Answer:
The ratio of the escape velocity to the orbital velocity is [tex]\sqrt 2[/tex].
Explanation:
The minimum velocity given to an object so that it escapes from the earth's gravitational pull is called escape velocity.
The formula of the escape velocity is
[tex]v=\sqrt\frac{2GM}{R}[/tex]
The velocity of an object in the orbit around the earth is called orbital velocity.
The formula of the orbital velocity is
[tex]v=\sqrt\frac{GM}{R}[/tex]
The ratio of the escape velocity to the orbital velocity is
[tex]\frac{v_e}{v_o}=\sqrt 2[/tex]
What type of electromagnetic waves do heat lamps give off?
A. infrared
B. ultraviolet
C. microwaves
D. radio waves
A truck travelling at 30m/s decelerates at 1.5m/s². How far does it travel during the 10th second after the brakes are applied?
Answer
225 meters.
Explanation:
x=x0+30t-(1/2)(1.5)t^2
x=0+30(10)-(1/2)(1.5)(10)^2
x=300-75
x=225
Two balls collide head-on in a perfectly inelastic collision. The first ball has a mass of 0.75 kg and an initial velocity of 5.0 m/s to the right. The second ball has a mass of 0.40 kg and an initial velocity of 3.5 m/s to the left. What is the decrease in kinetic energy during the collision?
Explanation:
Momentum conservation
V=3.38
Delta kinetic energy =1/2m(vi^2-v^2)
A educação física, enquanto componente curricular da educação básica. Qual a tarefa que educação física?? Alguem me ajuda por fvr ??
Answer:
como assim qual a tarefa que educação física? se você me explicar melhor eu consigo te responder !!
Explanation:
When magma flows on the surface on the surface, it is already called lava
TRUE OR FALSE
Answer:
True
Explanation:
I guess you made a mistake on question.
but I understood what you wanted to say.
Hope this helps... :)
A stone is thrown vertically upward with an initial velocity of 40m/s. Taking g = 10 m/s^2 find the maximum height reach by the stone and what is the net displacement and distance covered by the stone.
Explanation:
u=40
v=?
h=?
v²-u²=2gs
0²-40²=2×10×s
160=20s
s=160/20
=80m/s
total distance= upward distance ×downward distance
=80+80
=160m
total displacement=0 because u and v is the same.
Answer:
The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
Explanation:
Final velocity v = 0
Initial velocity u = 40m/s
We know that,
Using equation of motion
[tex]v^{2} =u^{2} +2gh[/tex]
[tex]0-40^{2} =2[/tex] × [tex]10[/tex] × [tex]h[/tex]
The maximum height is:
[tex]h=80[/tex] [tex]m[/tex]
The stone will reach at the top and will come down
Therefore, the total distance will be:
[tex]s=h_{1} +h_{2}[/tex]
[tex]s=80m-80m=160m[/tex]
The net displacement is:
[tex]D=h_{1} -h_{2}[/tex]
[tex]D=80m-80m=0[/tex]
Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
hope this helps.....
How do you use the periodic table to recall the ionic charge of an alkali metal, an alkaline earth metal, or aluminum?
The positive charge is the group number.
The negative charge is the group number.
The positive charge is the period number.
The negative charge is the period number.
Answer:
the positive charge is the period number
Explanation:
I might be wrong
Answer:
The positive charge is the group number.
Explanation:
The force of friction acting on a sliding crate is 223 N.
How much force must be applied to main- tain a constant velocity?
Answer:
Friction Opposes Motion of an Object.
Now
To get the Net force that Moves an Object and causes acceleration....You subtract the Frictional force
Net force = Pushing Force - Frictional Force
Recall
Net Force; F=Ma
Ma = P - Fr
Now the question asked for How Much force Must be applied to Maintain a Constant velocity.
In a Constant Velocity Motion... Acceleration do not change... Its Zero
So Putting this into the formula above
M(0) = P - Fr
0=P - Fr
Fr = P.
This means
That The force needed to keep this object Moving at Constant Velocity Must be equal to its Frictional Force
Since Frictional Force; Fr =223N
The Applied Force(Pushing Force) Must be equal to 223N too.
i have 5 eggs i grabbed one i a cracked 1 i cooked one i ate one how many eggs do i have
Answer:
4
Explanation:
4-3
What is a cyclotron??
What is cyclotron frequency?
Answer:
A cyclotron is a type of particle accelerator.
Explanation:
Cyclotron frequency is the frequency of a charged particle moving perpendicular to the direction of a uniform magnetic field B, since that motion is always circular, the cyclotron frequency is given by equality of centripetal force and magnetic Lorentz force.
