If a precipitation reaction occurs, what will be the products of the unbalanced
reaction shown below?
AgNO3(aq) + NaCl(aq) →
Solubility Table
A. AgCl(s) + NaNO3(s)
B. AgCl(s) + NaNO3(aq)
C. No precipitate will form.
D. AgCl(aq) + NaNO3(s)

Answers

Answer 1

Answer:

[tex]{ \sf{B. \: AgCl _{(s)} + NaNO _{3(aq)}}}[/tex]

Explanation:

Silver chloride precipitates out because it has a low value of Ksp.


Related Questions

Suppose that a certain atom possesses only four distinct energy levels. Assuming that all transitions between levels are possible, how many spectral lines will this atom exhibit

Answers

Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

[tex]= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6[/tex]

1.0 g of a compound A is prepared in 100 mL of water, and then extracted with 50 mL of ether. After the extraction, 0.25 g of the compound was recovered from the ether layer. What is the partitioning coefficient([A]ether/[A]water) for this compound in the system used?a. 4.0b. 3.0c. 1.5d. 0.75e. 0.25f. 0.67

Answers

Answer:

uh 2

Explanation:

Its 2 cause uh 2 sounds about right

To solve this we must know the concept behind partition coefficient. The partitioning coefficient for this compound in the system used is 0.67. Therefore, the correct option is option F.

What is partition coefficient?

The ratio of a solute's concentrations in two solids, immiscible liquids, or barely miscible liquids when they are in equilibrium throughout the interface connecting them is called partition coefficient.

In fundamental chemistry, partitioning is utilized to separate components in procedures like chromatography. Partitioning is a crucial factor in the distribution of chemicals and medications between the blood and bodily tissues in the field of pharmacology.

Mathematically,

partition coefficient= concentration of the solute in  stationary phase/concentration of the solute in mobile phase

partition coefficient={(0.25 /M)÷50}÷{(1.0/M)÷100 }

                                =0.005÷0.01

                                =0.67

Therefore, the correct option is option F.

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What will be the equilibrium temperature when a 245 g block of lead at 300oC is placed in 150-g aluminum container containing 820 g of water at 12.0oC?

Answers

Answer:

The correct approach is "12.25°C".

Explanation:

Given:

Mass of lead,

mc = 245 g

Initial temperature,

tc = 300°C

Mass of Aluminum,

ma = 150 g

Initial temperature,

ta = 12.0°C

Mass of water,

mw = 820 g

Initial temperature,

tw = 12.0°C

Now,

The heat received in equivalent to heat given by copper.

The quantity of heat = [tex]m\times s\times t \ J[/tex]

then,

⇒ [tex]245\times .013\times (300-T) = 150\times .9\times (T-12.0) + 820\times 4.2\times (T-12.0)[/tex]

⇒             [tex]3.185(300-T) = 135(T-12.0) + 3444(T-12.0)[/tex]

⇒             [tex]955.5-3.185T=135T-1620+3444T-41328[/tex]

⇒                         [tex]43903.5 = 3582.185 T[/tex]

⇒                                  [tex]T = 12.25^{\circ} C[/tex]

An experimental drug, D, is known to decompose in the blood stream. Tripling the concentration of the drug increases the decomposition rate by a factor of nine. Write the rate law for decomposition of D.

Answers

Answer:

R=k[D]^2

Explanation:

Given that it is a decomposition reaction;

D--->product

Hence;

The rate law is;

R= k[D]^x ----(1)

When we triple the concentration of D we have;

[D]' = [3D]^x

Therefore;

R'= 3R

R'= k[D]'----(2)

Hence dividing (1) by (2);

R/R' = k[D]^x/k[D]'

R/9R = k[D]^x/k[3D]^x

1/9 = 1/3^x (take inverse of both sides)

9 = 3^x

3^2 = 3^x

x= 2

Hence the rate law;

R=k[D]^2

which of the following kb values represents the weakest base?

Answers

Answer:

the weakest base will have a higher Kb value since it will be closer to an acid than a base

7 kb values represents the weakest base.

What is kb value?

Kb is the base dissociation constant which is a measure of how completely a base dissociates into its component ions in water. pKb is define as the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.

