Answer: The value of (f*g)(7) is 66.
Step-by-step explanation:
Given functions: [tex]f(x)= 4x-6\text{ and } g(x)=\sqrt{x+2}[/tex]
Since, product of two functions: [tex](u*v)(x)=u(x)\times v(x)[/tex]
[tex](f*g)(x)=f(x)\times g(x)\\\\=4x-6\times \sqrt{x+2}\\\\\Rightarrow\ (f*g)(x)=(4x-6) \sqrt{x+2}[/tex]
[tex](f*g)(7)=(4(7)-6)\sqrt{7+2}\\\\=(28-6)\sqrt{9}\\\\=22\times 3=66[/tex]
Hence, the value of (f*g)(7) is 66.
2. A 10 Mg truck hauls a 20 Mg trailer. If the unit starts from rest on a level road with a
tractive force of 20 kN between the driving wheels of the truck and the road, calculate the
acceleration of the unit and the tension in the horizontal draw-bar.
Drawbar
20 Mg Trailer
10 Mg Truck
a=0.667 m/s2
T= 13.3 KN
Oro
W
Answer:
The acceleration on the unit is 0.667 m/s^2
The tension on the draw-bar is 13.34 kN
Step-by-step explanation:
The mass of the truck = 10 Mg = 10 x 10^3 kg
The mass of the trailer = 20 Mg = 20 x 10^3 kg
Tractive force from the truck = 20 kN = 20 x 10^3 N
The total mass of the unit = 10 Mg + 20 Mg = 30 Mg = 30 x 10^3 kg
The tractive force on the unit will produce an acceleration that is given as
F = ma
where
F is the tractive = 20 x 10^3 N
m is the mass of the unit = 30 x 10^3 kg
a is the acceleration of the unit = ?
substituting into the equation
20 x 10^3 = 30 x 10^3 x a
a = (20 x 10^3)/(30 x 10^3) = 0.667 m/s^2
the tension on the draw-bar T is gotten from considering only the mass that is pulled by the draw-bar which is 20 Mg
The acceleration on the unit = 0.667 m/s^2
The drawn mass = 20 Mg = 20 x 10^3 kg
The tension on the draw bar = ma = 20 x 10^3 x 0.667 = 13340 N
= 13.34 kN
The acceleration is 0.00067m/s^2, while the tension on the horizontal bar is 13.4 N
The given parameters are:
[tex]\mathbf{m = 10Mg}[/tex] -- mass of the truck
[tex]\mathbf{M = 20Mg}[/tex] -- mass of the trailer
[tex]\mathbf{F_T = 20kN}[/tex] --- tractive force
Start by calculating the total mass
[tex]\mathbf{M_T = m + M}[/tex]
So, we have:
[tex]\mathbf{M_T = 10Mg + 20Mg}[/tex]
[tex]\mathbf{M_T = 30Mg}[/tex]
Convert to kilograms
[tex]\mathbf{M_T = 30 \times 10^3kg}[/tex]
[tex]\mathbf{M_T = 30000 kg}[/tex]
Force is calculated as:
[tex]\mathbf{F =ma}[/tex]
So, we have:
[tex]\mathbf{20kN =30000kg \times a}[/tex]
Divide both sides by 30000
[tex]\mathbf{a = 0.00067ms^{-2}}[/tex]
The tension on the horizontal bar (i.e. the 20 Mg trailer) is:
[tex]\mathbf{T=ma}[/tex]
So, we have:
[tex]\mathbf{T=20Mg \times 0.00067ms^{-2}}[/tex]
Rewrite as:
[tex]\mathbf{T=20 \times 10^3 kg \times 0.00067m/s}[/tex]
[tex]\mathbf{T=13.4N}[/tex]
Hence, the acceleration is 0.00067m/s^2, while the tension on the horizontal bar is 13.4 N
Read more about force and acceleration at:
https://brainly.com/question/20511022
200,000=2x10 to the power of 6
False.