1 .
crest
the energy of light
2 .
wavelength
makes it possible to see things
3 .
light
a source of light
4 .
X-rays
top of wave
5 .
sun
bottom of wave
6 .
radiant
distance from one point on one wave to the same point on the next wave
7 .
trough
longer wavelengths than visible light
8 .
infrared light
shorter wavelengths than visible light
Answer:
Find answers below.
Explanation:
1. Radiant: the energy of light.
2. Light: makes it possible to see things.
3. Sun: a source of light. This source of light is referred to as solar energy and it's renewable source of energy.
4. Crest: top of wave. Thus, it's typically the highest part of an electromagnetic wave.
5. Trough: bottom of wave. Thus, it's typically the lowest part of an electromagnetic wave.
6. Wavelength: distance from one point on one wave to the same point on the next wave.
7. Infrared light: it has longer wavelengths than visible light.
8. X-rays: shorter wavelengths than visible light.
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
An electromagnetic spectrum refers to a range of frequency and wavelength that an electromagnetic wave is distributed or extends. The electromagnetic spectrum comprises of gamma rays, visible light, ultraviolet radiation, x-rays, radio waves, and infrared radiation.
I need help with question 6
Answer:
0.16 h
Explanation:
Speed: 25km per hour
Speed=distance/time
25=4/t
t=4/25
t=0.16 hour
t=9.6 minuites
Brainliest please~~
A -0.00125 C charge is placed 3.62 m from a +0.00333 C charge. What is the magnitude of the electric force between them?
Answer:
The magnitude of the force between the charges is approximately -2,858.77 N
Explanation:
The given details are;
The magnitude of the given charges;
q₁ = -0.00125 C, q₂ = +0.00333 C
The distance between the charges, r = 3.62 m
The magnitude of the electric force between the charges, 'F', between two charged particles or objects is given as follows;
[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]
Where;
k = Constant = 9 × 10⁹ N·m²/C²
q₁ = The magnitude of charge on the first charged object = -0.00125 C
q₂ = The magnitude of charge on the second charged object = +0.00333 C
r = The distance between the charges = 3.62 m
Plugging in the values, gives;
[tex]F = \dfrac{9 \times 10^9 \ \dfrac{N \cdot m^2}{C^2} \times (-0.00125 \, C) \times (+0.00333 \, C)}{\left( 3.62 \, m \right)^2} \approx -2,858.77 \, N[/tex]
The magnitude of the force between the charges, F ≈ -2,858.77 N
A 15 cm length of wire is moving perpendicularly
through a magnetic field of strength 1.4 T at the rate
of 0.12 m/s. What is the EMF induced in the wire?
A. OV
C. 0.025 v
B. 0.018 V
D. 2.5 V
Answer: C or B
Explanation:
The EMF induced in the wire moving perpendicularly through a magnetic field is 0.025V. The correct option is C.
What is EMF?The EMF is the electro motive force which causes the current to induce in the object moving in the magnetic field.
Given is the length of wire L =15cm =0.15m, magnetic field strength B = 1.4T and velocity of wire V =0.12 m/s
EMF is related to the length of wire, magnetic field strength and velocity of wire proportionally.
ε = B x L x V
Plug the values, we get
ε = 1.4 x 0.15 x 0.12
ε = 0.025 Volts
Thus, the correct option is C.
Learn more about EMF.
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A swimmer is capable of swimming at 1.4m/s in still water. a. How far downstream will he land if he swims directly across a 180m wide river? b. How long will it take him to reach the other side.
Answer:
t = 180 / 1.4 = 129 sec (time to swim horizontally across river)
S = 129 sec * V where V is speed of current and S is the distance he will be carried downstream
The problem does not specify V the speed of the river
Answer:
Explanation:
From the given information:
a) the distance(D) showing how dar downstream he will land can be computed as follows:
Assuming the current of the river = 0.2 m/s
[tex]D = \dfrac{180 \ m \times 0.2 \ m/s}{1.4 \ m/s}[/tex]
D = 36 m ÷ 1.4
D = 25.71 m
The required time (t) to reach the other side is:
time (t) = 180 m/ 1.4 m/s
time (t) = 128.57 seconds
Parallel incident rays appear to bounce like they have all originated from the same point. What is this point called?
A. cross point
B. midpoint
C. bounce point
D. focal point
In the picture below, a car hits a wall. Using what you know about Newton’s Third Law, which is true?
The force of the wall on the car and the car on the wall are equal
The force of the wall on the car is greatest
The force of the car on the wall is greatest
There is not enough information to tell
Answer:
A...................................
The force of the wall on the car and the car on the wall are equal is true about Newton’s Third Law. Option A is the correct answer.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. This means that if the car hits the wall, there will be a force exerted by the car on the wall, and an equal and opposite force exerted by the wall on the car. Option A is the correct answer.
