If f(x) = x2, and
g(x) = x – 1, then
f(g(x)) = [? ]x2+[?]+ [?]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

Concepts:

Area of Square = s²

Area of Triangle = bh/2

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

Question # 16

Step One: Find the total area of two squares

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

Step Two: Find the area of the blank triangle

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

Step Three: Subtract the area of the blank triangle from the total area

Total area = 29

Area of Square = 7

29 - 7 = 22

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Question # 17

Step One: Find the length of PT

Given:

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

Step Two: Find the length of S to PT perpendicularly

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Three: Find the area of ΔPST

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Four: Find the length of Q to PT perpendicularly

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Five: Find the area of ΔPQT

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Six: Combine area of two triangles to find the total area

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

Answer:

9

Step-by-step explanation:

Using the rules of logarithms

log[tex]x^{n}[/tex] = nlogx

[tex]log_{b}[/tex] b = 1

Then

[tex]log_{x}[/tex] [tex]x^{9}[/tex]

= 9[tex]log_{x}[/tex] x

= 9

6√5 + 3√6 = 6√5 + 3√6 [cannot be simplified]

; roots do not contain any perfect squares, and the roots are not similar.

6√5(3√6) = 18√30 [can be simplified]

; although roots do not contain any perfect squares, the product rule can be applied to create a singular expression.

Answer:

x=10

Step-by-step explanation:

I hope this will help you

Initial value is your y intercept, and to find that you just need to substitute 0 for x. Anything to the power of 0 is just 1. So you get 34.2(1), which means that your initial value is 34.2.

========================================================

Explanation:

The two points mentioned in bold are midpoints of segments AB and AC respectively.

To find the coordinates of a midpoint, you add up the x coordinates and divide by 2. Do the same with the y coordinates.

For example, points A and B are at (7,6) and (1,-2)

If we add up the x coordinates and divide by 2, then we get (7+1)/2 = 4. Do the same for the y coordinates to get (6+(-2))/2 = 2. So that's how (4,2) is the midpoint of segment AB. You'll use similar logic to find that (8,2) is the midpoint of segment AC.

A slight alternative is that once you find one midpoint is (4,2), you can draw a horizontal line until you reach (8,2). We're using the idea that the midsegment is parallel to BC which is also horizontal.

Answers:

==============================================================

Explanation:

Refer to the diagram below.

The segment AB is the player's height of 6 ft.

The segment CD is the hoop's height, which is 10 ft.

There is a point E on CD such that rectangle BACE forms. This will help us form ED later.

Angle EBD is what we're after, which I'll call x.

Since the free throw line is 15 ft from the basket, this means segments EB and AC are 15 ft each.

In rectangle BACE, the side EC is opposite AB. So both of those sides are 6 ft each.

Since CD = 10 and EC = 6, this must mean ED = CD-EC = 10-6 = 4.

---------------------------------------

To summarize, we found that ED = 4 and EB = 15.

We'll focus our attention entirely on triangle EBD

We have two known legs of the triangle, specifically the opposite and adjacent sides.

So we'll use the tangent ratio.

tan(angle) = opposite/adjacent

tan(B) = ED/EB

tan(x) = 4/15 .... is the equation to solve

x = arctan(4/15) .... same as inverse tangent or [tex]\tan^{-1}[/tex]

x = 14.931417 ..... make sure to be in degree mode

x = 15 ..... rounding to the nearest whole degree

So that unknown angle in the diagram is approximately 15 degrees

Answer:

112

Step-by-step explanation:

The volume is given by l*b*h=4*4*7=112

Answer:

3/4 more hours

Step-by-step explanation:

Hours taken to clean bedroom = 5/4

Hours taken to clean den = 1/2

How much more = 5/4 - 1/2

5-2/4 (common denominator)

3/4 more hours (It's a propper fraction, so we can't write it as a mixed number)

Answer from Gauthmath

Answer:

The events are independent and are not mutually exclusive.

Step-by-step explanation:

Two events A and B are independent if the outcome of each of them does not affect the outcome of the other.

And two events are mutually exclusive if these can't occur at the same time.

Here the events are:

a = rolling a 4 on the first die

b = rolling a 3 on the second die.

Becuase, these are number cubes, we know that the outcome of one die has no impact in the outcome of the other die.

