ILL GIVE POINTS!!

Suppose a triangle has two sides of length 3 and 4 and that the angle
between these two sides is pi/3 What is the length of the third side of the
triangle?
A. sqrt13
B. 4sqrt3
C. sqrt3
D. 3

Answer:

Step-by-step explanation:

(√63 + 144)/5 = (3√7 + 144)/5 = 0.6√7 + 28.8

Answer:

A = 49/pi

Step-by-step explanation:

C = 2 * pi *r

14 = 2 * pi *r

Divide each side by 2 pi

14/2pi = r

7/pi = r

The area is given by

A = pi r^2

A = pi ( 7/ pi)^2

A  = pi * 49 / pi^2

A = 49/pi

Answer:

[tex]area = {15.61m}^{2} [/tex]

explanation is attached to the picture

Hope this helps you

Answer:

BC = [tex]\frac{12}{13}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

BC² + AC² = AB²

BC² + ([tex]\frac{5}{13}[/tex] )² = 1²

BC² + [tex]\frac{25}{169}[/tex] = 1 ( subtract [tex]\frac{25}{169}[/tex] from both sides )

BC² = [tex]\frac{169}{169}[/tex] - [tex]\frac{25}{169}[/tex] = [tex]\frac{144}{169}[/tex] ( take square root of both sides )

BC = [tex]\sqrt{\frac{144}{169} }[/tex] = [tex]\frac{12}{13}[/tex]

Answer:

7

Step-by-step explanation:

[tex]s = {a}^{2} \: thus \: a = \sqrt{s } = \sqrt{49} = 7[/tex]

Using Pythagorean thereon

[tex]\\ \Large\sf\longmapsto P^2=H^2-B^2[/tex]

[tex]\\ \Large\sf\longmapsto P^2=9^2-6^2[/tex]

[tex]\\ \Large\sf\longmapsto P^2=81-36[/tex]

[tex]\\ \Large\sf\longmapsto P^2=45[/tex]

[tex]\\ \Large\sf\longmapsto P=\sqrt{45}[/tex]

[tex]\\ \Large\sf\longmapsto P=6.3ft[/tex]

Answer:

The center is (9,-8) and the diameter is 8

Step-by-step explanation:

(x − 9)^2 + (y + 8)^2 = 16

A circle is in the form

(x − h)^2 + (y -k)^2 = r^2  where (h,k) is the center and r is the radius

(x − 9)^2 + (y -  -8)^2 = 4^2  

The center is (9,-8) and the radius is 4

The diameter is 2 times the radius so the diameter is 8

The center is (9,-8) and the diameter is 8

Answer:I’m not sure

Step-by-step explanation: try and use the scientific demos

Answer:

120.40 per payment

Step-by-step explanation:

Subtract the down payment

642 - 160.40

481.60

Divide this by 4

481.60 / 4

120.40

1 liter = 1000mL

Divide 1000mL by mL per minute:

1000 / 5 = 200 minutes ( 3 hours and 20 minutes)

Answer:

circumference = 25.12 yards

area = 50.24 yards squared or yd^2

Step-by-step explanation:

circumference = pi * d

3.14 * 8 =

25.12

area = pi* r^2

r = 1/2 of d = 4

area = pi * 16

3.14 * 16 =

50.24

Answer:

Area: 50.24yds^2            Circumference: 25.12yds

Step-by-step explanation:

Area: The formula for area of a circle is a = πr^2.

The radius (r) of the circle is 4yds because it is half the length of the diameter. The equation would like like this:

A = (3.14)(4)^2

A = (3.14)(16)

A = 50.24yds

Circumference: The formula for circumference is 2πr. We already know all of the variables so we can plug them in.

