilometers. Compute a 95% confidence interval for \mu A − \mu BμA−μB assuming the populations to be approximately normally distributed. You may not assume that the variances are equal.
A 95% confidence interval for μA-μB is 0.025
If we want to make a 95% confidence interval estimate for an unknown population mean. This means that there is a 95% probability that the confidence interval will have the true population mean.
Thus, P( [sample mean] - margin of error < μ < [sample mean] + margin of error) = 0.95.
We have,
n1 = 12
s1 = 5000
mean x1 = 36300
n2= 12
s2 =6100
mean x2 =38100
We have to find 95%confidence interval for μA- μB
from 95% = 100 (1-α%)
1-α = 0.95
α = 1-0.95 =0.05
α/2 = 0.025
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A(n) ____________________ is a dynamic variable on the free store without any pointer pointing to it.
A inaccessible object is a dynamic variable on the free store without any pointer pointing to it.
How to find the height of an inaccessible object using sextant?Utilize the sextant's arc to determine the angle. By dividing the object's distance from the point of observation by the tan of the angle you calculated, you may use a scientific calculator to get the object's height.
How can heights and distances that are absent or unavailable be measured?The measuring of heights and distances that are unreachable is made easier by right-triangle trigonometry. By drawing a right triangle with the unknown height or distance as one of its sides and a known side and angle on the other, it is possible to determine the unknown height or distance.
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Answer:
dynamic variable
aphasia
Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience:
Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience: aphasia.
Aphasia is the inability to understand or form language due to damage to certain areas of the brain The main causes are stroke and head trauma. Although the prevalence is difficult to determine, aphasia due to stroke is estimated at 0.1-0.4% in the Global North. Aphasia can also be the result of a brain tumor, brain infection, or neurodegenerative disease (such as dementia).
To be diagnosed with aphasia, communication after an acquired brain injury Speech or language must be significantly impaired in one (or more) of the four aspects of Alternatively, in the case of progressive aphasia, it must have decreased significantly over a short period of time. The four dimensions of communication are auditory comprehension, verbal expression, reading and writing, and functional communication.
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A 20 g ball of clay traveling east at 2.5 m/s collides with a 25 g ball of clay traveling north at 2.0 m/s .
What is the speed of the resulting 45 g ball of clay?
What is the direction of the resulting ball of clay?
The final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰.
The given parameters;
mass of the first clay ball, m₁ = 20 g = 0.02 kg
initial velocity of the first clay ball, u₁ = 3 m/s
mass of the second clay ball, m₂ = 30 g = 0.03 kg
initial velocity of the second ball, u₂ = 2 m/s
The initial momentum of the fist ball is calculated as follows;
P₁ = m₁u₁
P₁ = (0.02)(3)
P₁ = 0.06 kg.m/s
The initial momentum of the second ball is calculated as follows
P₂ = m₂u₂
P₂ = (0.03)(2)
P₂ = 0.06 kg.m/s
The resultant initial momentum of the two balls is calculated as follows;
Apply the principle of conservation of momentum, to determine the final velocity of the two balls;
The direction of the two ball's velocity is calculated as follows;
Thus, the final velocity of the two balls after collision is 1.7 m/s and the direction is 45⁰To know more about speed direction visit:
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a wire of length l is wrapped into a coil with n turns this coil is then placed in a magnetic field of strength b
Maximum torque developed is (BIL²/4[tex]\pi[/tex]n).
Torque is a measure of force that can cause an object to rotate about an axis.
A force causes an object to accelerate in linear kinematics. Similarly, torque causes angular acceleration. Torque can therefore be defined as the rotational equivalent of a linear force. The line about which the object rotates is called the axis of rotation. In physics, torque is simply the tendency of a force to rotate or twist.For any structure such as a solenoid, toroid, and circular arc, the magnetic field at a certain point of the structure is always proportional to the number of turns of the coil.
As we know magnetic field is (BIL²/4[tex]\pi[/tex]n)
2[tex]\pi[/tex]rn = L
r = (L/2[tex]\pi[/tex]n)
A = [tex]\pi[/tex]r²
A = (L²/4[tex]\pi[/tex]n²)
M = niA
M = (iL²/4n[tex]\pi[/tex])
Then Torque is Z = MBSin90°
The question is incomplete, the complete question is "a wire of length l is wrapped into a coil with n turns this coil is then placed in a magnetic field of strength b, the maximum possible torque developed is?"
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crane lifts a 400 kg crate upward with an acceleration of 3.00 m/?. Determine the force on the crane.
The crane is under 5120 N of force. The crane touches the rock boulder and uses mechanical force to lift it.
What are the units of a force?Force is a physical phenomenon that can change an object's shape as well as its state of motion or rest. The SI unit of force is the Newton.
Cranes fall under which of the following three forces?Jib, gantry, and overhead cranes are the three pieces of machinery used most frequently in the industry. Depending on the type of item to be moved, either a chain or wire rope hoist will be used. In the shipbuilding sector, material handling is the main use of overhead cranes during the assembly process.
Briefing:
Mass (m) = 400kg
Acceleration (a) = 3.00 m/s^2
Gravitational acceleration (g) = 9.81 m/s^2
Force (F) = mg + ma
Force (F) = m (g + a)
Force (F) = 400 (9.81+3)
Force (F) = 5120 N
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