Answer:
Explanation:
Hello,
In this case the molar fraction of sodium sulfide, whose molar mass is 78 g/mol, is 0.125, it means we have 0.125 moles of sodium sulfide per mole of solution, so we compute the mass of sodium sulfide and water as shown below:
[tex]m_{Na_2S}=0.125mol*\frac{78gNa_2S}{1molNa_2S} =9.75 gNa_2S\\\\m_{H_2O}=(1-0.125)molH_2O*\frac{18gH_2O}{1molH_2O} =15.75gH_2O[/tex]
Then, we can calculate the eight/weight % as follows:
[tex]w/w \%=\frac{9.75g}{9.75g+15.75g}*100\% \\\\w/w \%=38\%[/tex]
Regards.
Answer: 38
Explanation:
Which chemical is responsible for opening the hair cuticle?
A
Peroxide
B
Ammonia
С
Powder persulphate
D
None of the above
dentify the missing information for each atom or ion. Note that the atoms and ions are not necessarily neutral. A Se ion has a mass number of 78 and a charge of −2 . Determine the number of neutrons, protons, and electrons in this ion. number of neutrons: 44 number of protons: 34 number of electrons: 36 An ion has a mass number of 65, 36 neutrons, and a charge of +1 . Identify the element symbol, and determine the number of protons and electrons in this ion. element symbol: Cu number of protons: 30 number of electrons: 29 An atom or ion has 43 neutrons , 36 protons, and 36 electrons. Identify the element symbol, and determine the mass number and charge for this atom or ion. element symbol: Au mass number: 79 charge: 0
Answer:
Check the explanation
Explanation:
1)
Atomic number of Se = 34
So, number of proton = 34
use:
charge = number of proton - number of electron
-2 = 34 - number of electron
number of electron = 36
number of neutron = mass number - atomic number
= 78 - 34
= 44
Answer:
44
34
36
2)
number of proton = mass number - number of neutron
= 65 - 36
= 29
29 is atomic number for Cu
use:
charge = number of proton - number of electron
+1 = 29 - number of electron
number of electron = 28
Answer:
Cu
29
28
3)
Atomic number is 36 for Kr
use:
charge = number of proton - number of electron
= 36 - 36
= 0
use:
mass number = number of proton + number of neutron
= 36 + 42
= 78
Answer:
Kr
78
0
Anatom that has lewer neutrons than protons and more electrons than protons is
Answer:
a negative ion, and an isotope.
Explanation:
The perfect atom consists of an equal balance in all 3. If the neutrons are not even with the protons, it is an isotope since it is like another version of the so called (but not actually) 'perfect' atom. If there is more electrons, the charge is negative, making it an ion.
Question 1 of 10
2 Points
An engineering team is conducting a wind tunnel test to examine the
aerodynamics of a car it has designed. Which part of the engineering process
is the team in?
O A. Do the work.
O B. Evaluate the results.
O C. Improve and redesign.
D. Identify a need.
SUBMIT
Explanation:
Evaluate the results, letter B
2.92 A 50.0-g silver object and a 50.0-g gold object are both added
to 75.5 mL of water contained in a graduated cylinder. What is
the new water level in the cylinder? (2.7)
ifacturing of computer chins cylinders of silicon
Answer:
82.9 mL
Explanation:
1. Volume of silver
[tex]\begin{array}{rcl}\text{Density}&=& \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho&=& \dfrac{m}{V}\\\\V &=& \dfrac{m}{\rho}\\\\& = & \dfrac{\text{50.0 g}}{\text{10.49 g$\cdot$mL}^{-1}}\\\\& = & \text{4.766 mL}\\\end{array}\\\text{The volume of the silver is $\large \boxed{\textbf{4.766 mL}}$}[/tex]
2. Volume of gold
[tex]\begin{array}{rcl}V& = & \dfrac{\text{50.0 g}}{\text{19.30 g$\cdot$mL}^{-1}}\\\\& = & \text{2.591 mL}\\\end{array}\\\text{The volume of the gold is $\large \boxed{\textbf{2.591 mL}}$}[/tex]
3. Total volume of silver and gold
V = 4.766 mL + 2.591 mL = 7.36 mL
4 New reading of water level
V = 75.5 mL + 7.36 mL = 82.9 mL
Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine because A.the bromine radical is more reactive and therefore more selective. B.the chlorine radical is more reactive and therefore more selective. C.the chlorine radical is less reactive and therefore more selective. D.the bromine radical is less reactive and therefore more selective. E.none of these choices.
