If a substance has a density of 0.123 g/mL, 10.0 dL would weigh in g? ​

Answer:

The entropy increases

Explanation:

Just took the quiz

Answer:

b < c < a < d

Explanation:

The weak acid with the lowest pKa will be the most acidic. In the other way, the conjugate base which the acid is weak will be strong.

The weak base with the lowest pKb will be the most basic. And the conjugate base of the weak base will be a strong acid.

Ka Acetic acid = 1.8x10-5

Ka HCN = 1.9x10-10

Kb pyridine = 1.7x10-9

Kb NH3 = 1.8x10-5

NH4Br is the conjugate base of a weak base. That means is a strong acid.

NH4Br has the lowest pH

NaBr is the conjugate base of a strong acid, HBr. That means NaBr is neutral

The most basic between the conjugate base of the acetic acid, NaCH3CO2 and KCN is KCN because the acetic acid is the stronger acid regard to HCN.

The rank is:

NH4Br < NaBr < NaCH3CO2 < KCN

Answer:

6.) 3, 12, 1, and 4   8.) 4, 1, and 3

Explanation:

By multiplying subscripts inside and outside of the parentheses you can count the number of atoms that are present. I recently answered a question for you and I did the math wrong I am going to go back and comment so you know which one and I will correct my errors. Sorry for the inconvenience!

the number of atoms in number 6:

N: 3

H: 12

P: 1

O: 4

the number of atoms for number 8:

Ca: 4

C: 1

O: 3

hope I clarified my mistake and helped you! :)

Answer: The volume is 8.94 L.

Explanation:

Given: no. of moles = 0.350 mol,   Pressure = 0.980 atm

Temperature = [tex]32^{o}C = (32 + 273) K = 305 K[/tex]

Formula used to calculate the volume is as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]PV = nRT\\0.980 atm \times V = 0.350 mol \times 0.0821 L atm/mol K \times 305 K\\V = 8.94 L[/tex]

Thus, we can conclude that the volume is 8.94 L.

Answer:

c the pancreas produce enzyme that breakdown carbohydrate protein and fat

Answer:

[tex]Q_{sln}=-3219.25 J[/tex]

Explanation:

Hello there!

In this case, for this calorimetry problem, it is possible for us to infer that the heat of the reaction of dissolution of KNO3 is absorbed by the solution composed by the former and water so that we can write:

[tex]Q_{rxn}=-Q_{sln}[/tex]

Thus, given the mass, specific heat and temperature of the solution, we plug in the data to obtain the heat absorbed, by the reaction:

[tex]Q_{rxn}=-m_{sln}C_{sln}\Delta T _{sln}\\\\Q_{rxn}=-(13.3+213)g(4.184\frac{J}{yg\°C} )(19.60-23.00)\°C\\\\Q_{rxn}=3219.25J[/tex]

Also, we can say the the heat released by the solution was -3219.25 J.

Best regards!

Answer:

B. Eastern Europe

Explanation:

The economy of Eastern Europe depends on producing foods. For example, Poland and Belarus are two countries in Eastern Europe, and they both produce chocolates. Producing foods isn't the only detrimental part of the region's economic data. The other half depends on consumer goods. For example, Estonia and Latvia are good countries in packaging food. The answer to the question is B.

Explanation:

sexual reproduction has minimal changes of mutations compared to asexual reproduction

Answer:

sexual reproduction has minimal changes of mutations compared to asexual reproduction

I hope this helps

Answer:

There are 20 electrons.

Explanation:

Chlorine has 17 electrons in its atom to begin with (you can tell from the proton number in the periodic table).

A charge of -3 means that the chlorine atom gained 3 electrons, and now needs to lose 3 electrons to return to its atom configuration.

Answer:

No

Explanation:

thats scientifically impossible

Answer:

I'll explain.

Explanation:

The molecules of two different elements, nitrogen and oxygen, make up about 99 percent of the air. The rest includes small amounts of argon and carbon dioxide. Oxygen is the life-giving element in the air. You can tell because they're on the periodic table which is a table for elements.