2x10^6 you move the decimal point 6 places to the right. ( add 6 zeros after the 2)
2x 10^6 = 2,000,000
1/3 of a shipment of books weights 28 pounds
Answer:
84 pounds
Step-by-step explanation:
If 1/3 of a book is equal to 28 pounds then 28*3 will give you your answer
A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. The standard deviation of the sample was $7,568.
Required:
a. Construct a 90% confidence interval for the population mean.
b. Confidence interval for the population men between _______ up to_______________
Answer:
a
The 90% confidence interval is [tex]52561.13 < \mu < 57540.8[/tex]
b
Confidence interval for the population men between $52561.13 up to $57540.8
Step-by-step explanation:
From the question we are told that
The sample size is [tex]n = 25[/tex]
The sample mean is [tex]\= x = \$ 55,051[/tex]
The standard deviation is [tex]\sigma = \$ 7,568[/tex]
Given that the confidence level is 90% then the level of confidence is mathematically represented as
[tex]\alpha = 100 -90[/tex]
[tex]\alpha = 10\%[/tex]
[tex]\alpha = 0.10[/tex]
Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table the values is
[tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }[/tex]
substituting values
[tex]E = 1.645 * \frac{ 7568}{ \sqrt{ 25} }[/tex]
[tex]E = 2489.9[/tex]
The 90% confidence interval is mathematically evaluated as
[tex]\= x -E < \mu < \= x +E[/tex]
substituting values
[tex]55051 - 2489.8 < \mu < 55051 + 2489.8[/tex]
[tex]52561.13 < \mu < 57540.8[/tex]
Compute (3/4)*(8/9)*(15/16)*(24/25)*(35/36)*(48/49)*(63/64)*(80/81)*(99/100) Express your answer in the simplest way possible. (Suggestion: First, try computing 3/4*8/9 then 3/4*8/9*15/16 and so on. Look for patterns.
Answer:
[tex](\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}[/tex]
Step-by-step explanation:
Given
[tex](\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100})[/tex]
Required
Simplify
For clarity, group the expression in threes
[tex]((\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
Evaluate the first group [Divide 8 by 4]
[tex]((\frac{3}{1})*(\frac{2}{9})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 9 by 3]
[tex]((\frac{1}{1})*(\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex]((\frac{2}{3})*(\frac{15}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 15 by 3]
[tex]((\frac{2}{1})*(\frac{5}{16}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 16 by 2]
[tex]((\frac{1}{1})*(\frac{5}{8}))*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex](\frac{5}{8})*((\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
Evaluate the second group [Divide 35 and 25 by 5]
[tex](\frac{5}{8})*((\frac{24}{5})*(\frac{7}{36})*(\frac{48}{49}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 49 by 7]
[tex](\frac{5}{8})*((\frac{24}{5})*(\frac{1}{3})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[Divide 24 by 3]
[tex](\frac{5}{8})*((\frac{8}{5})*(\frac{1}{1})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex](\frac{5}{8})*((\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
Merge the first and second group
[tex]((\frac{5}{8})*(\frac{8}{5})*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex](1*(\frac{4}{7}))*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
[tex](\frac{4}{7})*((\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}))[/tex]
Evaluate the last group [Divide 99 by 9]
[tex](\frac{4}{7})*((\frac{63}{64})*(\frac{80}{9})*(\frac{11}{100}))[/tex]
[Divide 63 by 9]
[tex](\frac{4}{7})*((\frac{7}{64})*(\frac{80}{1})*(\frac{11}{100}))[/tex]
[Divide 64 and 80 by 8]
[tex](\frac{4}{7})*((\frac{7}{8})*(\frac{10}{1})*(\frac{11}{100}))[/tex]
[Divide 10 and 4 by 2]
[tex](\frac{4}{7})*((\frac{7}{4})*(\frac{5}{1})*(\frac{11}{100}))[/tex]
[Divide 100 by 5]
[tex](\frac{4}{7})*((\frac{7}{4})*(\frac{1}{1})*(\frac{11}{20}))[/tex]
[tex](\frac{4}{7})*((\frac{7}{4})*(\frac{11}{20}))[/tex]
[tex](\frac{4}{7})*(\frac{7}{4})*(\frac{11}{20})[/tex]
[tex]1*(\frac{11}{20})[/tex]
[tex]\frac{11}{20}[/tex]
Hence;
[tex](\frac{3}{4})*(\frac{8}{9})*(\frac{15}{16})*(\frac{24}{25})*(\frac{35}{36})*(\frac{48}{49})*(\frac{63}{64})*(\frac{80}{81})*(\frac{99}{100}) = \frac{11}{20}[/tex]
A researcher examines typing speed before a typing class begins, halfway through the class, and after the class is over. 4. Identify the number of levels: 5. Identify the type of design: 6. Identify the dependent variable:
Answer:
Number of levels = 2
Type of design = Repeated measure
Dependent variable = Typing Speed
Step-by-step explanation:
The number of levels in an experiment simply refers to the number of experimental conditions in which participants are subjected to. In the scenario above, the number of levels is 2. Which are ; Halfway through the class and After the class is over.
