Iliana rotated trapezoid WXYZ 180° about the origin.

On a coordinate plane, trapezoid W X Y Z has points (negative 4, 2), (negative 3, 4), (negative 1, 4), (0, 2).

What is the correct set of image points for trapezoid W’X’Y’Z’?

W’(4, –2), X’(3, –4), Y’(1, –4), Z’(0, –2)
W’(4, 2), X’(3, 4), Y’(1, 4), Z’(0, 2)
W’(–2, –4), X’(–4, –3), Y’(–4, –1), Z’(–2, 0)
W’(2, 4), X’(4, 3), Y’(4, 1), Z’(2, 0)

Answer:

[tex]\displaystyle \frac{\tan\theta}{\sec\theta - \cos\theta} = \frac{1}{\sin\theta} = \csc\theta[/tex]

Step-by-step explanation:

We have the expression:

[tex]\displaystyle \frac{\tan\theta}{\sec\theta - \cos\theta}[/tex]

And we want to write the expression in terms of sine and cosine and simplify.

Thus, let tanθ = sinθ / cosθ and secθ = 1 / cosθ. Substitute:

[tex]=\displaystyle \frac{\dfrac{\sin\theta}{\cos\theta}}{\dfrac{1}{\cos\theta}-\cos\theta}[/tex]

Multiply both layers by cosθ:

[tex]=\displaystyle \frac{\left(\dfrac{\sin\theta}{\cos\theta}\right)\cdot \cos\theta}{\left(\dfrac{1}{\cos\theta}-\cos\theta\right)\cdot \cos\theta}[/tex]

Distribute:

[tex]\displaystyle =\frac{\sin\theta}{1-\cos^2\theta}[/tex]

Recall from the Pythagorean Theorem that sin²θ + cos²θ = 1. Hence, 1 - cos²θ = sin²θ. Substitute and simplify:

[tex]\displaystyle =\frac{\sin\theta}{\sin^2\theta} \\ \\ =\frac{1}{\sin\theta}[/tex]

We can convert this to cosecant if we wish.

Answer:

no solution

Step-by-step explanation:

7x-12<7x-7

-13<-7

no solution

Answer:

The slope is Negative three-halves and contains the point (0, 2).

Step-by-step explanation:

(-3,-4)(3,0)

M= -4/-6 = 2/3

⊥M = -3/2

0 = 2/3(3) + B

B=2

Answer: =28x + 15y

Step-by-step explanation:

Step-by-step explanation:

Volume of the block

[tex] = lbh[/tex]

[tex] = \frac{3}{8} \times \frac{1}{8} \times \frac{5}{8} [/tex]

[tex] = \frac{3 \times 5}{ {8}^{3} } [/tex]

[tex] = \frac{15}{512} [/tex]

Answer:

Can u explain more pls?

Step-by-step explanation:

Answer:

Square

Step-by-step explanation:

[tex]\hookrightarrow \:

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (2, - 8) ← 2 points on the line

m = [tex]\frac{-8-0}{2-0}[/tex] = [tex]\frac{-8}{2}[/tex] = - 4

The line crosses the y- axis at (0, 0) ⇒ c = 0 , then

y = - 4x + c , that is

y = - 4x → A

The equation of line passes through the points (0, 0) and (2, -8) will be;

⇒ y = - 4x

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

Two points on the line are (0, 0) and (2, -8).

Now,

Since, The equation of line passes through the points (0, 0) and (2, -8).

So, We need to find the slope of the line.

Hence, Slope of the line is,

m = (y₂ - y₁) / (x₂ - x₁)

m = (- 8 - 0) / (2 - 0)

m = - 8 / 2

m = - 4

Thus, The equation of line with slope - 4 is,

⇒ y - 0 = - 4 (x - 0)

⇒ y = - 4x

Therefore, The equation of line passes through the points  (0, 0) and

(2, -8) will be;

⇒ y = - 4x

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[tex]\displaystyle\bf 3x+7\geq 52 \ ; \ x>15 \\\\3x\geq 45\\\\x\geq 15 \ \ \ and \ \ \ x>15[/tex] here is a contradiction because in one inequality x can be equal to 15 ; and in the other it cannot

Answer:

[tex]P = 4\sqrt{13}[/tex]

Step-by-step explanation:

Given

[tex]W = (7, 2)[/tex]

[tex]X = (5, -1)[/tex]

[tex]Y = (3, 2)[/tex]

[tex]Z =(5, 5)[/tex]

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2[/tex]

So, we have:

[tex]WX = \sqrt{(5- 7)^2 + (-1 - 2)^2[/tex]

[tex]WX = \sqrt{13}[/tex]

[tex]XY = \sqrt{(3-5)^2 + (2--1)^2}[/tex]

[tex]XY = \sqrt{13}[/tex]

