If a right triangle is rotated around one of its legs for 360 degrees, what three dimensional shape is produced?

Answers

Answer 1

Answer:

The shape of a cone

Step-by-step explanation:

If we rotate the right triangle for 360 degrees around one leg, we will have a shape of a cone (a conical shape).

the leg we choose to rotate around will be the height of the cone.

The other leg will be the radius of the cone's base.

And the hypotenusa of the right triangle will be the slant height of the cone.


Related Questions

I etavidewifdwcvefoewf

Answers

I’m not sure what that meant.

Answer:

cool

Step-by-step explanation:

I need help with these plzzz

Answers

Answer:

1. C 2. B

Step-by-step explanation:

1. find the total circumference, d times pi, then put 42 over 360 and multiply them to get that section

2. The actual value of x is 33.2

So I plugged in that value for all of them

The Answer is 1.c 2.b

evaluate the expression -3 times 0.4 to the power of 2 + -1.1 to the power of 3?

Answers

Answer:

idk i have the same question

Step-by-step explanation:

7h=-(2h-18)7h=−(2h−18) Solve for h

Answers

Answer:

h=2

Step-by-step explanation:

7h=−(2h−18)

Distribute the minus sign

7h = -2h +18

Add 2h to each side

7h +2h = -2h+2h +18

9h = 18

Divide each side by 9

9h/9 =18/9

h =2

Answer:

h = 2

I got it right on Kahn Academy

Evaluate the expression 3 x
{10 +1} +5.

Answers

Answer:

38

Step-by-step explanation:

3 x {10 +1} +5.

PEMDAS

Parentheses first

3 x {11} +5.

Then multiply and divide

33+5

38

Answer:

38

Step-by-step explanation:

3 x {10 +1} +5             Following PEMDAS, solve in the parentheses

3 x 11 + 5                   Multiply 3 x 11

33 + 5                       Add

38

Please help!!!! AWARDING BRAINLIEST!!

Answers

It’s a right triangle

how to simply this equation

Answers

Answer:

[tex]\sqrt[3]{2}[/tex]

Step-by-step explanation:

     18

 9 .     2

3 3

Select the expressions that are equivalent to 6(x + 7).
(7 + x) 6
6x + 42
(x + 7)6
42x + 6​

Answers

Answer:

[tex]6x + 42[/tex]

Step-by-step explanation:

Apply the distributive property:

[tex]6x + 6 \times 7[/tex]

Multiply 6 by 7

[tex]6x + 42[/tex]

The frame of the given window is made
of a rectangle with semi-circular top.
Find its perimeter and area.
2.1 m
1.4 m​

Answers

Answer:

3.7096902=area

Step-by-step explanation:

2.1x1.4=2.94m^2

2.94+(.5pi(.7^2))

what is m equal to.
4(m − 13) − 8 = 8

Answers

Answer:

m = 17

Step-by-step explanation:

[tex]4(m - 13) - 8 = 8 \\ 4(m - 13) = 8 + 8 \\ 4(m - 13) = 16 \\ (m - 13) = \frac{16}{4} \\ m - 13 = 4 \\ m = 4 + 13 \\ \huge \red { \boxed{m = 17}}[/tex]

Determinado automovel, apos sua compra, perde 10% do valor ano a ano nos 3 preimeiros anos. Calcule o valor do automovel ao final desse periodo sabendo que ele foi comprado por R$80.000

Answers

Answer:

The value of the car after 3 years is R$58.320.

O valor do carro ao final desse período é R$58.320.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

[tex]V(t) = V(0)(1-r)^{t}[/tex]

In which V(0) is the initial value and r is the yearly depreciation rate.

In this question, we have that:

[tex]V(0) = 80000, r = 0.1[/tex]

So

[tex]V(t) = V(0)(1-r)^{t}[/tex]

[tex]V(t) = 80000(1-0.1)^{t}[/tex]

[tex]V(t) = 80000(0.9)^{t}[/tex]

Value of the car at the end of 3 years:

[tex]V(3) = 80000(0.9)^{3} = 58320[/tex]

The value of the car after 3 years is R$58.320.

O valor do carro ao final desse período é R$58.320.

Find the volume of a pyramid with a square base, where the area of the base is
8.7 m and the height of the pyramid is 10 m. Round your answer to the nearest
tenth of a cubic meter.

Answers

Answer: 29.0

Step-by-step explanation:

The volume of a pyramid is equal to l*w*h/ 3  and we know that the length times the width is the same as the base.

so we will multiply 8.7 * 10= 87 /3=  29

Volume = 87 m³

You need to multiply the area and the height to find the volume. If you have the length, width, and height, then you need to multiply and 3 and divide it by 3. Hope I helped :)

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