C = 2(3.14)(4)

C = 25.12yds

Hope this helps

Answer:

Step-by-step explanation:

Because those lines are parallel, that means that the angle measuring 75 and the angle measuring 4x + 7 are alternate interior and by definition are congruent. Therefore,

75 = 4x + 7 and

68 = 4x so

x = 17

Answer:

1

Step-by-step explanation:

(1-x)/x=0

or, 1-x=0

or, -x=-1

or, x=1

Answer:

F(x) = 0 when x=1

Step-by-step explanation:

We need the numerator to equal zero

1-x = 0

Add x to each side

1-x+x = 0+x

1 =x

The denominator cannot equal zero( The denominator does not equal zero when x =1)

F(x) = 0 when x=1

Answer:

-14, 9 and - 54/7

Step-by-step explanation:

Answer:

-1

Step-by-step explanation:

[3-4(-1)^4]^3

=>(3-4)^3

=>(-1)^3

=>-1

Answer From Gauth Math

Answer:

-1

Step-by-step explanation:

[tex][3-4*(3-4)^4]^3[/tex]        

[tex](3-4)^4= 1\\Therefore, [3-4*1]^3= -1^3\\So, -1^3= -1\\\\[/tex]

Cube of any negative integer will be negative, or, a negative integer raised to any odd number will be negative. Likewise, a negative integer raised to an even number will be positive.

Answer: (3b+2)(b+2)

Step-by-step explanation:

Given:

The data set is:

0, 1, 1, 1, 2, 3, 4, 4, 6, 6, 9

To find:

The correct statement that represents the box plot of the data correctly.

Solution:

We have,

0, 1, 1, 1, 2, 3, 4, 4, 6, 6, 9

Divide the data in 2 equal parts.

(0, 1, 1, 1, 2), 3, (4, 4, 6, 6, 9)

Divide each parenthesis in 2 equal parts.

(0, 1), 1, (1, 2), 3, (4, 4), 6, (6, 9)

Here,

Minimum value = 0

First quartile = 1

Median = 3

Third quartile = 6

Maximum value = 9

A number line goes from 0 to 10. The whiskers range from 0 to 9, and the box ranges from 1 to 6. A line divides the box at 3.

Therefore, the correct option is D.

Answer:

its d

Step-by-step explanation: my yt Tray Clayps

======================================================

Explanation:

We get this point by doing two things.

If we started with x = -3, then x-2 = -3-2 = -5. Also, if we had y = -1 then y-7 = -1-7 = -8

So that's how we end up with Z(-3,-1) moving to Z ' (-5, -8)

You could also show your work like this

[tex](x,y) \to (x-2, y-7)\\\\(-3,-1) \to (-3-2, -1-7)\\\\(-3,-1) \to (-5, -8)\\\\[/tex]

Answer: [tex]9\sqrt{2}[/tex]

Step-by-step explanation:

Use the Pythagorean Theorem:

[tex]9^{2} +9^{2} =x^{2}\\x=\sqrt{9^{2} +9^{2}} =\sqrt{2(9)^{2} } =9\sqrt{2}[/tex]

Answer:

18.45

Step-by-step explanation:

I used a calculator

Answer:

i think you just extend the coordinates to the side, except the right point, by 3, and then the bottom ones go down by 3, and the top one goes up by 3

Step-by-step explanation:

Part 1

[tex]\left(\frac{g}{h}\right)(x) = \frac{g(x)}{h(x)}\\\\\left(\frac{g}{h}\right)(x) = \frac{3x-5}{-2x^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{3(3)-5}{-2(3)^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{4}{-11}\\\\\left(\frac{g}{h}\right)(3) = -\frac{4}{11}\\\\[/tex]

Answer:  -4/11

====================================================

Part 2

Set the denominator function equal to zero and solve for x to find which values to kick out of the domain.

[tex]h(x) = 0\\\\-2x^2+7 = 0\\\\7 = 2x^2\\\\2x^2 = 7\\\\x^2 = 7/2\\\\x^2 = 3.5\\\\x = \sqrt{3.5} \ \text{ or } x = -\sqrt{3.5}\\\\[/tex]

This shows that if x is equal to either of those values, then the denominator h(x) will be zero. These are the values to kick out of the domain to prevent a division by zero error. Any other value of x is valid in the domain.

Answer: [tex]x = \sqrt{3.5} \text{ and } x = -\sqrt{3.5}\\\\[/tex]

Answer:

Step-by-step explanation:

When we take an average of something, we have to add up all the data on the somethings and then divide by the number of somethings we have. Ed takes 5 tests, and we have scores for them; we also have his current average. What we don't know for sure are 2 of the 5 test scores, but we have enough to determine what they are.