[tex]YZ = \sqrt{(5-3)^2 + (5-2)^2}[/tex]

[tex]YZ = \sqrt{13}[/tex]

[tex]ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}[/tex]

[tex]ZW = \sqrt{13}[/tex]

The perimeter is:

[tex]P = WX + XY + YZ + ZW[/tex]

[tex]P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}[/tex]

[tex]P = 4\sqrt{13}[/tex]

Answer:

C on edge 2021

Step-by-step explanation:

I took the cumulative exam

Answer:

7:24 pm

Step-by-step explanation:

speed = distance/time

time * speed = distance

time = distance/speed

time = (195 miles)/(50 miles/hour)

time = 3.9 hours

The trip will take 3.9 hours.

3 hours + 0.9 hours = 3 hours + 0.9 hours * 60 minutes/hour =

= 3 hours + 54 minutes

The trip will take 3 hours and 54 minutes.

3:30 pm + 3:54 = 6:84 pm = 7:24 pm

Answer: 7:24 pm

Answer:

Step-by-step explanation:

Step-by-step explanation:

[tex] \rm{tangent \: = \: opposite \:/ adjacent} \\ \rm{tan \: x \: = \: 40 \:/ 34} \\ \rm \: x \: = arctan \: (40 \:/ 34) \\ \: \rm {x \: = \boxed{49. \: 60°}}[/tex]

Answer:

No

Step-by-step explanation:

x⁵ + 2x³ + x - 1  -> degree of  the polynomial is 5

So, when x⁵ is divided by x³, the quotient should be x⁵⁻³ = x².

So, x³ - 3x + 1 cannot be a quotient

Answer:

Step-by-step explanation:

resolver. Álgebra 1

14=4-6x-2

4-6x-2 : 2

Rpta: 2

Answer:2x^2 + 7x - 30

Step-by-step explanation:

1. x(2x-3)(x+3)^2

2. x(2x-3)(x+10)

3. 2x^2+10x-3x-30

4. 2x^2+7x-30

Answer:

Step-by-step explanation:

I'm assuming you need the age of the bowl. Start with the fact that you have remaining 28% of the original amount before any of it decayed. You always start with 100% of something unless you're told differently. That means that the equation looks like this:

[tex]28=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get

[tex].28=e^{-.0001t}[/tex] . To solve for t we have to be able to bring it down from its current position of exponential. To do this we would either take the log or the natural log since the rules for both are the same. However, the natural log is the inverse of e, so they undo each other. We take the natural log of both sides which allows us to pull down the -.0001t. At the same time remember that the natural log and e are inverses of each other so they are both eliminated when we do this.

ln(.28) = -.0001t Now it's easy to solve for t.

[tex]\frac{ln(.28)}{-.0001}=t[/tex] and

[tex]\frac{-1.272965676}{-.0001}=t[/tex] so

t = 12729.65676 years or rounded, 12730 years.

Answer:

x = 12

Step-by-step explanation:

The sum of angles in a triangle is 180°

Thus,

(x + 20) + (10x) + (x + 16) = 180°

Collect like terms

x + 10x + x + 20 + 16 = 180°

12x + 36 = 180°

12x = 180 - 36

12x = 144

Divide both sides by 12

x = 144 ÷ 12

x = 12

Substitute the value of x into the question

Therefore,

x + 20 = 12 + 20

= 32°

10x = 10(12)

= 120°

x + 16 = 12 + 16

= 28°

Answer:

[tex]{ \bf{volume = \pi {r}^{2}h }} \\ = 3.14 \times {7.5}^{2} \times 20 \\ { \tt{volume = 3534.3 \: {cm}^{2} }}[/tex]

Answer:

1

Step-by-step explanation:

Let the number be n.

We are given:

n/12=q1+(7/12) where q1 is the quotient

n/6=q2+(?/6) where q2 is the quotient and ? is the remainder value we are trying to find.

? must be a integer between 0 and 5, inclusive. A remainder cannot be bigger than or equal to the divisor.

Let's rewrite the first equations

Multiply equation 1 on both sides by 2:

n/6=2q1+7/6

Remainder cannot be 7.

Rewrite again.

6 goes into 7 1 time with remainder 1.

n/6=2q1+(1+1/6)

n/6=(2q1+1)+1/6

So q2=2q1+1 and the remainder is 1 when dividing n by 6.

For fun. What is a number n with such conditions on it?

So what number has remainder 7 when divided by 12 and a remainder 1 when divided by 6.

n=12q1+7

n=6q2+1

If q1=1, we find a number right away that works.

19/12=1+7/12

19/6=3+1/6

Answer:

x > 4

Step-by-step explanation:

4x + 3 > 19

4x + 3 - 3 > 19 - 3

4x > 16

4x/4 > 16/4

x > 4

Hope this helps.