Explanation:

nitrogen and oxygen are the gases in the air which are elements you can simply say it by looking the periodic table

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

[tex]AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)[/tex]

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

[tex]Ksp=[Ag^+][Cl^-][/tex]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

       [tex]\ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)[/tex]

I          -                   0             0

C        -                   +x           +x

E        -                    x             x

Which leads to the following modified equilibrium expression:

[tex]Ksp=x^2[/tex]

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

Regards!

Answer:

0.0010 M of HC2H302(aq)

Answer:

Explanation:

Remark

Interesting que8stion. You have to figure out how many mols are present in each reactant. Since all periodic tables are different, I'm going to use rounded numbers. If it is too close, I will go further.

NaCl

Na = 23

Cl = 35.5

1 mol = 58.5 grams

given = 50.0 grams

Mols for the reaction = 50/58.5 = 0.855

H2SO4

H2       =    2*1        2

S          =   1 * 32   32

O4       =   4*16     64

1 mol  =               98   grams

mols  present = 50/98 = 0.510

MnO2

Mn     = 1 * 55    = 55

O2   =   2*16      = 32

1 mol =                  87 grams

mols available    = 50/87 = 0.5747

Discussion

Na Cl and H2SO4 both require 2 moles for every mol of Cl2 produces.

H2SO4  has 0.51 mols available for a reaction

NaCl has  0.855 moles available for a reaction

MnO2 has 0.575 moles available for a reaction.

Given those numbers 0.510 mols of H2SO4 will only produce 0.255 mols of chlorine and the rest will be reduced in a similar manner. H2SO4 is the limiting reagent (reactant).

In other words only 0.510 moles of NaCl will be used and 0.855 - 0.510 moles will be left over on the reactants side.

only 0.575 moles of MnO2 will be used and 0.065 moles will be left over.

The oddity in the result shows up because the balance numbers in the equation give a ratio of 2 to 1 for H2SO4 and NaCl The 2 belongs to the reactants and the 1 for the chlorine.

Answer:

Volume is reduced to half

Explanation:

Acid base titration are commonly used reactions in a lab, and are ofter used to get pH or different kind of solutions.

The neutralization of an acid base reaction is reached, when the solution (having added an indicator previously) changes its original color. chemically speaking, this occurs when the number of moles of the acid and the base are balanced and equal. In other words the following:

n₁ = n₂   (1)

This expression can also be expressed in function of concentration and volume:

M₁V₁ = M₂V₂   (2)

From here, solving for V₁:

V₁ = M₂V₂  / M₁

Now, this expression is true only when we have the same kind of substance that can lose or gain the same number of hydrogens.

Lets suppose that we have as base NaOH (Monoprotic base) and HCl (monoprotic acid), the titration reaction would be:

NaOH + HCl --------> NaCl + H₂O

As both of the species are monoprotic, the number of moles are the same  when they reach the equilibrium, so, expression  (2) can be used, and calculate volume or concentrations.

However, in this case, a partner made a mistake and use a diprotic acid, in this case, H₂SO₄, In this case, things chance because H₂SO₄ is diprotic, meaning that we need to dissociate two hydrogens in equilibrium, therefore, expression (2) would be something like this.

Acid: 1; Base: 2

H₂SO₄ + 2NaOH ------> Na₂SO₄ + H₂O

nH₂SO₄ = n₁ = 1

nNaOH = n₂ = 2

n₁/n₂ = 1/2

2n₁ = n₂   (3)

Writting this, in function of concentration and volume, it would be:

2M₁V₁ = M₂V₂   (4)

From here, if we solve for the volume of the acid (V₁):

V₁ = M₂V₂ / 2M₁

Therefore, according to this expression, we can see that the volume required of the acid would be half the volume required of the monoprotic acid. For example, if we need 50 mL of Chloridic acid to reach the equivalence point with NaOH, then, with H₂SO₄ it will only need 25 mL. This, of course, assuming that concentrations are the same, and volume of the base used, the same.