The type of designed employed is REPEATED MEASURE, this is because the participants all took part in each experimental condition.
The dependent variable is TYPING SPEED, which is the variable which is measured with respect to the independent variable. Hence the observed value depends on period that is (halfway through the class or after the class is over).
Lydia drives from city a to city b to transport goods. her return speed is 3 times her departure speed and she takes 40 minutes less on her return trip. how long did her departure trip take?
Answer:
1 hour
Step-by-step explanation:
Hello, let's say that her departure trip takes t in minutes, as her return speed is 3 times her departure speed, she took t/3 for the return and we know that this 40 minutes less, so we can write.
t/3=t-40
We can multiply by 3
t = 3t -40*3 = 3t - 120
This is equivalent to
3t -120 = t
We subtract t
2t-120 = 0
2t = 120
We divide by 2
t = 120/2 = 60
So this is 60 minutes = 1 hour.
Thank you.
Look at the picture
Answer:
f(x) = {x^2 if x = (-inf , 2) , y = 5 if x [2, 4).
Step-by-step explanation:
First, we look at the quadratic. Luckily, it's only x^2. Putting in the range, we have f(x) = x^2 if x < 2, or (-inf, 2).
Then, we have the line. This is the line of y = 5, and the range is if 2 [tex]\leq[/tex] x < 4, or [2, 4).
What is the probability of drawing 3 kings and 2 aces in a 5 card hand of poker?
Answer:
the probability of getting 3 aces and 2 kings when you draw 5 cards from the deck is 24 / 2598960 = 9.234463016 * 10^-6.
Step-by-step explanation:
the number of ways you can get 3 aces out of 4 aces is c(4,3) = 4.
the number of ways you can get 2 kings out of 4 kings is c(4,2) = 6.
the number of ways you can get 2 kings and 3 aces is 4 * 6 = 24.
the number of ways you can get 5 cards out of a deck of 52 cards is c(52,5) = 2598960.
Choose two statements that are true for this expression.
5x3 – 6x2
25
y
+ 18
25
O A. The term
is a ratio.
B. There are three terms.
C. The entire expression is a difference.
O D. There are four terms.
Answer:
Step-by-step explanation:
I'm having difficulty reading your input: 25, y, + 18, 25. Please clarify your meaning.
5x3 – 6x2 is a polynomial expression with two terms.
The term is a ratio. False. See above.
The entire expression is a difference. True.
There are four terms. False. See above.
Two statements B and C are true for the expression 5x3 – 6x2 25y+ 18
How many options are correct for given expressio?
A. The term is a ratio. False
B. There are three terms.terms. True
C. The entire expression is a difference. True
D. There are four terms. False
Learn more about linear equation here: brainly.com/question/1884491
#SPJ2
Find the volume of the solid. When appropriate, use π=3.14 and round your answer to the nearest hundredth.
Answer:
3179.25
Step-by-step explanation:
Hello!