Answer:Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine because the bromine radical is less reactive and therefore more selective.
Explanation: Halogenation occurs when a halogen replaces one or more hydrogen atoms in an organic compound ie chlorine or bromine with the reactivity of the halogens decreasing in the order of F2 > Cl2 > Br2 > I2
Since fluorine reacts explosively making it is difficult to control, and iodine is unreactive. Free radical mono-halogenation of an alkane is typically conducted using bromine versus chlorine with Chlorination ie chlorine radical being more reactive and not selective and the Bromination of alkanes ie bromine radical occurring similarly but slower and less reactive but more selective which is due to the fact that a bromine atom is less reactive in the hydrogen abstraction than a chlorine atom evidence in the higher bond energy of H-Cl than H-Br.
Metamorphic rocks directly form from
Answer:
Metamorphic rocks are formed from pre-existing rock and sediment materials. They are formed when igneous, sedimentary, or other pre-existing metamorphic rocks are exposed to the heat and pressure as well as super-heated mineral-rich fluids. They are compacted together to form a new rock altogether. Metamorphism does not include the melting or liquefaction of the pre-existing rock. Instead, it compacts them and crushes them, pushing them together at extreme heat and pressure to form a new rock altogether composed of sedimentary, igneous, and other metamorphic rock. It's the rock hybrid of the geologic world.
Metamorphism is similar to when you squish playdough together, it doesn't form a new playdough color (unless you REALLY mixed that poor playdough together). It forms an amalgamation of different colors and patterns made from the other rock.
Taken from a paper I once wrote I explained this again:
"Metamorphic rocks are formed when pre-existing rocks and their minerals are compressed and altered by Earth’s internal processes; interior pressure, temperature (heat), and chemical reactions. The minerals and pre-existing rock necessary for the creation of metamorphic rock must then also be located deep underground if such processes are expected to make an impact and create a metamorphic rock."
PLEASEEEE help! BRAINLIEST to right answer!!!!
Answer:
D
Explanation:
No energy is lost during transforming into another because energy cannot be reated or destroyed
Answer:
i think is d
Explanation:
I'm not sure wait for a few more answers
If 120.4 grams of reactant completely breaks down (decomposes) to produce 106.4 grams of chlorine. What mass of nitrogen gas could be expected? *
Answer:
[tex]m_{nitrogen}=14g[/tex]
Explanation:
Hello,
In this case, since we are talking about a chemical reaction in which a compound having nitrogen and chlorine is decomposed into chlorine and nitrogen, we must remember that the law of conservation of mass must be obeyed, for that reason, we notice that the mass of the whole reactants must equal the mass of the whole products, as shown below:
[tex]m_{reactants}=m_{products}[/tex]
Next, we know there is only one single reactant and products are constituted by both chlorine and nitrogen:
[tex]m_{reactant}=m_{chlorine}+m_{nitrogen}[/tex]
In such a way, we can compute the mass of nitrogen as shown below:
[tex]m_{nitrogen}=m_{reactant}-m_{chlorine}=120.4g-106.4g\\\\m_{nitrogen}=14g[/tex]
Best regards.
To make a is to settle a disagreement by giving up some personal demands
Answer:
Compromise
Explanation:
Please give brainliest :-)
Answer:
Compromise
Explanation:
Problem PageQuestion Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 500. mL flask with 1.3 atm of sulfur dioxide gas and 4.1 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be 0.91 atm. Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.
