If a number is added to the numerator of 5/6 and twice as much is added to the denominator the result is 3/5 find the number

Answer:

Step-by-step explanation:

Answer:

Blablabka

Step-by-step explanation:

Blablabla

Answer:

x = 2[tex]\sqrt{5}[/tex]

Step-by-step explanation:

Pytago:

[tex]2^2 + 4^2 = x^2\\x = \sqrt{2^2 + 4^2} \\x = 2\sqrt{5}[/tex]

Answer:

4.47

Step-by-step explanation:

x²= 2² + 4²

x² = 4 + 16

x²= 20

x = √20

x= 4.47

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Answer:

  6

Step-by-step explanation:

The number of distinct zeros in the product will be the union of the sets of zeros. Duplicated values are not distinct, so show in the union of sets only once.

  F = {-2, 3, 7}

  G = {-3, -1, 4, 7}

  F∪G = {-3, -2, -1, 3, 4, 7} . . . . . . a 6-element set

The product has 6 distinct zeros.

_____

As you may notice in the graph, the duplicated zero has a multiplicity of 2 in the product.

Answer:

Logx(1/8) = -3/2

x = 4

Answered by GAUTHMATH

1) I think 15 choose (d)

2) The choose (C) -4fg+4g

3) The choose (d) 3xy/2

4) The choose (a) ab/6

5) The choose (C) 2p+4q-6

6)

[tex]\pi {r}^{2} h = 3.14 \times {3}^{2} \times 1.5 = 42.39 {m}^{3} = 42.390 {m}^{3} [/tex]

Point 6 I think there is an error because the unit m must be m³ because it is r² (m²) and h(m) becomes m³.

I hope I helped you^_^

Answer:

464 $

Step-by-step explanation:

Answer:

352

Step-by-step explanation:

I = PRT  where P is the principle, I is the interest rate, T is the time

I = 275 ( .08) ( 16)

I = 352

Answer:

- 5 > b

Step-by-step explanation:

- 9 > 3b + 6

- 9 - 6 > 3b

- 15 > 3b

Divide 3 on both sides,

- 5 > b

Answer:

-5 >b

Step-by-step explanation:

-9 > 3b + 6

Subtract 6 from each side

-9-6 > 3b + 6-6

-15 > 3b

Divide each side by 3

-15/3 > 3b/3

-5 >b

Answer:

45/27=30/18=x/24

x = 30×24/18

or, x = 40

Answer:

? = 40

Step-by-step explanation:

Since the polygons are similar then the corresponding sides are in proportion, that is

[tex]\frac{?}{24}[/tex] = [tex]\frac{?}{24}[/tex] = [tex]\frac{30}{18}[/tex] ( cross- multiply )

18 ? = 720 ( divide both sides by 18 )

? = 40

Answer:

It's 0

Edge said it's 0

The value of the ratio of the cos(x) and the sin(x) is 0.

Trigonometric ratios are mathematical functions that relate the angles of a right triangle to the ratios of the lengths of its sides. These ratios are fundamental in trigonometry and have applications in various fields, such as physics, engineering, and navigation.

Trigonometry is a branch of mathematics that deals with the relationships and properties of angles and triangles. It explores the ratios between the sides of a triangle and the angles within that triangle. The word "trigonometry" is derived from two Greek words: "trigonal," meaning "triangle," and "metron," meaning "measure."

The value of the sin(x) is 1. The value of cos(x) is 0.

The formula for the cot(x) is written below:

cot(x) = cos(x) / sin(x)

cot(x) = 0 / 1

cot(x) = 0

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Answer:

the cost of filling the pool is $386.3

Step-by-step explanation:

Given;

dimension of the rectangular pool, = 25 yd by 30 yd by 5.1 ft

covert the given dimensions to feet;

1 yd = 3 ft

25 yd = 25 x 3 ft = 75 ft

30 yd = 30 x 3 ft = 90 ft

The volume of the rectangular pool in cubic feet (ft³);

Volume = 75 ft  x 90 ft  x 5.1 ft

Volume = 34,425 ft³

Convert the volume to gallons;

1 ft³ = 7.481 gallons

10,125 ft³ = 34,425 x 7.481 gallons

               = 257,533.425 gallons

The cost per a 1000 gallons is $1.50, then cost of the 257,533.425 gallons is calculated as;

[tex]cost = \frac{\$ 1.50}{1000 \ gallons} \times 257,533.425 \ gallons = \$ 386.3[/tex]

Therefore, the cost of filling the pool is $386.3

Answer:

About 54

Step-by-step explanation:

To work backwards from average, you need to multiply the average by the total number of cases, which is 4, since there are 3 current cases/seasons and you want the 4th.