If one test has a score of x, and the other test is 3 points less than that, the score on that last test is x - 3. Putting all of that together into an average problem:

[tex]\frac{87+85+87+x+(x-3)}{5}=90[/tex] and simplfiying a bit:

[tex]\frac{256+2x}{5}=90[/tex]. Multiply both sides by 5 to get

256 + 2x = 450; subtract 256 from both sides to get

2x = 194 and divide by 2:

x = 97

The one test score was a 97 and the other one, which was 3 less than that, was a 94.

Answer:

[tex]55[/tex]

Step-by-step explanation:

We'll be using case-work to solve this problem. Let's call the ones digit of the telephone number [tex]B[/tex] and the tens digit [tex]A[/tex]. Each telephone number can be represented as [tex]AB[/tex].

Since the question states that numbers that are smaller when their digits are reversed are not used, we have the following inequality:

[tex]B\geq A[/tex]

This is because if [tex]A>B[/tex], the number would become smaller when [tex]A[/tex] and [tex]B[/tex] are switched in [tex]AB[/tex]. However, if [tex]A=B[/tex] or [tex]B>A[/tex], the number will not become smaller.

Let's work our way up starting with [tex]A=0[/tex]. If [tex]A=0[/tex], there are 10 other numbers (0-9) that we can choose for [tex]B[/tex] that adhere to the condition [tex]B\geq A[/tex]:

[tex]0B,\\01, 02, 03,...[/tex]

Therefore, there are 10 possible telephone numbers when the tens digit is 0.

Repeat the process, now assigning [tex]A=1[/tex]. Now, we only have the digits 1-9 to choose from for [tex]B[/tex], since [tex]B[/tex] needs to be greater than or equal to A. Therefore, there are 9 possible telephone numbers when the tens digit is 1.

This pattern continues. As we work our way up through the cases (when increasing [tex]A[/tex] by 1), the number of possible telephone numbers decreases by 1, since there becomes one less option for [tex]B[/tex].

The last case would be [tex]A=9[/tex] in which case there would only be one option for [tex]B[/tex] and that would be 9.

Since there are 10 cases (0-9), add up the possible telephone numbers for each case:

[tex]\displaystyle \sum_{n=1}^{10}n=1+2+3+4+5+6+7+8+9+10=\boxed{55}[/tex]

Alternatively, recall that the sum of this series can be found using [tex]\frac{n(n+1)}{2}[/tex], where [tex]n[/tex] is the number of values in the set. In this case, [tex]n=10[/tex], and we have:

[tex]1+2+3+4+5+6+7+8+9+10=\frac{10(11)}{2}=\frac{110}{2}=\boxed{55}[/tex]

Answer: B

Step-by-step explanation:

Its written in slope intercept form not standard

Answer:

6.8=6 8/5

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hope it help

Answer:

It is over 7 days

hope it helps

Answer:

the missing values is 5

I hope it's helps you

In this question, a piece-wise function is asked to be graphed.

Piece-wise function:

A piece-wise function is a function that has different definitions, depending on the input.

In this question, the function has three different definitions:

For x between -1(inclusive) and 0, y takes a constant value of -1.

For x between 0(inclusive) and 1, y takes a constant value of -2.

For x between 1(inclusive) and 2, y takes a constant value of -3.

Additionally:

At the inclusive points, the interval is circled, and thus, the graphic is given at the end of this answer.

For another example of the graphic of a piece-wise function, you can check https://brainly.com/question/16855064

Answer:

Step-by-step explanation:

1. (1, 3); (2, 3)

2. (0, 0) (1, 0)

3. (-1, 1) (0,0)

Answer:

It's actually: None of these.

Think about it: In this case we have an inequality, of x ≤ 0.

This basically means, that x can be less than OR equal to 0.

But 0 is neither negative or positive, so we can eliminate the following answer choices:

- all positive integers

- all negative real numbers

- all positive real numbers

- all negative integers

And we are left with "None of these"

Let me know if this helps!

Option B is correct. None of these options is the right answer since zero is neither an integer nor a real number

Before we can decide which option is correct, first we must integers and real numbers are.

Given the set of numbers {x | x ≤ 0}. The set of numbers in the set will be all integers less than zero including zero (zero is not an integer)

Hence the set of numbers are not all negative integers since 0 is not a negative integer.

They are not all positive integers rather they are mostly negative integers

They are not all positive and negative real values because zero is not a real integer.

Hence we can conclude that None of the options is correct.

Learn more here: https://brainly.com/question/2691012