Ka is define as the acid dissociation constant while pKa is the -log of this constant. Kb is define as the base dissociation constant, while pKb is the -log of the constant.

The acid and base dissociation constants are usually expressed in terms of moles per liter (mol/L).

Thus, 7 kb values represents the weakest base.

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Identify effective techniques for accurate pipet use. Select all that apply. Select one or more: Measure liquid by aligning the meniscus with the volume line. Leave any air bubbles in a pipet that occur after drawing up liquid. Do not let liquid enter the pipet bulb or pump. Use the pipet bulb to force the last drop out of the tip.

Answers

Answer:

Measure liquid by aligning the meniscus with the volume line.

Explanation:

A pipette is an instrument specially made for measuring a small volume of liquid.

The pipette comes in various sizes to be used in measuring various volumes of liquid. Generally, the pipette has a volume line which helps us to measure a liquid.

A liquid is measured by aligning the meniscus with the volume line.

Physical and psychological dependence, high-risk behaviour, and chronic high blood
pressure can result from excessive use of

Answers

Answer:

Physical and psychological dependence is high, and withdrawal symptoms include watery eyes, runny nose, loss of appetite, irritability, tremors, panic, abdominal cramps and diarrhea, nausea, chills, and sweating. Use of contaminated syringes/needles to inject drugs may result in serious blood borne infections such as HIV-AIDS and hepatitis.

2. 27.8 mL of an unknown were added to a 50.0-mL flask that weighs 464.7 g. The total mass of the flask and the liquid is 552.4 g. Calculate the density of the liquid in Lbs/ in3.

Answers

Answer:

[tex]d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to set the equation for the calculation of density and mass divided by volume:

[tex]d=\frac{m}{V}[/tex]

Thus, we can find the mass of the unknown by subtracting the total mass of the liquid to the mass of the flask and the liquid:

[tex]m=552.4g-464.7g=87.7g[/tex]

So that we are now able to calculate the density in g/mL first:

[tex]d=\frac{87.7g}{27.8mL}=3.15g/mL[/tex]

Now, we proceed to the conversion to lb/in³ by using the following setup:

[tex]d=3.15\frac{g}{mL}*\frac{1lb}{453.6g}*\frac{1in^3}{16.3871mL}\\\\d=4.24x10^{-4}\frac{lb}{in^3}[/tex]

Regards!

Postlab Questions (2 pts ea; 8 pts total be specific and answer all in complete sentences): 1. How would you distinguish benzaldehyde and acetophenone by the results of their qualitative tests

Answers

Answer:

Using the Iodoform test, we can differentiate both compounds.

Explanation:

Benzaldehyde (C6H5CHO -an aldehyde) and Acetophenone (C6H5COCH3 - a methyl ketone) can be differentiated by reacting both compounds with iodine in a basic (NaOH) solutions.

The methyl ketone (acetophenone) gives a pale yellow precipitate of triiodomethane (iodoform) while the aldehyde (benzaldehyde) would not react.

This is known as the IODOFORM test and is indicative for methyl ketones

g A gas is compressed in a cylinder from a volume of 20.0 L to 2.0 L by a constant pressure of 10.0 atm. Calculate the amount of work done on the system in Joules. (1 L.atm

Answers

Answer:

The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

Explanation:

Thermodynamic work is called the transfer of energy between the system and the environment by methods that do not depend on the difference in temperatures between the two. When a system is compressed or expanded, a thermodynamic work is produced which is called pressure-volume work (p - v).

The pressure-volume work done by a system that compresses or expands at constant pressure is given by the expression:

W system= -p*∆V

Where:

W system: Work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J) p: Pressure. Its unit of measurement in the International System is the pascal (Pa) ∆V: Volume variation (∆V = Vf - Vi). Its unit of measurement in the International System is cubic meter (m³)

In this case:

p= 10 atm= 1.013*10⁶ Pa (being 1 atm= 101325 Pa)ΔV= 2 L- 20 L= -18 L= -0.018 m³ (being 1 L=0.001 m³)

Replacing:

W system= -1.013*10⁶ Pa* (-0.018 m³)

Solving:

W system= 18234 J

The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

help plsssssssssssss

Answers

Answer:

The rate of the forward reaction equals the rate of the reverse reaction.

Explanation:

To know which option is correct, it important that we know what dynamic equilibrium is all about.

