If f(x) is a third degree polynomial function, how many distinct imaginary roots are possible?​

Answer:

5 13 and 10

blue cheese

Answer:

Similar to your other question. Now, you're looking for the score such that this time, 0.99 corresponds to a z-score of approximately, which means

Answer:

4.56% of the deliveries are likely to be outside the specification limits.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The average weight was 95.0 grams. The standard deviation was 0.25 grams.

This means that [tex]\mu = 95, \sigma = 0.25[/tex]

What percentage of the deliveries is likely to be outside the specification limits (outside the interval of [94.5, 95.5])?

Less than 94.5, or more than 95.5. Since the normal distribution is symmetric, these probabilities are the same, so we can find one of them and multiply by two.

The probability that it is less than 94.5 is the p-value of Z when X = 94.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{94.5 - 95}{0.25}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a p-value of 0.0228

2*0.0228 = 0.0456

0.0456*100% = 4.56%

4.56% of the deliveries are likely to be outside the specification limits.

Answer:

Solution given:

a.

tn=12-n

1 st term =12-1=11

2nd term =12-2=10

3rd term=12-3=9

4th term=12-4=8

10th term=12-10=2

b.

tn=5-2n

1st term=5-2*1=3

2nd term=5-2*2=1

3rd term=5-2*3=-1

4th term=5-2*4=-3

10th term=5-2*10=-15

(a) Solution

T(n) = 12 - n

T(1) = 12 - 1 = 11

T(2) = 12 - 2 = 10

T(3) = 12 - 3 = 9

T(4) = 12 - 4 = 8

T(10) = 12 - 10 = 2

(b) Solution

T(n) = 5 - 2n

T(1) = 5 - 2 = 3

T(2) = 5 - 4 = 1

T(3) = 5 - 6 = -1

T(4) = 5 - 8 = -3

T(10) = 5 - 20 = -15

Answer:3.31662479036.

Step-by-step explanation:To find the square root of 11, use the long division method to get the approximate value. Therefore, √11 = 3.31662479036. Register at BYJU'S to learn other interesting mathematical concepts.

Answer:

y = -3/8x -41/8

Step-by-step explanation:

Perpendicular lines intersect at 90° and their slopes are opposite reciprocals.

Therefore the slope changes from 8/3 to -3/8.

Now we must solve for the new y-intercept (b) by plugging in the given coordinate (-3,-4).

The result is b = -41/8 so our new equation is:

y = -3/8x -41/8

Answer:

The sum converges at: [tex]\frac{10}{3}[/tex]

Step-by-step explanation:

Given

[tex]\sum\limits^{\infty}_{n =2} \frac{8}{n^2 - 1}[/tex]

Express the denominator as difference of two squares

[tex]\sum\limits^{\infty}_{n =2} \frac{8}{(n - 1)(n+1)}[/tex]

Express 8 as 4 * 2

[tex]\sum\limits^{\infty}_{n =2} \frac{4 * 2}{(n - 1)(n+1)}[/tex]

Rewrite as:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{2}{(n - 1)(n+1)}[/tex]

Express 2 as 1 + 1 + 0

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1+1+0}{(n - 1)(n+1)}[/tex]

Express 0 as n - n

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1+1+n - n}{(n - 1)(n+1)}[/tex]

Rewrite as:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{(n + 1)-(n - 1)}{(n - 1)(n+1)}[/tex]

Split

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{(n + 1)}{(n - 1)(n+1)}-\frac{(n - 1)}{(n - 1)(n+1)}[/tex]

Cancel out like terms

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1}{(n - 1)}-\frac{1}{(n+1)}[/tex]

In the above statement, we have:

[tex]a_3 + a_5 = 4[(\frac{1}{2} - \frac{1}{4}) + (\frac{1}{4} - \frac{1}{6})][/tex]

[tex]a_3 + a_5 = 4[(\frac{1}{2} - \frac{1}{6})][/tex]