59 * 4 =  236

You then subtract the total home runs that you know of from 236.

236 - 55 - 58 - 69 = 54

To find average, you are adding to the total and then dividing by the number of groups, which is essentially mean (mean is basically the average).

Answer:

0

Step-by-step explanation:

0

Answer:

Option A, m⁴/n²

Multiply the exponent 6 with the exponents of m and n

Answer:

1107.

You are rounding up because the number in the tenths slot is over 5.

Answer:

A. 200 square inches

Step-by-step explanation:

First, use Pythagorean Theorem to find the base of each triangle.

[tex]a^2+b^2=c^2\\20^2+b^2=(28\frac{1}{4})^2\\400+b^2=798.0625\\b^2=398.0625\\b=\sqrt{398.0625}\\b=19.9515037[/tex]

Finally, use the area of a triangle formula to find the area of each triangle.

[tex]A=\frac{1}{2}bh\\A=\frac{1}{2}(19.9515037)(20)\\A=199.515037[/tex]

Therefore, the area of each triangle is approximately 200 in².

The area of each triangle in square inches is 200 square inches.

The area of triangle is defined as the region enclosed by its perimeter or the three sides of triangle.

Mathematically,

Area of triangle = 1/2(base*height)

Now given that,

Base of the triangle, B = 20''

Hypotenuse of the triangle, H = 28(1/4)'' = 28.25''

So, Height of the triangle, P = [tex]\sqrt{H^2 - B^2}[/tex]

or,  Height of the triangle, P = [tex]\sqrt{28.25^2 - 20^2}[/tex]

or,  Height of the triangle, P = [tex]\sqrt{398.0625} }[/tex]

or,  Height of the triangle, P = 19.95 inches

Finally, use the area of a triangle formula to find the area of each triangle.

Area of triangle = 1/2*(BasexHeight)

⇒Area of triangle = 1/2*(20x19.95)

⇒Area of triangle = 1/2*399

⇒Area of triangle = 199.5 square inches

or, Area of triangle ≈ 200 square inches.

Hence, The area of each triangle in square inches is 200 square inches.

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Answer:

  -1/2

Step-by-step explanation:

The factor outside parentheses multiplies each term inside.

  5/2(-8/5 +7/5)

  = (5/2)(-8/5) +(5/2)(7/5)

  = -8/2 +7/2 = -1/2

Answer:

The 90% confidence interval is (0.0131, 0.0845).

Step-by-step explanation:

Before finding the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Old process:

125 out of 580, so:

[tex]p_O = \frac{125}{580} = 0.2155[/tex]

[tex]s_O = \sqrt{\frac{0.2155*0.7845}{580}} = 0.0171[/tex]

New process:

130 out of 780. So

[tex]p_N = \frac{130}{780} = 0.1667[/tex]

[tex]s_N = \sqrt{\frac{0.1667*0.8333}{780}} = 0.0133[/tex]

Distribution of the difference:

[tex]p = p_O - p_N = 0.2155 - 0.1667 = 0.0488[/tex]

[tex]s = \sqrt{s_O^2+s_N^2} = \sqrt{0.0171^2 + 0.0133^2} = 0.0217[/tex]

Confidence interval:

[tex]p \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].

The lower bound of the interval is:

[tex]p - zs = 0.0488 - 1.645*0.0217 = 0.0131[/tex]

The upper bound of the interval is:

[tex]p + zs = 0.0488 + 1.645*0.0217 = 0.0845[/tex]

The 90% confidence interval is (0.0131, 0.0845).

Kurt Blixen must invest $85,2296.94.

Given the following data;

To find how much money Kurt Blixen must invest;

Mathematically, simple interest is given by the formula;

[tex]S.I = \frac{PRT}{100}[/tex]

Where:

First of all, we would convert the time in days to years.

Conversion:

365 days = 1 year

90 days = x year

Cross-multiplying, we have;

[tex]365 * x = 90\\\\x = \frac{90}{365}[/tex]

x = 0.247 year

Making P the subject of formula;

[tex]P = \frac{S.I(100)}{RT}[/tex]

Substituting the values into the formula, we have;

[tex]P = \frac{10000(100)}{4.75*0.247}\\\\P = \frac{1000000}{1.1733}[/tex]

P = $85,2296.94

Therefore, Kurt Blixen must invest $85,2296.94.

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Answer:

   B.  √6

Step-by-step explanation:

The circles are not tangent to one another. If they were, the distance between their centers would be the sum of their radii: 1 +1 = 2.

__

The center of the first circle is (√3, √3), and the center of the second is the origin. The distance between these two centers is given by the distance formula:

  d = √((x2 -x1)^2 +(y2 -y1)^2)

  d = √((√3 -0)^2 +(√3 -0)^2) = √(3+3) = √6 . . . . matches choice B

Answer:

26m^2

Step-by-step explanation:

Area of triangle=1/2b*h

We have,

b=6.5

h=8m

Now,

Area=1/2b*h=1/2*6.5*8=26m^2

We know that [tex]\log_a(bc)=\log_a(b)+\log_a(c)[/tex].

Using this rule,

[tex]\log_c(A^5B^3)=\log_c(A^5)+\log_c(B^3)[/tex].

We also know that [tex]\log_c(a^b)=b\log_c(a)[/tex].

Using this rule,

[tex]\log_c(A^5)+\log_c(B^3)=5\log_c(A)+3\log_c(B)[/tex]

Now we know that [tex]\log_c(A)=2,\log_c(B)=5[/tex] so,

[tex]5\cdot2+3\cdot5=10+15=\boxed{25}[/tex].

Hope this helps :)

The tangent vector for the given line is

T(t) = d/dt ⟨-2 - 3t, 1 - 4t, -5t⟩ = ⟨-3, -4, -5⟩

On its own, this vector points to a single point in space, (-3, -4, -5).

Multiply this vector by some scalar t to get a whole set of vectors, essentially stretching or contracting the vector ⟨-3, -4, -5⟩. This set is a line through the origin.

Now translate this set of vectors by adding to it the vector ⟨-2, -4, 0⟩, which correspond to the given point.

Then the equation for this new line is simply

L(t) = ⟨-3, -4, -5⟩t + ⟨-2, -4, 0⟩ = ⟨-2 - 3t, -4 - 4t, -5t⟩

The vector parametric equation for the line through the point is [tex]r = (-2, \ -4, \ 0) +(-3, \ -4, \ -5)t\\\\[/tex].

Give a vector parametric equation for the line through the point (−2,−4,0) that is parallel to the line ⟨−2−3t,1−4t,−5t⟩.

Parametric equations of the line segment are defined by its endpoints.

To find the vector equation of the line segment, we’ll convert its endpoints to their vector equivalents.

Two lines are parallel if they have the same direction, and in the parametric form, the direction of a line is always the vector of constants that multiply t (or the parameter).

The vector equation of a line is given by:

[tex]\rm v = r_0+tv[/tex]

Where v is the direction vector and [tex]\rm r_0[/tex] is a point of the line.

The tangent vector for the given line is

T(t) = d/dt ⟨-2 - 3t, 1 - 4t, -5t⟩ = ⟨-3, -4, -5⟩

Here,

[tex]\rm r_0 = (-2,-4,0) \ and \ v=(-3, \ -4, \ -5)t\\\\[/tex]

Then,

[tex]r = (-2, \ -4, \ 0) +(-3, \ -4, \ -5)t\\\\[/tex]

x = -2-3t, y = -4-4t, and z = 0-5t

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Answer:

7

Step-by-step explanation:

It looks like the term is [tex]2^3}x^2}yz^4[/tex]

First simplify

[tex]8x^2}yz^4[/tex]

[y has an exponent of 1 btw]

Then to find the degree of a term, just add up the values of all the exponents

2+1+4=7

I hope this helps!

Answer:

the answer to that is 10(N+14)=9N

Let the number = x

Set up an equation:

10(-150 + x ) = -110

Simplify:

-1500 + 10x = -110

Add 1500 to both sides

10x = 1390

Divide both sides by 10

X = 139

The number is 139

Answer: so there are 666 multiples of 3 between 2 and 2000.

Step-by-step explanation:

the smallest number = 3 which is 3*1. The largest number is = 1998 = 3*666

multiples of 3 between {2,2000} = 666-1+1 = 666

Answer:

The coordinate of any given point can be written as (x, y), where x is the x coordinate, and y is the y coordinate.

For example, point A has an x coordinate (horizontal) of 5, and a y coordinate (vertical) of 6. So the ordered pair is (5, 6).

Similarly, for the rest we have:

B: (-5,5)

C: (-2,3)

D: (-2,-2)

E: (3,-4)

F: (3,-6)

[tex]Hello[/tex] [tex]There[/tex]

The answer is...

[tex]5.[/tex]

[tex]HopeThisHelps!![/tex]

[tex]AnimeVines[/tex]