We'll begin by defining chemical equilibrium.

A chemical system is said to be in chemical equilibrium when there is no observable change in the properperties of the chemical system.

Dynamic equilibrium on the other hand can be defined as a state in which the forward and backward reaction is occurring at the same time. Thus, in dynamic equilibrium, the rate of the forward reaction is equal to the rate of the backward (i.e reverse) reaction.

Complete and balance the following chemical equations. Identify the reaction type as: combination, decomposition, single replacement, double replacement, or combustion.

Products:
Magnesium Oxide + Carbon dioxide.
a) MgCO₃ (Heat is supplied to the reaction (triangle over a arrow) -> Reaction type:

Products:
Aluminum Oxide
b) Al + O₂ -> Reaction type:

Answers

Answer:

the first one is a decomposition reaction

the second one is also a synthesis reaction

Solution:-1

[tex]\boxed{\sf {MgCO_3\atop Magnesium\:Carbonate}\overset{\Delta H}{\longrightarrow}{MgO\atop Magnesium \:Oxide}+{CO_2\atop Carbon\:Dioxide}}[/tex]

It is a thermal decomposition reaction

Solution:-2:-

[tex]\boxed{\sf {4Al\atop Aluminium}+{3O_2\atop Oxygen}\longrightarrow{2Al_2O_3\atop Aluminium\:oxide}}[/tex]

It is a combination reaction.

The standard reduction potential for O2 in acid is 1.23 V, according to Appendix E. Calculate the reduction potential for O2 at pH 7, for all other conditions being standard.
a. 0.40 V
b. 1.13 V
c. 1.23 V
d. 0.82 V
e. 1.64 V

Answers

Answer:

a. +0.40 V

Explanation:

Reduction of O2 in acid medium is +1.23 V. The reduction of O2 in basic medium will be calculated by subtracting equation of acidic medium from equation in base medium.

Kw^4 = [10^-14 ] ^ 4

solving we get -0.8274

Subtracting the value from oxygen reduction in acidic medium;

+ 1.23 - 0.8274 = +0.4026

In aqueous solution the Hg2+ ion forms a complex with four iodide anions. Write the formation constant expression for the equilibrium between the hydrated metal ion and the aqueous complex. Under that, write the balanced chemical equation for the first step in the formation of the complex.

Answers

Answer:

Following are the solution to the given question:

Explanation:

In the aqueous solution of [tex]Hg^{2+}[/tex] ion is used to represent a [tex][Hg(H_2O)_4]^{2+}[/tex].

It is used to form a complex with iodide ions as [tex][Hgl_4]^{2-}[/tex].  

Conversion reaction:

[tex][Hg(H_2O)_4]^{2+} +4I^{-} \to [HgI_4]^{2-}+4H_20[/tex]

Following are the formation constants:

[tex]k_f=\frac{[HgI_4]^{2-}}{[Hg(H_2O)_4]^{2+} [I^{-}]^4}[/tex]

Following are the first step to the conversion:  

[tex][Hg(H_2O)_4]^{2+} +I^{-} \to [HgI(H_2O)_3]^{+}+H_20[/tex]

Biphenyl, C12H10, is a nonvolatile, nonionizing solute that is soluble in benzene, C6H6.
At 25 ∘C, the vapor pressure of pure benzene is 100.84 Torr. What is the vapor pressure of a solution made from dissolving 10.9 g of biphenyl in 25.3 g of benzene?

Answers

Answer:

The correct answer is - 83. torr

Explanation:

We know that:

p = X solvent * P pure solvent,

where, X solvent = number of moles of solvent / total number of moles.

in this solution, solute is 10.9 g of C12 H10 and the solvent is 25.3 g C6H6.  

molar mass of C6H6 = 6 * 12 g/mol + 6 * 1g/mol = 78 g/mol ( =>  moles of solvent = mass in grams / molar mass)

moles of solvent = 25.3 g / 78 g/mol = 0.3243 mol

molar mass of C12H10 = 12 * 12g/mol + 10*1g/mol = 154 g/mol

moles of solute = 10.9 g / 154 g/mol = 0.07077 mol

=> X solvent = 0.3243 / (0.3243 + 0.07077) = 0.8208

=> p = 0.8208 * 100.84 torr = 82.77 torr ≈ 83.0 torr

Answer: 83.0 torr

A student pours a few drops of vinegar onto limestone and it starts bubbling. What kind of reaction is this? How does it relate to chemical weathering, monuments and statues?