Add [tex]a_7[/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{6}) + (\frac{1}{7 - 1} - \frac{1}{7+1})][/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{6}) + (\frac{1}{6} - \frac{1}{8})][/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{8})][/tex]

Notice that the pattern follows:

[tex]a_3 + a_5 + a_7 + ...... + a_{k}= 4[(\frac{1}{2} - \frac{1}{k+1})][/tex]

The above represent the odd sums (say S1)

For the even sums, we have:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1}{(n - 1)}-\frac{1}{(n+1)}[/tex]

In the above statement, we have:

[tex]a_4 + a_6 = 4[(\frac{1}{3} - \frac{1}{5}) + (\frac{1}{5} - \frac{1}{7})][/tex]

[tex]a_4 + a_6 = 4[(\frac{1}{3} - \frac{1}{7})][/tex]

Add [tex]a_8[/tex] to both sides

[tex]a_4 + a_6 +a_8 = 4[(\frac{1}{3} - \frac{1}{7}) + \frac{1}{7} - \frac{1}{9}][/tex]

[tex]a_4 + a_6 +a_8 = 4[\frac{1}{3} - \frac{1}{9}][/tex]

Notice that the pattern follows:

[tex]a_4 + a_6 + a_8 + ...... + a_{k}= 4[(\frac{1}{3} - \frac{1}{k+1})][/tex]

The above represent the even sums (say S2)

The total sum (S) is:

[tex]S = S_1 + S_2[/tex]

[tex]S =4[(\frac{1}{2} - \frac{1}{k+1})] + 4[(\frac{1}{3} - \frac{1}{k+1})][/tex]

Remove all k terms

[tex]S =4[(\frac{1}{2}] + 4[(\frac{1}{3}][/tex]

Open bracket

[tex]S =\frac{4}{2} + \frac{4}{3}[/tex]

[tex]S =\frac{12 + 8}{6}[/tex]

[tex]S =\frac{20}{6}[/tex]

[tex]S =\frac{10}{3}[/tex]

The sum converges at: [tex]\frac{10}{3}[/tex]

Answer:

[tex]y = 3x - 2[/tex]

Step-by-step explanation:

Required

The equation of the above linear function

From the table, we have:

[tex](x_1,y_1) = (1,1)[/tex]

[tex](x_2,y_2) = (2,4)[/tex]

Calculate slope (m)

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

[tex]m = \frac{4 -1}{2 -1}[/tex]

[tex]m = \frac{3}{1}[/tex]

[tex]m =3[/tex]

The equation is:

[tex]y = m(x - x_1) + y_1[/tex]

So, we have:

[tex]y = 3(x - 1) + 1[/tex]

[tex]y = 3x - 3 + 1[/tex]

[tex]y = 3x - 2[/tex]

35 × 2/7 =

2 × 35 / 7 =

2 × 5 × 7 / 7 =

Simplify 7

2 × 5 =

10

Answer:  

7.79771≤x≤8.20229  

Step-by-step explanation:  

Given the following  

sample size n = 8  

standard deviation s = 0.238  

Sample mean = 2.275  

z-score at 980% = 1.282

Confidence Interval = x ± z×s/√n  

Confidence Interval = 8 ± 1.282×0.238/1.5083)  

Confidence Interval = 8 ± (1.282×0.15779)

Confidence Interval = 8 ±0.20229    

CI = {8-0.20229, 8+0.20229}  

CI = {7.79771, 8.20229}

Hence the required confidence interval is 7.79771≤x≤8.20229

Answer:

The prime factors of the greatest 4 digit number are 3, 11 and 101.

Step-by-step explanation:

Hope it helps

Answer:

A = 0.25*j + 1

Step-by-step explanation:

The question presented here is an application of linear models. The $1 amount is fixed and does not depend on any factor such as the cups of orange juice sold.

Furthermore, we are informed that we earn $0.25 for every cup of orange juice sold. This means that we shall earn 0.25 j by selling  j cups of orange juice.

The variable total amount, A will thus depend on the fixed amount of $1 and the variable income 0.25 j.