Answer:
SO₂: 0.39atm
O₂: 3.645atm
Explanation:
Based on the reaction:
2 SO₂(g) + O₂(g) → 2 SO₃(g)
2 moles of sulfur dioxide react per mole of oxygen to produce 2 moles of sulfur trioxide.
When the reaction occurs an comes to equilbrium, the partial pressure of each gas is:
SO₂: 1.3atm - 2X
O₂: 4.1atm -X
SO₃: 2X
Where X is the reaction coordinate.
As pressure at equilibrium of SO₃ is 0.91 atm:
0.91atm = 2X
Thus: X = 0.455atm.
Replacing, pressures at equilibrium of the gases are:
SO₂: 1.3atm - 2×0.455atm = 0.39 atm
O₂: 4.1atm -0.455atm = 3.645 atm
please help! BRAINLIEST to right answer
Answer:
Hailey the answer is D.
Explanation:
if liquid to solid is exothermic then then the other way around would be endorhermic
A sample of gas occupies a volume of 120.0mL at a pressure of 0.75atm and a temperature of 295K. What will the volume be at a pressure of 1.25
atm and a temperature of 345K?
A)48mL
B)84mL
C)8mL
D)4mL
Answer:
A) 84 mL
Explanation:
use general gas equation P1×V1 / T1 = P2×V2/T2
rearrange the formula and solve for V2,it should give you V2= 84mL
Answer:
[tex]\large \boxed{\text{B) 84 mL}}[/tex]
Explanation:
We can use the Combined Gas Laws to solve this problem .
[tex]\dfrac{p_{1}V_{1} }{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}[/tex]
Data
p₁ = 0.75 atm; V₁ = 120.0 mL; T₁ = 295 K
p₂ = 1.25 atm; V₂ = ?; T₂ = 345 K
Calculations
[tex]\begin{array}{rcl}\dfrac{p_{1}V_{1} }{T_{1}} & = & \dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{\text{0.75 atm $\times$ 120.0 mL}}{\text{295 K}} & = & \dfrac{\text{1.25 atm} \times V_{2}}{\text{345 K}}\\\\\text{0.305 mL} & = & \text{0.003 523V}_{2}\\V_{2}& =& \dfrac{\text{0.305 mL}}{0.003523}\\\\& = & \textbf{84 mL}\\\end{array}\\\text{The new volume of the gas is $\large \boxed{\textbf{84 mL}}$}[/tex]
If you have 67.31g of CH4, how many moles do you have?
Answer:
If you have 67.31 g of CH₄, you have 4.21 moles
Explanation:
To know the amount of moles if you have 67.31 g of CH₄, you must know the molar mass, that is, the mass of one mole of a substance, which can be an element or a compound.
On the periodic table, the molar mass of the elements, also called the atomic mass or atomic weight, can be found at the bottom of the element. In this case:
C: 12 g/moleH: 1 g/moleTo calculate the molar mass of a compound, the molar mass of the elements of the compound must be added multiplied by the times they appear. So in this case the molar mass of CH₄ is:
CH₄= 12 g/mole + 4* 1 g/mole= 16 g/mole
Now you can apply the following rule of three: if 16 g are contained in 1 mole of CH4, 67.31 g in how many moles are present?
[tex]moles=\frac{67.31 g*1 mole}{16 g}[/tex]
moles= 4.21
If you have 67.31 g of CH₄, you have 4.21 moles
Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 42. g of butane is mixed with 150. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.