Answers

Answer:

The correct answer is - acid-base reaction or chemical weathering.

Explanation:

Vinegar is an acid that dissolves a material that is commonly found and known as calcium carbonate present in the limestone. When these two, vinegar mix with calcium carbonate of the limestone, the atoms in the acetic acid and the calcium carbonate come apart and rearrange in different ways to make new chemicals.

This rearrangement results in the release of carbon dioxide as a stream of bubbles. It is a form of weathering called chemical weathering and many monuments are based on rocks that have limestones in their composition and acid rain work similar to vinegar.

Can you please answer the 5 attached questions?

Answers

Answer:

10.4%

Explanation:

Recall that the formula for percent solution = mass of solute/mass of solution * 100

Mass of solute = 2.07 g

Mass of solution = 19.9 g

Hence mass percent of solute = 2.07/19.9 * 100

= 10.4%

High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to purify chemical substances. The pressures used in this procedure range from around 500 kilopascals (500,000 Pa) to about 60,000 kPa (60,000,000 Pa). It is often convenient to know the pressure in torr. If an HPLC procedure is running at a pressure of 6.50×106 Pa , what is its running pressure in torr?

Answers

Answer:

1 kpa = 7.5 torr

1.75*10^7 pa = 1.75*10^4 Kpa = (1.75/7.5)*10^4 torr = 2333 torr

Explanation:

A compound contains only carbon, hydrogen, and oxygen. Combustion of 65.76 g of the compound yields 96.38 g of CO2 and 39.46 g of H2O.
The molar mass of the compound is 90.078 g/mol.
1. Calculate the grams of carbon (C) in 65.76 g of the compound:
2. Calculate the grams of hydrogen (H) in 65.76 g of the compound.
3. Calculate the grams of oxygen (O) in 65.76 g of the compound.

Answers

Answer:

1. 26.30 g C.

2. 4.42 g H.

3. 35.04 g O.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required as follows:

1. Here, the only source of carbon is in CO2, and thus, we calculate the grams of carbon from the produced grams of this substance:

[tex]m_C=96.38gCO_2*\frac{1molCO_2}{44.01gCO_2} *\frac{1molC}{1molO_2} *\frac{12.01gC}{1molC} =26.30g[/tex]

2. Here, the only source of hydrogen is in H2O, and thus, we calculate the grams of hydrogen from the produced grams of this substance:

[tex]m_H=39.46gH_2O*\frac{1molH_2O}{18.02gH_2O} *\frac{2molH}{1molH_2O} *\frac{1.01gH}{1molH} =4.42gH[/tex]

3. Here, we subtract the mass of H and C from the mass of the sample, to obtain the mass of oxygen:

[tex]m_O=65.76g-26.30g-4.42g\\\\m_O=35.04g[/tex]

Regards!

Oleic acid and elaidic acid are isomeric alkenes.

a. True
b. False

Answers

Answer:

False

Explanation:

Because Elaidic acid is an isomer of oleic acid. I really hope this helps you.

4.If 15.00 mL of 3.00 M potassium iodide is needed to reach the equivalence point with 10.00 mL of lead (Il) nitrate, determine the molarity of the lead (Il) nitrate solution

Answers

Answer:

2.25 M

Explanation:

The reaction that takes place is:

2KI + Pb(NO₂)₃ → PbI₂ + 2KNO₃

First we calculate how many potassium iodide moles reacted, using the given volume and concentration:

15.00 mL * 3.00 M = 45 mmol KI

Then we convert 45 mmoles of KI into mmoles of Pb(NO₂)₃, using the stoichiometric coefficients of the balanced reaction:

45 mmol KI * [tex]\frac{1mmolPb(NO_3)_2}{2mmolKI}[/tex] = 22.5 mmol Pb(NO₂)₃

Finally we calculate the molarity of the Pb(NO₂)₃ solution, using the calculated number of moles and given volume:

22.5 mmol Pb(NO₂)₃ / 10.00 mL = 2.25 M

what is irrigation?Describe two methods of irrigation which conserve water​

Answers

The process of watering the crops is called irrigation.