The equation in two variables that will represent the total amount A (in dollars) you have after selling j cups of orange juice will thus be;

A = 0.25*j + 1

Hope this helped.....

Answer:

5 points huh thats mean

Step-by-step explanation:

Answer:

4 serving cups

Step-by-step explanation:

Given

[tex]Serving\ cup = \frac{1}{6}[/tex]

[tex]Rice\ cup = \frac{2}{3}[/tex]

Required

The number of serving cup (n)

This is calculated by dividing the rice cup by the serving cup

[tex]n = \frac{Rice\ cup}{Serving\ cup}[/tex]

[tex]n = \frac{2/3}{1/6}[/tex]

Rewrite as:

[tex]n = \frac{2}{3} \div \frac{1}{6}[/tex]

Change to multiplication

[tex]n = \frac{2}{3} * \frac{6}{1}[/tex]

[tex]n = \frac{12}{3}[/tex]

[tex]n=4[/tex]

Answer:

110 basic plans and 200 standard plans were purchased.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the number of basic plans.

y is the number of standard plans.

310 new subscribers

This means that [tex]x + y = 310[/tex], and so, [tex]y = 310 - x[/tex]

A cable network offers members a Basic plan for ​$7.26 per month. For ​$3.00 more per​ month. Total paid of $2580.60.

This means that:

[tex]7.26x + 10.26y = 2580.6[/tex]

Since [tex]y = 310 - x[/tex]

[tex]7.26x + 10.26(310 - x) = 2580.6[/tex]

[tex]7.26x + 3180.6 - 10.26x = 2850.6[/tex]

[tex]3x = 330[/tex]

[tex]x = \frac{330}{3}[/tex]

[tex]x = 110[/tex]

Then

[tex]y = 310 - x = 310 - 110 = 200[/tex]

110 basic plans and 200 standard plans were purchased.

Answer:

10000 litres

Step-by-step explanation:

using proportion

if 7000 litres equals 42 minutes

then, x litres equals 60 minutes

x = (60×7000)÷ 42

x = 10000 litres

Answer:

sin∅ = 12/13

Step-by-step explanation:

use pythagorean theorem to find the missing side

a² + 5² = 13²

a² = 13² - 5²

a² = 169 - 25

a² = 144

a = 12

-----------------------------

Sin∅ = opp/hyp

sin∅ = 12/13

Answer:

cost for adults=$8.29

cost for children=$6.47

cost for 2 adults and 4 children are =$(2×8.29)+(4×6.47)=$16.58+25.88=$42.46

Answer:

1/2( x+16)

Step-by-step explanation:

1/2x + 8

Factor out 1/2

1/2*x + 1/2 *16

1/2( x+16)

Answer:

3179cm^3

Step-by-step explanation:

[tex]volum = height × width × length \\ = 17cm \times 17cm \times 11cm \\ = {3179cm}^{3} [/tex]

Answer:

450g coffee or 21.95$ coffee

Step-by-step explanation:

again, divide whichever pair you want to and you still have the same answer whether it is less or more: 450/250 is math would be 9/5 and 21.95/12.35 is 1.77732793522. so if we find the true value of 9/5, which is 1.8, and since it is more that the original price that means the more coffe you get, the cheaper it gets (basically all of life is like this), so the 450 g coffee is worth alot less than and is bigger than the 250 g coffee

Answer:

23

UVW congruent to WFG

and

24

FHG congruent to LMN

Answer:

23 ) UVW is congruent to WGF

24 ) FHG is congruent to LMN

Given:

The solution of two equation is (3,-6).

To find:

The graphs that shows a pair of lines that represents the equations with the solution (3, −6).

Solution:

In first graph, both line intersect each other at point (-6,3). So, the solution of the pair of lines is (-6,3).

In second graph, both line intersect each other at point (-3,6). So, the solution of the pair of lines is (-3,6).

In third graph, both line intersect each other at point (3,-6). So, the solution of the pair of lines is (3,-6).