Answer:
127 grams of carbon dioxide
Explanation:
We need to determine the chemical equation first. Butane has a chemical formula of [tex]C_4H_{10}[/tex], oxygen is [tex]O_2[/tex], carbon dioxide is [tex]CO_2[/tex], and water is [tex]H_2O[/tex]. The reactants are butane and oxygen and the products are carbon dioxide and water. So we write:
[tex]C_4H_{10}+O_2[/tex] ⇒ [tex]CO_2+H_2O[/tex]
But remember! We need to balance this. Currently, there are 4 carbon atoms (C), 10 hydrogen atoms (H), and 2 oxygen atoms (O) on the left, while there are 1 carbon atom (C), 2 hydrogen atoms (H), and 3 oxygen atoms (O) on the right. Let's place a coefficient of 4 in front of the carbon dioxide and a coefficient of 5 on the water, so that we have equal numbers of carbon and hydrogen atoms on each side:
[tex]C_4H_{10}+O_2[/tex] ⇒ [tex]4CO_2+5H_2O[/tex]
However, we need to ensure that there are equal numbers of O atoms, as well. On the left, we have 2 and on the right we have 13, so let's put a coefficient of 6.5 on the oxygen:
[tex]C_4H_{10}+6.5O_2[/tex] ⇒ [tex]4CO_2+5H_2O[/tex]
Finally, multiply everything by 2 to get whole number coefficients:
[tex]2C_4H_{10}+13O_2[/tex] ⇒ [tex]8CO_2+10H_2O[/tex]
Ah, now we can actually get to the problem!
We need to determine the limiting reactant, so let's convert the 42 g of butane and 150 g of oxygen into moles of any product, say, carbon dioxide. To convert to moles, we need to find the molar mass of each compound.
The molar mass of butane is 4 * 12.01 + 10 * 1.01 = 58.14 g/mol, while the molar mass of oxygen is 2 * 16 = 32 g/mol. We can now set up the equations:
[tex]42 gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}} *\frac{8molCO_2}{2molC_4H_{10}} =2.8896molCO_2[/tex]
[tex]150 gO_2*\frac{1molO_2}{32gO_2} *\frac{8molCO_2}{13molO_2} =2.8846molCO_2[/tex]
Clearly, we see that 2.8846 < 2.8896, which means that oxygen is the limiting reactant. In other words, the most products can be made when the oxygen is all used up.
Now let's finally convert moles of carbon dioxide into grams by multiplying by its molar mass, which is 12.01 + 2 * 16 = 44.01 g/mol:
[tex]2.8846molCO_2*\frac{44.01gCO_2}{1molCO_2} =127gCO_2[/tex]
Notice that we have 3 significant figures because we had 3 significant figures at the start with 150. grams of oxygen.
~ an aesthetics lover
) A concentration cell is based on the aqueous reaction
Cu2+(1.00 M) Cu2+(0.0100 M)
The cell consists of copper electrodes dipping into solutions of Cu2+ ions. The anions present are sulfate ions. Draw a neat diagram to represent this cell, showing and labeling all necessary components including: anode, cathode, electron flow, cation flow and anion flow.
Answer:
Kindly check the attachment for the diagram representing the cell and showing all necessary components including: anode, cathode, electron flow, cation flow and anion flow.
Explanation:
So, the reaction in the concentration cell is given below as;
Cu2+(1.00 M) → Cu2+(0.0100 M).--(1).
The anode = Cu2+(0.0100 M) because it has lesser Concentration, thus, lesser potential value.
Cathode = Cu2+(1.00 M) because it has higher Concentration, hence higher potential value.
It must be noted that in the digaram depicting the Reaction, the electrons moves from the anode part of the cell to the cathode part of the cell and this is done through an external circuit. The following are the things that happens at each electrode;
At the Anode: in here is where oxidation occurs and Cu^2+ is released into the solution.
At the cathode: in here is where the reduction occur and the Cu^2+ moves in the direction to where the Cu electrode is, thus, causing the deposition of Cu.
What amount of heat will raise the temperature of 78g liquid water from 20 C to 80 C?
Answer:
19656J
Explanation:
Step 1:
Data obtained from the question.