And because each outcome is on a different die, we can conclude that these events are independent.

(rolling a 4 in the first die does not change the probability of getting a 3 when we roll the second die).

Now, the events are mutually exclusive?

No, we can roll both dices and get a 3 in the first one and a 4 in the second one, so these events can happen in the same time.

Answer:

YES.

Step-by-step explanation:

The event rolling a number '4' and the event rolling a number '3' are mutually exclusive events because both of them cannot occur at the same time.

Just took quick check

Answer:

The length of the segment is 10.

Step-by-step explanation:

Think of the segment as the hypotenuse of a right triangle.

Draw the legs and label the lengths.

See the picture below.

The length of the hypotenuse is c.

c^2 = a^2 + b^2

c^2 = 6^2 + 8^2

c^2 = 36 + 64

c^2 = 100

c = 10

Answer: 10

Answer:

16 × X + 3=

Step-by-step explanation:

u will get your answer

Answer:

ii

Step-by-step explanation:

from what you've written in the comments I think this question requires you to find the equation that can be expressed in two variables,so the best way to do this is to solve the pairs as simultaneous equations and see the ones that will give you two answers x and y

if you solve the first pair you will have

x + y = 5

2x+2y=10

2(x + y =5)

1(2x+2y=10)

2x+2y=10

2x+2y=10--

now from this you will see that it cannot be expressed as two variables because the answer is just zero..

for the second equation it can be expressed as two variables

x - y = 8

3x-3y =16

3(x-y =8)

1(x-3y=16)

3x-3y=24

x - 3y=16

2x/2=8/2

x=4

x-y=8

4-y=8

-y=8-4

-y/-1=4/-1

y=-4...

so you see it can be expressed as two variables..

if you solve the third one it will also give you an answer which is zero so it can't be expressed as two variables.

and the fourth one also cannot.

I hope this helps and if you don't understand feel free to ask..and sorry if it's wrong

Answer:

[tex]\boxed {\boxed {\sf y= 6x+5}}[/tex]

Step-by-step explanation:

We are asked to find the slope-intercept equation of a line. Slope-intercept form is one way to write the equation of a line. It is:

[tex]y=mx+b[/tex]

Where m is the slope and b is the y-intercept.

We are given a point (-1, -1) and the line is parallel to the line y= 6x-2. Since the line is parallel to the other line, they have the same slope, which is 6. We have a point and a slope, so we should use the point-slope formula to find the equation of the line.

[tex]y-y_1= m (x-x_1)[/tex]

Here, m is the slope and (x₁, y₁) is the point. We know the slope is 6 and the point is (-1, -1). Therefore:

Substitute the values into the formula.

[tex]y- -1 = 6(x- -1) \\y+1= 6(x+1)[/tex]

Distribute the 6. Multiply each value inside the parentheses by 6.

[tex]y+1 = (6*x)+ (6*1) \\y+1= 6x+6[/tex]

Slope-intercept form requires y to be isolated. 1 is being added to y. The inverse of addition is subtraction. Subtract 1 from both sides.

[tex]y+1-1=6x+6-1 \\y= 6x+5[/tex]

The equation of the line in slope-intercept form is y=6x+5

Answer:

C is the answer 3rd one...

Answer:

Kristi will pay $22.77 for the shirt.

Step-by-step explanation:

First, determine the sales price of the shirt. If the full price is $27.99, a 25% reduction is $7. Subtract the discount from the full price to get a sales price of $20.99 for the shirt.

Next, determine the amount of tax Kristi will pay for the shirt. In her state, the sales tax is 8.5% (0.085). Multiply $20.99 by 0.085 and you will see that the sales tax is $1.78. Add the amount of the tax, $1.78, to the sales price of the shirt, $20.99, and you will get $22.77 as the cost of the shirt after the sales tax is added.

Answer:

Step-by-step explanation:

The answer is 4.

Once you add 4, you get:

x^2 -2x + 4 = 7.

The left side is factorable:

(x-2)^2 = 7.

There is your perfect square.

Answer:

1) The length of [tex]DC[/tex] is 20.

2) The length of [tex]PS[/tex] is 17.

Step-by-step explanation:

1) If [tex]DR = RE[/tex] and [tex]CS = SB[/tex], then we can use the following proportionality ratio:

[tex]\frac{DE}{DR} = \frac{32 - x}{26 - x}[/tex] (1)

Where [tex]x[/tex] is the length of segment [tex]\overline{CD}[/tex].