In forth graph, both line intersect each other at point (6,-3). So, the solution of the pair of lines is (6,-3).

Therefore, the correct option is C.

Answer:

80

Step-by-step explanation:

djdjdjdjdjdjkkkdkjrr

The six trigonometric function of [tex]\theta[/tex] are [tex]\sin \theta \approx 0.781[/tex], [tex]\cos \theta = - \frac{5}{8}[/tex], [tex]\tan \theta \approx -1.250[/tex], [tex]\cot \theta \approx -0.800[/tex], [tex]\sec \theta = - \frac{8}{5}[/tex], [tex]\csc \theta \approx 1.280[/tex], respectively.

In this question, we assume that x-component of the terminal point is part of a unit circle. Then, we can find the value of y by means of the Pythagorean theorem:

[tex]y = \sqrt{1-x^{2}}[/tex] (1)

If we know that [tex]x = -\frac{5}{8}[/tex] and P is in the second quadrant, then the value of y is:

[tex]y = + \sqrt{1-\left(-\frac{5}{8} \right)^{2}}[/tex]

[tex]y \approx 0.781[/tex]

By trigonometry, we remember the following definitions for the six basic trigonometric functions:

[tex]\sin \theta = \frac{y}{1}[/tex] (1)

[tex]\cos \theta = \frac{x}{1}[/tex] (2)

[tex]\tan \theta = \frac{y}{x}[/tex] (3)

[tex]\cot \theta = \frac{1}{\tan\theta}[/tex] (4)

[tex]\sec \theta = \frac{1}{\cos \theta }[/tex] (5)

[tex]\csc \theta = \frac{1}{\sin \theta}[/tex] (6)

If we know that [tex]x = -\frac{5}{8}[/tex] and [tex]y \approx 0.781[/tex], then the six basic trigonometric functions are, respectively:

[tex]\sin \theta \approx 0.781[/tex], [tex]\cos \theta = - \frac{5}{8}[/tex], [tex]\tan \theta \approx -1.250[/tex], [tex]\cot \theta \approx -0.800[/tex], [tex]\sec \theta = - \frac{8}{5}[/tex], [tex]\csc \theta \approx 1.280[/tex]

The six trigonometric function of [tex]\theta[/tex] are [tex]\sin \theta \approx 0.781[/tex], [tex]\cos \theta = - \frac{5}{8}[/tex], [tex]\tan \theta \approx -1.250[/tex], [tex]\cot \theta \approx -0.800[/tex], [tex]\sec \theta = - \frac{8}{5}[/tex], [tex]\csc \theta \approx 1.280[/tex], respectively.

We kindly invite you to check this question related to trigonometric functions: https://brainly.com/question/6904750

Answer:

The joint probability of the two events is one.

Step-by-step explanation:

Complementary events:

If two events are complimentary, these three following things are true:

They are dependent.

The intersection of them is zero.

The joint probability of the two events is one.

The last one is the correct choice.

Answer:

Solution given:

19

<JKL=<KLS

20

FD=GD

9514 1404 393

Answer:

  19) ∠JKL ≅ ∠SLK

  20) FD ≅ GD

Step-by-step explanation:

It works well to identify the locations of the letters in the congruence statement, then use the letters in the same order from the other part of the congruence statement.

19) Letters JKL have the order 312 in the first part of the congruence statement ΔKLJ ≅ ....

The last part of the congruence statement is ... ≅ ΔLKS. The letters in order 312 from that part are SLK, so we want our angle congruence to read ...

  ∠JKL ≅ ∠SLK

__

20) The letters we're given (FD) are in positions 31 of the first part of the triangle congruence statement. The letters in those positions in the second part are GD, so our segment congruence is ...

  FD ≅ GD

Answer:

-2.76

-2.57

-2.5

-1.85

-1.58

2.5

2.85

Hopefully this is what you mean. Have a nice day!

Step-by-step explanation:

dogs alpha an 125789 SMS Skoda Eloisa 124579 harm Occam

Answer:

48

Step-by-step explanation:

correct on Edge 2021