Any two methods of irrigation are:

(i) Sprinkler system:

This system is used on the uneven land where less water is available. The perpendicular pipes, having rotating nozzles on top, are joined to the main pipeline at regular intervals. Water is allowed to flow through main pipe under pressure, which escapes from the rotating nozzles. In this way water gets sprinkled on the crop.

(ii) Drip irrigation:

This system is used to save water as it allows the water to flow drop by drop at the roots of the plants. It is the best technique for watering fruit plants, gardens and trees. Water is not wasted at all.

We need to prepare 0.0021 M solution of C2SO4. But there are only 80.7 grams of the chemical available. What is the maximum volume that can be prepared?

Answers

Answer:

320 L

Explanation:

We'll begin by calculating the number of mole in 80.7 g of C₂SO₄. This can be obtained as follow:

Mass of C₂SO₄ = 80.7 g

Molar mass of C₂SO₄ = (12×2) + 32 + (16×4)

= 24 + 32 + 64

= 120 g/mol

Mole of C₂SO₄ =?

Mole = mass /molar mass

Mole of C₂SO₄ = 80.7 / 120

Mole of C₂SO₄ = 0.6725 mole

Finally, we shall determine the volume. This can be obtained as follow:

Mole of C₂SO₄ = 0.6725 mole

Molarity = 0.0021 M

Volume =?

Molarity = mole / Volume

0.0021 = 0.6725 / Volume

Cross multiply

0.0021 × Volume = 0.6725

Divide both side by 0.0021

Volume = 0.6725 / 0.0021

Volume ≈ 320 L

Thus, the volume that can be prepared is approximately 320 L.

A reaction is thermodynamically unstable (spontaneous) but no change is observed. The reaction is probably Select the correct answer below: kinetically unstable. kinetically stable. thermodynamically stable but kinetically unstable. None of the above

Answers

Answer:

kinetically stable.

Explanation:

When we say that a system is thermodynamically unstable, it means that there is still a state in which the system is expected to have lower energy than it currently has. A thermodynamically unstable system is yet to attain equilibrium hence it can still undergo further chemical processes in order to attain thermodynamic stability.

When we say that a system is kinetically stable, it means that the activation energy or energy barrier for the reaction system is high. Thus reactants are not easily converted into products. The reaction system remains the same for a long while without change.

Finally, when a reaction is thermodynamically unstable (spontaneous) but no change is observed, the reaction is kinetically stable.

Amines and amides are organic compounds that contain nitrogen. Amines are ammonia derivatives, in which at least one hydrogen atom is replaced by an organic substituent. Methylamine is a simple amine in which one of the hydrogen atoms of ammonia is replaced by a methyl group:

Answers

Answer:

Following are the solution to the given question:

Explanation:

Identify each of the following half-reactions as either an oxidation half-reaction or a reduction half-reaction.

half-reaction identification
Cu+(aq)--->Cu2+(aq) + e- _________
I2(s) + 2e--->2I-(aq) _________

Answers

Answer:

Cu+(aq)--->Cu2+(aq) + e- : oxidation

reason: there is loss of electrons.

I2(s) + 2e--->2I-(aq) : reduction

reason: There is reduction of electrons.

You will observe a weak acid-strong base titration in this experiment. Select all statements that are true about weak acid-strong base titrations.
A. Weak acid-strong base titrations always start at a higher pH than strong acid-strong base titrations, no matter the initial concentration.
B. The pH is less than 7 at the equivalence point.
C. The pH is greater than 7 at the equivalence point.
D. Half way to the equivalence point, a buffer region is observed.

Answers

Answer:

The pH is greater than 7 at the equivalence point.

Explanation:

Equivalence point is the point where the acid reacts with the base as stipulated in the equation of the reaction.

When a weak acid and a strong base are titrated, the pH of the solution at equivalence point is actually found to be around about pH ~ 9.

Hence, for a weak acid and strong base titration, The pH is greater than 7 at the equivalence point.

A titration between a weak acid and a strong base yields a solution whose pH is greater than 7 at the equivalence point.

What are weak acids?

Weak acids are acids which only ionize partially in aqueous solutions.