[tex]4x + 3 > 19 \\ = > 4x > 19 - 3 \\ = > 4x > 16 \\ = > x > \frac{16}{4} \\ = > x > 4[/tex]

Answer:

x > 4

Hope you could understand.

If you have any query, feel free to ask.

Answer:

mean=14

median =4

Range=3

Step-by-step explanation:

Mean = 4+6+3+1+9+0+5/2

=28/2

=14

Median = ( N+1/2 )th item

= ( 7+1 )/2

= 8/2

= 4

Range = largest no- lowest no

= 9-6

= 3

Step-by-step explanation:

Given that,

The positions of the first particle,[tex]s_1=4t-t^2[/tex]

Velocity,

[tex]v_1=\dfrac{ds_1}{dt}\\\\v_1=\dfrac{d(4t-t^2)}{dt}\\\\v_1=4-2t[/tex]

Position,

[tex]s_2=5t^2-t^3[/tex]

[tex]v_2=\dfrac{ds_2}{dt}\\\\v_2=\dfrac{d(5t^2-t^3)}{dt}\\\\v_2=10t-3t^2[/tex]

Hence, this is the required solution.

Answer:

50

Step-by-step explanation:

Given:

140, 166, 132, 165, 152, 168, 181, 158, 173, 171, 180, 182, 163, 177, 180, 142, 147, 149, 178

Arranging in ascending order (from the lowest to the highest)

= 132, 140, 142, 147, 149, 152, 158, 163, 165, 166, 168, 171, 173, 177, 178, 180, 180 181, 182

Range = highest number - lowest number

= 182 - 132

= 50

Answer:

50

Step-by-step explanation:

              None

Answer:

2144

formula us v = 3/4 × pi × half of the diameter (radius)

=============================================================

Explanation:

Choice B has the GCF x we can factor out like so

10x^4-5x^3+70x^2+3x = x(10x^3-5x^2+70x+3)

Showing that choice B is not prime. If a polynomial can be factored, then we consider it not prime. It's analogous to saying a number like 15 isn't prime because 15 = 3*5, ie 15 can be factored into something that doesn't involve 1 as a factor.

In contrast, we consider 7 prime because even though 7 = 1*7, there aren't any other ways to write this integer as a factorization if we don't involve 1.

-----------------------------------

Choice C is a similar story. This time we can factor out 3

3x^2 + 18y = 3(x^2 + 6y)

So we can rule this out as well.

-----------------------------------

Choice D is a bit tricky, but we can use the difference of cubes factoring rule

a^3 - b^3 = (a-b)(a^2+ab+b^2)

where in this case a = x and b = 3y^2

Note how b^3 = (3y^2)^3 = 3^3*(y^2)^3 = 27y^(2*3) = 27y^6

All of this means choice D can be factored and it's not prime either.

------------------------------------

We've ruled out choices B through D. The answer must be choice A.

If you let w = x^2, then w^2 = x^4

The polynomial w^2+20w-100 is prime because setting it equal to zero and solving for w leads to irrational solutions. I'm assuming your teacher wants you to factor over the rational numbers.

Because w^2+20w-100 can't be factored over the rational numbers, neither can x^4+20x^2-100. This confirms that choice A is prime.

Answer:

[tex]y=|x-(-2)|+2[/tex]

Step-by-step explanation:

Hope this is helpful.

The required absolute function is given as y = |x - 2| + 2.

Given that,
From the graph, y = |x - h| + k, values of h and k is to be determined,

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

Here,
In the graph and function, h represents the shift on the x-axis, which 2 units left so the value of h is 2, while k is given the shift of the function over the y-axis which 2 units up means that k = 2

Thus, The required absolute function is given as y = |x - 2| + 2.

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Answer:

1) 2 × (-15) = -30

It could be 1+12 2+11 3+10 4+9 5+8 6+7 any of those

Step-by-step explanation:

ratio =4:1

total= 4+1 =5

1/5 × 52= 10.4 years

Answer:

Step-by-step explanation:

let age of Shyam=x

age of Ram=x+4

x+x+4=52

2x=52-4=48

2x=48

x=48/2=24

age of Shyam=24 years

age of Ram=24+4=28 years.

Answer:

$ 2,600

Step-by-step explanation:

It's given that 260 People donated $10 is to an organisation . We need to find the total money received by the organisation .

Here we just need to the number of people with the amount each person gave , that is ;

[tex]\implies \rm Total \ amount = \$ 10 \times 260 \\\\\rm\implies Total \ amount = \$ 2,600 [/tex]

Hence the total money received by the organisation is $ 2600 .

Answer:

True

Step-by-step explanation:

The definition of the function is a relation with exactly one x for each y. x is the domain, and y is the range, so all functions have a domain and a range.