If the molarity of sugar is 1.1, what will the freezing point be?

Answers

Answer 1

Answer:

The freezing point will be -2.046°C.

Explanation:

The freezing point depression equation is [tex]\Delta T_f = k_f \cdot m \cdot i[/tex]

Where;

[tex]\Delta T_f[/tex] = The temperature depression of the freezing point

[tex]k_f[/tex]= The constant of freezing point depression which is solvent dependent = 1.86°C/m

i = The number of particles the substance decomposes into in solution = 1 for sugar (a covalent compound)

m = The molality of the solution = 1.1

Therefore, we have;

[tex]\Delta T_f = 1.86 \times 1.1 \times 1 = 2.046 ^{\circ}C[/tex]

Therefore the freezing point will be 0 - 2.046°C = -2.046°C.


Related Questions


A white rhinoceros weighs about 1,500 pounds (lb). How many tons (T) does the rhinoceros weigh? (1 T =
A. 1.5 T
o
B. 1 T
C. 0.75 T
D. 0.5 T

Answers

Answer:

C

Explanation:

1 lb is 0.0005 T. So if you can do the math, (1500x.0005) it comes out to 0.75 T.

If you run a particular reaction, and in theory it was supposed to yield 50.0 grams of product, and the percent yield is 75%, how many grams did you actually end up with?

Answers

Answer:

37.5 grams

Explanation:

The percent yield shows how much of the reactant have been converted to product. The percent yield is the ratio of actual yield to theoretical yield multiplied by 100%. It is given by the formula:

%yield = Actual yield/ theoretical yield × 100%

Given that theoretical yield = 50 grams and the percent yield is 75%.

Using the formula and substituting:

75% = Actual yield/ 50 g × 100%

75% / 100% = Actual yield / 50 g

0.75 = Actual yield / 50 g

Actual yield = 0.75 × 50 g

Actual yield = 37.5 grams

Anna is excited about conducting her lab today. She takes out her lab sheet and reads over the lab. She goes and gathers all of the lab materials. She follows each lab procedure step-by-step until she has completed the procedure and recorded all of the data she collected. Afterwards, Anna takes two of the substances and mixes them together to see what would happen. Which lab safety rule did Anna break?

Answers

Answer:

Anna didn't wear a lab coat

Explanation:

The first thing anyone who is to carry out a procedure or an experiment in a lab needs to do when he/she enters a lab is to wear a lab coat. This is a lab safety rule that protects the individual from been affected by spillage that could occur as a result of the experiment been conducted.

From the narration in the question, it is not stated anywhere that Anna wore a lab coat before embarking on her lab procedure.

Answer:

C, wear goggles, anytime chemicals, heat, or glassware are used.

Explanation:

This is the correct answer on the Lincoln learning platform.

A 12.6 g block of a metal intially at a temperature of 94.0 °C is added to a 100.0 g sample of water intially at 21.0 °C. If the final temperature of the water is 25.1 °C, determine the specific heat of the metal. Write all equations or formulas you use, and show as much of your work as you can.

Answers

Answer:

The specific heat of the metal is 0.0482 joules per gram-Celsius.

Explanation:

Block of metal is cooled by adding water and thermal equilibrium is reached. According to the First Law of Thermodynamics and by supposing the absence of energy and mass interaction of the system with surroundings, the change in the energy of the system is represented by:

[tex]\Delta U_{m} + \Delta U_{w} = 0[/tex]

Where [tex]\Delta U_{m}[/tex] and [tex]\Delta U_{w}[/tex] are the changes in internal energies of the block of metal and water, measured in joules.

The expression described above is now extended by applying the definition of internal energy for constant mass systems:

[tex]m_{m}\cdot c_{v,m}\cdot (T_{m,in}-T_{m,out}) + m_{w}\cdot c_{v,w}\cdot (T_{w,in}-T_{w,out})= 0[/tex]

Where:

[tex]m_{m}[/tex], [tex]m_{w}[/tex] - Masses of the block of metal and water, measured in grams.

[tex]c_{v,m}[/tex], [tex]c_{v,w}[/tex] - Specific heats of the block of metal and water, measured in joules per gram-Celsius.

[tex]T_{in, m}[/tex], [tex]T_{in, w}[/tex] - Initial temperatures of the block of metal and water, measured in Celsius.

[tex]T_{out, m}[/tex], [tex]T_{out, w}[/tex] - Final temperatures of the block of metal and water, measured in Celsius.

The specific heat of the metal is cleared in the equation:

[tex]c_{v,m} = -\frac{m_{w}\cdot c_{v,w} (T_{w,in}-T_{w,out})}{m_{m}\cdot (T_{m,in}-T_{m,out})}[/tex]

If [tex]m_{m} = 12.6\,g[/tex], [tex]m_{w} = 100\,g[/tex], [tex]c_{v,w} = 4,186\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]T_{w,in} = 21\,^{\circ}C[/tex], [tex]T_{m,in} = 94\,^{\circ}C[/tex] and [tex]T_{m,out} = T_{w,out} = 25.1\,^{\circ}C[/tex], the specific heat of the metal is:

[tex]c_{v,m} = -\frac{(100\,g)\cdot \left(4,186\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (25\,^{\circ}C-25.1\,^{\circ}C)}{(12.6\,g)\cdot (94\,^{\circ}C-25.1\,^{\circ}C)}[/tex]

[tex]c_{v,m} = 0.0482\,\frac{J}{kg\cdot ^{\circ}C}[/tex]

The specific heat of the metal is 0.0482 joules per gram-Celsius.

Give two examples of neutralization

Answers

Answer:examples for neutralization - treating indigestion,treatment for insect bites.hope it help you

Explanation:

What is ionic bond and explain it​

Answers

Answer:

An ionic bond is a chemical bonding involving the attraction between oppositely charged ions

Explanation:

On the periodic table, elements from group 1 and 7 are attracted to each other and when they bond, it's called ionic bonding. This is because of their valence electrons and ions.

Answer:

Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions, and is the primary interaction occurring in ionic compounds. It is one of the main types of bonding along with covalent bonding.

A 0.477 mol sample of O_2 gas has a volume of 11.3 L at a certain temperature and pressure. If all this O_2 were converted to ozone (O_3) at the same temperature and pressure, what is the ozone volume (in liters)? 3 O_2(g) → 2 O_3(g)

Answers

Answer:

The volume of ozone produced is 7.53 L.

Explanation:

The reaction is:

3O₂(g)  →  2O₃(g)   (1)      

0.477 mol   V=?

11.3 L    

From the reaction (1) we have that 3 moles of O₂ produce 2 moles of O₃ so the volume of the ozone produced can be calculated as follows:

[tex] V_{O_{3}} = V_{O_{2}}*\frac{n_{O_{3}}}{n_{O_{2}}} = 11.3 L*\frac{2}{3} = 7.53 L [/tex]

Therefore, the volume of ozone produced is 7.53 L.

I hope it helps you!

The ozone volume (in liters) is 7.53 L.

The calculation is as follows:

The volume of the ozone in liters should be

[tex]= 11.3 \times 2\div 3[/tex]

= 7.53L

we have that 3 moles of O₂ produce 2 moles of O₃

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I’m having trouble with this assignment please help.

Answers

Q = m.c.AT

m = 50,0 g of iron

c = 0.450 J.g-1°C-1

AT = 10°C

Thus

Q = 50 * 0.450 * 10

Q = 225 J

Is the heat energy

Hope it helps xx

Which rule determines the charge on a monatomic ion formed from a nonmetal? group number ÷ 8 8 × group number 8−groupnumber groupnumber−8

Answers

Answer:

Group number – 8

Explanation:

To determine the charge on the ion formed by various elements, we simply consider their valence electrons.

However, this is only applicable to elements in group 1, 2 and 3 only.

To determine the charge on the ions formed by non metals i.e elements in group 4, 5, 6, 7 and 8(group 0) we simply subtract 8 from the group number i.e group number – 8

This can be further explained as follow:

Chlorine belong to group 7 because it has 7 valence electrons.

The charge on the chloride ion can be obtained as follow:

Group number = 7

Charge on ion =?

Charge on ion = Group number – 8

Charge on ion = 7 – 8

Charge on ion = – 1

Therefore, the charge on chloride ion is – 1.

One day, you decide to pop some popcorn. You put the bag in the microwave, but after a couple of minutes of cooking it is clear the popcorn is not popping. Why did this happen? What steps could you take to help locate the problem?

Answers

Maybe its not real popcorn

The substances are placed in separate containers at room temperature, and each container is gradually cooled. Which of these substances will solidify before the temperature reaches 0°C? benzene water butane nitrogen

Answers

Answer:

Benzene

Explanation:

You have to find the freezing point for each of these (make sure they're in Celsius). You might want to double check these but:

Benzene: 5.5

Water: 0

Butane: -138

Nitrogen: -210

The substances that will solidify before the temperature reaches 0°C is benzene. The correct option is A.

What is freezing point?

Freezing, also known as solidification, is a phase transition that occurs when the temperature of a liquid falls below its freezing point.

If the intermolecular forces between its molecules are strong, the freezing point is high.

When the forces are weak, the freezing point is low. The freezing point of a liquid or the melting point of a solid occurs when the solid and liquid phases are in equilibrium.

Pure benzene has a freezing point of 5.48 degrees Celsius. Because of the salt in it, fresh water freezes at 32 degrees Fahrenheit, but seawater freezes at around 28.4 degrees Fahrenheit.

Thus, as per the given scenario, the correct option is A.

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write the formula of three compounds which you know and name the elements in them​

Answers

Answer:

[tex]\boxed{\sf{view \ explanation}}[/tex]

Explanation:

Compound definition:

A compound is a chemical substance formed by two or more chemically bonded elements.

Three compounds:

Water is a compound with the formula [tex]\sf H_2O[/tex].

Two hydrogen atoms and one oxygen atom is present in one molecule of water.

Sodium chloride or table salt is a compound with the formula [tex]\sf NaCl[/tex].

One sodium atom and one chlorine atom is present in one molecule of sodium chloride.

Ammonia is a compound with the formula [tex]\sf NH_3[/tex].

In one molecule of ammonia, one nitrogen atom and three hydrogen atoms are present.

Answer:

See below

Explanation:

Three compounds are:

1) [tex]\mathrm {H_{2}SO{4}}[/tex] [Sulfuric acid]

The elements in this compound are hydrogen (H) , Sulfur (S) and Oxygen (O).

2) [tex]\mathrm {NaOH}[/tex] [Sodium hydroxide]

The elements in this compound are Sodium (Na) , Oxygen (O) and Hydrogen (H).

3) [tex]\mathrm {HCl}[/tex] [Hydrochloric acid]

The elements are Hydrogen (H) and Chlorine (Cl).

when an atom gains an electron,what charge does the ion have

Answers

Answer:

if an atom gains an electron, the ion has negetive charge

The primary function of a scuba regulator is to: Reduce high-pressure gas in the scuba cylinder to a more breathable intermediate pressure. Reduce high-pressure gas in the scuba cylinder to ambient (surrounding) pressure. Provide a diver with a continuous flow of oxygenated air. None of the above.

Answers

Answer:

Reduce high-pressure gas in the scuba cylinder to ambient (surrounding) pressure.

Explanation:

The primary function of a scuba regulator would be to reduce high-pressure gas in the scuba cylinder to ambient pressure.

A scuba regulator is a structure found attached to the scuba cylinder usually carried by scuba divers. The structure regulates the pressure of the breathing gas in the cylinder to a safe level before the gas becomes available for the breathing process of divers.

Usually, the gas in a scuba cylinder is at a high level. Hence, what the regulator does is to bring it down to a level that would be safe for the breathing of the diver.

HELP PLEASE NAME THESE COMPOUNDS topic of amines and amides please explain you steps so i can do the rest of the problems myself

Answers

The attachment shows the diagram of two molecules respectively;

The first molecule in the attachment is known as triethylamine,The functional group is amine Which is - CONH2

And there is a methyl group as an attachment, attached at the third(3) carbon atom,making the compound triethyamine.

The second molecule in the attachment is an example of a secondary amide.

The longest carbon chain is five which pentanamide.

The functional group is amide.

The compoud is named by replacing the suffix - ane in pentane (alkane) to the suffix - amide.

Making the compound pentanamide.

Increasing temperature can

Answers

A- Change the phase of the matter

Answer in the correct significant figures: 35.6 + 56.27 *

Answers

Answer:

101.87

Explanation:

that's the answer

Match the set of measurements of the boiling point of water with the best

description.

Measurements

Description

6. 103 °C, 90 °C, 101 °C

a.

Precise

7. 100 °C, 99 °C, 100 °C

b.

Accurate

8. 105 °C, 106 °C, 105 °C

c. Both accurate and precise

9. 99 °C, 101 °C, 100 °C

d. Neither accurate nor precise

Answers

Answer:

Matching

6.D

7.A

8.C

9.B

Explanation:

Took test

103 °C, 90 °C, 101 °C Neither accurate nor precise, 100 °C, 99 °C, 100 °C are Precise, 105 °C, 106 °C, 105 °C are Both accurate and precise, 99 °C, 101 °C, 100 °C are Accurate. These are the correct set of measurements of the boiling point of water.

what are  boiling point and melting point ?

The melting point is defined as the temperature at which solid and liquid phases are at equilibrium state, whereas the boiling point is defined as the temperature at which the pressure of a vapor of a  liquid is equal to the external pressure.

Melting point in which the melting of solid occur to become a liquid at a given temperature, here the molecules gain enough amount of kinetic energy to get the intermolecular forces to convert into another form.

In case of Boiling point the liquid phase enters into the gaseous phase, when the external pressure is high than a temperature for the vapor pressure equal to the external pressure.

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the mass of empty cylinder is 20 gram its mass when its filled completely with water is 30 gram and its mass when its filled completely with unknown liquid is 27 gram find the density of, the unknown liquid ​

Answers

Answer:

≈ 0.70 g/cm³ (answer rounded up to 2 decimal places)

Explanation:

The mass of empty cylinder is 20g

The mass of water filling the cylinder = 30g - 20g = 10g

The mass of unknown liquid filling the cylinder = 27g - 20g = 7g

Density of water = 997 kg/m³

Converting this density to g/cm³ we get;

1kg = 1000g , 1m³ = 1000000cm³

So density = [tex]\frac{997000}{1000000}[/tex] g/cm³ = 0.997 g/cm³

So the volume of water occupied by 10g is;

10 × 0.997 = 9.97 cm³

This volume is also occupied by 7g of the unknown liquid.

Density = mass/volume

Density of the unknown liquid = 7g ÷ 9.97cm³ = 0.702106319 g/cm³ ≈ 0.70 g/cm³ (answer rounded up to 2 decimal places)

What is the lowest value of n that allows g orbital to exit​

Answers

Answer:The lowest value of n that allows g orbitals to exist is 5.

(30 points) alright so there’s this girl I’m ab to slide in her dms I just need a pickup line but nothing inappropriate bc I don’t like to slide in thirsty so if anyone has a completely hydrated cute pickup line help a simp out

Answers

Answer:

Are you a fruit, because honeydew you know how beautiful you look right now?

or maybe

I hear you’re good at algebra…..Will you replace my eX without asking Y?

or maybe

On a scale of one to ten you’re a nine… Because I’m the one left that you need.

Explanation:

Hope these help you.

3.490x 10^-3 + 1.100x10^-2

[?]x10^[?]​

Answers

[tex]1.44\times 10^{-2}[/tex]

Explanation:

We need to find the value of [tex]3.49\times 10^{-3}+1.1\times 10^{-2}[/tex].