The forces involved in the interaction between the car and the wall are equal in magnitude but opposite in direction, as dictated by Newton's Third Law. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. This means that when an object exerts a force on another object, the second object exerts a force of equal magnitude but in the opposite direction on the first object.
Learn more about Newton here:
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The complete question is, "In the picture below, a car hits a wall. Using what you know about Newton’s Third Law, which is true?
a. The force of the wall on the car and the car on the wall are equal
b. The force of the wall on the car is greatest
c. The force of the car on the wall is greatest
d. There is not enough information to tell"
An elevator of 3 × 10^4N is raised to a height of 100m in 20s . The work done by electric motor is equivalent to ?
Answer:
we neglect the time data
Lamp is placed in the lamp holder. The switch is closed. The lamp glows brightly for a short time and then the lamp does not work. Explain these observations
Solution :
It is given that the lamp glows brightly for a shorter period of time when the switch is closed on it the switch is put on. But after the some time the lamp goes off and it stops working.
This is because as soon as we on the switch, the current start flowing to the lamp which makes the filament of the lamp to glow, but due to some issue, the current stop flowing even when the switch is on and this stops the lamp from glowing and hence the lamp does not work.
How to calculate displacement, velocity, acceleration.
A meter 0.0525 m from a wire measures a magnetic field of 7.14 x 10-6 T. How much current flows through the wire?
Answer:
[tex]I=1.9A[/tex]
Explanation:
From the question we are told that:
Meter distance [tex]d=0.0525[/tex]
Magnetic field [tex]B=7.14*19^{-6}T[/tex]
Generally the equation for Magnetic field B is mathematically given by
[tex]B =\frac{\mu *I }{2* \pi r}[/tex]
[tex]7.14*19^{-6}T =\frac{ 1.26 *10^{-6} *I }{2* 3.142*0.0525}[/tex]
Where
Constant[tex]\mu=1.26 *10^{-6}[/tex]
[tex]I=1.9A[/tex]
Therefore
The Current through the wire is
[tex]I=1.9A[/tex]
Answer: 1.87
Explanation:
acellus
At the local grocery store, you push a 14.5-kg shopping cart. You stop for a moment to add a bag of dog food to your cart. With a force of 12.0 N you now accelerate the cart from rest through a distance of 2.29 m in 3.00 s. What was the mass of the dog food?
Answer:
The mass of the dog food added is 9.03 kg
Explanation:
Given;
mass of the shopping cart, m₁ = 14.5 kg
let the mass of the bag added = m₂
the force applied, F = 12 N
initial velocity of the cart-bag system, u = 0
distance traveled by the system, d = 2.29 m
time of motion of the system, t = 3.0 s
The acceleration of the system is calculated as;
[tex]d = ut + \frac{1}{2} at^2\\\\2.29 = 0 + (\frac{1}{2} \times 3^2)a\\\\2.29 = 4.5 a\\\\a = \frac{2.29}{4.5} \\\\a = 0.51 \ m/s^2[/tex]
The total mass of the system (M) is calculated as follows;
F = Ma
M = F/a
M = (12)/(0.51)
M = 23.53 kg
The mass of the dog food added is calculated as;
m₂ = M - m₁
m₂ = 23.53 kg - 14.5 kg
m₂ = 9.03 kg
HELP, SCIENCE QUESTION I AM STUCK
6. Which of the following is NOT part of a circuit?
A. rim B. load C. power source D. conductor
Use the universal law of gravitation to solve the following problem.
Hint: mass of the Earth is = 5.97 x 1024 kg
A scientific satellite of mass 1300 kg orbits Earth 200 km above its surface. If Earth has a radius of 6378 km, what is the force of gravity acting on the scientific satellite?
a. Write out the formula for this problem.
b. Plug in the values from this problem into the formula.
c. Solve the problem, writing out each step.
d. Correct answer
Answer:
a.
[tex]F=G\cdot\dfrac{M \cdot m}{r^{2}}[/tex]
b.
[tex]F=6.67430 \times 10^{-11} \dfrac{N \cdot m^2}{kg^2} \times \dfrac{5.97 \times 10^{24} \ kg \times 1,300 \ kg}{(6,578 \ m)^{2}}[/tex]
c.
