If the vehiche has a speed of 24.0 m/s at point a what is the force of the track on the vehicle at this point?

Question:

A roller-coaster vehicle has a mass of 500 kg when fully loaded with passengers.  If the vehicle has a speed of 20.0 m/s at point A, what is the force exerted by the track on the vehicle at this point?

See attachment

Answer:

33700 Newton

Explanation:

Given

[tex]m = 500kg\\v = 24.0m/s\\r=10m[/tex]

First, we determine the forces acting on mass m.

They are: the force exerted by the track (Fn) and the weight of the vehicle (W)

So, the net force is:

[tex]F_{net} = F_n - W[/tex]

[tex]W=mg[/tex]

So:

[tex]F_{net} = F_n - mg[/tex]

Make Fn the subject

[tex]F_n = F_{net} + mg[/tex]

Fnet is calculated as:

[tex]F_{net} = F_c = \frac{mv^2}{r}[/tex] --- i.e. the centripetal force

So:

[tex]F_n = F_{net} + mg[/tex]

[tex]F_n = \frac{mv^2}{r} + mg[/tex]

[tex]F_n = \frac{500 * 24^2}{10} + 500 * 9.8[/tex]

[tex]F_n = 28800 + 4900[/tex]

[tex]F_n = 33700N[/tex]

TEST INTRO 20

The fact that a pen drops when you let it go is an example that can help explain ...
A: the hypothesis of gravity.
B: the theory of gravity.
C: the gravity of the situation.
D: the law of gravity: