If m\angle A=(6x+10)^{\circ}∠A=(6x+10) ∘ and m\angle B=(4x+30)^{\circ}∠B=(4x+30) ∘ , then find the measure of \angle B∠B.​

Answer:

C is my answer

Step-by-step explanation:

Answer:

[tex]Period = \pi[/tex]

Step-by-step explanation:

Given

[tex]y = -\frac{1}{3} * \sin(2x)[/tex]

Required

The period

A sine function is represented as:

[tex]y =A \sin(Bx + C) + D[/tex]

Where

[tex]Period = \frac{2\pi}{B}[/tex]

By comparing:

[tex]y =A \sin(Bx + C) + D[/tex] and [tex]y = -\frac{1}{3} * \sin(2x)[/tex]

[tex]B = 2[/tex]

So, we have:

[tex]Period = \frac{2\pi}{2}[/tex]

[tex]Period = \pi[/tex]

Hence, the period of the function is [tex]\pi[/tex]

Answer:

t = 18 minutes.

Step-by-step explanation:

We can find the time by using the following kinematic equation:

[tex] y_{f} - y_{0} = v_{0}t + \frac{1}{2}at^{2} [/tex]  

[tex] \Delta y = v_{0}t + \frac{1}{2}at^{2} [/tex]  

Where:  

Δy: is the difference between the initial and the final height = 50.4 m

t: is the time  

a: is the acceleration

v₀: is the velocity of the drill = 2.8 m/min

Since the speed of perforation is constant, the acceleration is zero so:

[tex]\Delta y = v_{0}t[/tex]    

Then, by solving the above equation for "t" we have:

[tex] t = \frac{\Delta y}{v_{0}} = \frac{50.4 m}{2.8 m/min} = 18 min [/tex]

Therefore, it takes 18 minutes to drill the hole.  

I hope it helps you!    

You can fill the 10 gallon pail all the way up. After that, you can pour the water from the 10 gallon pail, into the 4 gallon pail 2 times. That will leave you with 2 gallons in the 10 gallon pail.

Answer: hewo, there! I hope I Made it easier to Understand

the first method is to equally divide the top and bottom of the fraction by whole numbers larger than 1 until you cannot go any further. As an example, let's take the fraction 24/108: Divide each number by 2 to get 12/54. Divide by 2 again to get 6/27

Step-by-step explanation:

To work out a fraction of a number, all you need to do is divide that number by the denominator of the fraction, then multiply your result by the numerator of the fraction

Hope this helps you!!

Have a great day!!!

Answer:

8x^2 - 26x - 10

Step-by-step explanation:

3(6x2 + 3x - 5 ) = 18x^2 + 9 -15

5(2x2 + 7x - 1) = 10x^2 + 35 - 5

18^2 - 10x^2 = 8x^2

9x - 35x = - 26x

-15 -(-5) = -10

final answer = 8x^2 - 26x - 10

Complete question :

A data set includes data from student evaluations of courses. The summary statistics are nequals92​, x overbarequals4.09​, sequals0.55. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

Answer:

H0 : μ = 4.25

H1 : μ < 4.25

T = - 2.79

Pvalue =0.0026354

we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%

Step-by-step explanation:

Given :

n = 92​, xbar = 4.09​, s = 0.55 ; μ = 4.25

H0 : μ = 4.25

H1 : μ < 4.25

The test statistic :

T = (xbar - μ) ÷ s / √n

T = (4.09 - 4.25) ÷ 0.55/√92

T = - 0.16 / 0.0573414

T = - 2.79

The Pvalue can be obtained from the test statistic, using the Pvalue calculator

Pvalue : (Z < - 2.79) = 0.0026354

Pvalue < α ; Hence, we reject the Null

Thus, we conclude that there is enough evidence to conclude that population mean is different from 4.25 at 10%

Answer:

Step-by-step explanation:

The null and alternative hypotheses are:

Null hypothesis: The population mean of student course evaluations is equal to 4.25.