Mass (M) = 78g
Initial temperature (T1) = 20°C
Final temperature (T2) = 80°C
Change in temperature (ΔT) = T2 – T1 =
80°C – 20°C = 60°C
Specific heat capacity (C) = 4.2J/g°C
Heat (Q) =...?
Step 2:
Determination of the heat required for the reaction.
Q = MCΔT
Q = 78 x 4.2 x 60
Q = 19656J
Therefore, 19656J of heat is required.
Common additives to drinking water include elemental chlorine, chloride ions, and phosphate ions. Recently, reports of elevated lead levels in drinking water have been reported in cities with pipes that contain lead, Pb(s). When Cl2(aq) flows through a metal pipe containing Pb(s), some of the lead atoms oxidize, losing two electrons each, and aqueous chloride ions form. (a) Write a balanced, net-ionic equation for the reaction between Pb(s) , and Cl2(aq).
Answer:
See explaination
Explanation:
Balanced net ionic reaction.
Pb(s) + Cl2(g) ----- Pb2+ + 2Cl-
oxidation reaction :Pb(s) --- Pb2+ + 2e-
Reduction reaction:Cl2 + 2e- -----Cl-
Nitrogen gas has a volume of 10.00L when under a
pressure of 1000. mmHg. If the temperature stays constant calculate
the new volume if the pressure drops to 500.mmHg.
Answer:
THE NEW VOLUME OF THE NITROGEN GAS AT 500 mmHg IS 20 L
Explanation:
We will solve the question by using the Boyle's law equation;
P1V1 = P2V2
Write out the values of the variables involved in the question
P1 = 1000 mmHg
V1 = 10 L
P2 = 500 mmHg
V2 = ?
Substitute the values into the equation, we have;
V2 = PIV1 / P2
V2 = 1000 * 10 / 500
V2 = 10000 /500
V2 = 20 L
The new volume of the nitrogen gas at a pressure of 500 mmHg is 20 L.
Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty for missing matches. Use the References to access important values if needed for this question. Indicate whether each of the following compounds will gave an acidic, basic or neutral solution when dissolved in water.
1. ammonium bromide
2. potassium cyanide
3. sodium chloride
4. potassium iodide
Answer:
Explanation:
1 ) Ammonium bromide is a salt of ammonium hydroxide and hydrogen bromide . The former is a weak base and the later is a strong acid so the salt will make acidic solution in water. It happens due to salt hydrolysis.
2 ) Potassium cyanide is salt of potassium hydroxide and hydrogen cyanide . The former is strong base and the later is weak acid so its salt will be basic in nature .
3 ) sodium chloride is a salt of sodium hydroxide and hydrogen chloride . The former is strong base and later is strong acid. So the salt is neutral .
4 ) Potassium iodide is a salt of potassium hydroxide and hydrogen iodide . The former is a strong base and the later is a strong acid . So the salt is neutral or a bit basic.
How many milliliters of 0.200 M NH4OH are needed to react with 12.0 mL of 0.550 M FeCl3?
FeCl3 + 3NH4OH Fe(OH)3 + 3NH4Cl
Answer:
9.9 ml of 0.200M NH₄OH(aq)
Explanation:
3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)
?ml of 0.200M NH₄OH(aq) reacts completely with 12ml of 0.550M FeCl₃(aq)
1 x Molarity NH₄OH x Volume Am-OH Solution(L) = 2 x Molarity FeCl₃ x Volume FeCl₃ Solution
1(0.200M)(Vol Am-OH Soln) = 3(0.550M)(0.012L)
=> Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liter = 9.9 milliliters
The amount of [tex]0.200 M NH_{4} OH[/tex] required to react with [tex]12.0 ml[/tex] of [tex]0.550 M FeCl_{3}[/tex]would be [tex]9.9 ml.[/tex]
Given that,
Reaction:
[tex]3NH_{4} OH(Iaq) + FeCl_{3} (aq) => NH_{4} Cl(aq) + Fe(OH)_{3} (s)[/tex]
To find,
The amount of [tex]0.200 M NH_{4} OH[/tex]required to react with [tex]12.0 ml[/tex] of [tex]0.550 M FeCl_{3}[/tex] = ?