To find the volume of a cylinder we use the equation
[tex]V = \pi r^{2} h[/tex]
V is volume
r is radius
h is height
Put in what we know. It is says to use pi as 3.14
[tex]V = 3.14 * 7.5^{2} *18[/tex]
Solve
V = 3.14 * 56.25 * 18
V = 3179.25
Hope this Helps!
) A random sample of size 36 is selected from a normally distributed population with a mean of 16 and a standard deviation of 3. What is the probability that the sample mean is somewhere between 15.8 and 16.2
Answer:
The probability is 0.31084
Step-by-step explanation:
We can calculate this probability using the z-score route.
Mathematically;
z = (x-mean)/SD/√n
Where the mean = 16, SD = 3 and n = 36
For 15.8, we have;
z = (15.8-16)/3/√36 = -0.2/3/6 = -0.2/0.5 = -0.4
For 16.2, we have
z = (16.2-16)/3/√36 = 0.2/3/6 = 0.2/0.5 = 0.4
So the probability we want to calculate is;
P(-0.4<z<0.4)
We can get this using the standard normal distribution table;
So we have;
P(-0.4 <z<0.4) = P(z<-0.4) - P(z<0.4)
= 0.31084
I need help with these
Answer:
2. 20 oranges
3. 18 yellow tulips
4. 23 students
The triangle shown on the graph above is rotated 90 degrees clockwise about the original to form triangle P’Q’R which of the following are the (x,y) coordinates of the point P’
Hey there! I'm happy to help!
When rotating a point 90 degrees clockwise about the origin, our original point (x,y) becomes (-y,x), because it is now at a negative y-value.
We see that our point P is at (1,2). We can use this rotation formula to find the coordinates of P' (the new spot where P is)/
(x,y)⇒(-y,x)
(1,2)⇒(-2,1)
Therefore, the coordinates of the point P' are (-2,1).
Have a wonderful day! :D
What is the factorization of the polynomial below? 9x^2+12x+4
Answer:
(3x+2)^2
Step-by-step explanation:
This graph shows the US unemployment rate from August 2010 to November 2011.
Sample Unemployment Rate
Graph
Unemployment Rate
10%
80%
6%
Unemployment Rate
Aug 10
Jan 11
Jun 11
Nov 11
This graph suggests unemployment in the United States
O will continue to fall.
O will continue to rise.
O will remain the same.
O will only change a little.
Answer: Will continue to rise
Step-by-step explanation:
Looking at the graph one notices that after a slight dip in the unemployment rate from August 2010 to January 2011, the unemployment rate began to rise and by November 2011 was still rising.
The arrow on the graph serves to indicate the direction the unemployment rate is going and as it is pointing upwards, this means that the Unemployment rate will continue to rise.
This was down to the fact that in 2011 the US was still yet to recover from the Great Recession of 2008 - 2009.
Answer:
EDGE 2021
Step-by-step explanation:
1) 4%
2) Increase
I need to find AB can someone please help me ASAP :(
Answer:
AB = 11
Step-by-step explanation:
Using the external secant property,
CB*CA = CD*CL (=CT^2 if T is tangent throught C)
substitute values,
7*(7+2x+3) = 9*(9+x+1)
Expand and simplify
70+14x = 90 + 9x
5x = 20
x = 4
=>
AB = 2x+3 = 2(4)+3 = 8+2 = 11
The base of a triangle is 4 cm greater than the
height. The area is 30 cm. Find the height and
the length of the base
h
The height of the triangle is
The base of the triangle is
Answer:
Step-by-step explanation:
Formula for area of a triangle:
Height x Base /2
Base (b) = h +4
Height = h
h + 4 x h /2 = 30cm
=> h +4 x h = 60
=> h+4h =60
=> 5h = 60
=> h = 12
Height = 12
Base = 12 +4 = 16
Given the graph, find an equation for the parabola.