When weak acids are dissolved in water, they produce only few hydrogen ions.

A strong base on the other hand ionizes completely to produce hydroxide ions in aqueous solutions.

The titration of a weak acid and a strong base gives a solution whose pH is greater than 7 at equivalence point.

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A 0.245-L flask contains 0.467 mol co2 at 159 °c. Calculate the pressure using the ideal gas law.

Answers

Answer:

Pressure, P = 67.57 atm

Explanation:

Given the following data;

Volume = 0.245 LNumber of moles = 0.467 molesTemperature = 159°CIdeal gas constant, R = 0.08206 L·atm/mol·K

Conversion:

We would convert the value of the temperature in Celsius to Kelvin.

T = 273 + °C

T = 273 + 159

T = 432 Kelvin

To find the pressure of the gas, we would use the ideal gas law;

PV = nRT

Where;

P is the pressure.V is the volume.n is the number of moles of substance.R is the ideal gas constant.T is the temperature.

Making P the subject of formula, we have;

[tex] P = \frac {nRT}{V} [/tex]

Substituting into the formula, we have;

[tex] P = \frac {0.467*0.08206*432}{0.245} [/tex]

[tex] P = \frac {16.5551}{0.245} [/tex]

Pressure, P = 67.57 atm

4. A salvage operator recovered coins believed to be gold. A sample weighed 385.000g and has a volume of 20.0mL. Were the coins gold (Density= 19.3g/mL) or yellow brass (Density =8.47g/mL)? Show your calculation and explain your answer.

Answers

Answer:

The coins are gold

Explanation:

To solve this question we need to find the density of the sample knowing that density is the ratio between the mass of a sample (385.000g) and the volume that is occupying (20.0mL).

Density is:

385.000g / 20.0mL = 19.3g/mL

As the density of the sample is equal to the density of gold:

The coins are gold

why beta carbon hydrogen is easily replaceable but not alpha carbon hydrogen​

Answers

Answer:

Four common types of reactions involving carbonyl reactions: 1) nucleophilic addition; 2) nucleophilic acyl substitution; 3) alpha substitution; 4) carbonyl condensations. The first two were previously discussed and the second two involve the properties of the carbon directly adjacent to the carbonyls, α carbons.

Alpha-substitution reactions results in the replacement of an H attached to the alpha carbon with an electrophile.  

The nucleophile in these reactions are new and called enols and enolates.

Explanation:

The carbon in the carbonyl is the reference point and the alpha carbon is adjacent to the carbonyl carbon.  

Hydrogen atoms attached the these carbons denoted with Greek letters will have the same designation, so an alpha hydrogen is attached to an alpha carbon.  

Aldehyde hydrogens not given Greek leters.  

α hydrogens display unusual acidity, due to the resonance stabilization of the carbanion conjugate base, called an enolate.  

Tautomers are readily interconverted constitutional isomers, usually distinguished by a different location for an atom or a group, which is different than resonance.  

The tautomerization in this chapter focuses on the carbonyl group with alpha hydrogen, which undergo keto-enol tautomerism.  

Keto refers to the tautomer containing the carbonyl while enol implies a double bond and a hydroxyl group present in the tautomer.  

The keto-enol tautomerization equilibrium is dependent on stabilization factors of both the keto tautomer and the enol tautomer, though the keto form is typically favored for simple carbonyl compounds.  

The 1,3 arrangement of two carbonyl groups can work synergistically to stabilize the enol tautomer, increasing the amount present at equilibrium.

The positioning of the carbonyl groups in the 1,3 arrangement allows for the formation of a stabilizing intramolecular hydrogen bond between the hydroxyl group of the enol and the carbonyl oxygen as well as the alkene group of the enol tautomer is also conjugated with the carbonyl double bond which provides additional stabilization.

Aromaticity can also stabilize the enol tautomer over the keto tautomer.

Under neutral conditions, the tautomerization is slow, but both acid and base catalysts can be utilized to speed the reaction up.  

Biological enol forming reactions use isomerase enzymes to catalyze the shifting of a carbonyl group in sugar molecules, often converting between a ketose and an aldose in a process called carbonyl isomerization.