Alternative hypothesis: The population mean of student course evaluations is not equal to 4.25.

The significance level is 0.01, so the test will be a two-tailed test.

The test statistic is calculated as:

t = (x - μ) / (s / √n) = (4.18 - 4.25) / (0.54 / √97) = -2.63

The degrees of freedom for the t-distribution is n-1 = 96. Using a t-table or a calculator, the P-value for a two-tailed test with 96 degrees of freedom and a t-value of -2.63 is approximately 0.010.

Since the P-value (0.010) is less than the significance level (0.01), we reject the null hypothesis. We have sufficient evidence to conclude that the population mean of student course evaluations is not equal to 4.25.

In other words, the data provides strong evidence to suggest that the average student course evaluation rating is significantly lower than 4.25.

the answer is on the picture

Answer: x=8

Step-by-step explanation: Hope this help :D

Answer:1132858

Step-by-step explanation:

The total carbon dioxide the country emit over the course of the 10 year period would be 1,132,858 kilotons.

What is rate of decrease?

The rate of decrease is a constant amount of deduction from a fixed or primary amount.

Here, the carbon dioxide emits by the country per year is 130,000 kilotons.

The rate of decrease of the carbon dioxide emission per year would be 3.1%.

In the 1st year, the carbon dioxide emission = 130,000 kilotons.

In the 2nd year, the carbon dioxide emission = 130,000 × (100-3.1)/ 100 kilotons = 125,970 kilotons.

In the 3rd year, the carbon dioxide emission = 125,970 × (100-3.1)/ 100 kilotons = 122,064.93 kilotons.

In the 4th year, the carbon dioxide emission = 122,064.93 × (100-3.1)/ 100 kilotons = 118,280.92 kilotons.

In the 5th year, the carbon dioxide emission = 118,280.92 × (100-3.1)/ 100 kilotons = 114,614.21 kilotons.

In the 6th year, the carbon dioxide emission = 114,614.21 × (100-3.1)/ 100 kilotons = 111,061.17 kilotons.

In the 7th year, the carbon dioxide emission = 111,061.17 × (100-3.1)/ 100 kilotons = 107,618.27 kilotons.

In the 8th year, the carbon dioxide emission = 107,618.27 × (100-3.1)/ 100 kilotons = 104,282.1 kilotons.

In the 9th year, the carbon dioxide emission = 104,282.1 × (100-3.1)/ 100 kilotons = 101,049.35 kilotons.

In the 10th year, the carbon dioxide emission = 101,049.35 × (100-3.1)/ 100 kilotons = 97,916.82 kilotons.

Hence, total carbon dioxide emission by that country over 10 years = (130,000 + 125,970 + 122,064.93 + 118,280.92 + 114,614.21 + 111,061.17 + 107,618.27 + 104,282.1 + 101,049.35 + 97,916.82) kilotons = 1,132,857.77 kilotons ≈ 1,132,858 kilotons.

Learn more about rate of decrease here: https://brainly.com/question/14163915

#SPJ2

Answer:

y = [tex]\frac{1}{2}x+8[/tex]

Step-by-step explanation:

From the table given in the picture,

Two points lying on the graph are (-4, 6) and (-2, 7)

Let the linear function is,

y = mx + b

Here, m = slope of the line

b = y-intercept

Since, slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

Slope (m) = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Therefore, slope of the line passing through (-4, 6) and (-2, 7) will be,

m = [tex]\frac{7-6}{-2+4}[/tex]

m = [tex]\frac{1}{2}[/tex]

y-intercept is a point for which x = 0

From the given table,

For x = 0, y = 8

Therefore, y-intercept (b) = 8

Equation of the linear function will be,

y = [tex]\frac{1}{2}x+8[/tex]

Answer:

Step-by-step explanation:

19 of 22 participants (86.36%) from the high-power posing group took a gambling risk to double their money, while 12 of 20 (60%) from the low-power posing group took the gambling risk. Use a calculator tool from Module 10 to determine the p-value associated with the hypothesis test examining if there is a statistically significant difference between the proportion of people willing to take risks in the two groups. Round to 3 decimal places

H0 : P1 - P2 = 0

H1 : P1 - P2 ≠ 0

P1 = 0.8636

P2 = 0.6

q1 = 1 - P1 = 0.1364

q2 = 1 - P2 = 0.4

Tstatistic = (p1 - p2) ÷ √(p1q1)/n1 + (p2q2)/n2]

Tstatistic = (0.8636-0.6) ÷ √0.01735432]

Tstatistic = 0.2636 ÷ 0.1317357

Test statistic = 2.0009761

Test statistic = 2

The Pvalue from t statistics :

Tscore = 2 ; df = 20 + 22 - 2 = 40

Answer:

the answer is D, im doiing the flocab rn

Step-by-step explanation:

Answer:

191 ft

Step-by-step explanation:

If it's 45.5ft x 50ft, we'll need to put fence around two 45.5ft sides and two 50ft sides.

2*45.5ft + 2*50ft = 91ft + 100ft = 191ft

Answer:

69

Step-by-step explanation:

trust me

Answer:

As it says he is incorrect.

Step-by-step explanation:

To start, if you were to multiply something such as 5*1, then you would get the same number. Another example would be 8*0. Anything multiplied by 0 IS zero. He does give some valid answers, but there are also ones with smaller numbers. That is why Jackson is incorrect.

Answer:

Step-by-step explanation: $5.40 + $0.54 now equals $5.94

Answer:

[tex]Median = 90.4[/tex]

[tex]Q_1 = 88.6[/tex]

[tex]Q_3 = 92.2[/tex]

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

[tex]Smallest = 83.4[/tex]

[tex]Highest = 100.3[/tex]

Next, group each dataset base on common whole numbers.

So, we have:

[tex]83.4[/tex]

[tex]84.3\ 84.3[/tex]

[tex]85.3[/tex]

[tex]86.7\ 86.7\ 86.7[/tex]

[tex]87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9[/tex]

[tex]88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9[/tex]

[tex]89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9[/tex]

[tex]90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9[/tex]

[tex]91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\ 91.6\ 91.6\ 91.8\ 91.8[/tex]

[tex]92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7[/tex]

[tex]93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7[/tex]

[tex]94.2\ 94.2\ 94.4\ 94.7[/tex]

[tex]96.1\ 96.5[/tex]

[tex]98.8[/tex]

[tex]100.3[/tex]

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

[tex]\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}[/tex]

  [tex]\begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}[/tex]

From the above plot,

[tex]n = 83[/tex]

The median is calculated as:

[tex]Median = \frac{n+1}{2}th[/tex]

[tex]Median = \frac{83+1}{2}th[/tex]

[tex]Median = \frac{84}{2}th[/tex]

[tex]Median = 42nd[/tex]

i.e. the median is at the 42nd position.

From the above stem and leaf plot.

The 42nd position is at stem 90 and the leaf  .4

So the median is:

[tex]Median = 90.4[/tex]

The lower quartile (Q) is calculated as:

[tex]Q_1 = \frac{n+1}{4}th[/tex]

[tex]Q_1 = \frac{83+1}{4}th[/tex]

[tex]Q_1 = \frac{84}{4}th[/tex]

[tex]Q_1 = 21st[/tex]

i.e. the lower quartile is at the 21st position.

From the above stem and leaf plot.

The 42nd position is at stem 88 and the leaf .6

So the lower quartile is:

[tex]Q_1 = 88.6[/tex]

The upper quartile (Q3) is calculated as:

[tex]Q_3 = 3 * \frac{n+1}{4}th[/tex]

[tex]Q_3 = 3 * \frac{83+1}{4}th[/tex]

[tex]Q_3 = 3 * \frac{84}{4}th[/tex]

[tex]Q_3 = 3 * 21th[/tex]

[tex]Q_3 = 63rd[/tex]

i.e. the upper quartile is at the 63rd position.

From the above stem and leaf plot.

The 63rd position is at stem 92 and the leaf .2

So the upper quartile is:

[tex]Q_3 = 92.2[/tex]

Answer:

C. Rectangle

Step-by-step explanation:

Hope it helps you in your learning process.

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that [tex]n = 1067, \pi = \frac{74}{1067} = 0.069[/tex]

80% confidence level

So [tex]\alpha = 0.2[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.2}{2} = 0.9[/tex], so [tex]Z = 1.28[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079[/tex]

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Answer:

tan theta = 8/15

Step-by-step explanation:

Sin is equal to opposite over hypotenuse. So it means that the side opposite from theta is 8, and the hypotenuse is 17.

To find the value of the adjacent side from theta, use the Pythagorean Theorem.

a^2 + b^2 = c^2

8^2 + b^2 = 17^2

64 + b^2 = 289

Subtract 64.

b^2 = 225

Take the square root.

b = 15.

So that means:

the side opposite from theta is 8,

the side adjacent from theta is 15,

the hypotenuse is 17.

Now we take tan, opposite over adjacent, and use the values from the triangle.

tan = opposite / adjacent

tan = 8/15.

Answer:

The representative sample contained more girls than boys.

The true representative sample:

The representative sample contained more girls than boys.

The correct option is C.

A sample space is a set of potential results from a random experiment. The letter "S" is used to denote the sample space. Events are the subset of potential experiment results. Depending on the experiment, a sample area could contain a variety of results.

Given:

Students are voting on the color of T-shirts to wear on their field trip. There are 160 students-65 boys and 95 girls- going on the field trip.

A random sample of students is chosen.

Surveying the random sample produced a representative sample of the population.

The total number of students = 160

The number of girls = 95

The number of boys = 65

Clearly, the number of girls is more than the number of boys.

Therefore, the sample should contain more girls than boys.

To learn more about the sample space;

https://brainly.com/question/28043513

#SPJ3

Answer:

the answer is A.

Step-by-step explanation:

Answer: 10 days

Step-by-step explanation:

1/6 + 1/5 = 5/30 + 6/30 = 11/30 (total for the day)

4 / (11/30) = 10.90909091 (divide the total amount of packages by the daily total)

So 10 complete days.

Answer:

The price would go down as people would be more willing to buy cheaper potatoes and the producers would want to sell them for a lower price to get rid of them easy and fast.

Step-by-step explanation:

Hope this helps you :)

Answer:

Step-by-step explanation:

This should help I hope

Answer:

1200 hope this helps you;)

Answer:

1200 lol

Step-by-step explanation:

Answer:

121 donuts in each box

Step-by-step explanation:

969 divided by 8 = 121.125

(Ignore the remainder)

Step by step solution:

We know that there are 969 doughnuts, and there are 8 doughnuts per box. What we need to find out is how many boxes of doughnuts were made.

Step 1:

Set up an equation for Number of doughnuts (969) / Number of doughnuts per box (8) = Number of boxes made (x), which would look like this:

969/8 = x

Step 2:

Doing this, we can get 121.125, which leaves us with

121.125 = x

121.125 = 121.125

Which gives us the answer of 121.125, which we can shorten to 121, as the decimal is not necessary.

Checking our answer:

We can check our answer simply be rewording our 1st equation to solve for the number of doughnuts made. This would give us the equation Number of doughnuts per box (8) * Number of boxes made (121.125) = x. Solving this equation would look like

8 * 121.125 = x

969 = x

969 = 969

Answer: By completing the steps above we get 121, and we can check our work by rewording the problem to solve for the number of Doughnuts. Good Luck!