Answer:
[tex]\Large \boxed{\sf \bf \ \ y=\dfrac{1}{16}(a-3)^2-2 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
When the parabola equation is like
[tex]y=a(x-h)^2+k[/tex]
The vertex is the point (h,k) and the focus is the point (h, k+1/(4a))
As the vertex is (3,-2) we can say that h = 3 and k = -2.
We need to find a.
The focus is (3,2) so we can say.
[tex]2=-2+\dfrac{1}{4a}\\\\\text{*** We add 2. ***}\\\\\dfrac{1}{4a}=2+2=4\\\\\text{*** We multiply by 4a. ***}\\\\16a=1\\\\\text{*** We divide by 16. ***}\\\\a=\dfrac{1}{16}[/tex]
So an equation for the parabola is.
[tex]\large \boxed{\sf y=\dfrac{1}{16}(a-3)^2-2 }[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
NEED HELP ASAP
Which is best described as a part of the interior of a circle bounded by an arc
and the two radii that share the are's endpoints?
Answer:
The answer is sector. B.
Good day!Find the intervals on which f is increasing and the intervals on which it is decreasing. f(x)=-2cos^(2)x
Answer:
Increasing
0°≤x≤180°
Decreasing
180°≤x≤360°
1. If a bug can flap its wings at a rate of 92 times in 6 seconds, how many times do they flap their wings in 2.34 minutes? Round to 1 decimal.
Answer:
2152.8
Step-by-step explanation:
First, 2.34 minutes is 140.4 seconds. Next, the bug can flap its wings at a pace of 15.333..... flaps per second. Multiplying this, we get 2152.8
The polynomial P(x) = 5x2(x − 1)3(x + 9) has degree ____ It has zeros 0, 1, and ____ The zero 0 has multiplicity ____ , and the zero 1 has multiplicity ____
The complete question is;
The polynomial P(x) = 5x²(x − 1)³(x + 9) has degree ____. It has zeros 0, 1, and ____. The zero 0 has multiplicity ____ , and the zero 1 has multiplicity ____
Answer:
A) degree = 6
B) -9 is also a zero of the polynomial
C) 0 has multiplicity of 2
1 has multiplicity of 3
Step-by-step explanation:
A) To find the degree of the polynomial, we will first have to identify each term [term is for example (x - 1)³]. Thus, to find the degree of each term we will add the exponents.
The terms are;
5x², (x - 1)³, (x + 9)
The exponents are, 2, 3 and 1 respectively.
Thus, degree = 2 + 3 + 1 = 6
B) A zero of a polynomial is the value of x that causes the polynomial function to equal 0.
Since 0 and 1 are zeros, looking at the polynomial P(x) = 5x²(x − 1)³(x + 9), we can tell that when the term which when x = 0 makes the polynomial 0 is 5x².
Similarly, the term which when x = 1 makes the polynomial 0 is (x - 1)³
Thus,we are left with the term (x + 9)
So for the polynomial to be zero, (x + 9) = 0
Thus,x = -9
So -9 is a zero of the polynomial
C) The zero 0 is from the term 5x².
Thus,the multiplicity is the highest power of x which is 2.
The zero 1 is from the term (x - 1)³. Thus, the multiplicity is the highest power of x which is 3
What is the issue with the work? It is wrong. Please answer this for points!
Answer:
3 ( a ) : x = 3.6,
3 ( b ) : x = 5
Step-by-step explanation:
For 3a, we can calculate the value of x through Pythagorean Theorem, which seemingly was your approach. However, the right triangle with x present as the leg, did not have respective lengths 9.6 and 12. The right angle divides 9.6 into two congruent parts, making one of the legs of this right triangle 9.6 / 2 = 4.8. The hypotenuse will be 12 / 2 as well - as this hypotenuse is the radius, half of the diameter. Note that 12 / 2 = 6.
( 4.8 )² + x² = ( 6 )²,
23.04 + x² = 36,
x² = 36 - 23.04 = 12.96,
x = √12.96, x = 3.6
Now as you can see for part b, x is present as the radius. Length 3 forms a right angle with length 8, dividing 8 into two congruent parts, each of length 4. We can form a right triangle with the legs being 4 and 3, the hypotenuse the radius. Remember that all radii are congruent, and therefore x will be the value of this hypotenuse / radius.