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Solve for y in terms of x.2/3y-4=x A y= 3/2x+6B y=-2/3x+4 C y=-3/2x+6 D 2/3x+4 COULD A KIND SOUL PLEASE HELP ME OUT???!!!!!!Determine the measure of x in the figure below.show how you go the answer so I can see if it makes sense!!! another word for gasping gasping Discuss any two elements of a One-Act play providing examples from Enigma by Floyd Dell in your course book.The elements are setting, characters, conflict and theme. Choose any two elements. Which of the following statements is not true about metabolism?A. Older people tend to burn more calories than younger individuals.B. Basal metabolic rate is the number of calories your body needs to perform basic daily tasks.C. Muscle on the body burns more energy than body fat does.D. One pound of muscle may lead to an extra 3,500 calories being used each month. What percentage of all early death is due to unhealthy lifestyles?Group of answer choices75603590 John runs a computer software store. Yesterday he counted 140 people who walked by the store, 63 of whom came into the store. Of the 63, only 25 bought something in the store.(a) Estimate the probability that a person who walks by the store will enter the store. (Round your answer to two decimal places.)(b) Estimate the probability that a person who walks into the store will buy something. (Round your answer to two decimal places.)(c) Estimate the probability that a person who walks by the store will come in and buy something. (Round your answer to two decimal places.)(d) Estimate the probability that a person who comes into the store will buy nothing. (Round your answer to two decimal places.) Quines son las hermanas mayores de Rey Felipe? (Select all that apply.)A. CristinaB. LetiziaC. SofaD. Elena Which is a point on the circle whose center is (0, 0) and whose radius is 5?A. (2, 3)B. (0, 0)C. (3, 4)D. (4, 5) Solve the following systems of equations using the substitution method. 6x + 2y = 82 and x y = 3 y = 4x 1 and x + y = 9 4x + 3y =17 and y = 5 x Question 3 of 10What helped President Johnson get civil rights legislation passed?O A. He said Americans had talked enough about equality and neededto act.B. He said it would honor President Kennedy's memory.C. He was from the South.D. All of the aboveSURII f(x) = 2x3 + 7x2 4x 5g(x) = 3x 2Find (f - g)(x).A. (f - g)(x) = 2x3 + 7x2 2 3O B. (f g)(x) = 2x3 + 7x2 2 7O C. (f - g)(x) = 2x3 + 7m2 72 3O D. (f - g)(x) = 2x3 + 7x2 73 7 look at the image for the question What are the x-intercepts of the graph of the function below?y= x^2+3x 28A. (6,0) and (4,0)B. (-7,0) and (-4,0)C. (7,0) and (-4,0)D. (-7,0) and (4,0) The child has been diagnosed with severe iron deficiency anemia. The child requires 5 mg/kg of elemental iron per day in three equally divided doses. The child weighs 47.3 lb (21.5 kg). How many milligrams of elemental iron should the child receive with each dose Cho a thc f(x) = bit rng f(1)=f(-1); f(2)=f(-2).Chn cu ng :A. f ( x ) = f ( x) vi mi xB. f ( x ) = f ( x) vi mi xC. f ( x ) = 2 f ( x) vi mi xD. f ( x ) = 3 f ( x) vi mi x Describe three different measures that can be obtained from a single age distribution graph comparing males and females of a given population. The cells lie odjacent to the sieve tubes Read the following excerpt from "The Cask of Amontillado" and answer question.THE thousand injuries of Fortunato I had borne as I best could, but when he ventured upon insult I vowedrevenge. You, who so well know the nature of my soul, will not suppose, however, that gave utterance to athreat. At length I would be avenged; this was a point definitely, settled --but the very definitiveness withwhich it was resolved precluded the idea of risk. I must not only punish, but punish with impunity. A wrong isunredressed when retribution overtakes its redresser. It is equally unredressed when the avenger fails tomake himself felt as such to him who has done the wrong.It must be understood that neither by word nor deed had I given Fortunato cause to doubt my good will. Icontinued, as was my in to smile in his face, and he did not perceive that my smile now was at the thought ofhis immolationWhat character trait is revealed about Montresor in the passage above?He feels it is important to conduct himself as a gentlemanHe has the ability to be conniving and manipulative.He has always behaved kindly towards Fortunato,He has the ability to overlook wrongs in order to preserve relationships, help with this question 20pts