[tex]F=6.67430 \times 10^{-11} \dfrac{N \cdot m^2}{kg^2} \times \dfrac{5.97 \times 10^{24} \ kg \times 1,300 \ kg}{(6,578 \ m)^{2}} \approx 1.144 \times 10^{13} \ N[/tex]
d. The force of gravity acting on the satellite is approximately 1.144 × 10¹³ N
Explanation:
a. The formula for finding the force of gravity, F, acting object on an object is given as follows;
[tex]F=G\cdot\dfrac{M \cdot m}{r^{2}}[/tex]
Where;
F = The force acting between the Earth and the object
G = The gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
M = The mass of the Earth = 5.97 × 10²⁴ kg
m = The mass of the object
r = The distance between the center of the Earth and the object
b. Finding the gravitational force, 'F', between the Earth and the scientific satellite, we have;
The given mass of the satellite, m = 1,300 kg
The distance between the center of the Earth and the center of the satellite, r = The length of the radius of the Earth + The height of orbit of the satellite
The given height of orbit of the satellite, h = 200 km
∴ r = R + h = 6,378 km + 200 km = 6,578 m
Therefore, by plugging in the values, we get;
[tex]F=6.67430 \times 10^{-11} \dfrac{N \cdot m^2}{kg^2} \times \dfrac{5.97 \times 10^{24} \ kg \times 1,300 \ kg}{(6,578 \ m)^{2}}[/tex]
c. Solving the above equation gives;
[tex]F=6.67430 \times 10^{-11} \dfrac{N \cdot m^2}{kg^2} \times \dfrac{5.97 \times 10^{24} \ kg \times 1,300 \ kg}{(6,578 \ m)^{2}} \approx 1.144 \times 10^{13} \ N[/tex]
d. The force of gravity acting on the satellite, F ≈ 1.144 × 10¹³ Newton
id really appreciate it if you helped (I'll give you brainlist)
Explanation:
answer is in the picture above
can someone please help me I will mark you as brilliant.
The current in a resistor is 5 A and the voltage between its terminals is 40 V. Calculate the resistance.
An iron wire has a resistance of 24 Ω. If the voltage across its ends is 12 V, calculate the current in the wire.
Answer:
1=8 ohms 2=0.5 Amps
Explanation:
why trucks are made to have many tires?
Answer: Load carrying heavy vehicles have large number of wheels in order to reduce pressure on the contact patch on road. With large number of wheels, it becomes easy to distribute the entire pressure of loads in an even manner.
Explanation:
in a series circuit, how does the voltage supplied by the battery compare to the voltages on each load?
Answer:
In a series circuit, how does the voltage supplied by the battery compare to the voltage on each load? The voltage of the battery is equal to the voltage of each load added together. ... The voltage across the two resistors must both have the same voltage of the battery.
Explanation:
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Answer:
The voltage of the battery is equal to the voltage of each load added together. The voltage across the two resistors must both have the same voltage of the battery.
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Answer: The equations in column A is matched with gas laws in column B as follows:
21. PV = nRT : (g) Ideal gas law
22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law
23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law
24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law
25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law
26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law
27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion
Explanation:
(A) Ideal gas law: It states that the product of pressure and volume is directly proportional to the product of number of moles and temperature.
So, PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant
T = temperature
Boyle's law: At constant temperature, the pressure of a gas is inversely proportional to volume.So, [tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
Charles' law: At constant pressure, the volume of a gas is directly proportional to temperature. So,[tex]V \propto T\\\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\V_{1}T_{2} = V_{2}T_{1}[/tex]
Gay-Lussac's law: At constant volume, the pressure of a gas is directly proportional to temperature.So, [tex]P_{1}T_{2} = P_{2}T_{1}[/tex]
Avogadro's law: At same temperature and pressure, the volume of gas is directly proportional to moles of gas.So, [tex]V_{1}n_{2} = V_{2}n_{1}[/tex]
Combined gas law: When Boyle's law, Charles' law, and Gay-lussac's law are combined together then it is called combined gas law. So,[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\or, P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex]
Graham's law of effusion: It states that the rate of effusion of a gas is inversely proportional to the square root of mass of its particles.[tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex]
Thus, we can conclude that equation in column A is matched with gas laws in column B as follows:
21. PV = nRT : (g) Ideal gas law
22. [tex]V_{1}n_{2} = V_{2}n_{1}[/tex] : (f) Avogadro's law
23. [tex]P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}[/tex] : (e) Combined Gas Law
24. [tex]P_{1}T_{2} = P_{2}T_{1}[/tex] : (d) Gay-Lusaac's law
25. [tex]V_{1}T_{2} = V_{2}T_{1}[/tex] : (c) Charles' law
26. [tex]P_{1}V_{1} = P_{2}V_{2}[/tex] : (b) Boyle's law
27. [tex]\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}[/tex] : (a) Graham's Law of effusion
help please just give the answers asap no explanation needed
Answer:
where is the question? I can only see the diagram
d) is an atom of Sodium and an atom of Chlorine.
e) is a molecule of water.