Here,

The first number is [tex]3.49\times 10^{-3}[/tex]

The second number is [tex]1.1\times 10^{-2}[/tex]

To add these numbers as follows :

[tex]3.49\times 10^{-3}+1.1\times 10^{-2}=0.01449\\\\=1.44\times 10^{-2}[/tex]

So, the value of [tex]3.49\times 10^{-3}+1.1\times 10^{-2}[/tex] is [tex]1.44\times 10^{-2}[/tex]

. Fire can be extinguished by: - a. Lowering temperature below ignition temperature b. Cutting the supply of oxygen c. Removing non-combustible substances from surroundings d. Both a & b

Answers

Answer:

B. Cutting the supplies of oxygen

Abigail obtained 18.9 grams of calcium carbonate after performing a reaction. From her calculations, she knew she should have obtained 9.9 grams. What was her percent error? Round your answer to one place behind the decimal. Do not include the unit.

Answers

Answer:Percent error= 90.9%

Explanation:

Percent error or percentage error is defined as the  percentage of the  difference between a measured value usually from an experiment and an exact  value in comparison to the exact number.

its formula is thus

Percent error = experimental value - exact or actual value /exact value x 100

=(18.9 - 9.9 /9.9 ) x 100= 9/9.9) x 100

0.909 x 100 = 90.90 = 90.9%

What happens during an alpha decay?

Answers

Answer:

Alpha decay is a type of radioactive disintegration in which unstable atomic nucleus releases a helium nucleus or alpha particle and transform into a different element. The new element formed will be reduced by four and the atomic number will be reduced by two.

Example of alpha decay is: Uranium 238 transform into Thorium 234 with the emission of an alpha particle.

Which of the following is not an antioxidant _________
1) Sodium benzoate 2) Sulphur dioxide 3) Sulphite salts 4) Citric acid

Answers

Answer: 1. Sodium Benzoate

Explanation: An anti-oxidant is a substance that can help prevent or stop the damage done by free radicals. Examples include; Sulphur Dioxide, Sulphite Salts, Citric Acid, e.t.c

Sodium benzoate is a pure preservative.

Which of these is true about electrons? posses a positive electrical charge of one (+1) have a negative electrical charge of one (-1) indicates the number of protons in each atom equals the sum of protons plus neutrons in each atom

Answers

Answer:

have a negative electrical charge of one (-1)

Explanatio

Electrons have an electrical charge of negative one. When you think electron, always think -1

In ∆ABC, if sin A = and tan A = , then what is cos A?

Answers

Complete Question:

In ∆ABC, if sin A = 4/5 and tan A = 4/3, then what is cos A?

Answer:

[tex]cos A= \frac{3}{5}[/tex]

Explanation:

Given

[tex]sin A = 4/5[/tex]

[tex]tan A = 4/3[/tex]

Required

[tex]cos A[/tex]

In trigonometry;

[tex]tanA = \frac{sinA}{cosA}[/tex]

Multiply both sides by cosA

[tex]cos A * tanA = \frac{sinA}{cosA} * cos A[/tex]

[tex]cos A * tanA = sinA[/tex]

Divide both sides by tanA

[tex]\frac{cos A * tanA}{tanA} = \frac{sinA}{tanA}[/tex]

[tex]cos A= \frac{sinA}{tanA}[/tex]

Substitute values for sinA and tanA

[tex]cos A= \frac{4/5}{4/3}[/tex]

[tex]cos A= \frac{4}{5} / \frac{4}{3}[/tex]

[tex]cos A= \frac{4}{5} * \frac{3}{4}[/tex]

[tex]cos A= \frac{4 * 3}{5 * 4}[/tex]

[tex]cos A= \frac{3}{5}[/tex]

How many grams of silver will be produced if 86g of copper are used

Answers

10 or 30 grams

hope this help you

explain using diagrams how potassium forms the compound potassium flouride when it reacts with flourine

Answers

Answer:

The answer to your question is given below.

Explanation:

Potassium (K) has 19 electrons with electronic configuration of 2, 8, 8, 1.

Fluorine (F) has 9 electrons with electronic configuration of 2, 7.

Fluorine needs 1 electron to complete it's octet configuration.

Hence, potassium (K), will lose 1 electron to fluorine (F) to form potassium ion (K+) with electronic configuration of 2, 8, 8. The fluorine atom (F) will receive the 1 electron from potassium to form the fluoride ion (F-) with electronic configuration of 2, 8.

**** Please see attached photo for further details.

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