If [tex]DE = 2\cdot DR[/tex], then the value of [tex]x[/tex] is:

[tex]2 = \frac{32-x}{26-x}[/tex]

[tex]52 - 2\cdot x = 32 - x[/tex]

[tex]20 = x[/tex]

The length of [tex]DC[/tex] is 20.

2) If [tex]QV = VP[/tex] and [tex]RW = WS[/tex], then we can use the following proportionality ratio:

[tex]\frac{QP}{QV} = \frac{x-7}{12-7}[/tex] (2)

Where [tex]x[/tex] is the length of segment [tex]\overline{PS}[/tex].

If [tex]QP = 2\cdot QV[/tex], then the value of [tex]x[/tex] is:

[tex]2 = \frac{x-7}{5}[/tex]

[tex]10 = x-7[/tex]

[tex]x = 17[/tex]

The length of [tex]PS[/tex] is 17.

hope this helps! feel free to clarify if unsure

Answer:

Triangle ISK

Step-by-step explanation:

Answer:

Triangle ISK

Step-by-step explanation:

if the angles and sides of one triangle are equal to the corresponding sides and angles of the other triangle, they are congruent.

∠Q = ∠I

∠R = ∠S

∠S = ∠K

Answer:

D. [tex] \frac{15}{8} [/tex]

Step-by-step explanation:

Recall: SOH CAH TOA

Thus,

Tan A = Opposite/Adjacent

Reference angle (θ) = A

Length of side Opposite to <A = 15

Length of Adjacent side = 8

Plug in the known values

[tex] Tan(A) = \frac{15}{8} [/tex]

Answer:

-0.301

Step-by-step explanation:

Correct Question :-

If log 2 = 0.301 , find log 0.5

Solution :-

We are here given that the value of log 5 is 0.699 . Here the base of log is 10 .

[tex]\rm\implies log_{10}2= 0.301 [/tex]

And we are supposed to find out the value of log 0.5 . We can write it as ,

[tex]\rm\implies log_{10}(0.5) = log _{10}\bigg( \dfrac{5}{10}\bigg)[/tex]

Simplify ,

[tex]\rm\implies log _{10}\bigg( \dfrac{1}{2}\bigg)[/tex]

This can be written as ,

[tex]\rm\implies log_{10} ( 2^{-1})[/tex]

Use property of log ,

[tex]\rm\implies -1 \times log_{10}2 [/tex]

Put the value of log 2 ,

[tex]\rm\implies -1 \times 0.301 =\boxed{\blue{-0.301}} [/tex]

Hence the value of log (0.5) is -0.301 .

*Note -

Here here there was no use of log 5 in the calculation .

Answer:

1) -7929

2) -2401

3)-5414

4) -7592

5) 12888

6)-237726

7) 7287

8)-4588

9)-394495

10) 891856

Answer:

For a give event with outcomes:

{x₁, x₂, ..., xₙ}

Each with probabilities:

{p₁, p₂, ..., pₙ}

The expected value is:

Ev = x₁*p₁ + ... + xₙ*pₙ

Here we have the outcomes and probabilities:

win $1, with a probability 20%/100% = 0.2

win $2, with a probability 25%/100% = 0.25

win $5, with a probability of 35%/100% = 0.35

do not win, with a probability of 20%/100% = 0.2

Then the expected value of the game is:

Ev = $1*0.2 + $2*0.25 + $5*0.35 + $0*0.2 = $2.45

And if we know that the game costs $2, then the expected value is:

Ev = $2.45 - $2 = $0.45

The expected value is  $0.45

Answer:

value of K =16

I hope it's helps you

a=132°

b=20°

Answer:

Solution given:

a=132°[exterior angle of a cyclic quadrilateral is equal to the opposite interior angle]

again

In ∆ BCO is similar to ∆ BOE

so

b=20°[corresponding angle of similar triangle are equal]

Answer:

210 Km

Step-by-step explanation:

Distance travelled is calculated as

distance = speed × time ( time is in hours )

              = 90 × 2 [tex]\frac{1}{3}[/tex]

             = 90 × [tex]\frac{7}{3}[/tex]

            = 30 × 7

            = 210 Km