( 4 )² + ( 3 )² = ( x )²,
16 + 9 = x² = 25,
x = √25, x = 5
The value of y varies jointly with x and z. If y = 2 when z = 110 and x = 11, find the approximate value of y when x = 13 and z = 195.
Answer:
y = 4Step-by-step explanation:
To find the approximate value of y when
x = 13 and z = 195 we must first find the relationship between them
The statement
y varies jointly with x and z is written as
y = kxzwhere k is the constant of proportionality
From the question
y = 2
x = 11
z = 110
We have
2 = 11(110)k
2 = 1210k
Divide both sides by 1210
[tex]k = \frac{1}{605} [/tex]
So the formula for the variation is
[tex]y = \frac{1}{605} xz[/tex]
When
x = 13
z = 195
y is
[tex]y = \frac{1}{605} (13)(195)[/tex]
[tex]y = \frac{507}{121} [/tex]
y = 4.1900
We have the final answer as
y = 4Hope this helps you
 evaluate the expression for r=-10 -54-r=
Answer:
To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.
Step-by-step explanation:
Evaluate Algebraic Expressions. ... To evaluate an algebraic expression means to find the value of the expression when the variable is replaced by a given number. To evaluate an expression, we substitute the given number for the variable in the expression and then simplify the expression using the order of operations.
A sample of 36 observations is selected from one population with a population standard deviation of 4.2. The sample mean is 101.5. A sample of 50 observations is selected from a second population with a population standard deviation of 5.0. The sample mean is 100.1. Conduct the following test of hypothesis using the 0.10 significance level.H0 : μ1 = μ2H1 : μ1 ≠ μ2a. This is a_________tailed test.b. State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.)The decision rule is to reject H0 if z is ___________the interval.c. Compute the value of the test statistic. (Round your answer to 2 decimal places.) Value of the test statistic d. What is your decision regarding H0?e. What is the p-value? (Round your answer to 4 decimal places.)
Answer:
Step-by-step explanation:
Given that :
the null and the alternative hypothesis are computed as :
[tex]H_o: \mu_1 = \mu_2[/tex]
[tex]H_a : \mu _1 \neq \mu_2[/tex]
This is a two tailed test
This is because of the ≠ sign in the alternative hypothesis which signifies that the rejection region in the alternative hypothesis are at the both sides of the hypothesized mean difference .
Decision Rule: at the level of significance ∝ = 0 . 10
The decision rule is to reject the null hypothesis if z < - 1 . 64 and z > 1 . 64
NOTE: DURING THE MOMENT OF TYPING THIS ANSWER THERE IS A TECHNICAL ISSUE WHICH MAKES ME TO BE UNABLE TO SUBMIT THE FULL ANSWER BUT I'VE MADE SCREENSHOTS OF THEM AND THEY CAN BE FOUND IN THE ATTACHED FILE BELOW
Decide if the situation involves permutations, combinations, or neither. Explain your reasoning. Does the situation involve permutations, combinations, or neither? Choose the correct answer below. A. B. C. Neither. A line of people is neither an ordered arrangement of objects, nor a selection of objects from a group of objects.
Answer:
C. Neither
Step-by-step explanation:
The permutation is a selection of objects from a given sample in an ordered manner .
The combination is a selection of objects from a given sample irrespective of an order of arrangement.
The given line of people is neither an ordered arrangement of objects, nor a selection of objects from a group of objects So it fits neither of the combinations or permutations.
So the best answer is neither.
Someone help again:/
Given there are 26 alphabets in the English language, how many possible three-letter words are there?
We have 26 letters and 3 slots to fill. We can reuse a letter if it has been picked, so we have 26^3 = 26*26*26 = 17,576 different three letter "words". I put that in quotes because a lot of the words aren't actual words, but more just a sequence of letters.