Procedure:
As we know,
[tex]1[/tex] × molarity of [tex]NH_{4}OH[/tex]× [tex]Volume (Am-OH) Solution(l)[/tex] [tex]= 2[/tex] × molarity of [tex]FeCl_{3}[/tex]× volume of solution [tex]FeCl_{3}[/tex]
By substituting the given values in this formula, we get
⇒ [tex]1(0.200M)[/tex][tex](Vol Am-OH Sol)= 3(0.550M)(0.012L)[/tex]
⇒ [tex]Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M)[/tex]
⇒ [tex]Vol Am-OH Solution = 0.099 liters[/tex]
[tex]= 0.099[/tex] × [tex]1000[/tex]
[tex]=[/tex] [tex]9.9 milliliters[/tex]
Thus, [tex]9.9 ml[/tex] is the correct answer.
Learn more about 'compounds' here:
brainly.com/question/13516179
Suppose you digested 0.25 g of a copper ore samplein 15 mL of solution. One mL of this solution is transferred to a 10 mL volumetric flask, which is filled to the calibration level. The resulting concentrationwas 0.0087M Cu2+. What is the concentration of copper in the ore sample in units of percentage?
Answer:
Explanation:
10 mL = 10⁻² L
1 mL of solution contains .0087 x 10⁻² mole of Cu
15 mL of solution will contain .1305 x 10⁻² mole of Cu
.1305 x 10⁻² mole of copper = .1305 x 63.5 x 10⁻² gm of Cu
= .08286 gm
concentration of copper in the ore sample
= .08286 x 100 / .25
= 33 % approx .
methane Express your answer as a condensed structural formula omitting all bonds (e.g CH3CH2CH3). nothing Request Answer Part B ethane Express your answer as a condensed structural formula omitting all bonds (e.g CH3CH2CH3). nothing Request Answer Part C pentane Express your answer as a condensed structural formula omitting all bonds (e.g CH3CH2CH3). nothing Request Answer Part D cyclopropane Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. Include all hydrogen atoms.
Answer:
a
The condensed structural formula for methane is
[tex]CH_4[/tex]
b
The condensed structural formula for ethane is
[tex]CH_3 CH_3[/tex]
c
The condensed structural formula for pentane is
[tex]CH_2(CH_2)_3CH_3[/tex]
d
The diagram for the structural formula for cyclopropane is shown on the first uploaded image
Explanation:
Sometimes in the lab we collect the O2gas formed by a chemical reaction over water (see sketch at right). This makes it easy to isolate and measure the amount of gas produced. Suppose the gas evolved by a certain chemical reaction taking place at 55.0C is collected over water, using an apparatus something like that in the sketch, and the final volume of gas in the collection tube is measured to be 117mL. Calculate the mass of that is in the collection tube. Round your answer to significant digits. You can make any normal and reasonable assumptions about the reaction conditions and the nature of the gases.
Answer:
mass CO = 0.12166 g
Explanation:
Mass of CO = 0.12 grams
Explanation
Volume of CO gas = 117 mL = 0.117 L
Temperature of CO = 55.0 oC = 328 K
Assumption : Pressure of CO = atmospheric pressure = 1.0 atm
According to ideal gas law,
moles of CO = [(Pressure of CO) * (Volume of CO gas)] / [(R) * (Temperature of CO)]
where R = gas constant = 0.0821 L-atm/mol-K
moles of CO = [(1.0 atm) * (0.117 L)] / [(0.0821 L-atm/mol-K) * (328 K)]
moles of CO = 0.004345 mol
mass CO = (moles of CO) * (molar mass CO)
mass CO = (0.004345 mol) * (28.0 g/mol)
mass CO = 0.12166 g
cis-1-Bromo-4-tert-butylcyclohexane and trans-1-bromo-4-tert-butylcyclohexane both react with sodium ethoxide in ethanol to form 4-tert-butylcyclohexene. Explain why the cis isomer reacts much more rapidly than the trans isomer. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.