Hope this helps

Answer:

a. True

Explanation:

Distillation process is a process that is used to separate the components or the substances from the liquid mixtures by using selectively boiling and condensation.

While fractional precipitation is a process which separates the ions from solution based on the different solubilities.

Therefore, the answer is true.

The correct option is :

=》It has a high magnitude.

the damage caused by an earthquake is proportional to its magnitude, as much the magnitude is, that much damage will be caused by it.

The term used to indicate and earthquake that causes major damage to buildings in an area is called a high magnitude earthquake. Hence, option a is correct.

The most typical way to gauge an earthquake's size is by its magnitude. No matter where you are or how violent the shaking is, it is the same number since it represents the size of the earthquake's source.

The USGS no longer uses the outmoded Richter scale to determine the magnitude of major, teleseismic earthquakes. Several magnitude scales measure various aspects of the earthquake, but the Richter scale measures the biggest wobble (amplitude) on the recording.

Currently, the USGS uses the Moment Magnitude scale to report earthquake magnitudes, however many different magnitudes can be calculated for comparison and research. Therefore, option a is correct.

Find more on earthquakes:

https://brainly.com/question/29500066

#SPJ3

Answer:

electricity

Explanation:

I know this because I am currently learning about this and remember doing it

An ideal gas is one that follows the gas laws at all conditions of temperature and pressure. To do so, the gas would need to completely abide by the kinetic-molecular theory. On the other hand, a real gas is a gas that does not behave according to the assumptions of the kinetic-molecular theory.

Furthermore, the particles of an ideal gas are extremely small and have a mass equivalent to practically zero. Ideal gas particles also have no volume.

An example of a real gas is helium, oxygen, and nitrogen.

Answer:

True

Explanation:

This is because, The hydroboration oxidation of an alkene which is isobutene in the presence of a catalyst will result to alcohol as the product . Therefore, the OH group will attach or link itself to the carbon which is less obstructed. Thus this reaction is in accordance to Anti-Markownikoff's rule.

So isobutene on hydroboration oxidation will produce ter isobutyl alcohol.

Answer:no

Explanation:

Answer:

Scandium is a transition metal

Explanation:

Answer:

4258.82 g of Na₂SO₄

Explanation:

From the question given above, the following data were obtained;

Number of molecules of Na₂SO₄ = 1.8055x10²⁵ molecules.

Number of mole of Na₂SO₄ =?

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole

Therefore,

6.02×10²³ molecules = 1 mole of Na₂SO₄

Next, we shall determine the mass of 1 mole of Na₂SO₄. This can be obtained as follow:

1 mole of Na₂SO₄ = (23×2) + 32 + (16×4)

= 46 + 32 + 64

= 142 g

Thus,

6.02×10²³ molecules = 142 g of Na₂SO₄

Finally, we shall determine the mass of Na₂SO₄ that contains 1.8055x10²⁵ molecules. This can be obtained as follow:

6.02×10²³ molecules = 142 g of Na₂SO₄

Therefore,

1.8055x10²⁵ molecules

= (1.8055x10²⁵ × 142) / 6.02×10²³

= 4258.82 g of Na₂SO₄

Thus, 4258.82 g of Na₂SO₄ contains 1.8055x10²⁵ molecules

Answer:

Warm front

Explanation:

A warm front forms when a warm air mass pushes into a cooler air mass, shown in the image to the right (A). Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. Warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface. Warm fronts often form on the east side of low-pressure systems where warmer air from the south is pushed north.

You will often see high clouds like cirrus, cirrostratus, and middle clouds like altostratus ahead of a warm front. These clouds form in the warm air that is high above the cool air. As the front passes over an area, the clouds become lower, and rain is likely. There can be thunderstorms around the warm front if the air is unstable.

On weather maps, the surface location of a warm front is represented by a solid red line with red, filled-in semicircles along it, like in the map on the right (B). The semicircles indicate the direction that the front is moving. They are on the side of the line where the front is moving. Notice on the map that temperatures at ground level are cooler in front of the front than behind it.

Answer:

Q1) B

Q2) C

Kelvin is the SI unit of temperature.