Answer:
See explanation below
Explanation:
In order to explain this, is neccesary to draw both confomers, the cis and trans, but in the chair conformation, because in that way we can see much better the bonds and the reason of why the cis reacts faster than trans.
As you can see in picture attached, the more stable conformer is the one where the H and Br are in the axial position, and the tert butyl group in equatorial position. In these positions, the cis isomer can undergo an E2 reaction, and the ethoxide would have no problem to substract the hydrogen atom from the molecule to eliminate the Bromide. This is because the t-butyl group in equatorial position, is not exerting steric hindrance, therefore is faster.
In the case of the trans, the t-butyl group is in the axial position as well as the hydrogen and bromide, therefore, when the E2 reaction undergoes, the hydrogen is substracted by ethoxide, but it will be slow because the t.butyl group exerts steric hindrance in the axial positions, therefore, the hydrogen will be substracted slower than in the cis position. This is the main reason for the cis to be faster.
As for the second part of the question, which will be the answer of the whole question, see picture attached 2 for the whole sentence, and the match of the words is the following:
1. Axial
2. More
3. Blank (No word there)
4. less
5. Blank
6. Cis
7. Trans
8. Cis
The image shows two different species. the image is a dog and a lizered
Which is a shared characteristic of these two species?
tail
scales
hair
body shape
Answer:
the tail
Explanation:
Answer:
A.) tails
Explanation:
Calculate the pH of a [0.000765) M solution of KOH
Answer:
pH=10.88
Explanation:
Hello,
In this case, since potassium hydroxide is completely dissociated as shown below:
[tex]KOH\rightarrow K^++OH^-[/tex]
For which we understand it is a base, more specifically, a strong base; it means that the concentration of the OH⁻ equals the concentration of the potassium hydroxide, that is 0.000765M, for that reason we can directly compute the pOH:
[tex]pOH=-log([OH^-])=-log(0.000765)=3.12[/tex]
Finally, since the pOH and the pH are related by:
[tex]pOH+pH=14[/tex]
The pH turns out:
[tex]pH=14-3.12\\pH=10.88[/tex]
Best regards.
Which pigment is responsible for grey hair?
A
Eumelanin
В
Pheomelanin
с
Both Eumelanin and Pheomelanin
D
No pigment
3 of 10
Answer:
No pigment.
Explanation:
Pigment makes color, and hair loses color when it loses pigment.
What are the variables in Gay-Lussac’s law
Answer:
The variables in Gay-Lussac's law are the initial temperature (T1), the initial pressure (P1), the final temperature (T2) and the final pressure (P2)....
Explanation:
10. When the pressure on a gas inetcases three times, by how much will the volume incrcase or decrease?
Answer:The answer to this question comes from experiments done by the scientist Robert Boyle in an effort to improve air pumps. In the 1600's, Boyle measured the volumes of gases at different pressures. Boyle found that when the pressure of gas at a constant temperature is increased, the volume of the gas decreases. when the pressure of gas is decreased, the volume increases. this relationship between pressure and volume is called Boyle's law.
Explanation: So, at constant temperature, the answer to your answer is: the volume decreases in the same ratio as the ratio of pressure increases.
BUT, in general, there is not a single answer to your question. It depend by the context.
For example, if you put the gas in a rigid steel tank (volume is constant), you can heat the gas, so provoking a pressure increase. But you won't get any change in volume.
Or, if you heat the gas in a partially elastic vessel (as a tire or a soccer ball) you will get both an increase of volume AND an increase of pressure.
FINALLY if you inflate a bubblegum ball, the volume will be increased without any change in pressure and temperature, because you have increased the NUMBER of molecules in the balloon.
There are many other ways to change volume and pressure of a gas that are different from the Boyle experiment.
